The film The Lord of the Rings: The Return of the King, the last installment of The Lord of the Rings trilogy, was directed by Peter Jackson and released on December 17 2003 in the U.S. with huge success. Eventually, the film won 11 Oscars for all of its nominations. The film's box office has been more than $1 billion. In the film, there are long sequences in which not all main characters appear at the same time. And there are big scenes where everybody shows up. Thinking about the making of the film, behind the scenes, we can hypothetically break down the entire cinematic project into the following aggregate activities (We assume away all the complexities in shooting the three installments at the same time and other production details):
‐ Plan, screenplay, finance, cast, film crew, location
‐ Construction of movie sets
‐ Shooting sequence 1
‐ Shooting sequence 2
‐ Shooting sequence 3
‐ Big scene sequence
‐ Post‐production & finalization before release
We have the following hypothetical data on time in months and cost in millions of dollars:
ID IP T ES EF LS LF SLK NT NC CT CC CCR
A ‐ 6.0 6.0 13.0 6.0 13.0
B A 4.0 4.0 9.0 3.0 12.0
C B 4.0 4.0 12.0 4.0 12.0
D B 5.0 11.0 5.0 14.0 4.0 16.0
E B 6.0 0.0 6.0 16.0 4.0 19.0
F C,D,E4.0 4.0 19.0 4.0 19.0
G F 6.0 6.0 11.0 5.0 13.5
Note: IP = Immediate Predecessor; T = NT = Normal Time; ES = Earliest Start; EF = Earliest Finish; LS = Latest Start; LF = Latest Finish; SLK = Slack Time; NT = Normal Time; NC = Normal
Cost; CT = Crash Time; CC = Crash Cost; & CCR = Crash Cost/Time Unit (Crash Cost Rate).
Copy the table to your homework and complete the following parts:
By looking at the chart in part (a), find all possible paths through the network with their corresponding path times. Based on these path times, determine the critical path.
Based on part (a) By using the forward and backward passes together with the four time determination rules, fill your calculations for ES,
EF, LS, LF, and SLK in the appropriate cells.
(b) [2] Try to independently fill in the columns ES, EF, LS, LF, and SLK of the table. If you have difficulties, refer to part (a). Determine the activity with the most slack time.
c) [2] Based on part (a), find the critical path by going through the activities with no slack time.
Compare this result with the critical path found in part (b).
d) Use appropriate data to compute crash costs per time unit and fill in the CCR column. Cross out any CCR cells where the corresponding activities cannot be crashed.
(e) [2] Find the total normal cost of the film. Find the normal cost on the original critical path. Compute the cost proportion of the critical path in the film's budget.

Answer:

Shift to the right by 2 units, vertical translation upwards by 3 units.

Step-by-step explanation:

Answer:

The first one

Step-by-step explanation:

I did this and got it right and I solved it

8×3 equal 24/1 so make it to a whole number 24

Answer:

$6.24

Step-by-step explanation:

equation: $41.63 - 4.19 = 37.44

solve: 37.44 ÷ 6 = 6.24.

hope this helped!

Answer:

He pays a TOTAL of $41.63. Meaning everything is equal to that value

He pays 4.19$ for Milk

He buys 6bags of Oranges and each of these cist the same amount.. let's say x.

So 6 bags would cost 6x

So Total is

6x + 4.19 =41.63

6x= 41.63-4.19

6x=37.44

x=37.44/6

x=$6.24

To check this

6x + 4.19 should equal 41.63$

6(6.24) + 4.19= $41.63

Answer:

=180-50-70

=50

Step-by-step explanation:

=180-50-70

50

Answer: first 360 second 1080 third horizontal stretch

Step-by-step explanation:

The period of this parent cosine function [y=cos(x)] is equal to 360 degrees.

The period of a cosine function can be defined as the overall length of the interval of values on the x-axis over which a graph lies and it's repeated. Mathematically, the period of this parent cosine function [y=cos(x)] is given by:

T = 2π/A

Where:

When A = 1, we have:

T = 2π/1 = 360 degrees.

For the graphed function, the period of this cosine function is given by:

T = 6π

T = 6 × 360

T = 1080 degrees.

Read more on cosine function here: https://brainly.com/question/4599903

Answer:

[tex] \frac{20}{29} [/tex]

Step-by-step explanation:

Let x replace theta.

