The function f(x) = x2 sin(1/x), x ≠ 0, f(0) = 0 at x = 0 (A) Is continuous but not differentiable (B) Is discontinuous (C) Is having continuous derivative (D) Is continuous and differentiableRead more on Sarthaks.com - https://www.sarthaks.com/553151/the-function-f-x-x-2-sin-1-x-x-0-f-0-0-at-x-0-a-is-continuous-but-not-differentiable

The option that is NOT equivalent to 52% is Option B: 5.2.

To determine which option is not equivalent to 52%, we need to compare the given options with the value of 52%. Let's examine each option and determine if it is equivalent to 52%.

Option A: 0.52

Option B: 5.2

Option C: 0.052

Option D: 520

To find the equivalent decimal value of a percentage, we divide the percentage by 100.

Let's calculate the equivalent decimal value for 52%:

52% = 52/100 = 0.52

Now, let's compare this with the given options:

Option A: 0.52

This option is equivalent to 52%, as we calculated earlier.

Option B: 5.2

This option is not equivalent to 52%. It represents 520%, which is ten times greater than 52%.

Option C: 0.052

This option is not equivalent to 52%. It represents 5.2%, which is one-tenth of 52%.

Option D: 520

This option is not equivalent to 52%. It represents the whole number 520, which is a hundred times greater than 52%.

Therefore, the option that is NOT equivalent to 52% is Option B: 5.2.

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The correct answer is a. means.  Analysis of variance (ANOVA) is a statistical method used to compare the means of several populations or groups.

It determines whether there are statistically significant differences among the means of multiple groups based on the variation observed within and between the groups.

ANOVA is commonly used in various fields, such as experimental research, social sciences, and business, to assess the impact of different factors or treatments on a response variable. By comparing the means of multiple groups, ANOVA helps determine if there is evidence to suggest that the group means are different and not simply due to random chance.

Therefore, in the given context, the blank should be filled with "means" as ANOVA compares the means of several populations

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The population declines by approximately 2.96% each decade.

To determine the percentage decline of a population each decade, we need to consider the compounding effect of the annual decline over a 10-year period.

Given that the population declines by 0.3% each year, we can calculate the overall decline over a decade as follows:

(1 - 0.003)^10

Using a calculator, we find that (1 - 0.003)^10 ≈ 0.970439.

To express this as a percentage decline, we subtract this value from 1 and multiply by 100:

(1 - 0.970439) * 100 ≈ 2.96.

Therefore, the population declines by approximately 2.96% each decade.

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The value of x for the triangles are:

13) x = 7.5 units

14) x = 4√6 units

15) x = (10√3)/3  units

16) x = 12 units

Trigonometry deals with the relationship between the ratios of the sides of a right-angled triangle with its angles.

Check the attached for labeling. The value of x for the triangles can be determined as follow.

No. 13

Consider the left triangle:

sin 60° = y/10

y = 10 * sin 60°

y = 5√3 units

Consider the right triangle:

sin 60° = x/y

x = (5√3) * sin60°

x = 7.5 units

No. 14

Consider the upper triangle:

sin 60° = 6/y

y = 6 / sin60°

y = 4√3 units

Consider the lower triangle:

cos 45° = y/x

cos 45° = (4√3)/x

x = (4√3)/cos 45°

x = 4√6 units

No. 15

Consider the left triangle:

tan 60° = (10√3)/y

y = (10√3) / tan60°

y = 10 units

Consider the right triangle:

tan 60° = y/x

tan 60° = 10/x

x = 10/tan 60°

x = (10√3)/3  units

No. 16

Consider the right triangle:

sin 60° = 6/y

y = 6 / sin60°

y = 4√3 units

Consider the right triangle:

tan 60° = x/y

tan 60° = x/(4√3)

x = 4√3 * tan 60°

x = 12 units

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The correct answer is B. t-distribution.

In the testing of hypothesis about the population mean when the population standard deviation is unknown, the critical values are determined using the t-distribution.

When the population standard deviation is unknown, we use the t-distribution to account for the uncertainty in estimating the population standard deviation from the sample data.

The t-distribution is similar to the standard normal (z) distribution but has thicker tails, which allows for more variability in the data.

The critical values, also known as the cutoff values, are the boundary values that determine the rejection region for the hypothesis test. These values are obtained from the t-distribution table or using statistical software.

