The metric unit that is most often used to describe weight is the _________​

Explanation:

part 1.

s=60m

t=5s

v=s/t. =60/5 =12m/s

part 2

total s= 540+60. =600m

v=12m/s

t=s/v. =600/12 =50s

Answer:

A common dry-cell battery is the zinc-carbon battery, which uses a cell that is sometimes called the Leclanché cell. The cell is made up of an outer zinc container, which acts as the anode. The cathode is a central carbon rod, surrounded by a mixture of carbon and manganese(IV) dioxide (MnO2).

Answer:

c.

Explanation:

Answer:

The Letter answer that best fits the question is C(It authorized construction of interconnected highways.)

Explanation:

I took the test

Answer: He was labeled as one of Africa's cruelest dictators because during his eight year reign many civilians were massacred. He drove out Uganda's Indian and Pakistani citizens and spent large amount of money on the military which led to the economic decline of the country.

Explanation:

Answer:

I reckon towards b. Let me know if im right

Explanation:

Light passes from air into water at an angle of incidence of 42.3∘.42.3∘. Determine the angle of refraction in the water.

Answer:

d

Explanation:

Answer:

The inside of a hurricane

Explanation:

You will die

Answer:

30

Explanation:

well I got it right but I'm not sure if it's the same thing

Answer: 60 mph

Explanation:

Given

Truck takes [tex]1.5\ hr[/tex] to make [tex]90\ mile[/tex] trip

The average speed is the ratio of total distance traveled to the total time taken.

[tex]v_{avg}=\dfrac{\text{Distance}}{\text{time}}\\\\v_{avg}=\dfrac{90}{1.5}\\v_{avg}=60\ mph[/tex]

Answer:

Hypothesis #2 If an earthworm is exposed to a strong odor, then it will back away from the odor because it will think that the odor is a sign of danger. ... Second, you will test earthworms' response to dry conditions by providing both a dry surface and a moist surface for the earthworms to crawl on.

Answer:

if the earthworm smells the strong odor it will back away from it because it thinks it's a sign of danger.

Answer:

Explanation:

Use the one-dimensional equation for displacement:

Δx = v₀t + [tex]\frac{1}{2}at^2[/tex] where Δx is the displacement, v₀ is the initial velocity (which is 0 since someone had to be holding the penny still before it was dropped), t is the time it takes to travel a certain distance (which is given as 4 seconds), and a is the acceleration due to gravity which is -9.8 m/s/s. Filling in:

Δx = [tex](0\frac{m}{s})(4s)+\frac{1}{2}(-9.8\frac{m}{s^2})(4s)^2[/tex] I'm going to expand this first so you can see how the units work out. First of all, anything times 0 is 0, so what is right in front of the plus sign goes to 0 and I'm going to leave it out. How this looks expanded without doing any of the actual math yet is:

Δx = [tex]\frac{1}{2}(-9.8\frac{m}{s^2})(4^2s^2)[/tex] which makes it apparent that the seconds-squared cancel each other out, leaving us with the meters only. NOW doing the math and rounding to 2 sigfig's even though there's only 1 in the number 4:

Δx = 78 m(the negative would only be used if the question we were answering was how far the penny had to fall, which would then use the negative sign to indicate that the penny is falling to a point that is below th point from which it was released. Since height is a distance measurement, it will never be negative. Keep in mind, asking how far the penny fell is not the same thing in physics as asking how tall the building was that the penny fell from.)

Answer:

Its a barred spiral galaxy

Explanation:

Answer:

It is d

Explanation:

Answer:

please give me brainlist and follow

Explanation:

Nuclear fusion can be more reliable than nuclear fission in energy generation due to the following reasons: There are no radioactive waste products obtained as a result of nuclear fusion, unlike nuclear fission. This is because the elements involved in Nuclear fusion are relatively radioactively stable elements.

Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

[tex] x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2} [/tex]   (1)

Where:

[tex] x_{f}[/tex]: is the final position in the horizontal direction = 80 m

[tex] x_{0}[/tex]: is the initial position in the horizontal direction = 0

[tex]v_{0_{x}}[/tex]: is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?  

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:  

[tex] t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s [/tex]

b) The height of the hill is given by:

[tex] y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} [/tex]

Where:

[tex] y_{f}[/tex]: is the final position in the vertical direction = 0

[tex] y_{0}[/tex]: is the initial position in the vertical direction =?

[tex]v_{0_{y}}[/tex]: is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)            

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

[tex] y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m [/tex]  

I hope it helps you!

Answer:

λ = 2.4 m

Explanation:

The speed of a wave is defined as the product of the frequency and the wavelength of that wave:

[tex]v = f\lambda[/tex]

where,

v = speed of wave = 24 m/s

f = frequency of wave = 10 Hz

λ = wavelength of the wave = ?

Therefore,

[tex]24\ m/s = (10\ Hz)\lambda\\\\\lambda = \frac{24\ m/s}{10\ Hz}[/tex]

λ = 2.4 m

Answer:

I know that F=Gm1m2/r^2 or F=GMn/r^2 and G is like the universal gravitational constant so I hope this helps

Answer:

10 m/s²

Explanation:

Since the body is falling freely from the rest, it will be having an acceleration equal to the acceleration due to gravity.

∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².

Answer:

10 m/s^2 I hope it helps u a lot

Explanation:

A 4kg mass is under the action of a resultant force of (a) 4 N (b) 8N and (c) 12 N What are the resulting accelerations?

Given that,

Mass, m = 4 kg

(a) Force = 4 N

We know that,

Force, F = ma

Where

a is accelertaion,

a= F/m

a = 4/4 = 1 m/s²

(b) F = 8 N

a= F/m

a = 8/4 = 2 m/s²

(c) F = 12 N

a = 12/4 = 3 m/s²

Hence, this is the required solution.

CAN SOMEONE IN THE COMMETS ON EDG HELP ME WITH THIS IM NOT DOING THIS 4 POINTS I ACTULLY NEED HELP AND STRUGGLING U GUYS CAN CAN PUT A 1.0 STAR I REALLY DONT CARE BUT CAN SOMEONE HELP PLZ

Answer: Choice A)

Explanation:

The speed of wave with a wavelength of 4 m and a frequency of 85 Hz is 340m/s

The speed of a wave is the product of the frequency of the wave and its wavelength. Mathematically, it is expressed as:

[tex]v = f \lambda[/tex] where:

f is the frequency

[tex]\lambda[/tex] is the wavelength

Given the following:

f =85Hz

[tex]\lambda[/tex] = 4 m

Substitute the given parameter into the formula:

v = 85 × 4

v = 340m/s

Hence the speed of wave with a wavelength of 4 m and a frequency of 85 Hz is 340m/s

Learn more here: https://brainly.com/question/15721131

Answer: a variety of ohmic valu example, VIN = VR1 + VR2.

Potentiometer Example No1

A resistor of 250 ohms is connected in series with a second resistor of 750 ohms so that the 250 ohm resistor is connected to a supply of 12 volts and the 750 ohm resistor is connected to ground (0v). Calculate the total series resistance, the current flowing through the series circuit and the voltage drop across the 750 ohm resistor.

potentiometer example one

Explanation:

uman ear has a logarithmic response and is therefore non-linear.

If we where to use a linear potentiometer to control the volume, it would give the impression to the ear that most of the volume adjustment was restricted to one end of the pots track. The logarithmic potentiometer however, gives the impression of a more even and balanced volume adjustment across the full rotation of the volume control.

So the operation of a logarithmic potentiometers when adjusted is to produce an output signal which closely matches the nonlinear sensitivity of the human ear making the volume level sound as though it is increasing linearly. However, some cheaper logarithmic potentiometers are more exponential in resistance changes rather than logarithmic but are still called logarithmic because their resistive response is linear on a log scale. As well as logarithmic potentiometers, there are also anti-logarithmic potentiometers in which their resistance quickly increases initially but then levels off.

The all potentiometers and rheostats are available in a choice of different resistive tracks or patterns, known as laws, being either linear, logarithmic, or anti-logarithmic. These terms are more commonly abbreviated to lin, log, and anti-log, respectively.

The best way to determine the type, or law of a particular potentiometer is to set the pots shaft to the center of its travel, that is about half way, and then measure the resistance across each half from wiper to end terminal. If each half has more or less equal resistance, then it’s a Linear Potentiometer. If the resistance appears to be split at about 90% one way and 10% the other then chances are it’s a Logarithmic Potentiometer.

Potentiometer Summary

In this tutorial about potentiometers, we have seen that a potentiometer or variable resistor basically consists of a resistive track with a connection at either end and a third terminal called the wiper with the position of the wiper dividing the resistive track. The position of the wiper on the track is adjusted mechanically by rotating a shaft or by using a screwdriver.

Variable resistors can be categorised into one of two operational modes – the variable voltage divider or the variable current rheostat. The potentiometer is a three terminal device used for voltage control, while the rheostat is a two terminal device used for current control.

We can summarise this in the following table:

Type Potentiometer Rheostat

Number of

Connections Three Terminals Two Terminals

Number of Turns Single and Multi-turn Single-turn Only

Connection Type Connected Parallel with a Voltage Source Connected in Series with the Load

Quantity Controlled Controls Voltage Controls Current

Type of Taper Law Linear and Logarithmic Linear Only

Then the potentiometer, trimmer and rheostat are electromechanical devices designed so that their resistance values can be easily changed. They can be designed as single-turn pots, presets, slider pots, or as multi-turn trimmers. Wirewound rheostats are mainly used to control an electrical current. Potentiometers and rheostats are also available as multi-gang devices and can be classified as having either a linear taper or a logarithmic taper.

Either way, potentiometers can provide highly precise sensing and measurement for linear or rotary movement as their output voltage is proportional to the wipers position. The advantages of potentiometers include low cost, simple operation, lots of shapes, sizes and designs and can be used in a vast array of different applications.

However as mechanical devices, their disadvantages include eventual wear-out of the sliding contact wiper and/or track, limited current handling capabilities (unlike Rheostats), electrical power restrictions and rotational angles that are limited to less than 270 degrees for single turn pots