The mass of a car is 625kg. Calculate the weight of the gravitational field strength is 10 N/kg.

Answers

Answer 1

Ans: 62.5

Explanation: [tex]F{net}[/tex] = m x a

                    1N = 1kg x 1m/ [tex]s{2}[/tex]

                     


Related Questions

Best way to demonstrate that waves transfer energy

Answers

Answer:

Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.

Explanation:

The more matter in an object, the _____.(1 point)


lower its weight and mass

lower its weight and mass


more likely it is to have gravity

more likely it is to have gravity


greater its gravitational attraction to Earth

greater its gravitational attraction to Earth


less likely it is to have weight on the moon

Answers

Answer:

more likely it is to have gravity

Name the energy possessed by hot air

Answers

Answer:

geothermal energy

Explanation:

the energy is obtained from the heat within the surface of earth

Answer:

heat energy

Explanation:

Section 1: Basic Energy Relationships
1. Click/tap the Start button and observe the motion. View the bar
charts and the velocity value as the coaster car moves. Complete
the following paragraph by entering total mechanical energy
(ME), kinetic energy (KE), and potential energy (PE). The
labeled locations refer to the graphic at the right.
As the coaster car rolls down the track from A to E, the
________ values decrease and the _______ value
increase and the ________ values remain constant. The
_______ is greatest at point A and smallest at point E.
However, the _______ is smallest at point A and largest
at point E.
Section 2: Hill Design
2. Click/tap on the Bumps tab at the top of the
Interactive. Then drag the grey circles to modify the
track so that it looks like the track design at the right.
Pay attention to the background grid to help with the
design. Note that Dot G is at the same height as Dot E;
make sure that the same is true of your final design.
3. Run the simulation. Does the coaster car travel as high
as point H? ___________ Give an explanation for why
it does or doesn't reach point H.

Answers

As the coaster car rolls down the track from A to E, the potential energy values decrease and the kinetic energy value increase and the total mechanical energy values remain constant. The potential energy is greatest at point A and smallest at point E.  However, the kinetic energy is smallest at point A and largest at point E.

According the principle of conservation of mechanical energy, as the potential energy decreases, the kinetic energy increases.

[tex]P.E + K.E = M.A[/tex]

At point A, the coater has maximum potential energy.

At point E, the coaster has maximum kinetic energy.

We can fill the blanks as follows;

As the coaster car rolls down the track from A to E, the potential energy values decrease and the kinetic energy value increase and the total mechanical energy values remain constant.  The potential energy is greatest at point A and smallest at point E.  However, the kinetic energy is smallest at point A and largest at point E.

Based on the principle of conservation of mechanical energy, if the second simulation occurs at the same condition as the first, the height reached by coaster will be same.

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which one would cool down faster, water or a block of concrete? why?

Answers

Answer:

If you mean by temperature

Water, cause say the water just sits there, it'll take a few minutes to cool down. But for concrete having all the hot sun rays on it during summer, can make it very hot, if you put 'cold water' there, it'll only last there for a moments (and that's by effect not waiting), if you wait for it to cooldown by itself, it'll take quite awhile.

If you mean solidify:

The stuff required to make concretes takes HOURS and HOURS to finish solidifying, unlike water being turn into ice normally only takes about half an hour or an hour (maybe 2) in the freezer (I don't know how long for ice, but not long at all in comparison to concrete).

Explanation:

Explanation was mostly part of the answer

How much tension must a rope withstand if it is used to accelerate a 1710-kgkg car horizontally along a frictionless surface at 1.30 m/s 2 m/s2

Answers

Answer:

Explanation:

Lowest tension will occur when the rope is also horizontal.

F = ma

F = 1710(1.30)

F = 2223 N

A student removed a wool hat from her head. Her hair stood up from static electricity. What did her hat do to cause this

Answers

Answer:

A student removed a wool hat from her head. Her hair stood up from static electricity. What did her hat do to cause this? ... Yes, the motor would run faster because the increased electrical force increases the magnetic force in the motor.

