The Answer is 3.501591994
Explanation:
area of circle = πr^2
radius=
39.5 = 22/7*r^2
r^2 = 7*39.5/22
= 12.56
r=3.5
Does the sun rotate on an axis? Explain your answer using evidence from the video.
Answer:
yes it rotates on its own axis
Explanation:
rotation is the movement/spinning of the earth on its own axis
revolution is the movement of the earth around the sun
Answer:
yes, otation is the movement/spinning of the earth on its own axisrevolution is the movement of the earth around the sun
Explanation:
Does anyone have any idea what this means lol
Answer:
29.42 Litres
Explanation:
The general/ideal gas equation is used to solve this question as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K
According to the information provided in this question;
mass of nitrogen gas (N2) = 25g
Pressure = 0.785 atm
Temperature = 315K
Volume = ?
To calculate the number of moles (n) of N2, we use:
mole = mass/molar mass
Molar mass of N2 = 14(2) = 28g/mol
mole = 25/28
mole = 0.893mol
Using PV = nRT
V = nRT/P
V = (0.893 × 0.0821 × 315) ÷ 0.785
V = 23.09 ÷ 0.785
V = 29.42 Litres
Organisms trying to get the same resource.
Mutualism
Predation
Competition
Symbiosis
Which type of star has the greatest temperature on the HR diagram? Question 7 options: Red Supergiants Main Sequence White Dwarfs Red Giants
Answer:
Red supergiant
Explanation:
Their core is the hottest.
plz mark me as brainliest.
In the reaction, Hydrogen + Iodine --> Hydrogen Iodide at equilibrium, some Iodine is is added. What happens to the equilibrium?
Answer:
the concentration of hydrogen iodide will be higher than it was in the original equilibrium conditions.
2. A sample of helium gas has a volume of 200.0 mL at 0.960 atm. What pressure, in atmospheres, is needed to reduce the volume at constant tem-perature to 50.0 mL?
Answer:
3.840 atm
Explanation:
We use Boyle's law, which relates the pressure (P) and the volume (V) of a gas at a constant temperature. The change from initial P and V (P₁ and V₁) to final P and V (P₂ and V₂) is expressed as:
P₁V₁ = P₂V₂
We have the following data:
P₁= 0.960 atm
V₁= 200.0 mL
V₂ = 50.0 mL
Thus, we introduce the data in the equation and calculate the final pressure P₂:
P₂ = P₁V₁/V₂= (0.960 atm x 200.0 mL)/50.0 mL = 3.840 atm
Therefore, a pressure of 3.840 atm is needed to reduce the volume of the gas from 200.0 mL to 50.0 mL.
IS ANYONE GOOD AT CHEMISTRY?! like frr.
I need help
What are the 4 main layers of the Earth's Atmosphere?
Answer:
troposphere, stratosphere, mesosphere, thermosphere and exosphere
Explanation:
Why do you think some people prefer genetically modified food?
What mass of ethanol can you boil with 9986 J if the heat of vaporization is 854 J/g?
Answer:
51,069.2 J
Explanation:
Use the heat of vaporization formula:
q=m⋅Hv
The heat of vaporization of ethanol is 854 J/g (given in the question), which means that it takes 854 joules of energy to vaporize one gram of ethanol.
Since we have 59.8 grams of ethanol, plug 59.8 into the formula and multiply by 854.
q = (59.8) (854)
q= 51069.2 J
hope this helped somehow
6
Use the image of an element square to answer the following
questions:
C
Carbon
12.01
What does the 6 in the upper left
represent?
What does the 12.01 represent?
Answer:
the 6 stands for the atomic number
the 12.01 stands for the atomic mass
What is the difference between an imprint and an impression?
Answer:
As nouns the difference between impression and imprint
is that impression is the indentation or depression made by the pressure of one object on or into another while imprint is an impression; the mark left behind by printing something.
The term imprint is defined as to mark by or as if by pressure and the term impression is defined as the effect produced by impressing.
What is the difference between an imprint and an impression?The difference between an imprint and an impression is that the imprint is the mark left behind when anything is printed, whereas the impression is the indentation or depression caused by the pressure of one object against or into another.
While a shoe won't make an impression in loose sand, it will on a hard surface like concrete or linoleum. These imprints or impressions might be contrasted with the shoe of a suspect or the tire of a car to see if they belong to the same object.
Thus, The term imprint is defined as to mark by or as if by pressure and the term impression is defined as the effect produced by impressing.
To learn more about the imprint and the impression, follow the link;
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Question 26 of 33
How many energy levels contain electrons in an atom of calcium (Ca)?
The Periodic Table
A. Three
B. Four
C. One
D. Two
Answer:
B
Explanation:
four electron in atom in cal
A gas of certain mass occupies volume of 1.2 L at 37°C and 3 atm. At what temperature will the volume and pressure of this gas become one-third of their initial values?
Answer: At a temperature of 34.44 K the volume and pressure of this gas become one-third of their initial values.
