The data below are the temperatures on randomly chosen days during a summer class and the number of absences on those days: Temperature, x | 72 85 91 90 88 98 75 100 80 No. of absences, y | 3 7 10 10 8 15 4 15 5 a) Find the equation of the regression line for the data. b) Assuming that the variables x and y have a significant correlation, what is the predicted number of absences when the temperature is 91? c) Calculate the correlation coefficient. d) Calculate the standard error for the model.

Answers

Answer 1

The equation of the regression line is y=-30.27+0.449x and predicted number of absences when the temperature is 910= 10.589

See table for sum of values.

The regression equation is:

y=α+βx

β = [tex]\frac{Sxx}{Syy}[/tex]=6995-97799779[tex]\frac{6995-9\times\frac{779}{9}\times\frac{77}{9}}{68613-9(\frac{779}{9} )2}[/tex]= 0.449

α=y-βx= 779-(0.449)7799 = =-30.27

The equation is y=-30.27+0.449x

Where y = predicted variable; x = independent variable = 0.449; - 30.27 = intercept/ slope

Constructing a 91% prediction interval for y:

x = 910

Inputting x = 91 into the regression equation : y = 0.449(91) - 30.27

y = 40.859 - 30.27 = 10.589

Prediction interval = y pm error margin

To save computing time, error margin (E) can be obtained using the online error margin calculator.

Obtained error margin (E) value = 2.3398

(10.589- 2.3398, 10.589+ 2.3398)

(8.2492, 12.9288)

(8, 13)

The equation of the regression line is y=-30.27+0.449x and predicted number of absences when the temperature is 910= 10.589

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

[tex]\frac{15}{2}[/tex]×[tex]\frac{13}{4}[/tex]

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Answer:

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Answers

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Answer:

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Step-by-step explanation:

Given

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Answer:

14.53 is less than 16.3

Step-by-step explanation:

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Answers

Answer:

H0: u ≥ 9.5

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Step-by-step explanation:

The null hypothesis and the alternate hypothesis are reverse of each other.

The claim is either set as the null or alternate hypothesis

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Hello!

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Answer:

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