The function a(t) = 44,000(1.045)^t models Johanna’s annual earnings a, in dollars, t years after she starts her job.
Which of the following statements are true about Johanna’s salary?

Johanna initally earns $44,000 per year. True or False

Johanna initially earns $45,980 per year. True or False

Johanna’s salary increases by 1.045% per year. True or False

Johanna’s salary increases by 4.5% per year. True or False

Johanna’s salary increases by 104.5% per year. True or False

This represents an exponential growth. True or False

This represents exponential decay. True or False

The rate at which the grocery store clerk can scan products is 2 products per second.

Rate is the speed at which an activity can be carried out. Rate can be determined by dividing the total products that are bagged by the time it takes to bag the product.

Division is used to determine the product of two or more numbers. The sign that represent division is ÷. Division is a mathematical operations. Other mathematical operations include addition, subtraction and multiplication. Division entails grouping a number into equal groups using another number.

Rate = number of products ÷ time

1 ÷ 1/2

1 x 2 = 2 products per second

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Answer:

Step-by-step explanation:

36=p*60

36/60=(p*60)/60

p=0.6 or 60%

60%

Pls brainliest

Answer:

each chicken cost 3.65

Step-by-step explanation:

divide 18.25 by 5 and you'll get 3.65

the answer is 29 hope this helps

Answer:

17%

Step-by-step explanation:

Hello!

Out of the 6 options, only 1 option will be correct. This can be represented as a ratio of 1:6.

If you randomly guess, there is an equal chance of choosing any of the 6 options.

To find the percentage of guessing the correct option, simply divide 1 by 6 (1 option is correct out of 6), and multiply the outcome by 100 (for percentage).

The probability of getting an answer correct would be 17%.

The probability of getting an answer wrong would be 83%, which can be found by subtracting 17% from 100%.

9:

By taking the quotient between the total debt and what they earn in a sold-out show, we conclude that they need to sell a total of 7 sold-out shows.

10:

A discount of 30%. Correct option is B.

Answering part 9:

We know that they asked for a loan of $8,000, such that an interest of the 6% is applied to this, so the total amount that they need to return is:

$8,000*(1 + 6%/100%) = $8,000*(1.06) = $8,480

Now we know that the theater has 150 seats, and each ticket costs $8.50, so for every sold-out show they earn a total of:

T = 150*$8.50 = $1,275

Then the number of sold-out shows that they need is given by the quotient:

$8,480/$1,275 = 6.65

Rounding to the next whole number we get to 7. To cover the debt, they need to sell a total of 7 sold-out shows.

10. The original price is $180 and she pays $126, then the discount k is:

$180*k = $126

k = $126/$180 = 0.7

and 1 - 0.7 = 0.3

So the discount is of the 30%.

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Answer:

36.

Step-by-step explanation:

I get this answer as I know 30 is divisible by six, so I start to investigate by how much It is divisible by.

30 / 6 = 5

Since I now know that, I can infer that 6x6 is 36.

And since 30 would give you 5/6, I imagine the answer is 36.

Answer:

see explanation

Step-by-step explanation:

[tex]\frac{x+2}{3}[/tex] - [tex]\frac{2x-4}{2}[/tex] = 0

multiply through by 6 ( the LCM of 3 and 2 ) to clear the fractions

2(x + 2) - 3(2x - 4) = 0 ← distribute parenthesis on left side and simplify

2x + 4 - 6x + 12 = 0

- 4x + 16 = 0 ( subtract 16 from both sides )

- 4x = - 16 ( divide both sides by - 4 )

x = 4

------------------------------------------------------------

[tex]\frac{5x}{2}[/tex] + [tex]\frac{x-2}{8}[/tex] = 2 ( multiply through by 8 to clear the fractions )

4(5x) + x - 2 = 16

20x + x - 2 = 16

21x - 2 = 16 ( add 2 to both sides )

21x = 18 ( divide both sides by 21 )

x = [tex]\frac{18}{21}[/tex] = [tex]\frac{6}{7}[/tex]

-----------------------------------------------------------

[tex]\frac{x-5}{4}[/tex] - [tex]\frac{3x-1}{5}[/tex] = - [tex]\frac{3}{2}[/tex]

multiply through by 20 ( the LCM of 4, 5, 2 ) to clear the fractions

5(x - 5) - 4(3x - 1) = - 30 ← distribute parenthesis on left side and simplify

5x - 25 - 12x + 4 = - 30

- 7x - 21 = - 30 ( add 21 to both sides )