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The monetary costs for Job A are the cost to commute and the affording the formal work attire. For Job B, they are the low entry - level pay.

The non - monetary costs for Job A include the long commute and limited opportunities for advancement.  For Job B it is the repetitive work.

The opportunity cost that will be encountered with Job A is, other than commuting, individuals could utilize the time for various activities including spending quality time with loved ones, engaging in hobbies, or unwinding.

Also, working additional hours beyond regular schedules could result in burnout and reduced efficiency.

For Job B, the opportunity cost is instead of filling out and submitting paperwork, valuable time could be utilized for networking or acquiring new skills.

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Answer: 175cm^2

Step-by-step explanation:

area of parallelogram=base*height

a=14*5=60

area of trapezium=1/2*sum of parallel side*height

a(trapzium)=105

total area=a+a(trapzium)=60+105=175

The equation of the plane that is equidistant from points A and B is:

-6x - 4y - 2z = 0

To find the equation of the plane equidistant from points A = (3, 2, 1) and B = (-3, -2, -1), we can follow these steps:

1. Find the midpoint M between points A and B:

  M = ((3 + (-3)) / 2, (2 + (-2)) / 2, (1 + (-1)) / 2)

    = (0, 0, 0)

2. Find the vector v from point A to point B:

  v = B - A = (-3 - 3, -2 - 2, -1 - 1)

      = (-6, -4, -2)

3. Since the plane is equidistant from A and B, any vector that lies on the plane must be orthogonal (perpendicular) to the vector v. Therefore, the normal vector of the plane is the same as the vector v:

  n = v = (-6, -4, -2)

4. Now we have the normal vector n = (-6, -4, -2) and a point on the plane M = (0, 0, 0). We can use the point-normal form of the equation of a plane to obtain the equation:

  Ax + By + Cz = D

  Plugging in the values, we have:

  -6x - 4y - 2z = D

  To find the value of D, we substitute the coordinates of the midpoint M into the equation:

  -6(0) - 4(0) - 2(0) = D

  0 = D

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The total area of the composite figure is 198.54 square cm

From the question, we have the following parameters that can be used in our computation:

The composite figure

The total area of the composite figure is the sum of the individual shapes

So, we have

Area = circle + rectangle

This gives

Area = π * (10/2)² + 10 * (22 - 10)

Evaluate

Area = 198.54

Hence, the total area of the figure is 198.54 square cm

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The correct answer is:

b. Test statistic: t = -1.841

Critical value = ±2.045

Do not reject H0

To conduct the hypothesis test using the pooled t-test, we compare the calculated test statistic to the critical value at a significance level of α = 0.05.

Given the following statistics for two independent samples:

Sample 1: x1 = 11.1, s1 = 4.5, n1 = 14

Sample 2: x2 = 17.2, s2 = 4.9, n2 = 17

The pooled t-test assumes that the population variances are equal. We calculate the pooled standard deviation (sp) using the formula:

sp = sqrt(((n1-1)*s1^2 + (n2-1)*s2^2) / (n1 + n2 - 2))

Next, we calculate the test statistic (t) using the formula:

t = (x1 - x2) / (sp * sqrt(1/n1 + 1/n2))

For the given data, the calculated test statistic is t = -3.577.

To determine whether to reject or fail to reject the null hypothesis (H0), we compare the absolute value of the test statistic to the critical value from the t-distribution at a significance level of α = 0.05. In this case, the critical value is ±1.699.

Since the absolute value of the test statistic (-3.577) is greater than the critical value (1.699), we do not reject the null hypothesis (H0). Therefore, the correct answer is c. Test statistic: t = -3.577, Critical value = ±1.699, Do not reject H0.

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The probability that Lice has at least two books in her backpack that cover the same subject is 56/330, which can be simplified to 28/165.

To calculate the probability that Lice has at least two books in her backpack that cover the same subject, we can consider the different cases where she has duplicates.

Case 1: Two books of the same subject and one book of a different subject.

The probability of choosing two books of the same subject is given by:

(4/12) * (3/11) * (8/10) * ³C₂ (choose 2 subjects out of 3)

Case 2: Three books of the same subject.

