The notebook shows the money Lyla earned and spent over two days. A positive number represents money earned. A negative number represents money spent.

Answer:

LCD = 30

Step-by-step explanation:

[tex]\frac{5}{6}[/tex] x - [tex]\frac{1}{10}[/tex] x = [tex]\frac{2}{15}[/tex]

Multiply through by 30 ( the LCM of 6, 10, 15 ) to clear the fractions

25x - 3x = 4

22x = 4 ( divide both sides by 22 )

x = [tex]\frac{4}{22}[/tex] = [tex]\frac{2}{11}[/tex]

Answer:

5

Step-by-step explanation:

[tex] \frac{5}{6} x - \frac{1}{10} x = \frac{2}{15} \\ \frac{50x - 6x}{60} = \frac{2}{15} (criss \: cross) \\ \frac{44x}{60} = \frac{2}{15 } \\ \frac{11x}{15} = \frac{2}{15} (simplify) \\ 165x = 30(criss \: cross) \\ x = \frac{30}{165} = \frac{6}{33} = \frac{2}{11} \\ x = \frac{2}{11} [/tex]

Answer:

no

Step-by-step explanation:

if the y 79 was changed to 49 then yes(in that case y=x^2) but the x 7 y 79 messes the relationship up.

Answer:

the answer is 4

Step-by-step explanation:

if y=21 the we substitute in the main equation

21=8x-11

8x=32

x=4

The answer would be 512.

Answer 84 miles

Step-by-step explanation:

2hrs= 120min

7 miles/ 10 min = x miles/ 120 min

x = 84 miles

Answer:

second one

Step-by-step explanation:

Notice that there's a y intercept of 2 and an x intercept of -4

This means that the line has a positive slope of 1/2, which leaves us with

y<(1/2)x+2

[tex]\\(a)\\2^3 \times 2^6 \div 2^9 = 2^{3+6} \times \dfrac{1}{2^9} = 2^9 \times 2^{-9} = 2^{9-9} = 2^0 = 1\\\\ \\(b)\\\\(-5)^8 \div (-5)^4 \times (-5)^3\\ \\= (-5)^8 \times \dfrac 1{(-5)^4 \times (-5)^3} \\\\= (-5)^8 \times \dfrac{1}{(-5)^{4+3}} \\\\= (-5)^8 \times \dfrac{1}{(-5)^7} \\\\= (-5)^{8 - 7} \\\\=(-5)^1 \\\\ =-5\\\\\\(c)\\\\\\\dfrac{6^3 \times 6^5}{6^2 \times 6^4}= \dfrac{6^{3+5}}{6^{2+4}}= \dfrac{6^8}{6^6}=6^{8-6}=6^2 =36[/tex]

Answer:

80° because 50° 60° 70° and 80°

Answer:

103

Step-by-step explanation:

180-77=103

Answer:

I will ASSUME X = x

x² + 2bx - 4bx - 8b²

x² - 2bx - 8b²

Answer:

[tex]\\\\\\-8b^2-2bx+x^2[/tex]

Step-by-step explanation:

[tex](x+2b)(x-4b)\\=(x+2b)(x+(-4b)\\=(x)(x)+(x)(-4b)+(2b)(x)+(2b)(-4b)\\\\x^2-4bx+2bx-8b^2\\\\-8b^2-2bx+x^2[/tex]

Answer:77°

Step-by-step explanation:

Since we are trying to convert Celsius to Fahrenheit, we just need to replace C in the equation with the value of 25°.

[tex]F=\frac{9}{5}C+32[/tex]

[tex]F=\frac{9}{5}25+32[/tex]

[tex]F=45+32[/tex]

[tex]F=77[/tex]

The answer is 77°

Answer:

162 the answer i think bye have fun

Step-by-step explanation:

Answer:

Step-by-step explanation:

The standard form of a hyperbola whose transverse axis is horizontal is ...

  (x -h)²/a² -(y -k)²/b² = 1 . . . . center (h, k); transverse axis 2a; conjugate axis 2b

The distance between the two vertices is given as (9 -(-7)) = 16 = 2a, so the value of a is 8 and we have the partial equation ...

  (x -1)²/8² -(y -4)²/b² = 1

Filling in the given point value gives us an equation for b².

  (-11 -1)²/8² -(-6 -4)²/b² = 1

  9/4 -100/b² = 1

  5/4 = 100/b²

  b² = 80

So, the equation is ...

  (x -1)²/64 +(y -4)²/80 = 1

__

The distance between the foci is 2c, where c² = a² +b².

  c² = 64 +80 = 144 = 12²

  c = 12, so the foci are at ...

  (x, y) = (1 ±12, 4) . . . . . . . 12 units either side of the center

The foci are (-11, 4) and (13, 4).

_____

Additional comment

The steps are ...

The relevant relations are ...

  2a = length of transverse axis (distance between vertices)

  2b = length of conjugate axis (distance between co-vertices)

  ±b/a = slope of asymptotes, which are lines through the center

  2c = distance between foci, where c² = a² +b²

The equation is (x -h)²/a² -(y -k)²/b² = 1 for a hyperbola that opens horizontally with center (h, k). Swapping variables x and y will give a hyperbola that opens vertically. If the figure opens vertically, the asymptotes will have slope ±a/b.

The distances from a point to the foci have a constant difference of 2a.

