Answer:
weight=mass×gravity
the mass in this question is 54kg and the gravity is 10
therefore:
w=54×10
=540N
I hope this helps
when plate movement rocks to break its called
The basic SI unit of length is
Answer:
m
Explanation:
Metres, m, is the SI unit of length
Hope this helped you-have a good day bro cya)
-
In the balanced equation, 4KO2 + 2CO2 = 2K2CO3 + 302, which two chem-
icals have a molar ratio of 1:1?
The two chemical compounds having a molar ratio of 1 : 1 is CO₂ and K₂CO₃
4KO₂ + 2CO₂ —> 2K₂CO₃ + 3O₂
4 : 2 : 2 : 3
From the balanced equation above, the coefficients are 4, 2, 2, 3
A careful observation of the equation shows that CO₂ and K₂CO₃ exist in ratio 2 : 2 which can be simplified as 1 : 1
Therefore, we can conclude that CO₂ and K₂CO₃ has molar ratio of 1 : 1
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Help needed for science homework
Send right answers plzzzz plz
Answer:
I think A
Explanation:
do we use more freshwater in our homes to provide us with electricity
Answer:
No. Water can be used in a hydroelectric dam to generate electricity, but this does not make us use more or less water in our homes.
Explanation:
Answer:We use more freshwater to provide us with electricity. Water is the only compound that can be found naturally as a liquid, gas, and solid.
Explanation:
Your friend has a rubber band stretched between two fingers. When you pluck the rubber band, it vibrates and makes sound. What would you have to do to make the sound a higher pitch?
To make a higher pitch, stretch the rubber band more.
To make a higher pitch, pluck the rubber band less hard.
To make a higher pitch, stretch the rubber band less.
To make a higher pitch, pluck the rubber band harder.
Answer:
I think it is To make a higher pitch, stretch the rubber band more
Explanation:
I'm not too sure. Sry if u got it wrong
Answer:
To make a higher pitch ,pluck the rubber band more
What is the centripetal acceleration?
Answer:
centripetal acceleration is when an object accelerates going in a circular motion.
Two boats race in the water. One turns around to head back in the other direction to complete the race, but it collides into the boat that was now directly in front. What forces may have been a part of the collision? Describe them in detail.
The two forces involved in this collision are the colliding force and the reaction force which are equal in magnitude but opposite in direction.
According to Newton's third law, action and reaction are equal and opposite. This law is very important in describing head - on collisions between objects and is particularly apt in describing the collision between the two boats.
In this collision, two forces are important these are the action and the reaction. The action is the colliding force which the boat that was hit experiences. The reaction force is the force that this boat experiences as a result of hitting the boat in front of it. The both forces are equal in magnitude but opposite in direction.
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how many types Of Ornital does the atomic orbital have ?
Answer:
There are four types of orbitals that you should be familiar with s, p, d and f (sharp, principle, diffuse and fundamental). Within each shell of an atom there are some combinations of orbitals
I'll give brainlest
*the first pic is for Alberto and second for the mouse*
Question 1
Alberto created a graph to illustrate his trip. Answer the questions below.
A. How does Alberto's motion change at point B?
B. What is Alberto's speed from point C to point D?
C. What happens at point D? (1 point)
Question 2
Answer the question below about Smokey The Mouse.
A. Use inertia to explain how a balanced force will affect his motion. (Newton's 1st Law)
B. What are two ways Smoky can increase his speed? (Use Newton's 2nd Law to help you)
C. What is an example of an action and reaction at work in this picture? (Use Newton's 3rd Law to help you)
Answer:
The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.
At point B, Alberto's distance covered increases with time, equal distance is covered in equal time interval. The speed increases uniformly. At the point C to D, the distance covered with time remains the same. At the point D, equal distance is no longer covered in equal time intervals.
According to the law of inertia, an object will remain at rest or in a state of uniform motion unless it is acted upon by an unbalanced force. This means that smokey mouse will continue moving uniformly unless a force acts on it.
