The fifth term of a geometric sequence is 781. 25. Each term of the sequence is of the value of the following term. Which recursive formula represents the situation?.

Answers

Answer 1

Answer: an = 5an-1

Explanation: Given fifth term of a geometric sequence is 781.25.

a5 = 781

Also, each previous term is 1/5 of the value of the current term.

Therefore, common ratio would be 5.

But we just need to find the recursive formula .

Recursive formula of a geometric sequence is given by

Plugging value of r in above formula, we get

Therefore, recursive formula would be   represents the situation.

Answer 2

The recursive formula that represents the situation is: [tex]t_n = a^{(3/4)} * 781.25^{(1/4)} * n^{(1/4)}[/tex].

What is recursive formula?

A recursive formula is one that defines any term in a sequence in terms of the term(s) before it.

Let the first term of the geometric sequence be 'a' and the common ratio be 'r'.

We are given that the fifth term is 781.25, so we can write:

a * [tex]r^4[/tex] = 781.25

We also know that each term is the value of the following term, so we can write the recursive formula:

t_n = r * t_(n-1)

Where t_n is the nth term of the sequence and t_(n-1) is the previous term.

To express the recursive formula in terms of 'a' and 'r', we can use the formula for the nth term of a geometric sequence:

[tex]t_n = a * r^{(n-1)[/tex]

Substituting the recursive formula, we get:

[tex]r * t_{(n-1)} = a * r^{(n-1)[/tex]

Dividing both sides by r^(n-1), we get:

[tex]t_{(n-1)} = a * r^{(n-2)[/tex]

So the recursive formula in terms of 'a' and 'r' is:

t_n = r * t_(n-1)

[tex]= r * (a * r^{(n-2)})\\\\= a * r^{(n-1)[/tex]

Now we can substitute the value of the fifth term (781.25) to solve for 'a' and 'r':

a * [tex]r^4[/tex] = 781.25

Dividing both sides by a, we get:

[tex]r^4[/tex]= 781.25/a

Taking the fourth root of both sides, we get:

r = [tex](781.25/a)^{(1/4)[/tex]

Substituting this value of 'r' into the recursive formula, we get:

[tex]t_n = a * ((781.25/a)^{(1/4)}){^(n-1)}\\\\= a^{(3/4)} * 781.25^{(1/4)} * n^{(1/4)}[/tex]

Therefore, the recursive formula that represents the situation is:

t_n = a^(3/4) * 781.25^(1/4) * n^(1/4)

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