Apply pythagorean trig identity

[tex] \sin {}^{2} (x) + \cos {}^{2} (x) = 1[/tex]

[tex] (\frac{21}{29} ) {}^{2} + \cos {}^{2} (x) = 1[/tex]

[tex] \frac{441}{841} + \cos {}^{2} (x) = 1[/tex]

[tex] \cos {}^{2} (x) = 1 - \frac{441}{841} [/tex]

[tex] \cos {}^{2} (x) = \frac{400}{841} [/tex]

[tex] \cos(x) = \frac{20}{29} [/tex]

Cosine is positve in 1st quadrant so the answer is

[tex] \frac{20}{29} [/tex]

Answer:

the mean of those numbers is 17.1

Answer:

The M.A.D (mean absolute deviation) is 2.3

Bonus (Just in case you need it): The Mean is 17.1

Have a good day!

Answer:

7. D) 61in

8. A) 57in

9. A) 47in

Step-by-step explanation:

The perimeter is the distance around the area of a 2-dimensional figure. it can be found by adding up all of the sides of the figure. One can use this to solve for the value of the parameter (x). Then substitute the value back in to find the value of the side.

7.

AB + BC + AC = 145

Substitute,

2x + 2x + 5 + x = 145

Simplify,

5x + 5 = 145

Inverse operations,

5x + 5 = 145

-5

5x = 140

/5

x = 28

Substitute,

AC = 2x + 5= 2(28) + 5 = 61

8.

AB + BC + AC = 135

Substitute,

2x + 2x + 5 + x = 135

Simplify,

5x + 5 = 135

Inverse operations,

5x + 5 = 135

-5

5x = 130

/5

x = 26

Substitute,

AC = 2x + 5 = 2(26) + 5 = 57

9.

AB + BC + AC = 122

Substitute,

x + 22 + 2x + x = 122

Simplify,

4x + 22 = 122

Inverse operations,

4x + 22 = 122

-22

4x = 100

/4

x = 25

Substitute,

AB = x + 22 = 25 + 22 = 47

Answer:

D. Both of the dot A and B have the same mean

Answer:

y=-1/4x+2

Step-by-step explanation:

So the forumla for slope/intercept equation is:

y=mx+b

Y equals the y coordinates on the graph. This is the value that you plug in x to solve for.

m equals the slope of the graph. (In this case -1/4)

x equals the x coordinates. This will always be just x when writen in a slope intercept equation, since x is the value you plug in to solve for y.

b equals the y intercept. This is different from the y coordinates. This is a known value, which can be found when x=0. (In this case 2)

Now, using this lets plug in our numbers for the differet variables:

y=mx+b

We know that m, the slope, is -1/4. So:

y=-1/4x+b

We also know that b, the y inteercept, is 2. Since we have the coordiantes (0x, 2y). So:

y=-1/4x+2

This is all you have to do! This is because y is the number you solve for, and x is the value you plug.

Hope this makes sense and helps! :)

Answer:

The correct solution is "x=3 or x=9".

Step-by-step explanation:

The given equation is:

⇒  [tex]x^2 - 12x + 49 = 22[/tex]

On subtracting "22" from both sides, we get

⇒  [tex]x^2-12x+49-22=22-22[/tex]

⇒          [tex]x^2-12x+27=0[/tex]

On factorizing the above equation, we get

⇒  [tex]x^2-9x-3x-27=0[/tex]

By taking common, we get

⇒  [tex]x(x-9)-3(x-9)=0[/tex]

⇒          [tex](x-3)(x-9)=0[/tex]

⇒                        [tex]x-3=0[/tex]

                                 [tex]x=3[/tex]

Or,

⇒                        [tex]x-9=0[/tex]

                                [tex]x=9[/tex]

Answer:

[tex](6 \times 5) + (2 \times 3) \\ 30 + 6 \\ = 36cm^{2} [/tex]

Answer:

D (1, 2), (2, 4), (4,8)

Step-by-step explanation:

Points lying on the same line:

If three points lie on the same line, the change in y has to be always the same when x changes by 1.

А. (0, 1), (-1, 3), (1, 3)

(-1,3) to (0,1): x changes by 1, y by -2

(0,1) to (1,3): x changes by 1, y by 2

So these points are not on the same line.

B. (4, 2), (2, 1), (4, -2)

Two values for y when x = 4, so not on the same straight line.

C (0, 0), (8, 0), (0, 8)

Two values for y when x = 0, so not on the same straight line.

D (1, 2), (2, 4), (4,8)

Here, when x changed by 1(from 1 to 2), y changed by 2.

When x changed by 2(from 2 to 4), y changed by 2*2 = 4.

So these points are on a straight line, and D is the correct answer.

at lunch four friends drink 8 pints of milk. how many fluid ounces is this equal to?

