The lines of symmetry in a regular polygon are equal to the number of sides minus 2. True or False

Answers

Answer 1

Answer:

False

Step-by-step explanation:

A regular polygon may be defined as the polygon that have sides of equal length known as equilateral and angles made up of equal angles, known as equiangular.

The [tex]$\text{number of lines}$[/tex] of symmetry in a regular polygon is always equal to the number of sides of the polygon. For example, a regular pentagon have 5 sides, so the lines of symmetry of the regular pentagon is also 5, a square having 4 sides also has 4 lines of symmetry.


Related Questions

Find the volume of a pyramid with a square base, where the perimeter of the base is
9.9 cm and the height of the pyramid is 8.6 cm. Round your answer to the nearest
tenth of a cubic centimeter.

Answers

The volume of a pyramid with a square base is 17.6 cubic centimeter.

Given the following data;

Perimeter of base = 9.9 cmHeight of pyramid = 8.6 cm

To find the volume of a pyramid with a square base;

Mathematically, the volume of a pyramid with a square base is given by the formula;

[tex]V = A(\frac{h}{3})[/tex]

Where;

V is the volume of a pyramid with a square baseA is the area of the square base.h is the height of the pyramid.

First of all, we would determine the length of sides of the square base from its perimeter;

[tex]Perimeter \ of \ square = 4s\\\\9.9 = 4s\\\\s = \frac{9.9}{4}[/tex]

s = 2.475 cm

Next, we would determine the area of the square;

[tex]Area \ of \ a\ square = s^{2} \\\\Area \ of \ a\ square = 2.475^{2}[/tex]

Area of a square = 6.126 cm

Now, we would use the above value to find the volume of a pyramid with a square base.

Substituting the values into the formula, we have;

[tex]V = 6.126*(\frac{8.6}{3})\\\\V = 6.126*2.867[/tex]

Volume, V = 17.6 cubic centimeter

Therefore, the volume of a pyramid with a square base is 17.6 cubic centimeter

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Angel saved $100 a week for a year. She spent 40%
of her savings on a new bed. How much did she
spend on the bed?

Answers

Answer:

40 because 40 percent of 100 is 40. You can just multiply the number by the percentage $100x40%

A radio station broadcasts a signal over an area with a 120-mile diameter. The population density of the area is 100 people per square mile.

How many people are within receiving distance of the broadcast signal?

Use 3.14 for pi.

Answers

Answer:

1,130,400 people

Step-by-step explanation:

Find the area of the broadcasting area, using the circle area formula.

Since the diameter is 120 miles, the radius will be 60 miles.

Use the circle area formula, plug in 60 as r, and plug in 3.14 as pi:

A = [tex]\pi[/tex]r²

A = (3.14)(60²)

A = 11304

So, the area is 11304 square miles

To find how many people are in receiving distance, multiply this by 100, since there are 100 people per square mile.

11304(100)

= 1,130,400

So, 1,130,400 people are within receiving distance of the signal.

Answer:

1,130,400

Step-by-step explanation:

3
Select the correct answer.
Which data set has the greatest spread for the middle 50% of its data?
O A. {18, 13, 22, 17, 21, 24}
OB.
{17, 19, 22, 26, 17, 14}
Ос.
{13, 17, 12, 21, 18, 20}
D.
{18, 21, 16, 22, 24, 15)
Reset
Next

Answers

Answer:

D

Step-by-step explanation:

Please help me after this one I have one more

Answers

Answer:

3    2/21

Step-by-step explanation:

used a calculator

5. A construction area has 6 cylindrical posts protecting the
equipment. They are filled with sand to reinforce them. If each
cylinder is 4 feet tall and has a diameter of 1 foot, how much sand
was needed to fill the cylinders?
Record your answer and fill in the bubbles on your answer. (If it’s wrong or random you will be reported)
document. Be sure to use the correct place value.

Answers

Answer: what’s the answer ?

Step-by-step explanation:

If each cylinder is 4 feet tall and has a diameter of 1 foot then the amount of sand needed to fill the cylinders is 19 cubic feet.

Given that there are 6 cylindrical posts protecting the equipment

To find tge amount of sand needed for cylinders,

We need to find the volume of each cylinder.

The cylinder is 4 feet tall and has a diameter of 1 foot,

Height is 4 feet

Diameter is 1 foot and radius is 1/2 feet.

Volume of cylinder = πr²h

=3.14×(1/4)(4)

=3.142 cubic feet.

As there are six cylinders.

Multiply 6 with 3.142

Amount of sand needed = 6×3.142

= 18.852 cubic feet.

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Can some help with this Math question .?

No linksss

Answers

Answer:

I think ir is 2 -2

Step-by-step explanation:

hope it helps

Whoever solves it correctly will get 32 points

Answers

Ur answer is c!!!!!!!

please reply within 10 minutes​

Answers

Answer:

H

Step-by-step explanation:

For F  - Median For Class 1 is 52.5 Median for Class 2 is 75 ( False )

For G - Range for class 2 is 75 Range for class 1 is 45.9 ( False )

For H - IQR for class 1 is 30.45 IQR for class 2 is 60 ( True )

For J - Minimum for Class 2 is 30 Minimum for Class 1 is 30 ( False )

HELPPPPPPPPPPPP
ind the possibility that a random selected point within the circle falls in the red shaded area

Answers

Answer:

25cm

Step-by-step explanation:

one the possibility 36 - 11 =25 the answer is 25

You roll a 6-sided die.