The probability of choosing three books of the same subject is given by:

(4/12) * (3/11) * (2/10) * ³C₁ (choose 1 subject out of 3)

To find the total probability, we sum up the probabilities of these two cases:

P(at least two books of the same subject) = P(case 1) + P(case 2)

P(at least two books of the same subject) = [(4/12) * (3/11) * (8/10) * ³C₂] + [(4/12) * (3/11) * (2/10) * ³C₁]

Simplifying the equation, we have:

P(at least two books of the same subject) = [32/330] + [24/330]

P(at least two books of the same subject) = 56/330=28/165.

Therefore, the probability that Lice has at least two books in her backpack that cover the same subject is 56/330, which can be simplified to 28/165.

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A solid S has a circular base with radius r, and its cross-sections perpendicular to the base are squares. The task is to determine the volume of S by finding the area of each cross-section and integrating those areas.

To determine the volume of S, we can start by finding the area of each cross-section. Since the cross-sections are squares, the area can be found using the formula A = s^2, where s is the side length of the square. The side length of each square can be found by considering the radius of the circular base and the fact that the diagonal of each square is equal to the diameter of the circular base. Using the Pythagorean theorem, we can find that s = sqrt(2)r. The area of each cross-section is therefore A = (sqrt(2)r)^2 = 2r^2.

To find the volume of S, we need to integrate the areas of the cross-sections. Since the cross-sections are perpendicular to the base, the integral can be set up as ∫2r^2 dx, where x represents the distance from the base. The limits of integration are 0 to the height of S, which is not given in the problem. However, we can still find the general formula for the volume of S by integrating the expression for the area of each cross-section. This gives us V = ∫2r^2 dx = 2r^2x + C, where C is the constant of integration. The volume of S can be found by evaluating this expression at the limits of integration.

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The series ∑ₖ₌₁ᵢₙfₖ does not converge as the limit of the ratio of its terms is infinite (∞).

What is converge series?

In mathematics, a convergent series is one in which, as the number of terms rises, the sum of the terms approaches a finite value. In other words, a convergent series "converges" to a particular value or limit when its terms are added together.

To determine whether the series converges or diverges, we can use the limit comparison test. The limit comparison test states that if the limit of the ratio of the terms of the given series and a known convergent series is a positive finite value, then both series have the same convergence behavior.

Let's consider the known convergent p-series ∑ₖ₌₁ᵢₙ₁/k²,q where p = 2. Now, we can apply the limit comparison test by calculating the limit of the ratio of the terms of the given series and the known convergent series:

limₖ→∞ [(k³ - 6)/(k⁴ + 7)] / (1/k²)

Simplifying the expression inside the limit:

limₖ→∞ [(k³ - 6)/(k⁴ + 7)] * (k²/1)

Taking the limit as k approaches infinity:

limₖ→∞ [(k³ - 6)/(k⁴ + 7)] * (k²/1) = limₖ→∞ [(k³ - 6)(k²)] / (k⁴ + 7)

By evaluating the limit, we find:

limₖ→∞ [(k³ - 6)(k²)] / (k⁴ + 7) = ∞

Since the limit is divergent (∞), the given series does not converge.

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The Giapetto problem is a linear programming problem that involves maximizing profit from producing two types of wooden toys. In response to the questions:

a. The dual of the Giapetto problem can be obtained by interchanging the roles of the variables and constraints. The objective of the dual problem is to minimize the sum of the dual variables (representing the costs) subject to the constraints defined by the coefficients of the original primal problem.

b. To determine the optimal dual solution, we can examine the optimal tableau of the Giapetto problem. The dual solution is obtained by considering the dual variables associated with the constraints. These variables represent the shadow prices or the marginal values of the resources in the primal problem. By analyzing the optimal tableau, we can identify the values of the dual variables and determine the optimal dual solution.

c. In this instance, we can verify that the Dual Theorem holds. The Dual Theorem states that the optimal value of the dual problem is equal to the optimal value of the primal problem. By comparing the optimal solutions obtained in parts (a) and (b), we can confirm whether they are equal. If the optimal values match, it confirms the validity of the Dual Theorem, indicating a duality relationship between the primal and dual problems. The dual of the Giapetto problem involves minimizing costs instead of maximizing profit. By examining the optimal tableau, we can determine the optimal dual solution. Lastly, by comparing the optimal solutions of the primal and dual problems, we can verify the Dual Theorem's validity, which states that the optimal values of both problems are equal, demonstrating their duality relationship.

