The function h(t)=−16t2+7t+63 represents the height of a t-shirt launched from a t-shirt cannon after t seconds. a. Write an equation that tells us when the t-shirt hits the ground. b. At what time does the t-shirt hit the ground. SHOW ALL WORK. Round to 2 decimal places.

Answer:

[tex](a)\ -16t^2 + 7t + 63=0[/tex]

[tex](b)\ t = 2.215[/tex]

Step-by-step explanation:

Given

[tex]h(t) = -16t^2 + 7t + 63[/tex]

Solving (a): Equation when it hits the ground.

This means that [tex]h(t) = 0[/tex]

So, we have:

[tex]h(t) = -16t^2 + 7t + 63[/tex]

[tex]-16t^2 + 7t + 63=0[/tex]

Solving (b): The value of t in (a)

[tex]-16t^2 + 7t + 63=0[/tex]

Using quadratic formula, we have:

[tex]t = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

This gives:

[tex]t = \frac{-7 \± \sqrt{7^2 - 4*-16*63}}{2*-16}[/tex]

[tex]t = \frac{-7 \± \sqrt{49+ 4032}}{2*-16}[/tex]

[tex]t = \frac{-7 \± \sqrt{4081}}{-32}[/tex]

[tex]t = \frac{-7 \± 63.88}{-32}[/tex]

Split

[tex]t = \frac{-7 + 63.88}{-32}; or\ t = \frac{-7 - 63.88}{-32}[/tex]

[tex]t = \frac{56.88}{-32}; or\ t = \frac{-70.88}{-32}[/tex]

[tex]t = -1.7775; or\ t = 2.215[/tex]

Time can't be negative; So:

[tex]t = 2.215[/tex]

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