The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N
The mass of the baseball, m = 0.15 kg
The speed at which it moves, v = 30 m/s
Time at which the baseball was in contact with the bat, t = 0.75 ms
t = 0.75/1000 s
t = 0.00075 s
The impulsive force is given by the formula:
[tex]F=\frac{mv}{t}[/tex]
Substitute m = 0.15 kg, v = 30, and t = 0.00075s into the formula above:
[tex]F=\frac{0.15 \times 30}{0.00075} \\\\F=6000N[/tex]
The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N
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SOMEONE PLEASE HELP MEEEEEEE
Answer:
Weathering and erosion
Explanation:
25 gram saturated solution of potassium nitrate at 95 C is cooled down to 55 C then how much gram of crystals of potassium nitrate will be separated if the solubility of potassium nitrate at 95 c is 100 and 55 C is 25 correspondingly
The mass of potassium nitrate (KNO₃) crystals that will be separated is calculated as 6.25 g.
The given parameters:
Mass of KNO₃ = 25 gInitial temperature = 95 ⁰CFinal temperature = 55 ⁰CSolubility at 95 ⁰C = 100 MSolubility at 55 ⁰C = 25 MThe mass of KNO₃ at 95 ⁰C is calculated as follows;
[tex]m = \frac{25\ g \times 100\ g}{100\ g} \\\\m = 25 \ g[/tex]
mass of water = 100 g - 25 g = 75 g
The mass of KNO₃ at 55 ⁰C is calculated as follows;
[tex]m = \frac{75 \ g \times 25 \ g}{100 \ g} \\\\m = 18.75 \ g[/tex]
The mass of potassium nitrate (KNO₃) crystals that will be separated is calculated as;
[tex]m= 25\ g \ - \ 18.75 \ g\\\\m = 6.25 \ g[/tex]
Thus, the mass of potassium nitrate (KNO₃) crystals that will be separated is calculated as 6.25 g.
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A 1200 kg car moves due north with a speed of 15m/s. An identical car moves due east with the same speed of 15m/s what are the direction and the magnitude of the system’s total momentum
a.
The direction of the total momentum is 45°
The momentum of the first car is given by p = mv where m = mass of car = 1200 kg and v = velocity of car = 15 m/sj (since it moves due north).
So, p = mv
= 1200 kg × (15 m/s)j
= (18000 kgm/s)j
Also, the momentum of the identical car, p' = mv' where m = mass of car = 1200 kg and v' = velocity of car = (15 m/s)i (since it moves due east).
So, p' = mv'
= 1200 kg × (15 m/s)i
= (18000 kgm/s)i
So, the total momentum of the system P = p + p'
= (18000 kgm/s)j + (18000 kgm/s)i
= (18000 kgm/s)i + (18000 kgm/s)j
The direction of the total momentum of the system P is gotten from
tanФ = p'/p
= 18000 kgm/s ÷ 18000 kgm/s
= 1
Ф = tan⁻¹(1)
= 45°
The direction of the total momentum is 45°
b.
The magnitude of the total momentum of the system is 25455.84 kgm/s
The magnitude of the total momentum of the system P = √(p'² + p²)
= √[(18000 kgm/s)² + (18000 kgm/s)²]
= (18000 kgm/s)√(1 + 1)
= (18000 kgm/s)√2
= 25455.84 kgm/s
The magnitude of the total momentum of the system is 25455.84 kgm/s
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The mass of a car is 625kg. Calculate the weight of the gravitational field strength is 10 N/kg.
Ans: 62.5
Explanation: [tex]F{net}[/tex] = m x a
1N = 1kg x 1m/ [tex]s{2}[/tex]
If a person climbed Mt. Everest has a mass of 105 kg and a weight of 625 N what would be the acceleration due to gravity?
The acceleration due to gravity would be 5.95 m/s²
A force is known to be a push or pull and it is the change in momentum per time. It can be expressed by using the relation.
Force = mass × acceleration.From the parameters given:
Mass = 105 kgForce = 625 NBy replacing the given values into the above equation, we can determine the acceleration.
∴
625 N = 105 kg × acceleration.
[tex]\mathbf{acceleration = \dfrac{625 \ N}{105 \ kg}}[/tex]
acceleration = 5.95 N/kg
Since 1 N/kg = 1 m/²acceleration = 5.95 m/s²
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During take-off a 8kg model rocket is burning fuel causing its speed to increase
at a rate of 4m/s2 despite experiencing a 90N drag.
What’s is the strength of the thrust?
(Answer unit is in N)( and the answer isn’t 212)
The strength of the thrust is 122 newtons.