A student removed the wool from her head due to the static charge of electricity, it is caused.

What is charge?

A difference in electric charge within, on the surface of, or between two materials results in static electricity. Until it can be expelled through an electrical discharge or current, the charge stays. In contrast to current electricity, which transmits energy by letting an electric charge flow through a conductor or a space, static electricity does not transport energy.

When two surfaces come into contact, wear, and separate from one another when at least a single surfaces has a good resistance to electric current, a static electrostatic attraction can be produced. Because individuals can feel, hear, and even see a spark when the extra charge is neutralized when placed close to a powerful electrical conductor, most people are familiar with static electricity's effects.

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How much work does an elephant do while moving a circus wagon 60 meters with a pulling force of 240N

Answers

Answer:

14,400

Explanation:

You need to do 240x60 and you would get the answer as 14,000

What is work? A. What happens when energy is destroyed B. The number of molecules in a substance C. The total size of an object divided by its mass D. What happens when a force causes an object to move​

Answers

Answer:

Which extended definition would be most helpful to add to this body paragraph?

Laughter Yoga, a new form of yoga, is becoming increasingly popular.

Laughter Yoga, which is becoming more and more popular, was created in the 1990s.

Laughter Yoga is modeled after traditional yoga but includes laughter exercises.

Laughter Yoga is a form of yoga that was created by Dr. Madan Kataria in the 1990s.

Explanation:

c

PLEASE HELP FOR PHYSICS!
All objects exert a gravitational force on all other objects. This force is given by, F = GMm r2 , where the value of G = 6.673 × 10–11 N–m2/kg2 , M is the mass of the heavier object, m is the mass of the lighter object, and r is the distance between the two objects.
What is the force of gravity between two balls of mass 50 kg each if the distance between them is 25 m. Assume that there is no interference from any other gravitational field.

Answers

Hi there!

Recall Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]

Where:

Fg = Force of gravity (N)

G = Gravitational Constant

m1, m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the given values stated in the problem:

[tex]F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}[/tex]


A wheel with radius 41.5 cm rotates 5.13 times every second.
Find the period of this motion.
What is the tangential speed of a wad of chewing gum stick to the rim of the wheel?

Answers

The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.

Let suppose that the wheel rotates at constant angular speed ([tex]\omega[/tex]), in radians per second, the tangential speed of a wad of chewing gum to the rim of the wheel ([tex]v[/tex]), in centimeters per second, is:

[tex]v = 2\pi\cdot r\cdot f[/tex] (1)

Where:

[tex]r[/tex] - Radius of the wheel, in centimeters[tex]f[/tex] - Frequency, in hertz

If we know that [tex]f = 5.13\,hz[/tex] and [tex]r = 41.5\,cm[/tex], then the tangential speed of the chewing gum is:

[tex]v = 2\pi\cdot (41.5\,cm)\cdot (5.13\,hz)[/tex]

[tex]v \approx 1337.659\,\frac{cm}{s}[/tex]

The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.

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half-life questionnnnn:

Answers

120 and 150 and 180 and 210

Describe a vibration that is not periodic. NO LINKS PLEASE

Answers

Answer:

1)The position change of almost any manually operated room light switch.

2) Sunlight striking a point on the ground on a partly cloudy and windy day

Explanation:

Which car is experiencing negative acceleration?
A. a car sitting at a red light
B. a car slowing down as it approaches a red light
C. a car driving in a circle at a constant speed
D. a car changing its speed from 0 km/hr to 10 km/hr

Answers

Answer:B

Explanation:

Answer: b

Explanation: b as it slows down and decelerates

______ uses radioactive materials to create contrast in the body and help form images of the structure and function of organs.

Answers

Answer:

Nuclear medicine or PET scanning (Positron Emission Tomography)

Explanation:

Not super sure what your question is looking for but I think it can be either. PET is a technology used in the nuclear medicine field, and nuclear medicine is a broad field of using the technology the question described.