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To maintain equilibrium in the position shown, we need to determine the magnitude of the vertical force P at point C and the reactions at points A and B.

(a) To find the magnitude of the vertical force P at point C, we can use the principle of equilibrium. The sum of the vertical forces must be equal to zero. Since the weight of the load is 120 lbs acting downwards, the force P at point C should be equal to the weight of the load to maintain equilibrium. Therefore, the magnitude of force P is 120 lbs.

(b) Assuming that the bearing at point B does not exert any axial thrust, we can analyze the reactions at points A and B. Since the system is in equilibrium, the sum of the forces in the horizontal and vertical directions at points A and B should be equal to zero.

In the horizontal direction, the reaction at point B will balance the horizontal component of force P. However, without additional information or constraints, we cannot determine the specific value of the reaction at point B.

In the vertical direction, the reaction at point A will balance the weight of the load plus the vertical component of force P. Therefore, the magnitude of the reaction at point A is the sum of the weight of the load and the vertical component of force P, which is 120 lbs plus the vertical component of force P.

In summary, the magnitude of the vertical force P at point C should be 120 lbs, and the reactions at points A and B depend on additional information or constraints that are not provided in the given problem statement

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To maintain equilibrium in the given position with a small winch raising a 120-lb load, the magnitude of the vertical force P at point C needs to be determined. Additionally, the reactions at points A and B can be calculated, assuming the bearing at B does not exert any axial thrust.

(a) To maintain equilibrium, the vertical force P at point C should be equal to the weight of the load, which is 120 lbs. This is because for an object to be in equilibrium, the sum of the forces acting on it must be zero. In this case, the force P must balance out the weight of the load, ensuring there is no net force in the vertical direction.

(b) Assuming the bearing at B does not exert any axial thrust, the reactions at points A and B can be determined. The reaction at point A, denoted as RA, will be equal in magnitude and opposite in direction to the vertical force P. This is because the weight of the load is transmitted through the cable to point A. As for point B, the vertical reaction, denoted as RB, will be equal to the weight of the load (120 lbs) since there is no axial thrust from the bearing at B.

In summary, to maintain equilibrium, the magnitude of the vertical force P at point C should be 120 lbs. The reactions at points A and B are equal to 120 lbs and 120 lbs, respectively, assuming no axial thrust from the bearing at B.

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Answer:

To create a square snowflake, use the following steps. (See figure below.) 1. Draw a square. 2. Divide each of the square's straight lines into fourths. In a clockwise order: • Leave the first fourth alone. • Replace the second fourth with a square that's on the outer side of the line. • Replace the third fourth with a square that's on the inner side of the line. . Leave the last fourth alone. Apply the above procedure to each of the square's straight lines. Be sure to do the above in a clockwise order! 3. Apply the procedure from step 2 to each of the straight lines in step 2. 4. Apply the procedure from step 2 to each of the previous step's straight lines. Continue this process indefinitely. step 1 15 Dividing the lines into fourths Replacing the 2nd and 3rd fourths on the top line Replacing the 2nd and 3rd fourths on two lines Replacing the 2nd and 3rd fourths on all lines step 2 (a) Find a formula for the total perimeter P of step n of the process described above if the original square has sides of length 1 ft. Po = ft (b) Use the formula from part (a) to find the perimeter of a square snowflake. (Enter INFINITY for co if needed.) P= ft (c) Find a formula for the total area A of step n of the above process if the original square has sides of length 1 ft. HINT: It's an incredibly easy formula. Don't make it hard. A = sq ft (d) Use the formula from part (c) to find the area of a square snowflake. (Enter INFINITY for co if needed.) A = sq ft

Step-by-step explanation:

If a curve is defined by parametric equations with x-values in the range [2, 5] and y-values in the range [2, 5], then nothing can be said about the curve. The answer is D.

Given the parametric equations x = f(t) and y = g(t), where the range of f is [2, 5] and the range of g is [2, 5], we can't make any definitive statements about the shape or position of the curve without further information about the functions f(t) and g(t).

The ranges of f and g only provide constraints on the possible values of x and y, but they don't determine the specific behavior of the curve.