The motion of the rocket is described by the second Newton's law, whose model is shown below:
[tex]\Sigma F = F - D = m\cdot a[/tex] (1)
Where:
[tex]F[/tex] - Thrust, in newtons[tex]D[/tex] - Drag, in newtons[tex]m[/tex] - Mass of the rocket, in kilograms[tex]a[/tex] - Net acceleration of the rocket, in meters per square secondIf we know that [tex]D = 90\,N[/tex], [tex]m = 8\,kg[/tex] and [tex]a = 4\,\frac{m}{s^{2}}[/tex], then the strength of the thrust is:
[tex]F = D + m\cdot a[/tex]
[tex]F = 90\,N + (8\,kg)\cdot \left(4\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 122\,N[/tex]
The strength of the thrust is 122 newtons.
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Which feature of a balanced chemical equation demonstrates the law of
conservation of mass?
O A. It has the same types of atoms on both sides of the reaction
arrow.
O B. It shows the reactants of a chemical reaction to the left of the
reaction arrow.
O C. It has coefficients to show how much of each substance a
chemical reaction uses.
Thing
D. It shows the products of a chemical reaction to the right of the
reaction arrow.
Answer: A) It has the same types of atoms on both sides of the reaction
arrow.
Explanation: A balanced equation demonstrates the conservation of mass by having the same number of each type of atom on both sides of the arrow.
Where do inherited traits come from
Answer:
Your parents or anyone in your ancestry.
Explanation:
An action that has the ability to change an object’s state of motion is
Answer:
An unbalanced force
Explanation:
Answer:
Force
Explanation:
Trust me
22 Newton force is working on a 1,901 gram object. What is the acceleration in
meter/s^2 unit
Answer:
11.573
Explanation:
f = m*a
where f is the force in Newtons, m is the mass of the object (in kg) and a is the acceleration
so, we solve for a
a = f/m
a = 22/1.901
a = 11.573
The slope of a line on a distant-time graph is
A. distance
B. time
C. speed
Answer:
c. speed
Explanation:
In a distant-time graph the x value is usually the time and the y value is usually the distance.
If slope is the change in y over the change in x, on a distant time graph the slope would be the change in time over the change in distance
Or time / distance.
Time / distance happens to calculate speed.
Thus, the slope of a line on a distant-time graph is speed.
[tex]\huge\textbf{Hey there!}[/tex]
[tex]\large\textbf{The formula for Slope of a line is: }\mathbf{m = \dfrac{rise}{run}}\large\textbf{ whereas it is}\\\large\textbf{equal to/equivalent to }\mathbf{ \dfrac{y_2 - y_1}{x_2- x_1} \ .}\\\\\large\textbf{Basically, the slope of the line is measured with its }\\\large\textbf{\underline{steepness}. The word steepness simply means a}\\\lage\textbf{very sharp slope.}[/tex]
[tex]\large\textbf{On slope of a line on distant-time graph is basically how }\\\large\textbf{ \boxed{\bf FAST} a particular object is.}[/tex]
[tex]\large\textbf{Now, that we got that information out of the way we}\\\large\textbf{can find out our answer.}[/tex]
[tex]\large\textbf{The formula for distance is: }\mathbf{d= \sqrt{(x_2 - x_1)^2 + (y_2 +y_1)^2}}}[/tex]
[tex]\large\textsf{We cannot say that OPTION A isn't your answer because you}\\\large\textsf{cannot calculate slope of a line on a distant-time graph. You}\\\large\textsf{cannot calculate the speed of the object by using that formula.}\\\large\textsf{So, this eliminates Option A. as your answer.}[/tex]
[tex]\large\textbf{The formula of time is: }\mathbf{time = \dfrac{distance}{speed}}[/tex]
[tex]\large\textsf{Yes, it calculates the distance but it doesn't calculate how fast a(n)}\\\large\textsf{object is going. So this eliminates Option B. as your answer.}[/tex]
[tex]\large\textsf{The formula for speed is: }\mathbf{s = \dfrac{d}{t}}\large\textbf{ whereas s = \underline{speed}, }\\\large\textsf{d = \underline{distance} you have \underline{traveled}, \& t = \underline{time} that has}\\\large\textsf{been \underline{elapsed}.}\\\large\textsf{Option C. could possibly be your answer}[/tex]
[tex]\large\textbf{Option C. seems to be the closes to your result than the}\\\large\textbf{to your answer.}[/tex]
[tex]\large\boxed{\text{Therefore, your answer should be: \boxed{\textbf{Option C. Speed}}}}\huge\checkmark[/tex]
[tex]\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
i just want an answer please
Answer: An answer on what? I’ll never ignore you!
Explanation:
Answer:
an answer on what?
Explanation: Im here to help!!
Why is acceleration of an object moving at a constant velocity always zero?
Answer:
If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).
Explanation:
In the middle, when the object was changing position at a constant velocity, the acceleration was 0. This is because the object is no longer changing its velocity and is moving at a constant rate.
write the function of alcohol in a alcohol thermometer.