- 7x = - 9 ( divide both sides by - 7 )

x = [tex]\frac{9}{7}[/tex]

-------------------------------------------------------------

[tex]\frac{1}{x-1}[/tex] + [tex]\frac{1}{x+1}[/tex] = [tex]\frac{4x+2}{x^2-1}[/tex] ← x² - 1 is a difference of squares , then

[tex]\frac{1}{x-1}[/tex] + [tex]\frac{1}{x+1}[/tex] = [tex]\frac{4x+2}{(x-1)(x+1)}[/tex]

multiply through by (x - 1)(x + 1) to clear the fractions

x + 1 + x - 1 = 4x + 2

2x = 4x + 2 ( subtract 4x from both sides )

- 2x = 2 ( divide both sides by - 2 )

x = - 1

If we substitute this value back into the original equation, we find

[tex]\frac{1}{-1-1}[/tex] + [tex]\frac{1}{-1+1}[/tex] = [tex]\frac{4(-1)+2}{(-1)^2-1}[/tex]

[tex]\frac{1}{-2}[/tex] + [tex]\frac{1}{0}[/tex] = [tex]\frac{-2}{1-1}[/tex]

[tex]\frac{1}{-2}[/tex] + [tex]\frac{1}{0}[/tex] = [tex]\frac{-2}{0}[/tex]

division by zero is undefined

thus x = - 1 is an extraneous solution

the equation has no solution

Answer:

[tex]\textsf{1.} \quad x=4[/tex]

[tex]\textsf{2.} \quad x=\dfrac{6}{7}[/tex]

[tex]\textsf{3.} \quad x=\dfrac{9}{7}[/tex]

[tex]\textsf{4.} \quad \textsf{No solution}[/tex]

Step-by-step explanation:

Given equation:

[tex]\dfrac{x+2}{3}-\dfrac{2x-4}{2}=0[/tex]

[tex]\textsf{Add \; $\dfrac{2x-4}{2}$ \; to both sides of the equation}:[/tex]

[tex]\implies \dfrac{x+2}{3}-\dfrac{2x-4}{2}+\dfrac{2x-4}{2}=0+\dfrac{2x-4}{2}[/tex]

[tex]\implies \dfrac{x+2}{3}=\dfrac{2x-4}{2}[/tex]

Cross multiply:

[tex]\implies 2(x+2)=3(2x-4)[/tex]

[tex]\implies 2x+4=6x-12[/tex]

Subtract 2x from both sides:

[tex]\implies 2x+4-2x=6x-12-2x[/tex]

[tex]\implies 4=4x-12[/tex]

Add 12 to both sides:

[tex]\implies 4+12=4x-12+12[/tex]

[tex]\implies 16=4x[/tex]

[tex]\implies 4x=16[/tex]

Divide both sides by 4:

[tex]\implies \dfrac{4x}{4}=\dfrac{16}{4}[/tex]

[tex]\implies x=4[/tex]

--------------------------------------------------------------------------

Given equation:

[tex]\dfrac{5x}{2}+\dfrac{x-2}{8}=2[/tex]

Multiply the numerator and denominator of the first fraction by 4:

[tex]\implies \dfrac{5x \cdot 4}{2\cdot 4}+\dfrac{x-2}{8}=2[/tex]

[tex]\implies \dfrac{20x}{8}+\dfrac{x-2}{8}=2[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:[/tex]

[tex]\implies \dfrac{20x+x-2}{8}=2[/tex]

[tex]\implies \dfrac{21x-2}{8}=2[/tex]

Multiply both sides by 8:

[tex]\implies \dfrac{(21x-2) \cdot 8}{8}=2 \cdot 8[/tex]

[tex]\implies 21x-2=16[/tex]

Add 2 to both sides:

[tex]\implies 21x-2+2=16+2[/tex]

[tex]\implies 21x=18[/tex]

Divide both sides by 21:

[tex]\implies \dfrac{21x}{21}=\dfrac{18}{21}[/tex]

[tex]\implies x=\dfrac{18}{21}[/tex]