Without knowing the explicit forms of f(t) and g(t) or any additional information about the curve, we cannot determine its shape, whether it lies inside or outside certain regions, or whether it corresponds to a specific geometric figure like a circle or a line.

Hence, the correct option is D. Nothing can be said about the curve.

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Answer:

Density = Mass / Volume

3 g/cm^3 = 25 g / Volume

Volume = 25 g / 3 g/cm^3 = 8.33 cm^3

Round to two decimal places: 8.33 cm^3

Therefore, the volume of the block of wood is 8.33 cm^3.

The area of the domain enclosed by the curve with parametric equations x = tsin t, y = cost, t ∈ [0, 2π] is 2π + 2.

The parametric equations given are:

x = t sin t
y = cos t

To find the area of the domain enclosed by the curve, we can use the formula for the area of a region bounded by a curve given in parametric form:

A = ∫[a,b] y dx

where a and b are the limits of the parameter t that describe the domain of the curve.

In this case, we have:

a = 0
b = 2π

So, we need to compute:

A = ∫[0,2π] cos(t) (t sin(t)) dt

Using integration by parts with u = t and dv = sin(t) dt, we get:

A = [t cos(t)]|[0,2π] - ∫[0,2π] cos(t) dt + ∫[0,2π] sin(t) dt

The first integral evaluates to:

[t cos(t)]|[0,2π] = 2π

The second integral evaluates to:

∫[0,2π] cos(t) dt = [sin(t)]|[0,2π] = 0

The third integral evaluates to:

∫[0,2π] sin(t) dt = [-cos(t)]|[0,2π] = 2

Therefore, the area of the domain enclosed by the curve is:

A = 2π - 0 + 2 = 2π + 2

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For the function, f(x)=x, the most appropriate way to describe function is

(b) f is a bijection, because it is one-to-one and onto.

The function f(x) = x, is well-defined,

We let x ∈ R (real-numbers), then f(x) = x ,∈ R;

One-to-One : We have f(x) = f(y) ⇒ x = y,

So, the function "f" is one-to-one,

Onto : For all y∈ R, there exist x ∈ R, such that f(x) = y, which is  x = y,

Hence, the function "f" is one-to-one and onto, so, it can be called as an bijective function.

Therefore, the correct option is (b).

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The given question is incomplete, the complete question is

The domain and target of the following function is the set of real numbers. f(x)=x,

Which is the most appropriate way to describe this function?

(a) f is one-to-one but not onto,

(b) f is a bijection,

(c) f is onto but not one-to-one,

(d) f is not well defined.

The given distribution of frequency of yearly income represents a positively skewed distribution.

In a positively skewed distribution, the tail of the distribution extends towards higher values, and the majority of the data is concentrated towards the lower end. This means that there are relatively fewer high-income values and more low-income values in the distribution.

Regarding the effect on the mean, a positively skewed distribution tends to pull the mean towards the higher end of the distribution. This happens because the few higher values have a disproportionate impact on the overall average. As a result, the mean is typically greater than the median in a positively skewed distribution. The presence of extreme high-income values in the distribution can greatly influence and increase the mean value.

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In circle S with m/RST = 82° and RS 19, find the area of sector RST to the nearest hundredth is 18.27 ft²

First, find the ratio of the sector's central angle to 360°.

Code snippet

82° / 360° = 0.22727272727

Then multiply that ratio by the area of the whole circle to find the area of the sector.

πr² * 0.22727272727 = 18.267948969

Round to the nearest hundredth:

area of sector RST = 18.27 ft²

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In circle S with m/RST = 82° and RS 19, find the area of sector RST. Round to the nearest hundredth.

Answer:

Step-by-step explanation:

The sample space for rolling a number cube with faces labeled 1 to 6 is {1, 2, 3, 4, 5, 6}.

Event- A  is a set of all even number .hence

Event A:{2,4,6} ,

Event B is a set of all outcomes less than 4.hence

Event B:{1,2,3}

a.Event A and B is the intersection of the two events: {2}, as this is the only number that is even and less than 4.

Hence event A and B is {2}.

Explanation:

To find the outcomes for event A and B, we need to determine the intersection of the two events, which means finding the outcomes that satisfy both event A and event B. Event A is the event that the number rolled is even, and event B is the event that the number rolled is less than 4.

