Answers
As 3 is Angle of Incidence
4 is 90 degree - i
1 is 90 degree - r
Answer:
B 2
Explanation:
Angle of reflection is the measure of the angle taken from the normal.
Related Questions
Which of the following statements are true about scientific theories?
a.They are educated guesses made before an experiment.
b.They usually have no evidence supporting them yet.
c.They can be adjusted as new evidence emerges.
d.They are supported by a large body of evidence.
e.They are undeniable truths accepted by scientists.
Answers
The true statement about scientific theories are;
(d) They are supported by a large body of evidence and .
(e) They are undeniable truths accepted by scientists.
What is scientific theory?
A scientific theory is an explanation of an aspect of the natural world and universe that has been repeatedly tested and corroborated in accordance with the scientific method, using accepted protocols of observation, measurement, and evaluation of results.
Characteristics of scientific theory include the following;
The following are some of the characteristics of scientific theories;
Concise, coherent, systematic, predictivebroadly applicable, often integrating many hypothesesThus, scientific theories must be supported by a large body of evidence.
and they are undeniable truths accepted by scientists.
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Which saturated solution has the highest concentration of S2- ions at 25oC?
options:
NiS; Ksp = 3x10-21
CoS; Ksp = 5x10-22
FeS; Ksp = 4x10-19
SnS; Ksp = 1x10-26
Answers
Answer:
according to me the fourth one is the right answer
A 4.91 kg bucket of water is raised from a well by a rope. The upward acceleration of the bucket is 3.37 m/s2. It will be helpful if you can properly draw a free-body diagram. Find the force exerted by the rope on the bucket.
Answers
Answer:
F=ma
=(4,91kg)(3,37m/s)
=16,55N
Explanation:
Free body diagram- the only 2 forces that are acting on the bucket is the tension in the rope and the weight
The tension in the rope could also be called "Force applied" and is acting upwards since it's pulling the bucket upwards.
There also has to be a force acting downwards on the bucket and that is the Weight.
Which phrase describes an oxidizing agent? (1 point)
O a substance that provides electrons to other substances
a substance that reacts with oxyge
O a substance that provides oxygen in a reaction
O a substance that gains an electron in a reaction
Answers
A substance that gains an electron in a reaction is called as oxidizing agent.
What is an Oxidizing agent?An oxidizing agent, often known as an oxidizer or an oxidant, is a type of chemical that has the tendency to oxidize other substances, increasing their oxidation state by causing them to lose electrons. The substance losing electrons is the reducing agent and is being oxidized. The material that obtains electrons is the oxidizing agent and is being reduced. An element or compound that accepts an electron from another species in an oxidation-reduction (redox) reaction is known as an oxidizing agent (also oxidant, oxidizer, or oxidiser).
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If you are on 4.16 Chemical Reactions and have 18 questions, then go to the following on Quizlet for further help. Thanks and good luck!
Quizlet - "4.6 Chemical Reactions UT"
h t t p s : / / q u i z l e t . c o m / _ c 7 3 1 u j ? x = 1 q q t & i = 3 8 n a a s
All points on the chain of a bicycle have the same linear speed. Is the magnitude of the linear acceleration also the same for all points on the chain? How are the angular accelerations of the two sprockets related?
Answers
The magnitude of the linear acceleration is zero for all points on the chain. The angular accelerations of the two sprockets can be related as α[tex]_{Front}[/tex] / α[tex]_{Rear}[/tex] = ω[tex]_{Front}[/tex] * t[tex]_{Rear}[/tex] / ω[tex]_{Rear}[/tex] * t[tex]_{Front}[/tex]
There are two set of point that is needed to be taken into consideration. The points in between the two sprockets and points in which the chain is in contact with the sprocket. In the former set of points, the linear velocity is constant. So its linear acceleration will be zero. In the latter set of points, the tangential velocity ( Linear velocity in circular motion ) is constant. So the tangential acceleration ( Linear acceleration in circular motion ) will be zero.
Since the chain is constantly changing direction while on the sprocket, it will always have angular acceleration.