Answer:

x= -3

Step-by-step explanation:

[tex] \frac{x + 6}{3} - \frac{x + 8}{5} = 0[/tex]

Multiply both sides by 15 (LCM of 3 and 5):

[tex] \frac{15(x + 6)}{3} - \frac{15(x + 8)}{5} = 0[/tex]

5(x +6) -3(x +8)= 0

Expand:

5x +30 -3x -24= 0

2x +6= 0

-6 on both sides:

2x= -6

x= -6 ÷2

x= -3

The statements which best describe an effective claim in an argumentative essay are:

A. It is precise and clear.

E. It states a fact using precise language.

An argumentative essay can be defined as a literary work which comprises an expression of a writer's stance (position) on a specific topic or subject matter.

A claim refers to a statement that is used by a writer to prove, substantiate or support an argument. Thus, it is an assertive statement expressed by a writer to prove that an argument is true, factual, and real.

In this context, the main function of an effective claim in an argument is simply to precisely and clearly state a fact based on a writer's opinion.

In conclusion, the following statements which best describe an effective claim in an argumentative essay are:

Read more on argumentative essays here: https://brainly.com/question/11617771

Answer:

Its A and B

Step-by-step explanation

Answer:

seriously??

have you heard of calculators lol

the answer is 3.45

He will be eating pizza

S + will + be + V_ing

Answer:

C    [tex] \dfrac{9a^{12}}{b^3} [/tex]

Step-by-step explanation:

54/6 = 9

a^8 / a^-4 = a^{8 - (-4)} = a^12

b^2 / b^5 = b^-3 = 1/b^3

Answer:  C    [tex] \dfrac{9a^{12}}{b^3} [/tex]

Answer:

Option C

Step-by-step explanation:

[tex] \sf \dfrac{54 {a}^{8} {b}^{2} }{6 {a}^{ - 4} {b}^{5} } [/tex]

We know that

[tex] \sf \: \frac{ {a}^{m} }{a {}^{n} } = a {}^{m - n} [/tex]

[tex] \sf 9 \dfrac{a {}^{8} {b}^{2} }{ {a}^{ - 4} {b}^{5} } [/tex]

[tex] \sf \: 9 \dfrac{ {a}^{8 - ( - 4)} b {}^{(2 - 5)} }{1} [/tex]

[tex] \sf \: 9 \dfrac{ {a}^{12}b {}^{ - 3} }{1} [/tex]

[tex] \sf \: \dfrac{9 {a}^{12} }{ {b}^{3} } [/tex]

The equation of a line in point slope form is expressed according to the formula;

y-y0 = m(x-x0)

Given the following parameters

m = -3

(x0, y0) = (-4, 1)

Substitute into the formula above will givee;

y - 1 = -4(x+4)

y -1 = -4x - 16

y = -4x - 15

Next is to plot the graph of the line y = -4x - 15 on the coordinate plane as shown:

Learn more graphs here: https://brainly.com/question/19011142

Answer:

x < -15

Step-by-step explanation:

Divide both sides by -2.

Next you will reverse the sign because you are dividing by a negative number.

Answer:

7 Iron

Step-by-step explanation:

Just smort

Answer:

urs 6 2ab ytdguhdd bad wuy

Step-by-step explanation:

blank

Answer:

78.75

Step-by-step explanation:

Answer:

86493225

Step-by-step explanation:

Hope it helps

Answer:

If a function is restricted, it still has an end behavior!!!

Step-by-step explanation:

Let's say we have f(x)=(x-4)^2, x≥4.

If this function is graphed, we can see that the line starts at (4,0). It only has one side to it.

This means that it is restricted on the left side. In other words, x has to be greater than or equal to 4.

However, just because this function is restricted doesn't mean it doesn't have an end behavior!

As we can see, the graph continues on into eternity. As a result, we can write the end behavior as:

x --> ∞, f(x) --> ∞

There is no end behavior for the left side because that's where the graph is restricted.

Hope this helps!

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \impliedby y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{5}}x+7 \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{1}{5}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{5}{1}}\qquad \stackrel{negative~reciprocal}{-\cfrac{5}{1}\implies -5}}[/tex]

so then line K has a slope of -5 and pass through (-1, -3)

[tex](\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad \qquad slope=m=-5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-5}[x-\stackrel{x_1}{(-1)}] \\\\\\ y+3=-5(x+1)\implies y+3=-5x-5\implies y=-5x-8[/tex]

Answer:

57

Step-by-step explanation:

Together both angles equal 90

(3x - 15) + (5x -23) = 90

Combine like terms

8x - 38 = 90

Add 38 to both sides

8x = 128

Divide by 8

x = 16

You can check by replacing x with 16 and seeing if it still equals 90.

To find angle MON... replace x with 16

5(16) - 23

Angle MON = 57

I hope this helps!!

Answer:

Step-by-step explanation:

$6,146.76.

Hi!

We can see the numbers are increasing by 7, therefore your equation would be:

n = p + 7

"p" represents the previous number, and "n" represents the number you're trying to find.

Hope this helps! :D

Answer: 7 weeks

Step-by-step explanation:

Let x represent number of weeks

Let y represent the total amount

Amount = Paycheck deposited * number of weeks + Initial amount

y = 125x + 475

Number of weeks until she has $1350

1350 = 125x + 475

125x+475-475=1350-475

125x=875

x=7

Therefore, the student will have $1350 in her bank account after 7 weeks