Answer:
False
Explanation:
The outer part of the Earth that is hard and solid is termed as lithosphere. It is the outermost part of the Earth's surface. The lithosphere covered under the oceans is the oceanic lithosphere while the lithosphere comprising the continental area is the continental lithosphere. Oceanic lithosphere is denser than the continental lithosphere because of the thin layer of the Earth that exists under the oceans.
Please help!!!!!!!!!
What help do you want? If you tell, I may help you.
A huge asteroid that is moving at an incredibly fast speed impacts the Earth, will this change the momentum of the Earth? Explain.
Which model could represent a neutral atom of nitrogen? 2 3 4 A. 1 B. 3 C. 4 D. 2.
Answer:
B
Explanation:
because it has more power
The Model A represents a neutral atom. hence option A is correct.
What is Atom ?Atom is smallest entity of a body. Body is made up of atoms. it is basic building block of a body. An atom consist of electrons, protons and neutrons as sub atomic particle. whole mass of the atom is concentrated at the center of the atom which we call it as nucleus, nucleus consist of proton and neutron. Electron revolve around the nucleus at determined(fixed) orbit. Total number of protons in the atom decides the atomic number and the elements in the periodic table. The electrons which are completely filled orbitals are called as core shell electrons and which are not filled completely are called as valence electron. valence electrons are responsible for physical and chemical properties of the element. Elements which are on same column in periodic table have same number of valence electrons . Hence they have same properties.
Atomic number of Nitrogen is 7. Hence neutral atom of nitrogen has 7 electrons in his orbits.
Hence option A is correct.
To know more about Atom :
https://brainly.com/question/30898688
#SPJ5.
What are the rows on the periodic table called? What are the columns called? What do you know about elements in the same group?
Answer:
Rows are called periods, columns are called groups or families, and elements in the same group have the same number of valence electrons and often show similar properties and reactivity.
Explanation:
How can we represent a narrow beam of light?
Answer:
It is easy to imagine representing a narrow beam of light by a collection of parallel arrows—a bundle of rays. As the beam of light moves from one medium to another, reflects off surfaces, disperses, or comes to a focus, the bundle of rays traces the beam's progress in a simple geometrical manner.
I hope it's helpful!
Answer:It is easy to imagine representing a narrow beam of light by a collection of parallel arrows—a bundle of rays. As the beam of light moves from one medium to another, reflects off surfaces, disperses, or comes to a focus, the bundle of rays traces the beam's progress in a simple geometrical manner.
Explanation:
Density is the ____ of a substance. The density of a substance is _____ if its particles are packed tightly together. Hardness shows __________.
Answer:
degree
liquid
mass-volume
Explanation:
A tungsten wire is 1.5m long and has a diameter of A current of flows through the wire. The resistivity of the wire is 5.6 * 10 ^ - 8 What is the potential difference across the ends of the wire?
Complete Question:
A tungsten wire is 1.5 m long and has a diameter of 1.0 mm. A current of 60 mA flows through the wire. The resistivity of the wire is 5.6 * 10^-8 Ωm. What is the potential difference across the ends of the wire?
Answer:
Potential difference, V = 0.00642 Volts.
Explanation:
Given the following data;
Diameter = 1 mm to meters = 1/1000 = 0.001 m
Length = 1.5m
Current = 60mA = 60/1000 = 0.06 Amperes.
Resistivity = 5.6 * 10^-8 Ωm
To find the potential difference across the ends of the wire;
First of all, we would determine the cross-sectional area of the wire (circle);
[tex] Radius, r = \frac {diameter}{2} [/tex]
[tex] Radius = \frac {0.001}{2} [/tex]
Radius = 0.0005 m
Area of wire (circle) = πr²
Substituting into the above formula, we have;
Area = 3.142 × (0.0005)²
Area = 3.142 × 2.5 × 10^-7
Area = 7.855 × 10^-7 m²
Next, we find the resistance of wire;
Mathematically, resistance is given by the formula;
[tex] Resistance = P \frac {L}{A} [/tex]
Where;
P is the resistivity of the material.
L is the length of the material.
A is the cross-sectional area of the material.
Substituting into the formula, we have;
[tex] Resistance = 5.6 * 10^{-8} \frac {1.5}{7.855 * 10^{-7}} [/tex]
[tex] Resistance = 5.6 * 10^{-8} * 1909611.712 [/tex]
Resistance = 0.107 Ohms.
Now, we can find the potential difference using the formula;
[tex] V = IR[/tex]
Where;
V represents voltage or potential difference measured in volts.
I represents current measured in amperes.
R represents resistance measured in ohms.
Substituting into the formula, we have;
[tex] V = 0.06*0.107[/tex]
Potential difference, V = 0.00642 Volts.
A cyclist rides at 6.20 m/s through a intersection. A stationary car begins to
accelerate at 3.844 m/s2 when the bike is beside it. They reach the other side of
the intersection at the same time. Find the width of the intersection.