The even numbers in the sample space are 2, 4, and 6. The numbers less than 4 in the sample space are 1, 2, and 3. The only number that satisfies both events is 2, since it is both even and less than 4. Therefore, the outcomes for event A and B is the set {2}.

The next number in the given series 6 18 20 10 30 32 16 should be. 48

A series is produced by sequence, which is also known as progression. One of the fundamental ideas in mathematics is sequence and series.

A series is the total of the elements in a sequence, whereas sequences are groups of numbers arranged in an ordered and specific manner.

As an illustration, the series that corresponds to the four-element sequence 2, 4, 6, and 8 is 2 + 4 + 6 + 8;

the total of the series, or its value, is 20.

The next series follows the order as

6 × 3 = 18

18 + 2 = 20

20 / 2 = 10

10 × 3 = 30

30 + 2 = 32

32 / 2 = 16

The following figure will be 16 x 3 = 48.

Hence, the required answer number is 48.

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The distance traveled by a particle with position (x, y) as t varies in a given time interval can be determined by integrating the speed of the particle with respect to time over that interval. This integration involves calculating the derivatives of x and y with respect to t, representing the rates of change in the x and y coordinates over time. By integrating the speed function, we obtain the total distance traveled by the particle within the given time interval.

To compare this distance with the length of the curve, we need to consider the curve traced by the particle's path in the (x, y) plane. The length of the curve represents the total distance along the curve, taking into account its shape and curvature. Comparing the distance traveled by the particle with the length of the curve allows us to assess if the particle deviates from a straight path or follows a more complex trajectory, providing insights into the particle's motion characteristics.

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The distance traveled by a particle with position (x, y) as t varies in a given time interval, we need to integrate the speed of the particle with respect to time over that interval. This will give us the length of the curve traced by the particle's position.

The distance traveled by a particle is determined by integrating its speed over a given time interval. The speed of the particle is the magnitude of its velocity, which can be calculated using the derivatives of the position function.

Let's assume the particle's position is given by a parametric equation x = f(t) and y = g(t), where t represents time. The velocity of the particle can be found by taking the derivatives of f(t) and g(t) with respect to t.

The speed of the particle is then calculated as the magnitude of the velocity vector, which is the square root of the sum of the squares of the derivatives: sqrt((dx/dt)^2 + (dy/dt)^2).

To find the distance traveled by the particle over a specific time interval, we integrate the speed function over that interval with respect to t. This will give us the length of the curve traced by the particle's position.

In summary, to find the distance traveled by a particle, we calculate the speed as the magnitude of its velocity and integrate the speed function over the given time interval. The result will be the length of the curve traced by the particle's position.

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The series is convergent according to the ratio test.

Convergence of the series ∑[n=1 to ∞] (-3)[tex]^n[/tex] / (n² ) can be determined using the ratio test. First, we need to identify the general term (an) of the series, which is given by an = (-3)[tex]^n[/tex] / (n² ).

Now, let's apply the ratio test to evaluate the limit:

lim[n → ∞] |(a_{n+1}) / (a_n)|

Substituting the values:

lim[n → ∞] |((-3)[tex]^(n+1)[/tex]/ ((n+1)^2)) / ((-3)[tex]^n[/tex] / (n² ))|

Simplifying the expression:

lim[n → ∞] |-3(n² ) / ((n+1)² )|

lim[n → ∞] |-3n²  / (n²  + 2n + 1)|

Since both the numerator and denominator are of the same degree, we can divide every term by n²  to simplify further:

lim[n → ∞] |-3 / (1 + 2/n + 1/n² )|

As n approaches infinity, the terms 2/n and 1/n²  approach 0, so we have:

lim[n → ∞] |-3 / (1 + 0 + 0)|

lim[n → ∞] |-3 / 1|

The absolute value of -3 is simply 3, so the limit is:

lim[n → ∞] |-3 / 1| = 3

Now, we can evaluate the limit:

lim[n → ∞] (an+1 / an) = 3

Since the limit is less than 1 (3 < 1), the series converges by the ratio test.

In summary, the series ∑[n=1 to ∞] (-3)[tex]^n[/tex] / (n² ) is convergent, as determined by the ratio test.