128 FL

Answer:

The answer is choice #1 or 128 Fluid ounces

Step-by-step explanation:

8 pints = 128 oz

Answer:

cool neither do i

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 1, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = [tex]\frac{3-0}{0+1}[/tex] = [tex]\frac{3}{1}[/tex] = 3

The line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = 3x + 3 ← equation of line → A

Answer:

100

Step-by-step explanation:

Answer:

2/3 km per minute

Step-by-step explanation:

kilometers

1 1/3 - 2/3 = 2/3km

Minutes

2 - 1 = 1 minute

----------------------------

Spped

(2/3 km) / (1 minute)

2/3 km per minute

Answer:

15

Step-by-step explanation:

trust me bro

Answer: 4/5

How to: Convert to a mixed number by placing the numbers to the right of the decimal over  10 . Reduce the fraction.

Have a great day and stay safe ! so sorry if wrong

Answer:

8/9

Step-by-step explanation:

i got it righttt

Answer: THE ONE ABOVE IS WRONG

A= 3V/h

​

Step-by-step explanation:

Formulas may contain multiple variables, along with known numbers and letters that stand for known constants like \piπpi.

We can highlight a certain variable in the formula by treating the formula as an equation where we want to solve for that variable.

In this case, we need to solve the equation V =\dfrac{1}{3}AhV=

3

1

​

AhV, equals, start fraction, 1, divided by, 3, end fraction, A, h for AAA.

Hint #22 / 3

\begin{aligned} V&=\dfrac{1}{3}Ah \\\\ \dfrac{3V}{h}&=A \end{aligned}

V

h

3V

​

​

=

3

1

​

Ah

=A

​

Hint #33 / 3

This is the result of rearranging the formula to highlight the base area:

A=\dfrac{3V}{h}A=

h

3V

​ It works I did it in Khan

Answer:

26º

Step-by-step explanation:

746 - 360 = 386

386 - 360 = 26

Answer:

2,2122.64

Step-by-step explanation:

equation -

3.14*(26*26) or 3.14*26^2

26*26=676

676*3.14=2,122.64

Hope this helps :)

Answer:

93

Step-by-step explanation:

(85 + 92 + 87 + 93 + 90 + x)/6 = 90

(447 + x)/6 = 90

multiply both sides of the equation by 6:

447 + x = 540

subtract 447 from both sides:

x = 93

Answer:

log(.25)

Step-by-step explanation:

[tex]log(a)-log(b)=log(\frac{a}{b})\\log(2)-log(8)=log(\frac{2}{8})\\log(\frac{1}{4})[/tex]

Answer:

The y-intercept is y = -4.

The x-intercepts are [tex]x = 4[/tex] and [tex]x = -\frac{1}{2}[/tex]

The vertex is [tex](\frac{7}{4},-\frac{81}{8})[/tex]

Step-by-step explanation:

Quadratic equation:

Has the following format:

[tex]y = ax^2 + bx + c[/tex]

The y-intercept is c.

Finding the x-intercepts:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

Vertex:

Suppose we have a quadratic function in the following format:

[tex]f(x) = ax^{2} + bx + c[/tex]

It's vertex is the point [tex](x_{v}, y_{v})[/tex]

In which

[tex]x_{v} = -\frac{b}{2a}[/tex]

[tex]y_{v} = -\frac{\Delta}{4a}[/tex]

Where

[tex]\Delta = b^2-4ac[/tex]

In this question:

The quadratic equation is [tex]2x^2 - 7x - 4[/tex], which has [tex]a = 2, b = -7, c = -4[/tex]. This means that the y-intercept is y = -4.

x-intercepts:

[tex]\Delta = (-7)^2-4(2)(-4) = 81[/tex]

[tex]x_{1} = \frac{-(-7) + \sqrt{81}}{2*2} = 4[/tex]

[tex]x_{2} = \frac{-(-7) - \sqrt{81}}{2*2} = -\frac{1}{2}[/tex]

The x-intercepts are [tex]x = 4[/tex] and [tex]x = -\frac{1}{2}[/tex]

Vertex:

[tex]x_{v} = -\frac{(-7)}{2*2} = \frac{7}{4}[/tex]

[tex]y_{v} = -\frac{81}{4(2)} = -\frac{81}{8}[/tex]

The vertex is [tex](\frac{7}{4},-\frac{81}{8})[/tex]

Answer:

The relevants cost are $2,000

Step-by-step explanation:

Based on the information given in a situation where the student have to decide whether to repair the car or purchase another car the correct statement is: THE RELEVANTS COST ARE $2,000 because the cost of repairs of the Amount of $2,000 represent the RELEVANT COST.

Therefore RELEVANT COSTS are costs or expense that can be incurred due to some certain decisions and on the other hand RELEVANT COSTS which is also known as AVOIDABLE COST can be seen as the cost or expense a person or an individual can do away with depending on other alternative such person choose to pick.

Answer:

2000

Step-by-step explanation: