Answer:
These destructive frequencies entrain the thoughts towards disruption, disharmony, and disunity. Additionally, they also stimulate the controlling organ of the body — the brain — into disharmonious resonance, which ultimately creates disease and war.
6. Which of the following types of energy is not lost when energy is
transferred between one of the Earth's four physical systems?*
heat
light
sound
nuclear
vibration
movement
Answer:
heat light sound viberation
Explanation:
i'm built different
A projectile is projected from the origin with a velocity of 45.0 m/s at an angle of 30.0 degrees above the horizontal. What is the velocity when the projectile hits the ground?
Answer:
velocity = 44.98 m/s
Explanation:
given data
velocity = 45.0 m/s
angle = 30.0 degrees
solution
first we get here time that is
time = 2u × sin θ ÷ g .............1
time = 2×45 × sin 30 ÷ 9.8
time = 4.59 sec
and
velocity = [tex]\sqrt{vx^2+vy^2}[/tex] .....................2
here
vx = 45 cos30 = 38.97 m/s
vy = uy - gt
vy = 45 sin30 - 9.8 × 4.59 = -22.48 m/s
so velocity will be
velocity = [tex]\sqrt{38.97^2+22.48^2}[/tex]
velocity = 44.98 m/s
Which of the following is not one of the four muscle shapes?
A. Triangular
B. Flat
C. Spindle
D. Cylindrical
Answer:
When elements bond together or when bonds of compounds are broken and form a new substance
Explanation:
which of the following is an example of projectile motion?
a) a child tumbling down a hillside
b) a bowler rolling her ball down an alley
c) a football in flight during a field goal
d) a surfer riding a wave
An object falling from a great height in Earth's atmosphere eventually reaches a speed called Terminal velocity. What cause a falling object to stop increasing in speed once it reaches terminal velocity? Really struggling, I need an answer--quick. Which letter is correct and why please?
A. Its mass and weight have become equal
B. It has no more potential energy
C. No forces are acting on it any longer
D. The forces acting on it are balanced
Answer:
A.
Explanation:
If its at a height the Gratitude of it falling down with only Gravity if Any other Forces are acting on it so as Friction But Sideways.
In a two-slit experiment using coherent light, the distance between the slits and the screen is 1.10 m, and the distance between the slits is 0.0400 mm. If the second order bright fringe is measured to be 4.20 cm from the centerline on the screen, what is the wavelength of light?
A) 620 nm
B) 200 nm
C) 401 nm
D) 763 nm
E) 381 nm
Answer:
D) 763 nm
Explanation:
Calculation for the wavelength of light
Using this formula
Wavelength of light=Delta Y*Distance / Length
Where,
Delta Y represent the 2nd order bright fringe
Length represent the distance between both the slits and the screen
Distance represent the Distance between the slits
Let note that cm to m = (4.2) x 10^-2 and mm to m= ( 0.0400x 10^-3)
Now Let plug in the formula
Wavelength of light=[(4.2 x 10^-2m)(0.0400 x 10^-3m) / 2(1.1m)]*10^-7 meters
Wavelength of light=[(0.042m) (0.0004m)/2.2m]*10^-7 meters
Wavelength of light =(0.0000168m/2.2m)*10^-7 meters
Wavelength of light =7.63 *10^-7 meters
Wavelength of light =763 nm
Therefore the Wavelength of light will be 763 nm
What is the key variable for calculating potential energy?
Telephone signals are often transmitted over long distances by microwaves. What is the frequency of microwave radiation with a wavelength of 3.5 cm?
Express your answer in GHz and using two significant figures.
f = ________GHz
Microwave signals are beamed between two mountaintops 52 km apart. How long does it take a signal to travel from one mountaintop to the other?
Express your answer in ms and using two significant figures.
t = ________ms
Answer:
1) f= 8.6 GHz
2) t= 0.2 ms
Explanation:
1)
Since microwaves are electromagnetic waves, they move at the same speed as the light in vacuum, i.e. 3*10⁸ m/s.There exists a fixed relationship between the frequency (f) , the wavelength (λ) and the propagation speed in any wave, as follows:[tex]v = \lambda * f (1)[/tex]
Replacing by the givens, and solving for f, we get:[tex]f =\frac{c}{\lambda} =\frac{3e8m/s}{0.035m} = 8.57e9 Hz (2)[/tex]
⇒ f = 8.6 Ghz (with two significative figures)
2)
Assuming that the microwaves travel at a constant speed in a straight line (behaving like rays) , we can apply the definition of average velocity, as follows:[tex]v =\frac{d}{t} (3)[/tex]
where v= c= speed of light in vacuum = 3*10⁸ m/s
d= distance between mountaintops = 52 km = 52*10³ m
Solving for t, we get:[tex]t = \frac{d}{c} = \frac{52e3m}{3e8m/s} = 17.3e-5 sec = 0.173e-3 sec = 0.173 ms (4)[/tex]
⇒ t = 0.2 ms (with two significative figures)
How would you go about measuring the speed of a vehicle? What measurements would you have to take? What calculations would you have to perform?
Answer:
For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.
A ball connected to a 1.1 m string and is swing in circular fashion. It’s tangential velocity is 15 m/s. What is its centripetal acceleration?
Answer:
ac = 204 [m/s²]
Explanation:
To solve this problem we must use the following equation that relates the tangential velocity to the radius of rotation.
ac = v²/r
where:
v = tangential velocity = 15 [m/s]
r = radius = 1.1 [m]
Now replacing we have:
ac = (15)²/1.1
ac = 204 [m/s²]
The transfer of thermal energy between objects of different
temperatures is called...
A.) Heat
B.) Temperature
C.) Specific Heat
D.) Internal Energy
Answer:
A
Explanation:
heat transfer occurs between two objects that are not in thermal equilibrium (do not have the same temperature)(heat flows from hot to cold objects)
temp= measure of how hot/cold something is
internal E= total E of a closed system
The transfer of thermal energy between objects of different temperatures is called Heat.
What is heat?Heat is the energy transferred from one object to another as a result of a temperature differential. When two bodies of different temperatures come into contact, energy is transferred—that is, heat flows— towards the colder body from the hotter.
As we know that when two bodies are not in thermal equillibrium then the heat starts to flow, from the higher temperature body towards the lower temperature body. Thus, The transfer of thermal energy between objects of different temperatures is called Heat.
Learn more about Heat:
https://brainly.com/question/1429452
Does the weight of the projectile affect the horizontal range?
Answer:
no
Explanation:
This downward force and acceleration results in a downward displacement from the position that the object would be if there were no gravity. The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it.
Pete is driving down 7th Street. He drives 300 meters in 18 seconds. Assuming he does not speed up or slow down, what is his speed in meters per second? Round answer to the hundredths place.
Answer:
16.67m/s
Explanation:
Given parameters:
Distance Pete drove = 300m
Time taken = 18s
Unknown:
Speed = ?
Solution:
Speed is the distance traveled per unit of time.
It is mathematically expressed as;
Speed = [tex]\frac{distance}{time}[/tex]
Insert the parameters and solve;
Speed = [tex]\frac{300}{18}[/tex] = 16.67m/s
A rotating wheel requires 8.00 s to rotate 27.0 revolutions. Its angular velocity at the end of the 8.00-s interval is 99.0 rad/s. What is the constant angular acceleration (in rad/s) of the wheel?
Answer:
∝ = 28.92 rad/s²
Explanation:
Applying third equation of motion to the angular motion, we have:
2∝θ = ωf² - ωi²
where,
∝ = angular acceleration = ?
θ = angular displacement = (27 rev)(2π rad/1 rev) = 169.64 rad/s
ωf = final angular velocity = 99 rad/s
ωi = initial angular velocity = 0 rad/s
Therefore,
(2)∝(169.64 rad) = (99 rad/s)² - (0 rad/s²)
∝ = (9801 rad²/s²)/(38.8 rad)
∝ = 28.92 rad/s²
2.
Which statement is true regarding the launch of a rocket?
The downward force of the rocket exhaust is greater than the upward force on the rocket.
The downward force of the rocket exhaust is equal to the upward force on the rocket.
The upward force of the rocket exhaust is equal to the downward force on the rocket.
The downward force of the rocket exhaust is less than the upward force on the rocket.
Answer:
First one,
Its because
Downward force must greater to uplift its weight.
From 3rd law of motion
Answer:
The downward force of the rocket exhaust is greater than the upward force on the rocket.
Explanation:
Your Welcome (;
The achilles tendon is subjected to a large tension stress that results in a strain of 6%. if the unloaded tendon is 10 cm long, how much does it elongate as a result of this strain?
The answer is .6cm I need to understand the work to get here.
Answer: 0.6cm
Explanation:
Strain is defined as how much an object can be stretched or deformed when force is applied to it . it measures the fractional change of the object’s length when the object faces tensional stress. It is calculated by using the formulae
Strain = ΔL/ L
where strain = 6%
L= Original length
ΔL= change in length
6% = ΔL/ 10 cm
ΔL= 10cm X 0.06
ΔL=0.6cm
In a binary star system, the average separation between the stars is 5.0 AU, and their orbital period is 5.0 years. What is the sum of their two masses?The average distance of Star A from the center of mass is four times that of Star B. What are their individual masses?
