The circumference of the Earth is
approximately 40,075 kilometers.
How many significant figures are
there in the numerical value?

Answer:oxygen is converted to chemical energy

Explanation:

I got it right

Answer:

The difference between reversible and irreversible is reversible can be changed but irreversible can not.

Answer:

Option D. 16 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 13 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

We can determine how fast (i.e final velocity) the ball is traveling when it reaches the ground as illustrated below:

v² = u² – 2gh

v² = 0² – (2 × 9.8 × 13)

v² = 0 – 254.8

v² = 254.8

Take the square root of both side.

v = √254.8

v = 15.96

v ≈ 16 m/s

Thus, the ball is travelling with a velocity of 16 m/s when it reaches the ground

Answer:

40 J

Explanation:

Answer: Your using your skeletal muscle

Explanation:

Answer:

The robot should hold the bucket at 137.6 m from the start of the field

Explanation:

Horizontal Motion

When an object is launched horizontally with a speed v from a height h, it describes a curved path exclusively ruled by gravity until it eventually hits the ground.

The range or maximum horizontal distance d traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

Birdman flies horizontally at a  speed of v=40 m/s and a height of h=58  m. He releases a turd above the start of the field. If the robot was exactly down  Birdman, then it won't catch the turd with the bucket because it would land farther away by a distance equal to the range. Thus:

[tex]\displaystyle d=40\cdot\sqrt{\frac {2*58}{9.8}}[/tex]

[tex]\displaystyle d=40\cdot\sqrt{11.84}[/tex]

d = 137.6 m

The robot should hold the bucket at 137.6 m from the start of the field

Answer:

there are a number of types of asexual reproduction including fission, fragmentation, budding, vegetative reproduction, spore formation and gamogenesis. Spore formation occurs in plants, and some algae and fungi, and will be discussed in additional concepts

the production of new living organisms by combining genetic information from two individuals of different types (sexes). In most higher organisms, one sex (male) produces a small motile gamete which travels to fuse with a larger stationary gamete produced by the other (female)

The advantages of sexual reproduction: produces genetic variation in the offspring. the species can adapt to new environments due to variation, which gives them a survival advantage. a disease is less likely to affect all the individuals in a population.

Explanation:

Answer:

5.5 m/s

Explanation:

Right on Edge

The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.

RNA polymerase is an enzyme that aids in the transcription of DNA into RNA during transcript in the nucleus. The enzymes prevent many genetic mutations from being expressed.

Primase is an enzyme that synthesizes short RNA sequences called primers. These primers serve as a starting point for DNA synthesis during replication as the DNA polymerases cannot begin the synthesis of the new strand, they only extend it after primase begins it and primase produces RNA molecules, the enzyme can be said to be a type of RNA polymerase.

Therefore, The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.

Learn more about genetic mutations on:

brainly.com/question/1282397

#SPJ6

Answer:

i) 5 [tex]m[/tex]/[tex]s^{2}[/tex]  ii) 54 [tex]N[/tex]  iii) 54 [tex]N[/tex]

Explanation:

i) [tex]a = \frac{v^{2}}{r}[/tex] ⇒ [tex]a[/tex] = 5² ÷ 5 = 5 [tex]m/s^{2}[/tex]

ii) [tex]m = \frac{W}{g}[/tex] ⇒ [tex]m[/tex] = 108 ÷ 10 = 10.8 [tex]kg[/tex] , [tex]F = ma[/tex] ⇒ [tex]F =[/tex] 10.8 × 5 = 54 [tex]N[/tex]

iii) F1 = F2 = 54 [tex]N[/tex]

Answer:

When thermal energy is added to a substance, its temperature increases, which can change its state from solid to liquid (melting), liquid to gas (vaporization), or solid to gas (sublimation). ... When the pressure exerted on a substance increases, it can cause the substance to condense.

Explanation:

Hope it will help use

Answer:3.0m/s

Explanation:

Answer:

Water cannot be used in thermometer because of its higher freezing point and lower boiling point than other liquids .  If water is used in a thermometer , it will start phase change at 0[tex]degree\\[/tex]C and 100[tex]degree[/tex]C and will not measure temperature , out of this range . This range is very small as compared  to other liquids as mercury , having freezing point about −39[tex]degree[/tex]C and boiling point 356[tex]degree[/tex]C.