Answer:
The width of the intersection is 20 meters
Explanation:
The speed with which the cyclist is riding, v₁ = 6.20 m/s
The rate at which the car starts to accelerate, a = 3.844 m/s²
The initial velocity of the car = The car is stationary at the start = 0 m/s
The time at which the cyclist and the car reach the other side of the intersection = The same time;
Let 't' represent the time at which the cyclist and the car both reach the other side of the intersection, we have;
The distance travelled by the cyclist = The distance traveled by the car
∴ v₁ × t = 1/2 × a × t²
Plugging in the values for 'v₁', and 'a' in the above equation, we get;
6.20 × t = 1/2 × 3.844 × t²
∴ 1.922·t² - 6.20·t = 0
∴ t·(1.922·t - 6.20) = 0
t = 0, or t = 6.20/1.922 = 100/31
The time at which the cyclist and the car both reach the other side of the intersection, t = 100/31 seconds
The with of the intersection, w = v₁ × t
∴ w = 6.20 × 100/31 = 100/5 = 20
The width of the intersection, w = 20 meters.
if a cup of ice is left in the sun all day will the ice undergo a chemical or physical change?
help me please!
Answer:
Physical change
Explanation:
its changing matter but is still water so its not chemicly changing
A disk-shaped space station 125 m in diameter spins at a constant angular velocity. If the acceleration of a point on the rim of the disk is to be equal to "g", how long does it take for the station to make one revolution?
Answer:
t = 22.44 s
Explanation:
The acceleration of the station is centripetal which has the formula
a = v² / r
linear and angular velocity are related
v = w² r
as they indicate that the acceleration is equal to the acceleration of gravity
g = w² r
w = [tex]\sqrt{ \frac{g}{r} }[/tex]
let's calculate
w = [tex]\sqrt{ \frac{9.8}{ 125} }[/tex]
w = 0.28 rad / s
to calculate the time use us
w = θ / t
in a complete revolution θ = 2pi
t = θ / w
let's calculate
t = 2π / 0, 28
t = 22.44 s
What kind of image is formed when an object is placed at the focal point of a convex lens? Explain WHY this is the image that occurs
Answer:
Since light does not actually pass through this point, the image is referred to as a virtual image. Observe that when the object in located in front of the focal point of the converging lens, its image is an upright and enlarged image that is located on the object's side of the lens.
Explanation:
10. Which of the following is an electrical insulator?
A. a penny
B. a bike chain
C. a tree
D. a gold tooth
Answer:
c
Explanation:
every other option is a conductor
A 50kg gymnast is bouncing on a trampoline. If she is going down at 5m/s when she lands on the trampoline, and it bouncesher up in the opposite direction at a velocity of 4m/s, whatis her change in momentum?
Answer:
450 kgm/s upward
Explanation:
From the question,
Change in monentum = mass× change in velocity
ΔM = mΔv....................... Equation 1
ΔM = m(v-u).................. Equation 2
Where ΔM = Change in momentum, m = mass of the gymnast, v = final velocity, u = initial velocity
Given: m = 50 kg, v = -4 m/s. u = 5 m/s
Substitute these values into equation 2
ΔM = 50(-4-5)
ΔM = 50(-9)
ΔM = -450 kgm/s
Hence the change in momentum of the gymnast is 450 kgm/s upward
If the work done when a charge of 5.2 × 10-13 coulombs is moved between two points is 4.7 × 10-12 joules, what is the potential difference?
A.
4.7 volts
B.
5.2 volts
C.
9.0 volts
D.
10 volts
E.
12 volts
Answer:
9.0, might be to late but someone in the future might need it.
Answer:
C. 9.0
Explanation:
I like boys
what substance might impact the formation of volcanic rock?
marking brainliest!
Answer:
Magma is less dense than the surrounding rock which causes it to rise. When magma reaches the surface it is then called lava and the eruptions of lava and ash produce volcanoes. The lava that reaches the Earth's surface will harden and become igneous rock.
what does an electric circuit mean?
Answer: An electric circuit includes a device that gives energy to the charged particles constituting the current, such as a battery or a generator; devices that use current, such as lamps, electric motors, or computers; and the connecting wires or transmission lines.
Explanation: Hope this helped! <3
A ____ changes mechanical energy into ____. A____changes electric energy into _____. _____changes the voltage of an
Answer:
An electric current into a magnetic field
Explanation:
:) please give a heart if this helped you in any way. ;O)
i dont need answers, i just want to know what you guys think....just anything
if energy can't be created or destroyed, then it means there must have been a certain amount of energy when the universe was born, right? Is it possible to measure how much energy there was in the beginning?
Answer:
I am not sure really.
Explanation:
I just don't know
8. List the objects in order from least to greatest inertia
A
B
D
5 kg
4 kg
3 kg
10 kg
a = 1 m/s/s
a 3 m/s/s
a 2 miss
a= 0 m/s/s
Answer:
mhibyguftyftfrehlknmjhbn
Explanation:
njhvvtfryvbnyuhnuihnjhk
What challenges do scientists face in studying the Sun?
Answer:
Explanation:
The sun sends out solar wind constantly - charged particles that can degrade visual sensors and the skin of spacecraft, and the occasional blast of a solar flare, which can send out clouds of charged ions that can disrupt communications and electronics on board probes and satellites.