Answer:
A. 5.03 solar mass.
B. the masses of Star A and B are 1.01 solar mass and 4.02 solar mass respectively.
Explanation:
A. The sum of their two masses can be found using Kepler's third law:
[tex]\frac{P^{2}}{a^{3}} = \frac{4\pi^{2}}{G(m_{A} + m_{B})}[/tex]
Where:
P: is the period = 5 y = 1.58x10⁸ s
a: is the separation between the stars = 5 AU = 7.5x10¹¹ m
G: is the gravitational constant = 6.67x10⁻¹¹ m³kg⁻¹s⁻²
[tex]m_{A}[/tex] and [tex]m_{B}[/tex] are the masses of Star A and Star B respectively.
[tex]m_{A} + m_{B} = \frac{4\pi^{2}a^{3}}{P^{2}G} = \frac{4\pi^{2}(5 AU*\frac{1.5\cdot 10^{11} m}{1 AU})^{3}}{(1.58 \cdot 10^{8} s)^{2}6.67 \cdot 10^{-11} m^{3}*kg^{-1}*s^{-2}} = 1.00 \cdot 10^{31} kg*\frac{1 M_{\bigodot}}{1.989\cdot 10^{30} kg} = 5.03 M_{\bigodot}[/tex]
Hence, the sum of their two masses is 5.03 solar mass.
B. Their individual masses can be found using the center of the mass equation:
[tex] a_{B} = (\frac{m_{A}}{m_{A} + m_{B}})a [/tex]
Where:
[tex]a_{B}[/tex] is the distance of Star B from the center of the mass
Since, [tex]a_{A}[/tex] is four times [tex]a_{B}[/tex] and a = 5 AU we have:
[tex] a_{A} = 4a_{B} [/tex]
[tex] a = a_{A} + a_{B} [/tex]
[tex] a_{B} = a - a_{A} = a - 4a_{B} \rightarrow a_{B} = \frac{a}{5} [/tex]
Then, their individual masses are:
[tex]\frac{a}{5} = (\frac{m_{A}}{5.03 M_{\bigodot}})a[/tex]
[tex]m_{A} = \frac{5.03 M_{\bigodot}}{5} = 1.01 M_{\bigodot}[/tex]
Now, the mass of Star B is:
[tex]m_{B} = m_{T} - m_{A} = 5.03 M_{\bigodot} - 1.01 M_{\bigodot} = 4.02 M_{\bigodot}[/tex]
Therefore, the masses of Star A and B are [tex]1.01 M_{\bigodot}[/tex] and [tex]4.02 M_{\bigodot}[/tex] respectively.
I hope it helps you!
: To determine the focal length of a lens, the following except _ is needed
Answers options
Needles
Siphon
Converging Lens
Diverging Lens
If the magnetic field of an electromagnetic wave is in the x-direction and the electric field of the wave is in the y-direction, the wave is traveling in the
Answer:
wave is in the y-direction, the wave is traveling in the
Explanation:
For mechanical waves, such as sound waves or ocean waves, increasing the intensity of the wave increases both the amplitude (height) of the wave and the energy it carries. In that situation, a low-frequency but high-intensity wave should have the same effect as a high-frequency but low-intensity wave. How does light behave differently from this model?
Answer:
the effect is given by the energy that depends on the frequency, but not on the intensity
Explanation:
There are similarities and differences between mechanical waves and electromagnetic waves. The main difference is that mechanical waves depend on a material medium for their propagation, whereas electromagnetic waves are maintained by the oscillation of their electrical magnetoscope fields.
In the case of light (electromagnetic wave) the energy is given by the relation
E = h f
where h is Planck's constant and f is the frequency.
Then the intensity is given by the number of waves or quasiparticles (photons) that are in the ray.
Consequently the effect is given by the energy that depends on the frequency, but not on the intensity
The energy in the given model depends on the frequency, but not on the intensity.
The given problem is based on the mechanical wave and electromagnetic waves. The mechanical waves depend on a material medium for their propagation, whereas electromagnetic waves are maintained by the oscillation of their electrical magneto scope fields.
In the case of light (electromagnetic wave) the energy is given by the relation,
E = h f
Here,
h is Planck's constant.
And f is the frequency.
Then the intensity is given by the number of waves (photons) that are in the ray. So, it is evident the effect is given by the energy that depends on the frequency, but not on the intensity.
Thus, we can conclude that the energy in the given model depends on the frequency, but not on the intensity.
Learn more about the intensity of wave here:
https://brainly.com/question/14697045
The first excited state of a particular atom in a gas is 5.8 eV above the ground state. A moving electron collides with one of these atoms, and excites the atom to its first excited state. Immediately after the collision the kinetic energy of the electron is 3.7 eV. What was the kinetic energy of the electron just before the collision?