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Answer:

23.6 m

Step-by-step explanation:

In a right-angled triangle, a ² + b ² = c ²

b² = 10² - 8.8²

100 - 77.44

b = 4.75

perimeter = 4.75 + 8.8 + 10 = 23.55 = 23.6 m to nearest tenth

Answer:

The answer is 23.5m to 1 d.p

Step-by-step explanation:

c²=a²+b²

b²=c²-a²

b²=10²-8.8²

b²=100-77.44

b²=22.56

√b²=√22.56

b=4.7m

Perimeter =a+b+c

P=8.8+4.7+10

P=23.5

P=23.5m to 1 d.p

The relation n² ≡ 1 (mod 8) for any odd positive integer n.

To prove that if n is an odd positive integer, then n² ≡ 1 (mod 8), we can use direct proof.

Let's consider an odd positive integer n. We can express n as n = 2k + 1, where k is a non-negative integer.

Now let's square both sides of the equation:

n² = (2k + 1)²

n² = 4k² + 4k + 1

n² = 4k(k + 1) + 1

Now we need to consider two cases:

Case 1: k is even.

If k is even, we can write k = 2m, where m is a non-negative integer. Substituting this into the equation, we get:

n² = 4(2m)(2m + 1) + 1

n² = 8m(2m + 1) + 1

In this case, 8m(2m + 1) is clearly divisible by 8, so we can write it as 8p, where p is an integer. Therefore, we have:

n² = 8p + 1

Case 2: k is odd.

If k is odd, we can write k = 2m + 1, where m is a non-negative integer. Substituting this into the equation, we get:

[tex]n² = 4(2m + 1)(2m + 2) + 1 \\ n² = 4(2m + 1)(m + 1) + 1 \\ n² = 8(m + 1)(2m + 1) - 8(m + 1) + 1 \\ n² = 8(m + 1)(2m + 1) - 8m - 7

[/tex]

In this case, we can see that 8(m + 1)(2m + 1) is clearly divisible by 8, so we can write it as 8p, where p is an integer. Therefore, we have:

n² = 8p - 8m - 7

n² = 8(p - m) - 7

Now, we need to consider two subcases:

Subcase 2.1: p - m is even.

If p - m is even, we can write p - m = 2q, where q is an integer. Substituting this into the equation, we get:

n² = 8(2q) - 7

n² = 16q - 7

Subcase 2.2: p - m is odd.

If p - m is odd, we can write p - m = 2q + 1, where q is an integer. Substituting this into the equation, we get:

n² = 8(2q + 1) - 7

n² = 16q + 1

In both subcases, we can see that n² ≡ 1 (mod 8).

Therefore, regardless of whether k is even or odd, we have shown that n² ≡ 1 (mod 8) for any odd positive integer n.

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Answer:

C ≈ 10.63

Step-by-step explanation:

A= π r^2

C=2 π r

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Answer:  B   6[tex]\sqrt{\pi }[/tex]

Step-by-step explanation:

Given:  A=9

Find: Circumference

Solution:

Formula for C=2[tex]\pi[/tex]r

We need r which is not given but we can find r from the Area

A=[tex]\pi r ^{2}[/tex]                       >substitute what is given: A=9

9 = [tex]\pi r ^{2}[/tex]                     >Divide both sides by pi

[tex]\frac{9}{\pi }=r^{2}[/tex]                      > take square root of both sides

r  = [tex]\sqrt{\frac{9}{\pi } }[/tex]                    >take square root of top

r=[tex]\frac{3}{\sqrt{\pi } }[/tex]

Now that we have r we can substitute into C

C= 2[tex]\pi[/tex]r                     >substitute r

C = 2 [tex]\pi[/tex] ([tex]\frac{3}{\sqrt{\pi } }[/tex])             >can't have root on bottom, multiply by [tex]\frac{\sqrt{\pi } }{\sqrt{\pi } }[/tex]

C =  2 [tex]\pi[/tex] ([tex]\frac{3}{\sqrt{\pi } }[/tex])  [tex]\frac{\sqrt{\pi } }{\sqrt{\pi } }[/tex]      >simplifiy roots on bottom

[tex]C = \frac{2\pi (3)(\sqrt{\pi } }{\pi }[/tex]       > the pi's cancel

C=2(3)[tex]\sqrt{\pi }[/tex]

C= 6[tex]\sqrt{\pi }[/tex]

B