Reduce the fraction by dividing the numerator and denominator by 3:

[tex]\implies x=\dfrac{18 \div 3}{21 \div 3}[/tex]

[tex]\implies x=\dfrac{6}{7}[/tex]

--------------------------------------------------------------------------

Given equation:

[tex]\dfrac{x-5}{4}-\dfrac{3x-1}{5}=-\dfrac{3}{2}[/tex]

Multiply the numerator and denominator of the first fraction by 5, and the numerator and denominator of the second fraction by 4:

[tex]\implies \dfrac{(x-5) \cdot 5}{4\cdot 5}-\dfrac{(3x-1)\cdot 4}{5\cdot 4}=-\dfrac{3}{2}[/tex]

[tex]\implies \dfrac{5x-25}{20}-\dfrac{12x-4}{20}=-\dfrac{3}{2}[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}-\dfrac{b}{c}=\dfrac{a-b}{c}:[/tex]

[tex]\implies \dfrac{5x-25-(12x-4)}{20}=-\dfrac{3}{2}[/tex]

[tex]\implies \dfrac{5x-25-12x+4}{20}=-\dfrac{3}{2}[/tex]

[tex]\implies \dfrac{-7x-21}{20}=-\dfrac{3}{2}[/tex]

Cross multiply:

[tex]\implies 2(-7x-21)=-3(20)[/tex]

[tex]\implies -14x-42=-60[/tex]

Add 42 to both sides:

[tex]\implies -14x-42+42=-60+42[/tex]

[tex]\implies -14x=-18[/tex]

Divide both sides by -14:

[tex]\implies \dfrac{-14x}{-14}=\dfrac{-18}{-14}[/tex]

[tex]\implies x=\dfrac{18}{14}[/tex]

Reduce the fraction by dividing the numerator and denominator by 2:

[tex]\implies x=\dfrac{18 \div 2}{14 \div 2}[/tex]

[tex]\implies x=\dfrac{9}{7}[/tex]

--------------------------------------------------------------------------

Given equation:

[tex]\dfrac{1}{x-1}+\dfrac{1}{x+1}=\dfrac{4x+2}{x^2-1}[/tex]

Factor the denominator of the fraction on the right side of the equation:

[tex]\implies \dfrac{1}{x-1}+\dfrac{1}{x+1}=\dfrac{4x+2}{(x+1)(x-1)}[/tex]

Multiply the numerator and denominator of the first fraction by (x+1), and the numerator and denominator of the second fraction by (x-1):

[tex]\implies \dfrac{x+1}{(x+1)(x-1)}+\dfrac{x-1}{(x+1)(x-1)}=\dfrac{4x+2}{(x+1)(x-1)}[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:[/tex]

[tex]\implies \dfrac{x+1+x-1}{(x+1)(x-1)}=\dfrac{4x+2}{(x+1)(x-1)}[/tex]

[tex]\implies \dfrac{2x}{(x+1)(x-1)}=\dfrac{4x+2}{(x+1)(x-1)}[/tex]

Multiply both sides by (x+1)(x-1):

[tex]\implies \dfrac{2x(x+1)(x-1)}{(x+1)(x-1)}=\dfrac{(4x+2)((x+1)(x-1)}{(x+1)(x-1)}[/tex]

[tex]\implies 2x=4x+2[/tex]

Subtract 4x from both sides:

[tex]\implies 2x-4x=4x+2-4x[/tex]

[tex]\implies -2x=2[/tex]

Divide both sides by -2:

[tex]\implies \dfrac{-2x}{-2}=\dfrac{2}{-2}[/tex]

[tex]\implies x=-1[/tex]

However, if we substitute x = -1 into the original equation we get:

[tex]\implies \dfrac{1}{(-1)-1}+\dfrac{1}{(-1)+1}=\dfrac{4(-1)+2}{(-1)^2-1}[/tex]

[tex]\implies -\dfrac{1}{2}+\dfrac{1}{0}=\dfrac{-2}{0}[/tex]

A number divided by zero is undefined.  Therefore, there is no solution for this equation.