From Newton's second law; F = ma and a = F/m. F = force , m= mass, a = acceleration. This implies that smokey mouse can increase its speed by;
Increasing the force acting on the mouse
Decreasing the mass of the mouse
Action and reaction is encountered as the mouse is walking. The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.
Explanation:
A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000 J of additional energy. If 3666.67 J of this energy must be used to overcome friction, what is the final speed of the car
The final speed of the car at the given conditions is 30.1 m/s.
The given parameters:
Mass of the car, m = 1700 kgVelocity of the car, v = 21 m/sTime of motion, t = 10 sAdditional energy provided by the engine, E₁ = 22,000 JEnergy used in overcoming friction, E₂ = 3,666.67 JThe change in the energy applied to the car is calculated as;
[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]
The final speed of the car is calculated as follows;
[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]
Thus, the final speed of the car at the given conditions is 30.1 m/s.
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If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci?(1 point)
460,000,000 km
0.00000018 km
4,600,000 km
5,000,000 km
Answer:
it’s the third option: 4,600,000 km
Explanation:
just took the test and that was correct
If Force = 200 N and Mass = 20 kg, what is acceleration?
[tex]\text{Given that,}\\\\\text{Force, F =200 N}\\\\\text{Mass, m = 20 kg}\\\\\text{Using Newton's second law,}\\\\F = ma \\\\\implies a = \dfrac{F}{m} = \dfrac{200}{20}= 10 ~ \text{ m s}^{-2}\\\\\text{The acceleration is 10 m s}^{-2}.[/tex]
A car drives 84 meters forward. It's displacement and distance would be the same?
Answer:
Yes.
Explanation:
Displacement is a vector quantity, meaning it has to be a straight graph jointing from starting point to final point and has a direction as well as magnitude and it can also be negative as well as positive and zero.
Displacement is also changes in position (points) of distance. A distance is scalar quantity meaning it only has magnitude and does not have direction. Since distance is scalar quantity, it cannot be negative. Also graph of distance can be a curve graph or any graph.
So when does displacement equal to distance? If an object is moving in straight path or line in one/fixed direction, both displacement and distance are same.
Because if a distance is a straight path and the displacement is simply a straight line (or ray) jointing from starting point to end point, both distance and displacement are both straight path or rays. Since distance and displacement have same graph, we can conclude that both are same in values.
If we go by calculus, given x = 2t as example of straight graph where x stands for position and t stands for time. We can find the displacement from b to a by using the following formulas:
Displacement
[tex]\displaystyle \large{s=\int\limits^b_a {v} \, dt}[/tex]
Distance
[tex]\displaystyle \large{l=\int\limits^b_a {|v|} \, dt}[/tex]
v stands for velocity which we can find from:
Velocity
[tex]\displaystyle \large{v=\frac{dx}{dt}}[/tex]
If you have learnt calculus, first, differentiate x = 2t with respect to t.
[tex]\displaystyle \large{v=2}[/tex]
Then substitute v = 2 in s and l to find find if both displacement and distance are equal in straight path.
Displacement
[tex]\displaystyle \large{s=\int\limits^b_a {2} \, dt}\\\displaystyle \large{s=[2t]\limits^b_a}\\\displaystyle \large{s=2b-2a = 2(b-a)}[/tex]
Distance
[tex]\displaystyle \large{l=\int\limits^b_a {|2|} \, dt}\\\displaystyle \large{l=\int\limits^b_a {2} \, dt}\\\displaystyle \large{l=[2t]\limits^b_a}\\\displaystyle \large{l=2b-2a=2(b-a)}[/tex]
Since both displacement and distance are equal when integrating on straight graph, we can conclude that an object moving in straight fixed point has same distance and displacement.
Which turn (left or right) requires the truck to slow down more in order to make the turn safely? Explain your answer using appropriate relationships.