Explanation:
Given : [tex]V_{1}[/tex] = 1.2 L, [tex]T_{1} = 37^{o}C = (37 + 273) K = 310 K[/tex]
[tex]P_{1}[/tex] = 3 atm, [tex]V_{2} = \frac{1.2}{3} = 0.4 L[/tex] , [tex]P_{2} = \frac{3}{3} = 1 atm[/tex]
Formula used to calculate the final temperature is as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{3 atm \times 1.2 L}{310 K} = \frac{1 atm \times 0.4 L}{T_{2}}\\T_{2} = \frac{1 atm \times 0.4 L \times 310 K}{3 atm \times 1.2 L}\\= \frac{124}{3.6} K\\= 34.44 K[/tex]
Thus, we can conclude that the final temperature is 34.44 K.
How many moles of calcium oxide are formed when 3 moles of calcium react with oxygen?
Answer:
3 moles of calcium oxide are formed
Explanation:
Based on the reaction of Calcium Ca, with oxygen, O₂, to produce calcium oxide, CaO is:
2Ca + O₂ → 2CaO
where 2 moles of calcium produce 2 moles of Calcium oxide.
That means, if 3 moles of Ca react in presence of oxygen:
3 moles of calcium oxide are formed
What is the molarity of a 511 ml solution containing
205 mg of NH3?
Answer: The molarity of given solution is 0.0235 M.
Explanation:
Given : Volume of solution = 511 mL
Convert mL into L as follows.
[tex]1 mL = 0.001 L\\511 mL = 511 mL \times \frac{0.001 L}{1 mL}\\= 0.511 L[/tex]
Mass of [tex]NH_{3}[/tex] (solute) = 205 mg
Convert mg into gram as follows.
[tex]1 mg = 0.001 g\\205 mg = 205 mg \times \frac{0.001 g}{1 mg}\\= 0.205 g[/tex]
As molar mass of [tex]NH_{3}[/tex] is 17 g/mol. Hence, number of moles of [tex]NH_{3}[/tex] are calculated as follows.
[tex]No. of moles = \frac{mass given}{molar mass}\\= \frac{0.205 g}{17 g/mol}\\= 0.012 mol[/tex]
Molarity is the number of moles of a solute dissolved in a liter of solution.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}[/tex]
Substitute the values into above formula as follows.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.012 mol}{0.511 L}\\= 0.0235 M[/tex]
Thus, we can conclude that the molarity of given solution is 0.0235 M.
A partir de 140 g de n2 y una cantidad de h2 se obtuvo 153G de NH³. Cual es el % de rendimiento de la reacción química
Respuesta:
90.0 %
Explicación:
Paso 1: Escribir la ecuación química balanceada
N₂ + 3 H₂ ⇒ 2 NH₃
Paso 2: Calcular el rendimiento teórico de NH₃ a partir de 140 g de N₂
En la ecuación balanceada, participan de N₂: 1 mol × 28.01 g/mol = 28.01 g y de NH₃: 2 mol × 17.03 g/mol = 34.06 g.
140 g N₂ × 34.06 g NH₃ /28.01 g N₂ = 170 g NH₃
Paso 3: Calcular el rendimiento porcentual de NH₃
El rendimiento experimental de NH₃ es 153 g. Podemos calcular el rendimiento porcentual usando la siguiente fórmula.
R% = rendimiento experimental / rendimiento teórico × 100%
R% = 153 g / 170 g × 100% = 90.0 %
An unopened, cold 2.00 L bottle of soda contains 46.0 mL of gas confined at a pressure of 1.30 atm at a temperature of 5.0 ℃. If the bottle is dropped into a lake and sinks to a depth at which the pressure is 1.52 atm and the temperature is 2.09 ℃, what will be the volume of the gas in the bottle? Explanation needed
Answer:
[tex]V_2= 38.9mL[/tex]
Explanation:
Hello there!
In this case, since this is a problem about the combined gas law because the temperature, volume and pressure undergo a change:
[tex]\frac{P_2V_2}{T_2}= \frac{P_1V_1}{T_1}[/tex]
Thus, since we need the final volume, V2, we solve for it as shown below:
[tex]V_2= \frac{P_1V_1T_2}{T_1P_2}[/tex]
Now, we plug in the data to obtain:
[tex]V_2= \frac{1.30atm*46.0mL*(2.09+273)K}{(5+273)K*1.52atm}\\\\V_2= 38.9mL[/tex]
Best regards!
A 1.0 g sample of which substance contains the largest
number of molecules?
Answer:
Hydrogen (since this is all the info I'm working with)
Explanation:
Since we need to know how which substance has the most amount of molecules, we would need to look at the Atomic masses of these elements. Hydrogen has an atomic mass of 1.01g/mol whereas something like oxygen has an atomic mass of 16.00g/mol. Judging this, we can determine since a mole is made up of 6.02*10^23 molecules(Avogadro's number), and we have 1/1.01grams of hydrogen, we can deduce that Hydrogen would contain the largest amount of molecules
there is 115 mL of a gas is at 45.8 kPa and 57.2°C. What is the volume of the gas at 99.3 kPa and 112.3°C?