The expression for the cube of the sum of a number and 3 is  (x+3)³

Algebraic expressions are simply defined as arithmetic expressions made up  of variables, terms, coefficients, factors and constants

They may also be known to consist of certain mathematical operations, such as;

Based on the information given, we have;

cube of the sum of a number and 3

Let the number be x

We have the expression to be;

x + 3

Find the cube

(x+3)³

Hence, the expression is (x+3)³

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The complete question is;

Write the expression for The cube of the sum of a number and 3

The two consecutive whole numbers that √72 lies between are 8 and 9.

As per the question statement, we are supposed to find two consecutive whole numbers that √72 lies between.

We know,

8 squared is 64 and 9 squared is 81

since 72 lies in between 64 and 81, then the square root must lie between 8 and 9 which are also whole numbers and consecutive too.

Hence we accept out answer to be 8 and 9.

Hence the two consecutive whole numbers that √72 lies between are 8 and 9.

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The fraction of the  blue T-shirts that are on sale and are size medium are 1/7.

A fraction is used to represent the portion/part of the whole thing. It represents the equal parts of the whole. A fraction has two parts, namely numerator and denominator. The number on the top is called the numerator, and the number on the bottom is called the denominator.

Of all the shirts in the shop , 2/3 of the t-shirts are blue.

Of the blue shirts, 3/7 are on sale.

= 2/3  x 3/7

= 2/7

Out of all the shirts, 2/7 shirts are blue and are on sale.

Of the blue shirts on sale, 1/2 are size medium.  

= 2/7 x 1/2

= 1/7

The fraction of the  blue T-shirts that are on sale and are size medium are 1/7.

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The expression of the number 0.133333 as a fraction would give us 133333/1000000.

Let us recall that the term fraction is used to show that there is a top and a bottom part in the expression. The top part of the fraction is called the numerator while the bottom part of the fraction is called the denominator.

If we want to convert the fraction as we have it back to the decimal then we just have to divide the numerator by the denominator and we are back to the decimal. The decimal is marked by the presence of a decimal point.

To convert 0.133333 to fraction, we would take the decimal point as 1 and all other digits after it as zero thus we have;

133333/1000000.

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Answer:

d(-6,-9),e(3,-9),f(3,-3),g(-6,-3

Step-by-step explanation:

first you look at the location of the point and follow in the direction of which number it is on the X line, then in the direction of which number it is on the Y line and in the parentheses of the coordinates, first write the number from the X line, then from the Y line

ps: I hope I helped you a bit :)

The probability of getting 2 at least once is 1/6.

So, the probability of getting a 2 at least once:

Formula of probability: P = favourable events/total events

Now, substitute the values in the formula as follows:

Therefore, the probability of getting 2 at least once is 1/6.

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The calculation shown in the number line is -4/10 + ( -7/10) = - 1 1/10

This is a sequential arrangement of numbers in a straight line. The scale of number line is shown to suit the problem at hand.

The number line in the question here has a scale of 1. This means that every number represent a unit. However in between the numbers are 10 strokes.

The value of each stroke is gotten from division of one by ten which is

1 ÷ 10 = 1/10

So every line in the number line represent 1/10. The positive side is 1/10 while the negative side is -1/10

The calculation done here is counting from 0 in the negative direction to get -4/10. Then adding -7/10 units to arrive at the point which  is -1 1/10

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Answer:

Step-by-step explanation:

-5/9* -4 = 20/9

Answer=20/9

When you multiply them, there is nothing to simplify in any of them. So when you multiply, the negatives become a positive because -*- is + so the answer is 20/9.

Answer:

5u

Step-by-step explanation:

9-4=5

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{9u - 4u}\\\large\text{COMBINE the LIKE TERMS}\\\mathsf{= (9u - 4u})\\\mathsf{= 9u - 4u}\\\mathsf{= 5u}\\\huge\text{Therefore, your answer should be: \boxed{\mathsf{\mathsf{5u}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

[tex](\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\hspace{10em} \stackrel{slope}{m} ~=~ 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{ 2}(x-\stackrel{x_1}{(-2)}) \implies y -6= 2 (x +2) \\\\\\ y-6=2x+4\implies {\Large \begin{array}{llll} y=2x+10 \end{array}}[/tex]

Based on the population density of the area in 1980 and the area, the population in 1980 was 807,750 people

The population density of an area is based on the population of the area and the area. The formula is:

Population density = Population of area / Surface area

Given that the surface area is 750 square miles and the population density in 1980 was 750 square miles, the population of the area can be found by the formula:

Population in 1980 = Population density in 1980 x surface area

Population in 1980 = 1,077 x 750

= 807,750 people

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The answer to 32z - 48 using factoring is 3/2.