The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)
Answer:
F = G M m / R^2 = 6.67E-11 * 1.99E30 * 5.98E24 / (1.5E11)^2
F = 6.67 * 1.99 * 5.98 / 2.25 E21 Newtons
F = 3.53E22 N
what is the definition for volume and density
Answer:
volume :: is the level at which something is heard or the amount of space that something takes up.
Density :: is a measure of mass per volume. The average density of an object equals its total mass divided by its total volume.
Answer:
The density, of a substance is its mass per unit volume. The symbol most often used for density is ρ, although the Latin letter D can also be used. Mathematically, density is defined as mass divided by volume: {\displaystyle \rho ={\frac {m}{V}}} where ρ is the density, m is the mass, and V is the volume
give answer or fight me
Answer:
translucent
Explanation:
Hope this helps! Pls give brainliest! Also, please sub to Kgirl633 on yt.
How many volts would it take to push 1 amp through a resistance of 1 ohm?
Answer:
[tex]1\; \rm V[/tex].
Explanation:
Ohm's Law give the following relationship between the potential [tex]V[/tex] across a conductor, the electrical resistance [tex]R[/tex] of that conductor, and the current [tex]I[/tex] through that conductor:
[tex]V = I \, R[/tex].
It is given that the current through this conductor is [tex]I = 1\; {\rm A}[/tex], and that the electrical resistance of this conductor is [tex]R = 1\; \rm \Omega[/tex].
Note, that the unit of electrical resistance Ohm is a composite unit; [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex] (volts per ampere.)
Substitute the value of [tex]I[/tex] and [tex]R[/tex] into the equation [tex]V = I \, R[/tex] from Ohm's Law to find the potential across this conductor:
[tex]\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}[/tex].
What is the current in a 120V circuit if the resistance is 20Ω?
We have: [tex]I=\frac{U}{R}=\frac{120}{20}=6A[/tex]
ok done. Thank to me :>
Answer:
The Current is 6 Ampere.
Step-by-step explanation:
Given :
[tex]\small\red\bull[/tex] Voltage = 120V[tex]\small\red\bull[/tex] Resistance = 20ΩTo Find :
[tex]\small\red\bull[/tex] CurrentUsing Formula :
[tex] \star{\small{\underline{\boxed{\sf{ I = \dfrac{V}{R}}}}}}[/tex]
[tex]\small\blue\star[/tex] I = Current[tex]\small\blue\star[/tex] V = Voltage[tex]\small\blue\star[/tex] R = ResistanceSolution :
Substituting all the given values in the formula to find Current :
[tex]{\dashrightarrow{\pmb{\sf{ I = \dfrac{V}{R}}}}}[/tex]
[tex]{\dashrightarrow{\sf{ Current = \dfrac{Voltage}{Resistance}}}}[/tex]
[tex]{\dashrightarrow{\sf{ Current = \dfrac{120}{20}}}}[/tex]
[tex]{\dashrightarrow{\sf{ Current = \cancel{\dfrac{120}{20}}}}}[/tex]
[tex]{\dashrightarrow{\sf{ Current = 6A}}}[/tex]
[tex]{\star{\underline{\boxed{\sf{\red{ Current = 6A}}}}}}[/tex]
Hence, the Current is 6 Ampere.
[tex]\rule{300}{1.5}[/tex]
Can you see people on puppies not to do stairs exercise when it is very hot and humid what is the reason for this warning Ate it makes muscles Louis loser in Punta do you speak it can you spell ate the whole way too unhealthy levels see it needs to be cool outside for exercise to be effective date it is really uncomfortable to exercise when it is really hot
Answer:
Exercising is not only good for their physical and mental health, but also helps them to socialise with other dogs and puppies, which is crucial to their ...
Explanation:
explain the difference between vector and scalar quantities
Answer:
vector quantity have both magnitude and direction but scalar quantities have only magnitude
how does the function of the parts of the system contribute to its function as a whole
plsss help i need it rn i’ll give brainliest
You plug your microwave into an outlet and then you heat up a piece of pizza in it. This is an example of an...
Microwave Radiation????????????