What is P(divisor of 63)? Choose the closest answer.

Answers

Answer:

the divisors of 63 are

Step-by-step explanation:

1,3,7,9,21,63

Answer:

Fraction Form: 2/6 or 1/3

or Decimal Form: .333

or Percent Form: 33.333?%

Step-by-step explanation:

The divisors of 63 that are 1-6 is 1 and 3

So there are TWO numbers out of SIX.

We would turn that into the fraction 2/6 and then simplify (optional) it to 1/3.

Then we use 2/6 to convert it to multiple forms if needed.

I need answers asap. ​

Answers

J. The wonderful answer is J

The spinner shown has congruent sections. The spinner is spun 63 times. What is a reasonable prediction for the number of times the spinner will land on a section that is shaded red?​

Answers

Answer:

36 times

Step-by-step explanation:

Given

[tex]Red = 4[/tex]

[tex]Total = 7[/tex]

[tex]n = 63[/tex]

See attachment

Required

Predicted number of times to land on red

First, we calculate the probability of landing on red

[tex]Pr = \frac{Red}{Total}[/tex]

[tex]Pr = \frac{4}{7}[/tex]

The predicted number of red is the =n calculated as:

[tex]Red = Pr * n[/tex]

[tex]Red = \frac{4}{7}*63[/tex]

[tex]Red = 4 * 9[/tex]

[tex]Red = 36[/tex]

Identify the following solid figure.

hexagonal prism
pentagonal prism
rectangular prism
triangular prism

QUICK PLEASE!!

Answers

The Answer is A. Hexagonal prism

God bless u! ❤️

The base is a hexagon

The top is also hexagon

The sides are rectangle

Hence the polygon is hexagonal prism

For a new year's party 911 red balloons, 910 green balloons and 915 white balloons were used What is the total number of balloons used?​

Answers

the total balloon are used is 2736

Work out the size of the angle marked X.
Give your answer correct to 1 decimal place.

Answers

Answer:

41.8°

Step-by-step explanation:

We solve using the Trigonometric function of Sine

Hypotenuse = 15cm

x = θ

Opposite = 10cm

sin θ = Opposite/Hypotenuse

sin θ = 10/15

θ = arc sin ( 10/15)

θ = 41.810314896°

θ = Approximately to 1 decimal place = 41.8°

Therefore, x = θ = 41.8°

A bag contains 3 yellow marbles and 6 blue marbles. You randomly select two marbles from the bag. What is the probability that both marbles are
yellow when you do not replace each marble before selecting the next marble? Write your answer as a decimal rounded to three decimal places.

Answers

1/12

explanation- the first draw the probability is 3/9 or 1/3 and the second draw would be either 2/8 or 3/8 depending on the first marble color. but the likely hood of two yellow marbles in a row would be 6/72 chances or 1/12.

I NEED HELP RIGHT NOW!!PLEASE!! π∆π ¶×¶

Find the RATIO and the EXACT VALUE of the given Cot A.​

Answers

A right angled triangle with its side length is given. The sides of the triangle are 12ft , 13ft and 5ft. And we need to find out the value of cot A .

Here :-

Base = 12 ft .Perpendicular = 5ft. Hypotenuse = 13ft.

We know :-

[tex]\tt\implies cot \theta = base / perpendicular [/tex]

Substitute the respective values :-

[tex]\tt\implies cot \theta = base / perpendicular\\\\\tt\implies\boxed{\red{\tt cot A = 12/5 }}[/tex]

Hence the required answer is 12/5.

hey! i’ll give brainliest please help

Answers

Answer:

The second option, external conflict w/other citizens who don't want the Cinema.

Step-by-step explanation:

List these from least to greatest π2, 12, √80

Answers

Answer:

π2,√80,12

Step-by-step explanation:

π2= 6.28

√80= about 8

12=12

Hope I could help!

An online music store offers 2 downloads for $7.50. Another online music store offers 12 downloads for $20.20 which store offers the better deal

Answers

Answer:

the second store has the better deal.

Step-by-step explanation:

12 ÷ 2 = 6

7.5 × 6 = 45

20.2 < 45

What is the perimeter of the triangle? Show your work.
Y
12
9

Answers

Answer:

36

Step-by-step explanation:

So to find the last angle first. The formula is a power 2+b power 2=c power 2

So 9 power 2 is 81 and 12 power 2 is 144

144+81=225

the square root of 225 is 15. So x is 15

No we just have to do 9+12+15=36.

36 is the perimeter

hey! i’ll give brainliest pls help.

