The diagram below shows a force of 5N acting on an object P at an angle of 30° to the horizontal.
By drawing appropriate lines on the diagram using a ruler to determine:
a.)The horizontal component of the 5N force.
b.)The vertical component of the 5N force .
Answers
Given :
The diagram below shows a force of 5N acting on an object P at an angle of 30° to the horizontal.
To Find :
By drawing appropriate lines on the diagram using a ruler to determine:
a.)The horizontal component of the 5N force.
b.)The vertical component of the 5N force.
Solution :
Horizontal component is given by :
=F cos θ
=5 cos 30°
= 5×0.866
= 4.33 N
Vertical component is given by :
= F sin θ
= 5 sin 30°
= 5×0.5
= 2.5 N
Therefore, horizontal and vertical component are 4.33 N and 2.5 N.
Hence, this is the required solution.
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Someone in a car going past you at the speed of 32 m/s drops a small rock from a height of 2 m. How far from the point of the drop will the rock hit the ground? the acceleration due to gravity is 9.8m/s^2. answer in units of m.
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Answer:
The rock will hit the ground at 20.44 m from the point of the drop
Explanation:
Horizontal Motion
It occurs when an object is thrown horizontally from a height h at an initial speed v.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
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A copper rod of crosssectional area 0.500 cm2 and length 1.00 m is elongated by 2.00 * 10-2 mm and a steel rod of the same cross-sectional area but 0.100 m in length is elongated by 2.00 * 10-3 mm. Which rod is under greater tensile strain?
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Answer:
They have the same tensile strainExplanation:
Strain of a material is the ratio of its extension to its original length.
strain = e/lo
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lo is the original length
For a copper rod;
e = 2.00 * 10^-2mm
lo = 1.00m
convert 1.00m to mm
1.00m = 1*10^-3mm
get the strain
Strain = 2.00 * 10^-2mm/1*10^-3mm
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Strain = 2*10^1 = 20
For the steel
e = 2.00 * 10^-3mm
lo = 0.100m
convert 0.100m to mm
0.1m = 0.1*10^-3mm
0.1m = 10^-4mm
get the strain
Strain = 2.00 * 10^-3mm/10^-4mm
Strain = 2 * 10^{-3+4}
Strain = 2*10^1 = 20
Since the value of their strain are the same, this means that they a re under the SAME tensile strain. No one is greater that the other.
The rod under greater tensile strain is ; Neither of them i.e. They both have the same tensile strain
Given data :
Cross sectional area of copper rod = 0.5 cm²
Length of copper rod = 1.0 m = 1 * 10³ mm
Elongation of copper rod ( Ec ) = 2.0 * 10⁻² mm
For Steel
Cross sectional area of steel = 0.5 cm²
Length of steel rod = 0.1 m = 1 * 10² mm
Elongation of steel rod ( Es )= 2.0 * 10⁻³ mm
Determine the Tensile strain of each rod
i) For copper rod
Tensile strain = Ec / Length of copper rod
= ( 2.0 * 10⁻² ) / ( 1 * 10³ )
= 2.0 * 10⁻⁵
ii) For the steel rod
Tensile strain = Es / Length of steel rod
= ( 2.0 * 10⁻³ ) / ( 1 * 10² )
= 2.0 * 10⁻⁵
The Tensile strain for the copper rod and the steel rod is the same ( 2.0 * 10⁻⁵ ) This means that both rods are under the same tensile strain
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Answer:
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Answers
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Answer:
F = 20.61 N
Explanation:
Given that,
Mass of the object, m = 2 kg
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It is acted upon by a 5 N of friction.
The force of gravity acts in downward direction which is given by :
W = mg
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The net force is given by the resultant of two vectors as follows :
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Given the following data:
Mass = 2 kgSpeed = 10 m/sForce of friction = 5 NWe know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex].
To calculate the net force:
First of all, we would determine the normal force acting on the mass.
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[tex]F_N = mg[/tex]
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Net force = 13.6 Newton.
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O A
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v² = 64+160
v² = 224
v = √224
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Answer:
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