A 10.0-kg crate slides along a raised horizontal frictionless surface at a constant speed of 4.0 m/s. The crate then slides down a frictionless incline and across a second, roughened horizontal surface as shown in the figure. What is the kinetic energy of the crate as it reaches the lower surface?
The kinetic energy of the crate as it reaches the lower surface is 80 J
Kinetic energy is the energy possed by an object in motion. Mathematically, the kinetic energy can be expressed as follow:
KE = ½mv²
With the above formula, the kinetic energy of the crate can be obtained as follow:
Mass (m) = 10 KgVelocity (v) = 4 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 10 × 4²
KE = 5 × 16
KE = 80 J
Therefore, the kinetic energy of the crate is 80 J
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What net force is needed to increase the velocity of a 5 kg object by 3 m/s over the course of 2.5 seconds?
Hi there!
Recall Newton's Second Law:
[tex]\large\boxed{\Sigma F = ma}[/tex]
∑F = net force (N)
m = mass (kg)
a = acceleration (m/s²)
We must begin by solving for the acceleration using the following:
a = Δv/t
In this instance:
Δv = 3 m/s
t = 2.5 sec
a = 3/2.5 = 1.2 m/s²
Now, plug this value along with the mass into the equation for net force:
[tex]\Sigma F = 5(1.2) = \boxed{6 N}}[/tex]
Answer:
[tex]\boxed {\boxed {\sf 6 \ Newtons}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration. The mass of the object is 5 kilograms, but the acceleration is unknown.
We can find acceleration using the following formula:
[tex]a= \frac{ \Delta v}{t}[/tex]
The velocity of the object increases by 3 meters per second. It accelerates in 2.5 seconds.
Δv= 3 m/s t= 2.5 sSubstitute the values into the formula.
[tex]a= \frac{3 \ m/s}{2.5 \ s}[/tex]
[tex]a= 1.2 \ m/s/s = 1.2 \ m/s^2[/tex]
Now we know the mass and acceleration.
m= 5 kg a= 1.2 m/s²Substitute the values into the force formula.
[tex]F=ma[/tex]
[tex]F= (5 \ kg)(1.2 \ m/s^2)[/tex]
[tex]F= 6 \ kg*m/s^2[/tex]
Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 6 kilogram meters per second squared is equal to 6 Newtons.
[tex]F= 6 \ N[/tex]
A rocket consists of a shuttle and a fuel tank. The rocket flies through the air with a momentum of 180000kgm/s at a velocity of 120m/s. If the fuel tank has a mass of 500kg, what is the mass of the shuttle?
Answer:
Answer is 1000kg
Hope it help
the graph is tied to the reading
here is the reading for the question
students in a physics class observing the race note that each runner maintains the same acceleration from the start ofthe 8.0 second interval until they each reach the finish line where each of the runners slows to a stop. Two students inthe class make the following claims about the runners’ accelerations from the start of the 8.0 second interval until bothrunners are at rest.
Student 1:“Runner A has a positive acceleration until reaching the finish line and then a negative acceleration aftercrossing the finish line in order to “undo” all of the positive velocity she gained. Since Runner B neverhad any positive acceleration, she doesn’t need any negative acceleration to slow to a stop; heracceleration will be zero the whole time.”
Student 2:“But negative values mean away south in this case – how could runner A be turning around? I think bothrunners must have positive accelerations the whole time since they are always moving north.”
For part (c), do not simple repeat the students’ arguments in your answers.
here are the questions:
i.Which aspects of student 1’s reasoning, if any, are correct? Explain your answer.
ii.Which aspects of student 1’s reasoning, if any, are incorrect? Explain your answer.
iii.Which aspects of student 2’s reasoning, if any, are correct? Explain your answer.
iv.Which aspects of student 2’s reasoning, if any, are incorrect? Explain your answer
THANK YOU THANK YOU THANK YOU
What is the anomalous expansivity of water
Answer:
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense. The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph.
Explanation:do you want me to explain it more??