Answer:
Ethanol-filled thermometers are used in preference to mercury for meteorological measurements of minimum temperatures and can be used down to −70 °C (−94 °F). The physical limitation of the ability of a thermometer to measure low temperature is the freezing point of the liquid used.
Use the periodic table to answer the question.
An illustration shows the periodic table of elements with elements arranged in increasing order of atomic number in 18 columns (groups) and 7 rows (periods).
Which comparison is correct?
(1 point)
PH3 is a stronger acid than NH3.
PH, 3, is a stronger acid than NH, 3, .
HF is a stronger acid than HCl.
HF is a stronger acid than HCl.
H2S is a stronger acid than HCl.
H, 2, S is a stronger acid than HCl.
NH3 is a stronger acid than HF.
Answer:
A: P and N are both nonmetals, same strength: No
B: Most likely not
C: Same saying as B
D: Most likely yes
Explanation:
I don't actually know if i'm right, I just want to help you okay, so if it's wrong than sorry. Also I couldn't tell if the CI is a Ci(17) or CL(6+53)
Part reason why I was saying that B and C are most likely incorrect. And D the NH3 has more value than HF (if I remember)
As per the given situation, [tex]PH_3[/tex] is stronger acid than [tex]NH_3[/tex]. The correct option is A.
What is an acid?Any substance that tastes sour in water, turns blue litmus paper red, reacts with some metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions is considered an acid (acid catalysis).
Because strong acids have mostly ions in solution, the bonds that hold H and A together must be weak. Strong acids easily dissociate into ions.
Because weak acids exist primarily as molecules with only a few ions in solution, the bonds that hold H and A together must be strong.
[tex]PH_3[/tex] is a more potent acid than [tex]NH_3[/tex]. as PH3 has a pKa of -5.5 and [tex]NH_3[/tex] has a pKa of 9.9.
Thus, the correct option is A.
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In a police ballistics test, 2.00-g bullet traveling at 700 m/s suddenly hits and becomes embedded in a stationary 5.00-kg wood block. What is the speed of the block immediately after the bullet has stopped moving relative to the block
Answer:
Here we use the conservation of momentum theorem.m stands for mass, and v stands for velocity. The numbers refer to the respective objects.
m1v1 + m2v2 = m1vf1 + m2vf2
Since the equation is perfectly inelastic, the final velocity of both masses is the same. Let’s account for this in our formula.
m1v1 + m2v2 = vf(m1 + m2)
Let’s substitute in our givens.
(0.002 kg)(700 m/s) + (5 kg)(0 m/s) = vf(0.002 kg + 5 kg)
I assume you are proficient in algebra I, so I will not include the steps to simplify this equation.
Note that I have considered the bullet’s velocity to be in the positive direction,
The answer is vf = 0.280 m/s
The planar simple harmonic wave travels in the positive direction of x axis with wave velocity u=2m/s, and the vibration curve of the particle at the origin in cosinusoidal form is shown in the figure.
Try to find (1) the vibration function of the particle at the origin, (2) the wave function of the planar simple harmonic wave according to the origin.
The planar simple harmonic wave travels in the positive direction of x axis with wave velocity u=2m/s, and the vibration curve of the particle at the origin in cosinusoidal form is shown in the figure.
Try to find (1) the vibration function of the particle at the origin, (2) the wave function of the planar simple harmonic wave according to the origin.
Answer:
Figure 16.8 The pulse at time
t
=
0
is centered on
x
=
0
with amplitude A. The pulse moves as a pattern with a constant shape, with a constant maximum value A. The velocity is constant and the pulse moves a distance
Δ
x
=
v
Δ
t
in a time
Δ
t
.
The distance traveled is measured with any convenient point on the pulse. In this figure, the crest is used.
If you have to measure the temperature > above 80°c, do you use an alcohol or mercury thermometer? why?
Answer:
I use mercury thermometer to measure the temperature above 80°C because the boiling point of alcohol is 78°C . So, it can't measure the temperature above 78°C.
How do I measure the drag of a paper airplane?
Answer:
hmmmmm ill get back later
Explanation:
Please help
According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:
A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.
B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.
D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
Answer:
don't know ....?
Explanation:
Please help
According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:
A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.
B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.
D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
3. a car takes off with initial velocity of 20m/s and move with uniform acceleration of 12m/s2 for 20s. It maintained a constant velocity for 30s and come to rest with uniform acceleration of 2m/s2. Calculate the total distance covered by the car.
The total distance traveled by the car at the given velocity and time is 900 m.
The given parameters:
initial velocity of the car, u = 20 m/sacceleration of the car, a = 12 m/s²time of motion of the car, t = 20 sfinal time = 30 sfinal acceleration = 2 m/s²The final time of motion of car before coming to rest is calculated as follows;
[tex]v_f = v_0 -at\\\\0 = 20 - 2t\\\\t = 10 \ s[/tex]
The graph of the car's motion is in the image uploaded.