Explanation:

Answer:

a) La piedra es lanzada desde una altura de 0,785 metros.

b) La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

Explanation:

a) Dado que la piedra es lanzada horizontalmente, tenemos que la piedra experimenta un movimiento horizontal a velocidad constante y uno vertical uniformemente acelerado debido a la gravedad. La altura de la que fue lanzada la piedra se puede determinar mediante la siguiente ecuación cinemática:

[tex]y = y_{o}+v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex] (1)

Donde:

[tex]y[/tex] - Altura final, medida en metros.

[tex]y_{o}[/tex] - Altura inicial, medida en metros.

[tex]v_{o,y}[/tex] - Componente vertical de la velocidad inicial, medida en metros por segundo.

[tex]t[/tex] - Tiempo, medido en segundos.

[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que [tex]y = 0\,m[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex], [tex]t = 0,4\,s[/tex] y [tex]g = -9,807\,\frac{m}{s^{2}}[/tex], entonces la altura inicial de la piedra es:

[tex]y_{o} = y-v_{o,y}\cdot t -\frac{1}{2}\cdot g\cdot t^{2}[/tex]

[tex]y_{o} = 0\,m-\left(0\,\frac{m}{s} \right)\cdot (0,4\,s)-\frac{1}{2}\cdot \left(-9,807\,\frac{m}{s^{2}} \right) \cdot (0,4\,s)^{2}[/tex]

[tex]y_{o} = 0,785\,m[/tex]

La piedra es lanzada desde una altura de 0,785 metros.

b) Ahora, obtenemos el componente horizontal de la velocidad inicial a partir de la siguiente ecuación cinemática:

[tex]v_{o,x} = \frac{x-x_{o}}{t}[/tex] (2)

Donde:

[tex]x_{o}[/tex], [tex]x[/tex] - Posiciones horizontales iniciales y finales, medidas en metros.

[tex]t[/tex] - Tiempo, medido en segundos.

Si tenemos que [tex]x_{o} = 0\,m[/tex], [tex]x = 2,5\,m[/tex] y [tex]t = 0,4\,s[/tex], entonces el componente horizontal de la velocidad inicial es:

[tex]v_{o,x} = \frac{2,5\,m-0\,m}{0,4\,s}[/tex]

[tex]v_{o,x} = 6,25\,\frac{m}{s}[/tex]

La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

Answer:

The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.

Answer:

Dynamic   a, b and d

Deformer  c and d

Explanation:

When a force is applied to an object, the acceleration may or may not change, which is analyzed from Newton's second law, this effect is a dynamic effect on the system; The environment can change the shape of the object, in this case the force creates a deformation in it.

With these clarifications let's analyze the different situations.

a) Dynamic. When pushing a car initially an acceleration is created in it, shortly after this decreases to zero and continues with constant speed.

b) Dynamic. When the nail moves it does not change the shape of the body that contains it, nor the shape itself, therefore the system can be analyzed with Newton's second law and the force is of the Dynamic type

c) Deformer. In this case the body (clay) has no net movement, but it does change its shape, so the effect of the force translates into a deformation of the system

d) Deformar and Dynamic. The launch of tennis balls has an initial deformation stage during the acceleration process, in this part the force is of the DEFORMING type, but during the trajectory the deformation disappears and the ball has (gravity) a DYNAMIC action

Answer: the answer is a

Explanation: I got it correct on test

Answer:

as it is halfway through the fall and it has reached a speed of 19.8 meters per second

Explanation:

Studying energy involves determining the amount of energy an object has. This energy can be kinetic or potential, or it could be a combination of both. Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls toward the ground. Think about the amounts kinetic energy the bowling ball has as it falls, select the when the ball would have the most kinetic energy from the choices given.