Answers

i believe the answer is A. because the theory of continental drift and sea-floor spreading causes new rock to form and creates the old rock .. older

Answer:

Life forms change over time

Step-by-step explanation:

z2+4z-165=(z-11)(z+-15)

Answers

Answer: look at the picture

Step-by-step explanation: Hope this help :D

Liam puts 40$ in savings in March and 175% of this amount in savings in April. How much does Liam put in savings in April?

Answers

Answer:

$70

Step-by-step explanation:

You want 175% of $40.

175% as a decimal = 1.75

1.75 times 40 = 70

Therefore Liam put $70 in savings in April

Answer:

70

Step-by-step explanation:

Multiply 40$ by 175% :)

Ken recorded the weights (in pounds) of 78 boxes. He created a box plot of his data. What is the interquartile range of Ken’s data?

A) 8

B) 10

C) 17

D) 48

Answers

The answer is d 48 I just took the test

The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.

What is the interquartile range of a data?

The interquartile range(IQR) = third quartile(Q3) - first quartile(Q1)

The third quartile of in the box plot given is : 56 pounds

The third quartile of the data as represented in the box plot given :

39 pounds

The interquartile range(IQR) of ken's data = 56 - 39

= 17 pounds

Hence, The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.

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Using the figure show, find the missing values. Round each value. Every time I put this up people get it wrong

Answers

Answer:

I'm sorry, I can help you with only this one :( ∠F = 44°

Step-by-step explanation:

∠F = 180° - (46° + 90°) = 44°

Find the mean of this data set: 2, 5, 5

Answers

Answer:

Mean = 4

Step-by-step explanation:

[tex]Mean = \frac{\sum x}{n} = \frac{2 + 5+ 5}{3} = \frac{12}{3} = 4[/tex]

Answer:

4

Step-by-step explanation:

Mean is average, so you would add every number up, then divide by the numbers you have, So 2+5+5 divided by 3 would be 4

[tex]2h-3\ \textgreater \ 15[/tex]

Answers

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{2h - 3 }\mathsf{>}\large\textsf{ 15}[/tex]

[tex]\large\text{ADD 3 to BOTH SIDES}[/tex]

[tex]\large\textsf{2h - 3 + 3 }>\large\textsf{ 15 + 3}[/tex]

[tex]\large\text{CANCEL out: \textsf{-3 + 3} because that gives you 0}[/tex]

[tex]\large\text{KEEP: \textsf{15 + 3} because it helps you solve for your h-value}[/tex]

[tex]\large\textsf{15 + 3 = \boxed{\large\textsf{\bf 18}}}[/tex]

[tex]\large\text{NEW EQUATION: \textsf{2h} }\mathsf{>}\large\textsf{ 18}[/tex]

[tex]\large\text{DIVIDE 2 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{2h}{2}>\dfrac{18}{2}}[/tex]

[tex]\large\text{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\text{ because it gives you 1}[/tex]

[tex]\large\text{KEEP: }\mathsf{\dfrac{18}{2}}\large\text{ because it gives you your h-value is being compared to}[/tex]

[tex]\large\text{NEW EQUATION: }\mathsf{h > \dfrac{18}{2}}[/tex]

[tex]\mathsf{\dfrac{18}{2}}[/tex]

[tex]\mathsf{= 18\div 2}[/tex]

[tex]=\boxed{\mathsf{\large\textsf {\bf 9}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf h > 9}}}\huge\checkmark\\\\\boxed{\boxed{\rm \bf It\ it\ an\ O P E N E D\ circle\ shaded}}\\\boxed{\boxed{\rm \bf to\ the\ right\ starting\ at\ point\ 9}}\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Problem:

[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]

Let's solve!

[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]

Add both sides by 3.

[tex] \quad \quad \quad \quad\tt{2h - 3 + 3 > 15 + 3}[/tex]

[tex]\quad \quad \quad \quad\tt{2h \: \: \cancel{ \color{red}- 3 + 3} \: > 15 + 3}[/tex]

[tex]\quad \quad \quad \quad\tt{2h > 18}[/tex]

Divide it by 2.

[tex]\quad \quad \quad \quad\tt{ \frac{2h}{2} > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ \frac{ \cancel{ \color{red}2}h}{ \cancel{ \color{red}2}} > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ h > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ h > 9}[/tex]

Hence the answer is:

[tex]\quad \quad \quad \quad \boxed{\tt { \color{green}h > 9}}[/tex]

________

#LetsStudy

Simplify the expression and write any restrictions.

Answers

Answer:

Numerator :

[tex]8x^2 - 10x + 3 = 8x^2 -6x -4x + 3[/tex]

                     [tex]= 2x(4x -3)-1(4x -3) \\= (2x-1)(4x-3)[/tex]

Denominator :

[tex]6x^2 + 3x -3 = 6x^2 +6x -3x - 3[/tex]

                   [tex]=6x(x+1)-3(x+1)\\=(6x-3)(x+1)\\=3(2x-1)(x+1)[/tex]

[tex]\frac{8x^2-10x+3}{6x^2+3x -3} = \frac{(2x-1)(4x-3)}{3(2x-1)(x+1)} = \frac{(4x-3)}{3(x+1)}[/tex]

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