A block of mass m = 3.0 kg is pushed a distance d = 2.0 m along a frictionless horizontal table by
a constant applied force of magnitude F= 20.0 N directed at an angle 0= 30.0° below the horizontal
as shown in Figure. Determine the work done by (a) the applied force, (b) the normal force exerted
by the table, and (d) the net force on the block.

Answers

Explanation:

We apply the definition of work by a constant force in the first three parts, but then in the fourth part we add up the answers. The total (net) work is the sum of the amounts of work done by the individual forces, and is the work done by the total (net) force. This identification is not represented by an equation in the chapter text, but is something you know by thinking about it, without relying on an equation in a list.

The definition of work by a constant force is W=FΔrcosθ.

(a) The applied force does work given by

W=FΔrcosθ=(16.0N)(2.20m)cos25.00=31.9J

(b), (c) The normal force and the weight are both at 900 to the displacement in any time interval. Both do 0 work.

(d) ∑W=31.9J+0+0=31.9J

Magma usually stays below the Earth's
under great pressure.
o mantle
Inner core
outer core
Crust

Answers

Answer:

In the inner vote part of the earth

Which is an electromagnetic wave A. The waves that heat a cup of water in a microwave oven B. A flag waving in the wind C. Turning on a flashlight D.The changes in the air that result from blowing a horn

Answers

Answer:

The answer would be A. The waves that heat a cup of water in a microwave oven

Are these a Chemical or Physical Change??

1. Sodium Bicarbonate breaks down into sodium carbonate and water.
A. Chemical Change
B. Physical Change

2. Mercury is cooled until it is in the solid state.
A. Chemical Change
B. Physical Change

Answers

1. chemical change, as it is the breaking of bonds

2. physical change, as it is a change in temperature

The change of sodium bicarbonate breaking down into sodium carbonate and water is a chemical change. The cooling of mercury until it is in the solid state is physical change. The correct option for 1 is A and for 2 is B.

What is chemical and physical change?

A chemical change occurs as a consequence of a reaction, whereas a physical change occurs when transformation occurs forms but retains its chemical identity.

Chemical changes include burning, cooking, rusting, and rotting. Physical changes include boiling, melting, freezing, and shredding.

A physical change is required to a specimen of matter in which some of the material's properties change but the matter's identity does not.

Physical changes can be classified as either reversible or irreversible. Melting is a reversible physical change because the melted ice cube can be refrozen.

In the first case, sodium bicarbonate is breaking down and forming sodium carbonate and water, this implies a chemical change.

In the second case, mercury is just cooling down, changing its physical shape. So it is physical change.

Thus, the correct option for 1 is A and for 2 is B.

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You are in Paris, 50. m up on an Eiffel Tower support leg observation deck. If you throw a euro downward at a velocity of -1.0 m/s, how long would it take the coin to hit the ground?​

Answers

Here’s my work to your question. I used kinematic equations to solve. :)

a 4kg sample of water absorbs 500 joules of energy.How much did the water temp change.The specific heat of water is 4200 J/(kg C)

Answers

Answer:

0.02976°C

Explanation:

Heat Supplied = mcø

ø = 500/(4*4200)

ø = 0.02976 °C

Calculate the net force acting on a body of mass 20 kg moving with a
uniform velocity of 4 ms-1.

Answers

Answer:

0 N

Explanation:

Uniform velocity means no acceleration and therefore no net force.

Please respect! Can you answer this for me?

Answers

Answer:

ıf u find the answer can u comment me to notification thank u

Explanation:

Draw the graphs for exothermic and endothermic reactions Label: axes, reactants, products, Energy of reaction, heat energy change​

Answers

Answer:

axes, reactants, products, Energy of reaction, heat energy

Explanation:

axes, reactants, products, Energy of reaction, heat energyaxes, reactants, products, Energy of reaction,grreactantsaphs heat energy

Car 1 of mass m1 is waiting at a traffic light.
Car 1 is struck from behind by Car 2 of mass m2.
The two cars stick together after the collision.
Car 2 was traveling at v2i = 30.0 m/s before the collision.