Answer:

Answer:

3 g/cm          

Explanation:

Mass of stone = 30 g

Initial volume of cylinder = 50 cm

Increased volume = 60 cm

Volume = 60-50

= 10 cm

Density of stone = Mass/Volume

= 30/10

= 3 g/ml            as 1 ml = 1 cm

= 3 g/ml          

Explanation:

Answer:

a) Magnet attracts to ferromagnetic substances like Iron.

b) Scientific thinking (critical thinking)

Answer:

Explanation:

The monsoon rains are the main source of water for 55 percent of the country’s arable land. This means the rains are crucial — not only for India’s farmers, but for its economy as a whole. Now, that’s a good thing when the monsoon arrives on time and brings the right amount of rain. But when it’s late or weak, it leads to drought.

Answer:

77N

Explanation:

Since we are not told what to find, we can as well look for the net force acting on the ball.

According Newton's second law;

F = mass × acceleration

Given

Mass = 3.5kg

Acceleration = 22m/s²

Net force F = 3.5×22

F = 35/10×22

F = 7/2×22

F = 7×11

F =77N

Hence the magnitude of force required is 77N

Answer:

The space cadet that weighs 800 N on Earth will weigh 1,600 N on the exoplanet

Explanation:

The given parameters are;

The mass of the exoplanet = 1/2×The mass of the Earth, M = 1/2 × M

The radius of the exoplanet = 50% of the radius of the Earth = 1/2 × The Earth's radius, R = 50/100 × R = 1/2 × R

The weight of the cadet on Earth = 800 N

[tex]The \ weight, W =G\dfrac{M \times m}{R^{2}} = 800 \ N[/tex]

Therefore, for the weight of the cadet on the exoplanet, W₁, we have;

[tex]W_1 =G\dfrac{\dfrac{M}{2} \times m}{ \left ( \dfrac{R}{2} \right ) ^{2}} = G\dfrac{\dfrac{M}{2} \times m \times 4}{ R ^{2}} = 2 \times G \times \dfrac{M \times m}{R^{2}} = 2 \times 800 \, N = 1,600 \, N[/tex]

The weight of a space cadet on the exoplanet, that weighs 800 N on Earth = 1,600 N.

Answer:

Energy that is dependant on height is called gravitational potential energy.

The formula for potential energy is:

                    G.P.E.=mgh

Weight (mass x gravity) determines the amount of potential energy.

Is there potential energy in the 5 forms of energy?

Yes, potential energy can be found in fossil fuels, within the foods you eat, and the batteries that you use.  

Conservation of Energy:

It is important to understand that each form of energy does not exist separately but undergoes change from one to another without a net loss in energy.  Consider this example:

As a projectile is launched into the air KE is at its maximum.  As the projectile gains altitude PE becomes greater than KE.  At the top of its arc, PE is at its maximum.  The whole cycle reverses itself on the way down.

As you can see, the loss in KE is a gain in PE.  Energy is not lost but conserved.

Law of conservation of energy.

   Energy cannot be created nor destroyed.  It can be transformed from one form to another, but the total amount of energy never changes.

Answer:

to transfer the voltage

Explanation:

The brushes make physical contact with the commutator. When a DC voltage is applied to the brushes, that voltage is transferred into the commutator which, in turn, powers the windings. This electrical input generates a magnetic field around the armature.

The  mass of the scale pan : 0.11 kg

Given

A spiral spring's length = 20 cm

mass 50 g ⇒ the length = 22 cm

mass 70 g ⇒ the length = 22.25 cm

Required

the  mass of the scale pan

Solution

Hooke's Law :

[tex]\tt F=k.\Delta x[/tex]

The spring constant (k) :

[tex]\tt k=\dfrac{\Delta F}{\Delta x}=\dfrac{g.(70-50)}{22.25-22}=\dfrac{g.20}{0.25}=g.80~g/cm=10~m/s^2\times 8~kg/m=80~N/m[/tex]

mass of the scale pan=m(for 50 g mass) :

[tex]\tt (m+0.05).g=80\times (0.22-0.20)\\\\m=0.11~kg[/tex]

Answer:                                                                              

Explanation:(40.0)×(9.8)=392

764N-392=372