The total distance traveled by the car is calculated as follows;
[tex]total \ distance = A \ + B \ + C\\\\total \ distance = (\frac{1 }{2} \times 20 \times 20) \ + (20 \times 30) \ + (\frac{1}{2}\times 10 \times 20)\\\\total \ distance = 900 \ m[/tex]
Thus, the total distance traveled by the car at the given velocity and time is 900 m.
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1. Wha' is the relationship between potential and kinetic energy?
As potential energy increases, kinetic energy increases.
b. As potential energy increases, kinetic energy decreases.
C. As potential energy decreases, kinetic energy decreases.
d. Potential and kinetic energy are two separate things and have no
relationship.
Answer:
B
Explanation:
The kinetic energy in an object is converted into potential energy. This makes the kinetic decrease, while the potential increases.
During what time period does the balloon drift in a counterclockwise direction?
An automobile moving along a straight track changes its velocity from 40 m/s to 80 m/s in a distance of 200 m. What is the (constant) acceleration of the vehicle during this time
Answer:
[tex]\huge\boxed{\sf a = 1200\ m/s\²}[/tex]
Explanation:
Given Data:
Initial Velocity = Vi = 40 m/s
Final Velocity = Vf = 80 m/s
Distance = S = 200 m
Required:
Acceleration = a = ?
Formula:
2aS = Vf² - Vi² (THIRD EQUATION OF MOTION)
Solution:
2a (200) = (80)² - (40)²
400a = 6400 - 1600
400a = 4800
Divide 400 to both sides
a = 4800 / 400
a = 1200 m/s²
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807If an object accelerates from rest, what will its velocity be after 1.3 s if it has a constant acceleration of 9.1 m/s^2?
[tex]\text{Given that,}\\\\\text{Initial velocity,} ~v_0 = 0~ \text{m~s}^{-1}\\\\\text{Time, t = 1.3~sec}\\\\\text{Acceleration, a = 9.1 m s}^{-2}\\\\\\\\\text{Velocity,}\\\\v = v_0 +at\\\\\implies v = 0 + 9.1 \times 1.3 = 11.83~~ \text{m~s}^{-1}[/tex]
n a distant solar system, a planet of mass 5.0 x 1024 kg orbits a sun of mass 3.0 x 1030 kg at a constant distance of 2.0 x1011 m. How many earth days does it take for the planet ot execute one complete orbit about the sun
Answer:
F = M2 ω^2 R centripetal force of sun on planet
ω = (F / (M2 R))^1/2 = 2 pi f = 2 pi / P where P is the period
P = 2 pi (M2 * R / F)^1/2
F = G M1 M2 / R^2 gravitational force on planet
P = 2 pi {R^3 / (G M1)]^1/2
P = 6.28 [(2.0E11)^3 / (6.67E-11 * 3.0E30)]^1/2
P = 6.28 (8 / 20)^1/2 E7 = 3.9E7 sec
1 yr = 3600 * 24 * 365 = 3.15E7 sec
P = 3.9 / 3.2 = 1.2 years
what is dispersion of light?
Answer:
[tex] \huge \bold \blue{ \underline{ answer}}[/tex]
The splitting up of light into its constituent colours while passing from one medium to the other is called dispersion.
The fastest possible rate of rotation of a planet is that for which the gravitational force on material at the equator just barely provides the centripetal force needed for the rotation. Calculate the minimum rotation period assuming a density of 3.70 g/cm3.
Answer:
m ω^2 R = centripetal force
G M m / R^2 = gravitational force
ω^2 = G M / R^3 for the forces to be equal
d (density) = M / V = M / (4/3 R^3) = 3/4 M / R^3
or M / R^3 = 4 d / 3
Then
ω^2 = G 4 d / 3
d = 3.7 g/cm^2 = 3700 kg/m*3 converting
ω^2 = 6.67E-11 * 3700 * 4 / 3 = 32.9E-8
ω = 5.74E-4
P = 1 / f = 2 pi / ω = 6.28 / 5.74E-4 = 1.09E4 sec
10900 / 3600 = 3.04 hrs for the minimum rotation period
what type of stretching is beneficial for sports performance and involves momentum
Answer:
Dynamic stretching
Explanation:
Dynamic stretching is a form of stretching beneficial in sports utilizing momentum from form.
A ball is launched as a projectile with initial speed v at an angle θ above the horizontal. using conservation of energy, find the maximum height hmax of the ball's flight. express your answer in terms of v, g, and θθ.
Answer:
Explanation:
I will us θ as the angle above horizontal as I don't know how to make your chosen symbol for angle.
KEy = PE
½m(vsinθ)² = mgh
h = (vsinθ)²/2g