Given,

32z - 48

We have to find the answer using factoring:

Factoring:

Finding things to multiply together to produce an expression is known as factoring. It is comparable to splitting an expression into numerous smaller expressions.

Here,

32z - 48 = 0

Add 48 to both sides

32z - 48 + 48 = 0 + 48

32z = 48

Divide 32 on both sides

32z/32 = 48/32

z = 48/32

Now, we can factorize 48/32

Take 2 as common factor

(48/2) / (32/2) = 24/16

Again, take 2 as common factor

(24/2) / (16/2) = 12/8

Now, take 4 as common factor

(12/4) / (8/4) = 3/2

Here, z = 3/2

That is, the answer for 32z - 48 using factoring is 3/2.

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The number of days that Rosa can continue to buy breakfast and lunch with the money is; 12 days

We are given the following parameters;

Amount held by Rosa = $254

Amount per breakfast = $7

Amount per Lunch = $13

Thus;

Amount spent each day = $7 + $13

Amount spent each day = $20

Now, to find out how many days this money can last her if she doesn't get any more income is;

Number of days = 254/20 = 12 days with $14 left

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In case whereby the the Roman Empire began in 31 B.C. and fell to the Goths in A.D. 476,the Roman civilization lasted for 445 years.

The Roman Empire  can be described as the post-Republican period that can be associated with the ancient Rome , it can be described as the empire that came into the lime light around the 8th century BC , and actually came to an end around  5th century AD and the period it laste can be calculated below as :

In this case as regards to the question, we can calculate how long the Roman civilization lasted as [476+(-31)]

=445 years.

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Answer:

95% of adult males have diastolic blood pressure readings that are at least 102 mmHg

Step-by-step explanation:

The empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean . The empirical rule is further illustrated below

68% of data falls within the first standard deviation from the mean.

95% fall within two standard deviations.

99.7% fall within three standard deviations.

From the information given, the mean is 80 mmHg and the standard deviation is 11 mmHg.

2 standard deviations = 2 × 11= 22

80+ 22= 102 mmHg

Therefore, 95% of adult males have diastolic blood pressure readings that are at least 102 mmHg.

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Lines through the given points are as follow:

a. Line1 is perpendicular to line2.

b. Line1 is neither perpendicular nor parallel to line2.

c. Line1 is parallel to line2.

As given in the question,

Slopes of the lines through the given points are as follow:

Let m₁ and m₂ be the slope of line1 and line2 respectively.

a. Line1 ( 2,-3) , (-4, -6) and Line2 (-3,2) ,  (2,-8)

m₁=(-6+3)/ (-4-2)

    =1/2

m₂=(-8-2)/ (2+3)

    =-2

m₁ × m₂ = -1

Line1 and line2 are perpendicular.

b. Line1(-4, -5) , (4,1) and line2 (6,10) , (-3,-2)

m₁=(1+5)/ (4+4)

    =3/4

m₂=(-2-10)/ (-3-6)

    =4/3

m₁ × m₂=1

Line1 and line2 are neither perpendicular nor parallel .

c. Line1 (0,-4) , (-2,-8) and line2 (-1,5), (1,9)

m₁=(-8+4)/ (-2-0)

    =2

m₂=(9-5)/ (1+1)

    =2

m₁=m₂

Line1 and line2 are parallel

Therefore, lines through the given points are as follow:

a. Line1 is perpendicular to line2.

b. Line1 is neither perpendicular nor parallel to line2.

c. Line1 is parallel to line2.

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Answer:70.409

Step-by-step explanation:73.261-2.852

Answer:

t = 10b + 10c

Step-by-step explanation:

As stated in the problem, 1 bag holds 10 doughnuts so that give us 10b since we don't know how many bags were bought/sold but we do know how many comes in each. Same goes for cartons.

Were asked to write a formula for t, and since we don't know how many bags(b) or cartons(c) were sold, our t remains t.

Answer: f(1)=0

Step-by-step explanation:

f(x)=1-x

f(1)=1-1

f(1)=0