The average price of an item is $42 with a standard deviation of $3
Find a 98% confidence interval about the mean (one decimal place).
Is a value of X=48 unusually high or is it normal? Choose correct explanation!

Answer:

n=22.23

Step-by-step explanation:

21+n=43.23

-21 to both sides

0+n=22.23

n=22.23

Answer:

three hours every 1 book

Step-by-step explanation:

36-12

6-2

3-1

Answer:

66

Step-by-step explanation:

66 is the only number between 63 and 68 that is divisible by both 2 and 11.

66/2=33   66/11=6

Answer:

Step-by-step explanation:

total of 15(36) = 540 person•hours was used

540 / 30 = 18 people

18 - 15 = 3 people need to be added

Answer:

1,200

Step-by-step explanation

Multiply 720 and 100 = 72,000

Divide by 60 = 1,200

Answer:

The answer is 1,200

Step-by-step explanation:

First Multiply 720 and 100 which = 72,000

Then Divide 72,000 by 60 = 1,200

Answer:

25cm^2

Step-by-step explanation:

A square has 4 equal sides so each side will be 20/4 = 5cm

Easily calculate the area by taking 5 x 5 = 25cm^2

Answer:

7½ cups of sugar

Step-by-step explanation:

2 cups of flour needs 3 cups of sugar

1 cups of flour needs 3/2=1.5 cups of sugar

1×5 cups of flour needs 1.5×5=7.5 cups of sugar=7½ cups of sugar ANS

Answer:

Step-by-step explanation:

(y + 3) = (1/8)(x - 2)

Answer: B

Step-by-step explanation: Jacob doesn't know either colleges' actual price. Bayside could still be equal to or more expensive than Lakeshore.

Answer:

Step-by-step explanation:

trapezoid is a 4-sided figure with one pair of parallel sides. For example, in the diagram to the right, the bases are parallel. To find the area of a trapezoid, take the sum of its bases, multiply the sum by the height of the trapezoid, and then divide the result by 2, The formula looks like this:

area_trapezoid1.gif or area_trapezoid2.gif

Where b1.gif is base1.gif, b2.gif is base2.gif, h.gif is height and · means multiply.

Each base of a trapezoid must be perpendicular to the height. In the diagram above, both bases are sides of the trapezoid. However, since the lateral sides are not perpendicular to either of the bases, a dotted line is drawn to represent the height.

Answer:

hello

Step-by-step explanation:

say hell-o

[tex]1)3k - 2k \\ = k(3 - 2) \\ = k(1) \\ = k[/tex]

[tex]2) {5x}^{2} - 10x - {8x}^{2} + x \\ = {5x}^{2} - {8x}^{2} - 10x + x \\ = - 3 {x}^{2} - 9x \\ = - 3x(x - 3)[/tex]

[tex]3) - (m + n) + 2(m - 3n) \\ = - m - n + 3m - 6n \\ = - m + 2m - n - 6n \\ = m - 7n [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

a

Step-by-step explanation:

(x-2)(x-11) less than or equal to 0

which means x is between 2 and 11 when it is less than 0

Answer:

Focus on planting trees and and getting healthier soil, improve energy efficiency and not use so much pesticides using natural ways to plant things.

Step-by-step explanation:

Answer:

The gradient is negative.

Step-by-step explanation:

The gradient represents the rise/run ratio. Always read the line's path left to right, and if it goes up, then it is positive, down means negative gradient, and if it doesnt move then it 0. It is undefined if the line is vertical.

Answer:

[tex]x=98.13^\circ,135^\circ,278.13^\circ,315^\circ[/tex]

Step-by-step explanation:

[tex]tan^2x+7tanx+8=0,[0^{\circ},360^\circ)[/tex]

[tex]tan^2x+7tanx+8=0[/tex]

[tex]u=tanx[/tex] <-- U-substitution

[tex]u^2+7u+8=0[/tex]

[tex](u+7)(u+1)=0[/tex]

[tex](tanx+7)(tanx+1)=0[/tex] <-- Replace u with tanx

[tex]tanx+7=0[/tex]

[tex]tanx=-7[/tex]

[tex]x=98.13^\circ,278.13^\circ[/tex]

[tex]tanx+1=0[/tex]

[tex]tanx=-1[/tex]

[tex]x=135^\circ,315^\circ[/tex]

Therefore, [tex]x=98.13^\circ,135^\circ,278.13^\circ,315^\circ[/tex]

Answer:

D!!!

Step-by-step explanation:

you have to make a table to see that randy has run 3 miles.!!!

Answer: D is the correct answer!

Step-by-step explanation: Like the one above me!

1/27

Explanation:

You would multiply to get to the answer.                                                                                    

I'll do the first two parts to get you started.

=====================================================

Part (i)

We can show that the operation [tex]\nabla[/tex] is not commutative by picking two random and different real numbers for a,b. In other words, I'm using a counter-example.

Let's say we go for a = 1 and b = 2

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\1 \nabla 2 = \frac{3*1+2}{5} - 1\\\\1 \nabla 2 = \frac{5}{5} - 1\\\\1 \nabla 2 = 1 - 1\\\\1 \nabla 2 = 0\\\\[/tex]

Now let's swap the values. We'll try a = 2 and b = 1

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\2 \nabla 1 = \frac{3*2+1}{5} - 1\\\\2 \nabla 1 = \frac{7}{5} - 1\\\\2 \nabla 1 = 1.4 - 1\\\\2 \nabla 1 = 0.4\\\\[/tex]

We can see that [tex]1 \nabla 2[/tex] and [tex]2 \nabla 1[/tex] are not the same value. In general, [tex]a \nabla b \ne b \nabla a[/tex] Therefore, the operation [tex]\nabla[/tex] is not commutative.

The only time [tex]a \nabla b = b \nabla a\\\\[/tex] is true is when [tex]a = b[/tex], since,

[tex]\frac{3a+b}{5}-1 = \frac{3b+a}{5}-1\\\\\frac{3a+a}{5}-1 = \frac{3a+a}{5}-1\\\\\frac{4a}{5}-1 = \frac{4a}{5}-1\\\\[/tex]

It's when [tex]a \ne b[/tex] is where the operation becomes noncommutative.

Another way to arrive at the [tex]a = b[/tex] condition is to solve the original equation for either 'a' or b.

=====================================================

Part (ii)

Using the previous part as inspiration, we'll do a counter-example to show that the operation is not associative. Pick 3 random values for a,b,c. Here are the values I'll pick.

Then,

[tex]d = b \nabla c = \frac{3b+c}{5}-1 = \frac{3*2+3}{5}-1 = 0.8\\\\a \nabla (b \nabla c) = a \nabla d = \frac{3a+d}{5}-1 = \frac{3*1+0.8}{5}-1 = -0.24\\[/tex]

Next, we can say:

[tex]d = a \nabla b = \frac{3a+b}{5}-1 = \frac{3*1+2}{5}-1 = 0\\\\(a \nabla b) \nabla c = d \ \nabla c = \frac{3d+c}{5}-1 = \frac{3*0+3}{5}-1 = -0.4[/tex]

Let's compare the two outputs:

[tex]a \nabla (b \nabla c) = -0.24\\\\(a \nabla b) \nabla c = -0.4[/tex]

They don't match up, so [tex]a \nabla (b \nabla c) \ne (a \nabla b) \nabla c[/tex] when (a,b,c) = (1,2,3).

In general, the operation is not associative in R.

Answer:

7 hours

Step-by-step explanation:

Answer:

she could park there for 7 hours

Step-by-step explanation:

13-4=9 9/1.50=6

Answer:

Diagonal and horizontal lines

Step-by-step explanation:

To answer this question it is first important to know what a function is. A function is a relationship that has a singular y value for each x-value. This means that x-values will never repeat.

Linear functions are functions that increase in a constant way. Meaning that the slope of the line is constant and there is a common difference between the points. Because the change is constant, there is no change in direction. Thus, the function will be one straight line.

This line can obviously be diagonal because a diagonal line has unique x and y values. However, the line can also be horizontal. Horizontal lines many have repeating y-values but because the x-values don't repeat it is still a function. This reason is also why vertical lines are the only straight line to not be a liner function. In vertical lines, the x-values repeat. So, it does not work as a function.

Answer:

the answer is A)5+0.5n=11

Step-by-step explanation:

5 is increased by half a number, so half of. a number(n) is added to 5

Answer:

D is correct

Step-by-step explanation:

I hope this helps

5 increased by half a number is 11.

5 increased by half a number is 11. 5 + 1/2n = 11 where n is the unknown number. 1/2n = 11 - 5 = 6 n = 6 * 2 = 12 The number is 12.

Answer:

Step-by-step explanation:

=> 3x + 4y + 6z = 15

=> 3x + 4y + 6z - 4y = 15 - 4y

=> 3x + 6z = 15 - 4y

=> 3x + 6z - 6z = 15 - 4y - 6z

=> 3x = 15 - 4y - 6z

[tex] = > \frac{3x}{3} = \frac{15 - 4y - 6z}{3} [/tex]

[tex] = > x = 5 - \frac{4}{3} y - 2z \: (ans)[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{QUESTIONS:}[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{ANSWER:}[/tex]

[tex]x = 5 - \frac{4}{3} y - 2z[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{SOLUTION:}[/tex]

[tex]3 \orange{+ 4y + 6z = 15}[/tex]

Move the variables to the right-hand side and change their signs.

[tex]3x = 15 \orange{ - 4 - 6z}[/tex]

Divide both sides of the equation by 3

[tex]\orange{3x = 15 - 4 - 6z}[/tex]

[tex]↓[/tex]

[tex]\orange{x = 5 - \frac{4}{3} y - 2z}[/tex]

The x-intercepts of 3x+4y+6z=15 is

[tex]x = 5 - \frac{4}{3} y - 2z[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

#CarryOnlearning

Answer:

Yes, this is a function

Step-by-step explanation:

You know this because it passes the vertical line test.

I hope this helps!

Answer:

Function

Step-by-step explanation:

Answer: [tex]f(x) = 5(x+1)^{2} - 13[/tex]

Vertex = (-1, -13)

Step-by-step explanation:

[tex]f(x) = 5x^{2} + 10x - 8\\f(x) = 5(x^{2}+2x)-8\\f(x) = 5(x^{2}+2x+1-1)-8\\f(x) = 5((x+1)^{2}-1)-8\\f(x) = 5(x+1)^{2}-5-8\\f(x) = 5(x+1)^{2}-13[/tex]

Vertex = (h, k) = (-1, -13)

Answer:

gradient M = 4

Step-by-step explanation:

pick any two pairs

M= change in Y / change in X

considering the last pairs

3--1/0--1=4✓

considering first pair

-1--5/-1--2 is also 4✓

I hope it helps

Using it's formula, it is found that the slope of the line formed from the two given places is of [tex]\mathbf{\frac{6}{7}}[/tex]

Given two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex], the slope is given by change in y divided by change in x, that is:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

In this problem:

Hence, applying the formula for the slope, considering [tex](x_1, y_1) = (-1, -4)[/tex] and [tex](x_2,y_2) = (6,2)[/tex]:

[tex]m = \frac{2 - (-4)}{6 - (-1)} = \frac{6}{7}[/tex]

The slope is of [tex]\mathbf{\frac{6}{7}}[/tex]

A similar problem is given at https://brainly.com/question/5427529

Answer:

Step-by-step explanation.

The answers are:

5x + 3y = 41

2x + 3y = 20

           -2x - 3y = -20

Therefore, the answers are:

Hoped this helped

[tex]-BrainiacUser1357-[/tex]

Answer:

Step-by-step explanation:

It looks like you need to solve this system of equations.

That means we need to find a value for x and a value for y that makes both equations true.

Since both equations have a 3y in them, this system is ready to use a method called "elimination method"

Since the x terms are lined up, and the y terms are lined up, the equal signs are lined up, and the constants are lined up...you can subtract the bottom equation from the top equation.

5x + 3y = 41

2x + 3y = 20

Subtract and you will get

3x + 0y =21

We don't need to write that 0y, because it is 0.

3x = 21, now divide by 3

x = 7, almost finished!

Use x = 7 in either of the original equations to find y.

5x + 3y = 41 and x = 7

5•7+ 3y = 41

35 + 3y = 41

-35 -35

3y =6

y = 2

So the solution is x=7 and y=2

That can also be written as an ordered pair (7, 2)