What is the kinetic, in [J], of the system after the collision if m1 = 2500 kg and m2 = 1000 kg?

Answers

Answer:

Explanation:

Conservation of momentum

2500(0) + 1000(30) = (2500 + 1000)v

v = 8.57 m/s

KE = ½(2500 + 1000)8.57² = 128,571.428... = 128 KJ

The kinetic energy of the system after the collision would be 128.5  KJ.

What is momentum?

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem Car 1 of mass m1 is waiting at a traffic light.

Car 1 is struck from behind by Car 2 of mass m2. The two cars stick together after the collision. Car 2 was traveling at v2i = 30.0 m/s before the collision.

By using the conservation of the momentum,

2500(0) + 1000(30) = (2500 + 1000)v

v = 8.57 m/s

The final velocity of the system comes out to be  8.57 m/s.

The kinetic energy of the system after the collision,

KE =1/2×(2500 + 1000)×8.57² = 128,571.4

    = 128.5  KJ

Thus, the kinetic energy of the system after the collision would be 128.5  KJ.

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Help me outttt pls and thanks

Answers

ANSWER: C. Weight
EXPLANATION: Weight is a non-contact force because gravity exerts its force through a field. An object does not need to be touching the Earth to have a weight.

One potato plant makes 7.5
potatoes. There are 10.000
people on a ship and 3
potatoes per person. How
many potato plants are
needed per person.

Answers

If all conditions are ideal, you may harvest about five to 10 potatoes per plant for your gardening efforts. Yields are based on both the care your give your plants during the growing season and the variety of potatoes you choose to grow.

answer

7.5×10.000=75÷3=25

AP Physical problem the wording is really throwing me off and im totally lost on how to do this. I would love some help please and thank you! ​

Answers

Explanation:

a) Here is the free-body diagram. Note that I included the components of the weight mg (shown in dotted arrows) for use in the other parts of the problem.

b) The component of the weight parallel to the plane (shown in the diagram as a dotted arrow along the x-axis) is [tex]mg\sin15[/tex] and it is equal to

[tex]mg\sin15 = (25\:\text{kg})(9.8\:\text{m/s}^2)\sin15 = 63.4\:\text{N}[/tex]

c) Applying Newton's 2nd law to the y-axis, we can write

[tex]y:\;\;\;N - mg\cos15 = 0 \Rightarrow N = mg\cos15[/tex]

[tex]N = (25\:\text{kg})(9.8\:\text{m/s}^2)\cos15 = 236.7\:\text{N}[/tex]

d) The component of the weight mg into the plane is the same as the normal force, hence it's also 236.7 N.

e) To solve for the coefficient of friction, we apply Newton's 2nd law to the x-axis:

[tex]x:\;\;\;mg\sin15 - F_f = 0[/tex]

[tex]\Rightarrow F_f = mg\sin15\;\;(2)[/tex]

where [tex]F_f[/tex] is the frictional force defined as [tex]F_f = \mu N[/tex] so we can use Eqn(1) on Eqn (2) to write

[tex]\mu (mg\cos15) = mg\sin15[/tex]

Solving for [tex]\mu,[/tex] we get

[tex]\mu = \dfrac{\sin15}{\cos15} = \tan15 = 0.27[/tex]

What does the horizontal line through the center of the wave on a graph represent?

Answers

Answer:

This is the midline or the medium which is the exact middle of the graphs minimum and maximum points(which are the amplitude)

someone plz help
An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?

Answers

Answer:

Explanation:

v² = u² + 2as

a = (v² - u²) / 2s

a = (93² - 0²) / (2(49))

a = 88.255102...

a = 88 m/s²

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