Answer:
115 mL of a gas is at 45.8 kPa and 57.2°C. What is the volume of the gas at 99.3 kPa and 112.3°C?[5] 11. ... What is the pressure of 62.76 g of carbon dioxide (CO2) gas if it occupies a volume of 35,000 mL at standard temperature?
Explanation:
By using gas law , the volume will be 61.9 mL .
What is gas law?
According to the gas law, the pressure of a gas generally directly proportional to its temperature at a fixed volume.
Gas law can be represented as:
[tex]P_{1} V_{1}/ T_{1} = P_{2} V_{2} / T_{2}[/tex]
Calculation of volume with the aid of gas law:
It is given that, [tex]P_{1}[/tex] = 45.8 kPa, [tex]P_{2}[/tex] = 99.3 kPa , [tex]T_{1}[/tex] = 57.2°C, [tex]T_{2}[/tex] = 112.3°C, [tex]V_{1}[/tex] = 115 mL .
Now, put the values of given data in gas laws equation.
(45.8kPa)(115mL)/(330K)= (99.3kPa)([tex]V_{2}[/tex])(385.3K)
[tex]V_{2}[/tex] = 61.9 mL
Therefore, the volume will be 61.9 mL .
To know more about gas law click here.
https://brainly.com/question/12669509.
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A 45.0 cm3 sample of gas is heated from 280. K to 315 K. What is the new volume of the gas sample?
Answer:
50.63 cm³
Explanation:
Using Charles law equation as follows:
V1/T1 = V2/T2
Where;
V1 = initial volume (cm³)
V2 = final volume (cm³)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the question, V1 = 45.0 cm³, V2 = ?, T1 = 280 K, T2 = 315 K
Using; V1/T1 = V2/T2
45/280 = V2/315
Cross multiply
45 × 315 = 280 × V2
14175 = 280V2
V2 = 14175 ÷ 280
V2 = 50.625
V2 = 50.63 cm³
Brainliest grind of 2014i-
Answer:
IM just too pogchamp
Explanation:
Solve for 1. Enter the solutions from least to greates (x + 3)2 - 4= 0 lesser ,greater
Answer:
Explanation:
If you would like to solve 1/(x + 3) = (x + 10)/(x - 2), you can do this using the following steps:
1/(x + 3) = (x + 10)/(x - 2)
1 * (x - 2) = (x + 10) * (x + 3)
x - 2 = x^2 + 3x + 10x + 30
0 = x^2 + 13x + 30 - x + 2
0 = x^2 + 12x + 32
0 = (x + 8) * (x + 4)
1. x = -8
2. x = -4
What is the net ionic equation for ammonium carbonate and barium nitrate?
What is the volume, in liters, of 573 g of SO2 gas at STP?
Answer:
Explanation:
The answer is 202
PLEASE HELP PLEASE!!ASAP!
Answer:
The mass of oxygen will be 19.53g
How long will it take for the 1.35 mg sample of Pt-236 in to decay to 1.00 mg, half life of Pt-236 is 2.86 years?
Answer:
1.238 years will it take
Explanation:
The isotope decay of an atom follows the equation:
Ln[A] = -kt + ln[A]₀
Where [A] could be taken as the amount of the isotope after t years
[A] = 1.00mg
t = ?
k is the decay constant; k = ln2 / Half-life
k = ln 2 / 2.86 years = 0.2424 years⁻¹
[A]₀ is the initial amount of the isotope = 1.35mg
Replacing:
ln1 = -0.2424years⁻¹*t + ln 1.35
0.2424years⁻¹*t = ln 1.35
t =
1.238 years will it takeCalculate the Density of the substances below to determine if they will float or sink in water.
Mass
Volume
Density
Float or Sink
45. Substance 1
90 ml
46. Substance 2
450 grams
35 grams
24 grams
70 ml
47. Substance 3
12 ml
Explanation:
If the density of the object is more than that of water, it will sink. Otherwise it will float. The density of water is 1 g/mL.
Substance 1,
Mass, m = 450 g, Volume, V = 90 mL
Density = mass/volume
So,
[tex]d_1=\dfrac{450}{90}\\\\=5\ g/mL[/tex]
It will sink.
Substance 2,
Mass, m = 35 g, Volume, V = 70 mL
Density = mass/volume
So,
[tex]d_2=\dfrac{35}{70}\\\\=0.5\ g/mL[/tex]
It will float.
Substance 3,
Mass, m = 24 g, Volume, V = 12 mL
Density = mass/volume
So,
[tex]d_3=\dfrac{24}{12}\\\\=2\ g/mL[/tex]
It will sink.
Project: Communicating Design Details
Answer:
Do you have an idea that you want the design to be about? if you do I can help! if not I can give you ideas you can try to work with and you can tell me if theyre good or not.
Explanation:
What is the molarity of a 511 ml solution containing
205 mg of NH3?
401M 0.0235M 0.401M 0.0000235M