Computers And Technology College

The following procedure is intended to return the number of times the value val appears in the list nylist. The procedure does not work as intended, Line 1: PROCEDURE countNumoccurences (mylist, val) Line 2: Line 3: FOR EACH item IN mylist Line 4: Line 5: count = 0 Line 6: IF(item = val) Line 7: tine 8: count count + 1 tine 9: Line 10: Eine 11: RETURN (count) Line 12:) Which of the following changes can be made so that the procedure will work as intended?
A. Changing line 6 to IF(item = count)
B. Changing line 6 to IF(myList[item) - val)
C. Moving the statement in line 5 so that it appears between lines 2 and 3
D. Moving the statement in line 11 so that it appears between lines 9 and 10 ->

Answers

Answer 1

Answer:

C. Moving the statement in line 5 so that it appears between lines 2 and 3

Explanation:

Given

The attached procedure

Required

What should be modified

The problem in the procedure is on line 5

i.e. count = 0

This line is within the loop, and this means that the count variable is initialized to 0 each time the loop is repeated.

To solve this, the count variable has to be removed from the loop to somewhere before the loop.

Hence, option (c) is correct

Answer 2

Throughout our procedure, even though we proclaimed count = 0 inside the for loop, the count has been valued at 0.  

After that, When a certain value is found equal to Val, the count has been incremented by 1. The count is set to 0 again in the next iteration, so at the end, if we found an element equivalent to Val 1, its real count has been returned.To get around this, we'll define count outside of the for loop to acquire the true count of instances of that specific value.

Therefore, the answer is "Option C".

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Related Questions

Programming errors can result in a number of different conditions. Choose all that apply.
The program will halt execution.
An error message will be displayed.
Incorrect results will occur.
Code will run faster.
the first 3

Answers

Answer:

The program will halt execution and and error message will be displayed. Probably number 3 too.

Answer:

A, B and C

Explanation:

NEED HELP IMMEDIATELY!!
What is the difference between a worm and a typical virus?
A) Worms are a type of spyware; viruses are a type of malware.
B) Worms are impossible to remove; viruses can be tracked and removed.
C) Worms are stronger than viruses; viruses are stronger than spam.
D) Worms travel independently of human action; viruses require human actions.

Answers

Answer:

Option C

Explanation:

Option A is incorrect as Worm is a form of malware

Option B is incorrect because antivirus can remove all forms of malware

Option C is correct because a worm is more problematic as compared to the virus. Also, viruses are weaker than worm because they need a host file to run but a worm can work independently.

Option D is also incorrect because both are able to self replicate.

Use at Least one hundred words to explain what you did the last time your handheld personal computer went slow.​

Answers

Answer:

Disk defragmentation

clear up storage

restart the computer

Explanation:

PC's going slow is a very common occurence nowadays and what i had to do to usually fix slow computers is to first use disk defragmentation which will automatically sort our files and put them in the right order.Second is to delete any unnessary files,folders,programs that i no longer use or its just sitting there eating dust and finally my last resort is to restart the pc which usually helps fix most of the issues including slow PCs which might be caused by some errors during startup.

Hope this helped

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