α = ω / t
α = Angular acceleration
ω = Angular velocity
t = Time
α[tex]_{Front}[/tex] / α[tex]_{Rear}[/tex] = ω[tex]_{Front}[/tex] * t[tex]_{Rear}[/tex] / ω[tex]_{Rear}[/tex] * t[tex]_{Front}[/tex]
Therefore,
The magnitude of the linear acceleration is zero for all points on the chain.The angular accelerations of the two sprockets can be related as α[tex]_{Front}[/tex] / α[tex]_{Rear}[/tex] = ω[tex]_{Front}[/tex] * t[tex]_{Rear}[/tex] / ω[tex]_{Rear}[/tex] * t[tex]_{Front}[/tex]To know more about angular acceleration
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Determine the speed, frequency, period, wavelength, and amplitude of Wave A.
Answers
Given:
Waves A, B, and C travel 12.0 meters in 2.0 seconds through the given medium.
To find:
The speed, frequency, period, wavelength, and amplitude of wave A.
Explanation:
As the wave covers a distance of 12 m in 2 seconds, the speed "v" of the wave can be calculated as:
[tex]v=\frac{d}{t}[/tex]Here, d is the distance covered by the wave and t is the time required to cover the distance.
Substituting the d = 12 m and t = 2 s in the above equation, we get:
[tex]v=\frac{12\text{ m}}{2\text{ s}}=6\text{ m/s}[/tex]The speed of the wave A is 6 m/s.
The frequency of a wave is defined as the number of wave cycles occurring per second.
From the above graph, we observe that there are a total of four wave cycles occurring in 2 s. Thus, the frequency of wave A can be calculated as:
[tex]f=\frac{N}{t}[/tex]Here, f is the frequency of the wave, N is the number of times the wave occurs and t is the time.
Substituting N = 4 and t = 2 s in the above equation, we get:
[tex]f=\frac{4}{2\text{ s}}=2\text{ Hz}[/tex]The frequency of wave A is 2 Hz.
The period "T" of the wave is related to the frequency "f" as:
[tex]T=\frac{1}{f}[/tex]Substituting the values in the above equation, we get:
[tex]T=\frac{1}{2\text{ Hz}}=0.5\text{ s}[/tex]The period of wave A is 0.5 s.
The wavelength λ of the wave is related to its speed "v" and frequency "f" as:
[tex]\begin{gathered} v=f\lambda \\ \\ \lambda=\frac{v}{f} \end{gathered}[/tex]Substituting the values in the above equation, we get:
[tex]\lambda=\frac{6\text{ m/s}}{2\text{ Hz}}=3\text{ m}[/tex]The wavelength of wave A is 3 m.
The amplitude of the wave is the maximum distance or displacement of the point on a vibrating body measured from the equilibrium position. Thus, from the given graph, we observe that the amplitude of wave A is 2 m.
Final answer:
The speed of wave A is 6 m/s.
The frequency of wave A is 2 Hz.
The time period of wave A is 0.5 s.
The wavelength of wave A is 3 m.
The amplitude of wave A is 2 m.
In which of the following reactions will the amount of product at equilibrium increase if the total gas pressure is raised from 5 atm to 20 atm? Find the best possible answer.
N2(g) + O2(g) < -- > 2 NO(g)
options:
1. Reactants: 2 moles of gases and Products: 2moles of gases but with higher energy, therefore equilibrium shift to the right
2. Reactants and products have equal moles in the gas phase, but the reactants have a less restrictive motion than the products, therefore the equilibrium shifts to the left
3. This is an endothermic reaction, therefore the equilibrium should shift to the products side.
4. Reactants: 2 moles of gases. Products: 2 moles of gases.
5. Both sides have the same number of moles of gases so there will be no shift in the equilibrium.
Answers
If the total gas pressure is raised from 5 atm to 20 atm in N2(g) + O2(g) < -- > 2 NO(g), there will be no shift in the equilibrium as both sides have the same number of moles of gases (5)
According to Le Chatelier's principle, some factors like pressure, temperature, concentration can affect the equilibrium of the reaction. If the factors that affects the equilibrium are changed, the equilibrium will shift in the same direction of the effects caused by these changes. As a result, the changes would be nullified.
In the reaction N2(g) + O2(g) < -- > 2 NO(g), as the reactants and products have the same number of moles, the pressure has no effect on them. Even if we increase or decrease the pressure, the equilibrium remains the same as the change in pressure doesn’t cause any effects on the reaction.
Therefore, if the total gas pressure is raised from 5 atm to 20 atm, there will be no shift in the equilibrium as both sides have the same number of moles of gases (5)
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In a diagrams the incident ray makes an angle of 25 degree with the normal. If the mirror is rotated through 15 degree to make a new angle of incidence of 40 degree. Through what angle does the reflected ray turns ?
Answers
The term "reflected ray" refers to a beam of light or other radiant energy that is reflected back from a nonpermeable or non absorbing surface. The light beam that returns from the surface of reflection is referred to as the reflected ray. The incident's normal and reflected rays all rest on the same plane.
The angle of incidence is the angle formed by an incident ray and the normal, or line perpendicular to the incident surface, at its point of incidence. Any wave, including optical, acoustic, microwave, X-ray, and others, can create a ray.
When light strikes a smooth surface, reflection occurs when the light bounces back.
Refraction is the bending of light beams as they pass through different media. usually happens on shiny surfaces that only allow light to bounce off of them rather than pass through them.
A mirror image is a reflected duplicate of a seemingly identical item that is turned the other way in the plane perpendicular to the mirror surface. It appears as an optical phenomenon as a result of reflection from surfaces like water or mirrors.
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A way to test the tensile strength of a wire is to place a mass at the end of it and spin the mass with uniform circular motion. The speed at which the wire breaks is a measure of its strength. The maximum frequency of rotation before a certain wire breaks is 35.5 Hz. The wire is 50.5 cm long and has a mass of 0.656 kg. (a) Determine the speed with which the mass moves. (b) Calculate the centripetal force acting on the wire
Answers
ANSWER:
(a) 112.58 m/s
(b) 16463.98 N
STEP-BY-STEP EXPLANATION:
Given:
Frequency (F) = 35.5 Hz
Mass (m) = 0.656 kg
Radius (r) = 50.5 cm = 0.505 m
(a) To determine the speed with which the mass moves, we must first calculate the angular speed, like this:
[tex]\begin{gathered} \omega=2\pi f \\ \\ \omega=(2)(3.14)(35.5) \\ \\ \omega=222.94\text{ rad/s} \end{gathered}[/tex]Now we can calculate the speed, with the help of the radius:
[tex]\begin{gathered} v=\omega r \\ \\ v=(222.94)(0.505) \\ \\ v=112.58\text{ m/s} \end{gathered}[/tex](b) The centripetal force is calculated using the following formula:
[tex]\begin{gathered} F_c=\frac{mv^2}{r} \\ \text{ } \\ \text{ we replacing} \\ \\ F_c=\frac{0.656\cdot(112.58)^2}{0.505} \\ \\ F_c=16463.98\text{ N} \\ \end{gathered}[/tex]A proposed mechanism for the decomposition of N2O is given below:
Which species is the catalyst?
NO + N2O --> N2 + NO2
2NO2 --> 2NO + O2
Answers
NO is the catalyst in this reaction. Because, a Catalyst increases the rate of a reaction without being used up. Catalyst does this by lowering the activation energy needed.
A rocket is fired at an angle from the top of a tower of height h0 = 36.8 m . Because of the design of the engines, its position coordinates are of the form x(t)=A+Bt2 and y(t)=C+Dt3, where A, B, C , and D are constants. Furthermore, the acceleration of the rocket 1.20 s after firing is a=( 3.30 i^+ 2.50 j^)m/s2. Take the origin of coordinates to be at the base of the tower.
What are the x- and y-components of the rocket's velocity 12.2 s after it is fired?
Enter your answers numerically separated by a comma.
How fast is it moving 12.2 s after it is fired?
What is the position vector of the rocket 12.2 s after it is fired?
Answers
36.8 (m) are the x- and y-components of the rocket's velocity 12.2 s after it is fired.
0.41 m / s³ is the position vector of the rocket 12.2 s after it is fired
What does acceleration mean?Any process where the velocity varies is referred to as acceleration. There are only two ways to accelerate: increasing your speed or changing your direction, or altering both. This happens because speed is both a speed and a guidance.
Briefing:This is an exercise in kinematics in two dimensions, the easiest way to solve it is to work each axis independently
To find the other two constants we must know the acceleration formula,
a = dv / dt = d²v / dt²
vₓ = dx / dt = 2Bt
d²x / dt² = 2B
aₓ = 2B= dy / dt = 3D t2
d²y / dt² = 6D t
They give us the acceleration for time t = 1.20s
aₓ = 2B = 3.30 m / s2
B = 1.65 m / s²
ay = 6D t = 2.50
D = 3.00 / 6 1
D = 0.41 m / s³
The acceleration vector is
a = aₓ i ^ + j ^
a = 3.3 i ^ + 2.5 t j ^
v = vx i ^ + vyj ^
v = 3.3 t i ^ + 1.25 t²
velocity for t= 12.2 s
v = 3.3 t i ^ + 1.25 t²
v = 3.3 10 i^ + 1.5 10² j^
v= (33 i^ + 150 j^ ) m/s
Position for t = 12.2 s
x = 1.65 t² = 7 10²
x = 165 m
y = 36.8 +0.41 t³ = 36.8 + 0.41 10³
y = 446.8 m
D = (165 i ^ + 446.8 j ^) m
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A group of physics students launched a rocket in a field at their school. They recorded the time it took for the rocket to launch into the air and come back to the ground. They calculated their average time for their rocket to land to be 12.74 seconds.
1. How long did the rocket take to reach max height?
2. What is the velocity of the rocket at max height?
3. What is the initial velocity of the rocket?
4. What was the maximum height of the rocket?
Answers
1) The time taken is 6.37 s
2) The velocity at maximum height is 0 m/s
3) The initial velocity is 62.4 m/s.
4) The maximum height is 198.66 m
What is the velocity?Let us recall that in this case, we have to use the equation of the motion that occurs under gravity In this case we have to take into account the the upwards motion is negative in the opposite direction as gravity and the down wards motion is positive and in the same direction as gravity.
1) Given that;
time is the same as the time taken to go up and come down thus the time taken to reach the maximum height is 12.74 seconds/2 = 6.37 s
2) The velocity of the rocket at the maximum height is zero because it momentarily comes to rest.
3) The initial velocity of the rocket is;
v = u - gt
At the maximum height v = 0 m/s
u = gt
u = 9.8 m/s^2 * 6.37 s
u = 62.4 m/s
4) The maximum height is obtained from;
v^2 = u^2 - 2gh
v = 0 m/s
u^2 = 2gh
h = u^2/2g
h = (62.4 m/s)^2/2 * 9.8 m/s^2
h = 198.66 m
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According to Dallas Morning News in June 2021, the 386.243 kilometers high-speed rail would run from Dallas to Houston in 90 minutes, with a stop in the Brazos Valley, between College Station and Huntsville. What would be the average speed of the train in meters per second?
Answers
The average speed of the train is 71.52 meters per second.
The total distance the object covers in a given amount of time is its average speed. It's a scalar quantity. Average speed has no direction and is represented by the magnitude. The equation of average speed is given below.
[tex]v_{avg} = \frac{distance}{time}[/tex]
The distance and time is given in the problem and they are 386.243 kilometers and 90 minutes respectively.
The distance in meters = 386.243*1000 = 386243 m
The time in seconds = 90*60 = 5400 s
The average speed = 386243 m/5400 s = 71.52 m/s
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If a cat is thrown upward at an angle with an initial velocity of 11 m/s and a horizontal velocity of 8 m/s, what is the cats impact speed when he lands?
Answers
ANSWER:
13.6 m/s
STEP-BY-STEP EXPLANATION:
The speed of the impact would be the resulting velocity between the initial velocity (which according to the statement is a vertical velocity) and the horizontal velocity.
Now we know the vertical and horizontal components of velocity we can find the resultant by means of the Pythagorean theorem. Using Pythagoras we can say that:
[tex]\begin{gathered} c^2=a^2+b^2 \\ \text{ In this case:} \\ V^2_r=V^2_v+V^2_h \\ \text{Replacing:} \\ V^2_r=11^2+8^2 \\ V^2_r=121+64 \\ V_r=\sqrt[]{185} \\ V_r=13.6\text{ m/s} \end{gathered}[/tex]Therefore, the impact speed is 13.6 m/s
The angular velocity of the belt of a grindstone is 30rad/s to what angle dues the belt rotate in one minute
Answers
Explanation:
unit conversion
30 rad/sec * 60sec/min= 1,800 rad/min
A plane travels 2.5 km at an angle of 35 degrees to the ground and then changes directions and travels 5.2 km at an angle of 22 degrees to the ground. what is the magnitude and direction of the plane's total displacement?
Answers
The magnitude and direction of the plane's total displacement are 7.66 km and angle of 26.2 degree respectively.
What is displacement and how the magnitude and direction is calculated out to be so ?Displacement as studied earlier is the shortest distance between initial point and final point .Here in this question is given plane is travelling with speed 2.5 km at an angle of 35 degrees to the ground and then changes direction. So , d1=2.5 , theta 1 =35 degree, d2=5.2 km , theta 2 = 22 degree, to find the resultant displacement , Rx = d1 cos theta 1 + d2 cos theta 2 = 2.5 x sin 35 degree + 5.2 x sin 22 degree = 3.38 km.By applying pythagoreon theorum , the magnitude will be , R = (Rx^2 + Ry^2 )^1/2 = 7.66 km.To find the direction , theta = tan^-1 ( Ry/Rx) = tan^-1 ( 3.38km/6.87km) = 26.2 degree.To know more about displacement visit:
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A rectangular pane of glass is 91.1 cm wide and 155.9 cm long, and its area is equal to the length multiplied by the width. Using the correct number of significant figures, what is the area of the glass?14,200 cm^214,202 cm^214,202.5 cm^214,202.49 cm^2
Answers
Answer:
14,200 cm^2
Explanation:
When multiplying two numbers with different significant figures, the significant figures of the product carries the significant of figures of the number with the least significant figures.
Therefore, in finding the area, we have to multiply 91.1 ( 3 significant figures) by 155. 1 (4 significant figures). This tells us that our product will have 3 significant figures.
Now,
[tex]155.9\operatorname{cm}\times91.1\operatorname{cm}=14202.49\operatorname{cm}^2[/tex]rounding to the three significant figures gives
[tex]14200\operatorname{cm}^2[/tex]Hence, the area of the rectangle is 14200 square centimetres.
You are designing an experiment to determine the acceleration of a motorized toy car over 1 meter of distance. You perform the following steps in your experiment:
1. Release the toy car from rest.
2. Take a video of the car accelerating.
3. Determine the time the car took to reach 1 meter using the video.
If you followed the steps above, could you determine the acceleration of the toy car?
Answers
Yes, if one follows the mentioned steps, they could determine the toy car's acceleration from the data of time taken in the video.
a = v / t
v = d / t
a = Acceleration
v = Velocity
d = Distance
t = Time
d = 1 m
Let the video time recorded from the video be x s.
t = x s
v = 1 / x
a = 1 / x / x
a = 1 / x² m / s²
Velocity is the rate of change of distance. Its unit is m / s. It is denoted as v. Acceleration is defined as the rate of change in velocity with respect to time. Its unit is m / s². It is denoted as a.
Therefore, if I follow steps given, I could determine the acceleration of the toy car as 1 / x² m / s²
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Which one of the following is not a step used for balancing chemical
equations?
A. Write the chemical equation using formulas and symbols.
B. Choose coefficients that will balance the equation.
C. Determine how long the reaction will take.
D. Count the atoms in each substance in the reactants and products.
Answers
Answer: C. Determine how long the reaction will take.
A signaling whistle measures 5.0 cm from its open end to its closed end. Find the wavelength of the sound emitted and the frequency of the whistle if the speed of sound is 344 m/s.
Answers
L = 5 cm =0.05 m
sound speed = 344 m/s
F =v x λ
F = 344 x 0.05 = 17.2 hz
When an object experiences uniform circular motion, the direction of the acceleration isSelect one:A) is directed away from the center of the circular path.B) depends on the speed of the object.C) is directed toward the center of the circular path.D) in the opposite direction of the velocity vector.E) in the same direction as the velocity vector.
Answers
An object under uniform circular motion experiences a centripetal acceleration, directed towards the center of the circular trajectory.
Therefore, the correct option is:
[tex]\begin{gathered} C) \\ \text{ Is directed toward the center of the circular path.} \end{gathered}[/tex]what does not affect the strenth of elecromagnets
A. Number of time the the wire is looped around the core
B. Size of the object being attached by the core
C.type of material in the core
D.among of material in the core
Answers
A magnetic core made of a magnetic material, such as iron, that is encircled by a wire coil. The core is magnetized by an electric current that is passed through the coil.
How do electromagnets function? What are they?Permanent magnets are not the same as electromagnets. Coils of wire with electricity running through them make up electromagnets. An electromagnet's wire coils act like magnets when an electric current flows through them because moving charges produce magnetic fields.