Hope this Helps <3
For a 25 kg object to have the same momentum as a 5kg object, the
25kg object must have
a. a greater velocity than the 5 kg object
b. a smaller velocity than the 5kg object
c. the same velocity as the 5kg object
d. not enough information to determine
Answer:
b.
Explanation:
due to the higher mass of the 25 kg body as compared to the 5kg body ,a smaller velocity will catch up quickly with the 5kg object, but a slight increase in its velocity will have a much higher momentum
A charge q1 of -5.00 x 10^-9 C and a charge q2 of -2.00x 10^-9 C are separated by a distance of 40.0 cm. Find the equilibrium position for a third charge of +15.0x 10^-9 C.
Answer:
Explanation:
Let the equilibrium position of third charge be x distance from q₁.
Force on third charge due to q₁
= 9 x 10⁹ x 5 x 10⁻⁹ x 15 x 10⁺⁹ / x²
Force on third charge due to q₂
= 9 x 10⁹ x 2 x 10⁻⁹ x 15 x 10⁺⁹ /( .40-x)²
Both the force will act in opposite direction and for balancing , they should be equal.
9 x 10⁹ x 5 x 10⁻⁹ x 15 x 10⁺⁹ / x² = 9 x 10⁹ x 2 x 10⁻⁹ x 15 x 10⁺⁹ /( .40-x)²
5 / x² = 2 / ( .4 - x )²
Taking square root on both sides
2.236 / x = 1.414 / .4 - x
2.236 ( .4 - x ) = 1.414 x
.8944 - 2.236 x = 1.414 x
.8944 = 3.65 x
x = .245 m
24.5 cm
So the third charge should be at a distance of 24.5 cm from q₁ .
True or false the weak force also called the weak nuclear interaction is by far the weakest of the four fundamental forces
Answer:
True
Explanation:
There basically four type of forces in nature that govern the entire laws of nature. These four forces are
1.Gravity.
2.The weak force.
3.Electromagnetism.
4.The strong force.
The weak force as it is called is the weakest of the all the forces mentioned above. It is also called weak nuclear interaction force and is responsible for particle decay.
By the end of the 19th century, more than half of the population believed in the presence of atoms.
Answer:
hello your question is vague hence I will provide a general answer about what was known about atoms in the 19th Century
answer :
By the end of the 19th century more than half of the population believed in the presence of atoms and also in the 19th Century is was a known fact that atoms determine the chemical properties of an element
Explanation:
By the end of the 19th century more than half of the population believed in the presence of atoms and also by the 19th Century is was a known fact that atoms determine the chemical properties of an element.
John Dalton reintroduced the presence of atoms in 1800 with evidence which he used to develop atomic theory. with this theory people believed in the presence of atoms in nature and also that atoms determine the chemical properties of an element .
Sodium lamps give off light at
589 nm. When that light passes
through a diffraction grating with
d = 3.88 x 10-6 m, what is the angle of
its second order (m = 2) maximum?
Answer:
θ = 17.67°
Explanation:
The grating equation can be used here to find the angle. The grating equation is given as follows:
[tex]m\lambda = dSin\ \theta[/tex]
where,
m = order = 2
d = 3.88 x 10⁻⁶ m
λ = wavelength of light = 589 nm = 5.89 x 10⁻⁷ m
θ = angle = ?
Therefore, using these values in the equation, we get:
[tex](2)(5.89\ x\ 10^{-7}\ m) = (3.88\ x\ 10^{-6}\ m)Sin\theta \\Sin\theta = \frac{(2)(5.89\ x\ 10^{-7}\ m)}{(3.88\ x\ 10^{-6}\ m)}\\\\\theta = Sin^{-1}(0.3036)[/tex]
θ = 17.67°
Answer:17.67
Explanation:
2 points
What element in this equation indicates that this is a combustion reaction: CH4(g) + 2 O2(g) — CO2(g) + 2 H2O(g)? i
1. Matter is made up of small particles called
2. What is the volume of this rectangular prism?
cm^3
Calculate the volume of this regular solid.
6 cm
5 cm
9 cm
The weather map shows air pressure in Millibars. Which set of conditions 10 por
best describes the weather at the area of lowest air pressure?"
1004
1004
1008
1008
1008
1004
41004
(1008
1-000
1000
1000
996 L
1-004
1004
1000
1000M
2008
2004
-1004
1008
A. Bright sun with no wind
O B. Mostly sunny with no winds
O C. Partly cloudy with no wind
O D.Overcast skies with strong winds
I think the answer for the following question is A.
write four importance of pressure
A man pulls a sled at a constant velocity across a horizontal snow surface . If a force of 80 n is being applied to the sled at an 53 degree to the ground . What is the force of friction between sled and snow
Answer:
Explanation:
The force of 80N is applied on sled at 53⁰
Its horizontal component = 80cos53
= 48.14 N .
Its horizontal component will pull forward the sled and friction will prevent its forward motion . As sled is moving with constant velocity , net force on it is zero .
Hence forward push = frictional force
Frictional force = 48.14 N.