Ki = ____eV
Answer:
E₀ = 9.5 eV
Explanation:
In the processes of absorption, excitation and shocks the energy must be conserved therefore the energy before the shock is
E₀ = E_excitation + E_residual
E₀ = 5.8 + 3.7
E₀ = 9.5 eV
this is the energy of the electron before the collision
Which is an example of a chemical change?
What happens to the gravitational potential energy between two particles if the distance between them is halved? (a) It does not change(b) It is multiplied by 2(c) It is multiplied by 4(d) It is multiplied by 8What happens to the gravitational force between two particles if the distance between them is doubled? (a) It does not change(b) It decreases by a factor of 2(c) It decreases by a factor of 4(d) It decreases by a factor of 8
Answer:
The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).
Explanation:
The gravitational force is the force of mutual attraction that two objects with mass experience.
The Law of Universal Gravitation enunciated by Newton says that every material particle attracts any other material particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically this is expressed as:
[tex]F=G*\frac{m1*m2}{r^{2} }[/tex]
where m1 and m2 are the masses of the objects, r the distance between them and G a universal constant that receives the name of constant of gravitation.
If the distance between two particles is reduced by half, then, where F' is the new value of the gravitational force:
[tex]F'=G*\frac{m1*m2}{(\frac{r}{2} )^{2} }[/tex]
[tex]F'=G*\frac{m1*m2}{\frac{(r )^{2} }{2^{2} } }[/tex]
[tex]F'=G*\frac{m1*m2}{\frac{(r )^{2} }{4} }[/tex]
[tex]F'=4*G*\frac{m1*m2}{r^{2} }[/tex]
F'=4*F
The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).
A 12-volt battery maintains a 4.5A current through a resistor. What is the resistance of the resistor.
A skateboarder is moving at 2.00m/s and increases his velcity at a rate of 1.6m/s/s for 6.0 seconds. What is the displacement of the skateboarder during this game? Must include Given, Find , and Equation. Show all work .
Answer:
S = 40.8m
Explanation:
Given the following data;
Initial velocity, u = 2m/s
Acceleration, a = 1.6m/s²
Time, t = 6secs
Required to find the displacement
Displacement, S = ?
The displacement of an object is given by the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Where;
S represents the displacement measured in meters. u represents the initial velocity measured in meters per seconds. t represents the time measured in seconds. a represents acceleration measured in meters per seconds square.Substituting into the equation, we have;
[tex] S = 2*6 + \frac {1}{2}*(1.6)*6^{2}[/tex]
[tex] S = 12 + 0.8*36[/tex]
[tex] S = 12 + 28.8 [/tex]
S = 40.8m
Therefore, the displacement of the skateboarder during this game is 40.8 meters.
A horizontal force of 100 N is required to push a 50 kg crate across a factory floor at a constant speed. What is the acceleration on the cart?
Answer:
a = 2m/s^2
Explanation:
Force (F) = 100 N
Mass (m) = 50 kg
Here,
F = m×a
100 = 50 × a
a = 100÷50
a = 2m/s^2
Thus, the acceleration on the cart is a = 2m/s^2
-TheUnknownScientist
the lanthanides are all radioactive true or false
Answer:
False
Explanation:
All the lanthanides are not radioactive in nature. Just one of the lanthanides are radioactive.
The lanthanides belong to the f-block on the periodic tableOnly Promethium in this group are radioactive in nature. Other elements in the lanthanide series might have radioactive isotopes.Object A is 71 degrees and object B is 75 degrees how will thermal energy flow
Given :
Object A is 71 degrees and object B is 75 degrees .
To Find :
How will thermal energy flow.
Solution :
We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.
So, in the given question energy will flow from object B from object A.
Hence, this is the required solution.
Kathryn decides to take her dog for a walk one day. Her dog tries pulling on her with a force of 15N. Kathryn pulls back with force of 20N. What is the net force?
Assuming both forces act horizontally, the net force is in Kathryn's direction with a magnitude of 5 N.
If "towards Kathryn" is taken the be the positive direction, then the net force is
∑ F = 20 N - 15 N = 5 N
A squirrel falls from this tree after being shocked by the falling apples. If the
squirrel was 3.5 meters above the ground, how long until the squirrel hits the
ground?
Answer:
0.85m
Explanation:
Given parameters:
Height of fall = 3.5m
Unknown:
Duration of fall = ?
Solution:
To solve this problem, we apply the right motion equation.
Since we know the height, we can use the equation below;
S = ut + [tex]\frac{1}{2} gt^{2}[/tex]
S is the height
u is the initial velocity = 0m/s
t is the time
g is the acceleration due to gravity
3.5 = 0 + [tex]\frac{1}{2}[/tex] x 9.8 x t²
3.5 = 4.9t²
t² = [tex]\frac{3.5}{4.9}[/tex]
t² = 0.71
t = √0.71 = 0.85m