Electromagnets generate electricity in what way?Electrons are pushed and pulled by moving magnetic fields. Electrons in metals like copper and aluminum are slackly held. The electrons in the wire are pushed by rotating a coil of wire around a magnet, or vice versa, and an electrical current is produced.
What kind of thing is an electromagnet like?Electromagnets are a component of every machine with an electric motor. Hairdryers, CD players, power drills, electric saws, and electric mixers are a few further examples.
What exactly is a basic electromagnet?Magnets produced by electric fields are known as electromagnets. The fact that they can be turned on and off gives them an edge over normal magnets. By wrapping a wire around an iron nail and passing current through it, electromagnets can be made.
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Let me know if you need more information. I need help with the arrows.
Answers
Answer:
The change in momentum is 2 times the length of the momentum vector put in the negative direction.
Explanation:
The change in momentum is defined as
[tex]\Delta p=p_f-p_i[/tex]meaning it is the difference between the final and the inital momentum.
Now, our initial momentum is
[tex]p_i=mv_i\vec{i}[/tex]it is in the positive i-direction.
The final momentum is
[tex]p_f=-mv_i\vec{i}[/tex]and it is in the negative i-direction.
Therefore, the change in momentum is
[tex]\Delta p=p_f-p_i=p_f=-mv_i\vec{i}-mv_i\vec{i}[/tex][tex]\boxed{\Delta p=-2mv_i\vec{i}}[/tex]which is our answer!
Now, what is the direction and magnitude of this momentum vector?
This vector has length 2 and points in the negative i-direction.
A bicyclist decreases his speed from 6.1 meters per
second to 3.7 meters per second over a period of 17
seconds. What is his acceleration during this time?
Answers
The acceleration of the car within the time frame that have been shown in question is obtained as -0.14 m/s^2.
What is the acceleration?We define the acceleration as the rate of change of the distance of the object with time. We know that acceleration is a vector quantity thus the magnitude and the direction of the acceleration is counted as important in the process.
We have;
a = v - u/t
a = acceleration
v = final velocity
u = initial velocity
t = time taken
a = 3.7 m/s - 6.1 m/s/ 17 s
a = -0.14 m/s^2
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a satellite moves in a circular orbit around the earth at a speed of 6 km/s. determine the satellite's altitude above the surface of the earth. assume the earth is a homogeneous sphere of radius 6370 km and mass 5.98 x 10^24 kg. the value of the universal gravitational constant is 6.67259 x10^-11 N*m^2/hg^2. Answer in units of km.
Answers
The satellite's altitude above the surface of the earth is mathematically given as
h =9590835m
This is further explained below.
What is the satellite's altitude above the surface of the earth?Generally, When we write Newton's Second Law and Newton's Gravitational Law on the satellite (which has a mass of m and is undergoing an acceleration of a), which is circling Earth (which has a mass of M), and we use r to represent the distance between their centers, we get the following equation:
[tex]F=m a=\frac{G M m}{r^2}[/tex]
Since this acceleration is centripetal, we can write:
[tex]\frac{v^2}{r}=a=\frac{G M}{r^2}[/tex]
So we have:
[tex]v^2=\frac{G M}{r}[/tex]
This distance r is equal to the sum of Earth's radius R and the satellite's height h (r=R+h)$, therefore for our values, we get (in standard international format):
[tex]h=\frac{G M}{v^2}-R\\\\\=\frac{\left(6.67250 \times 10^{-11} \mathrm{Nm}^2 / \mathrm{kg}^2\right)\left(5.98 \times 10^{24} \mathrm{~kg}\right)}{(5000 \mathrm{~m} / \mathrm{s})^2}-6370000 \mathrm{~m}\\\\[/tex]
h =9590835m
In conclusion, the satellite's altitude above the surface of the earth
h =9590835m
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An electron of mass 9.11×10^−31 kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 1.40 cm away. It reaches the grid with a speed of 4.0×10^6 m/s. The accelerating force is constant.
A)Find the acceleration. (m/s)
B)Find the time to reach the grid. (s)
C)Find the net force. (You can ignore the gravitational force on the electron). (N)
Answers
A. The acceleration of the electron is 5.71×10¹⁴ m/s²
B. The time taken for the electron to reach the grid is 7.01×10⁻⁹ s
C. The net force of the electron is 5.20×10⁻¹⁶ N
A. How to determine the acceleration of the electron
The acceleration can be obtained as illustrated below:
Initial velocity (u) = 0 m/sFinal velocity (v) = 4.0×10⁶ m/sDistance (s) = 1.4 cm = 1.4 / 100 = 0.014 mAcceleration (a) =?v² = u² + 2as
(4.0×10⁶)² = 0² + (2 × a × 0.014)
(4.0×10⁶)² = 0 + 0.028a
(4.0×10⁶)² = 0.028a
Divide both side by 0.028
a = (4.0×10⁶)² / 0.028
a = 5.71×10¹⁴ m/s²
B. How to determine the time
The time taken for the electron to reach the grid can be obtained as follow:
Initial velocity (u) = 0 m/sFinal velocity (v) = 4.0×10⁶ m/sAcceleration (a) = 5.71×10¹⁴ m/s²Time (t) =?a = (v – u) / t
5.71×10¹⁴ = (4.0×10⁶ – 0) / t
5.71×10¹⁴ = 4.0×10⁶ / t
Cross multiply
5.71×10¹⁴ × t = 4.0×10⁶
Divide both sides by 5.71×10¹⁴
t = 4.0×10⁶ / 5.71×10¹⁴
t = 7.01×10⁻⁹ s
C. How to determine the net force
Mass (m) = 9.11×10⁻³¹ KgAcceleration (a) = 5.71×10¹⁴ m/s²Net force (F) =?Net force = mass × acceleration
Net force = 9.11×10⁻³¹ × 5.71×10¹⁴
Net force = 5.20×10⁻¹⁶ N
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if you increase the amount if spinach you eat, then you will increase the iron in your blood. whats the dependent variable
Answers
Answer:
Iron in Your Blood
Explanation:
Hope this helps.
A runner starting from rest reaches a velocity of 9.6 m/s in 2.0s. What is her average acceleration?
Answers
Answer:
Explanation:
From the given information if we assume that the runner didn't come back to her original position.
Her initial velocity = 0 m/s
Final Velocity = 9.6 m/s
Time Taken = 2 seconds
She started from rest therefore her initial time would be 0 seconds.
We know that,
Average acceleration = (final velocity - initial velocity)/(final time - initial time)
=(v-u)/t1-t0
=(9.6 - 0)/(2-0) m/s^2
=4.8 m/s^2
What evidence would you expect to find on the Moon if it had been subjected to plate tectonics? (Select all that apply.)
the equivalent of mid ocean rifts and rift valleys
long folded mountains
the presence of vesicular basalts
the absence of smooth plains
the presence of jumbled terrain
Answers
The evidence would you expect to find on the Moon if it had been subjected to plate tectonics here would be volcanos and mountains.
The iron core of the collision object may have fallen into a larger body. The moon is primarily made of silver rock, but the earth contains more metal and volatile compounds. The earth has an iron core, but not the moon. There is liquid water on the surface of the earth, but not on the moon. Mercury contains much more metal than the moon with a considerable amount of iron-nickel core.
Both celestial bodies lack the water of the liquid that erases the collision crater over time. Also, on planets such as Earth and Venus, there is no atmosphere that can be disassembled before the meteor clashes on the ground. However, old craters can be eroded by new collision events. Moon rocks are similar to the earth's crust but rarely contain metal. The rotation speed is too slow.
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4. A .005kg paper airplane at a height of 1.5m is about to be thrown across the room. How much
gravitational potential energy does it have?
Answers
The gravitational potential energy paper airplane have PE = 0.735J.
Equation :To calculate the potential energy we are going to use the formula,
PE = mgh
where,
PE is gravitational potential energy
m is mass of object
g is gravitational acceleration
h is height
So, given data are :
m = 0.005Kg
g = 9.8 m/s²
h = 1.5 m
PE = ?
Now, putting the values
PE = 0.005Kg x 9.8 m/s² x 1.5 m
PE = 0.0735 J
Hence, the gravitational potential energy paper airplane have is PE = 0.0735J
Gravitational potential energy :The potential energy that a huge item has in relation to another massive object due to gravity is known as gravitational energy or gravitational potential energy. When two objects descend toward one another, potential energy associated with the gravitational field is released.
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