Answer:
In a 30°-60°-90° right triangle, the length of the longer leg is √3 times the length of the shorter leg.
A = (1/2)Pa
= (1/2)(2)(8/√3)(6)(8)
= (384√3)/3 = 128√3 = 221.7 units^2
A circle has a diameter whose end points are at (-3, -1) and (7, 7). What is the equation of the circle?
Therefore, the equation of the circle in standard form is: (x - 2)² + (y - 3)² = 40.
What is the circle's general form equation?(xh)2+(yk)2=r2 is the equation of a circle in standard form. The radius is r units, and the centre is at (h,k). Mark points r units up, down, left, and right from the centre of the circle to graph it. Through these four points, draw a circle.
We must first determine the circle's centre and radius before we can determine its equation.
The circle's centre is defined as the point on a line segment that connects the diameter's two endpoints. Taking the average of the x-coordinates and the average of the y-coordinates will get the midpoint:
Midpoint: ((-3+7)/2, (-1+7)/2) = (2, 3)
The distance formula can be used to determine that the circle's radius is equal to half of its diameter:
diameter = √((7-(-3))²+ (7-(-1))²) = √(160) = 4√(10)
radius = (1/2)diameter = 2sqrt(10)
So the center of the circle is (2, 3) and the radius is 2sqrt(10).
Consequently, the circle's standard form equation is as follows:
(x - 2)²+ (y-3)²= (2√(10))²
Simplifying:
(x - 2)²+(y-3)²=40
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Mathematic desmos
6.7 Readiness Check
Write point P as a fraction and as a decimal.
Fraction
Decimal
The coordinates of P when written as a fraction and as a decimal, is:
Fraction - (3/4, 5/6)Decimal - (0.75, 0.83 )How to convert to fractions ?Point P has the coordinates of ( 3/4 , 5/6 ) which means that it is already in fraction form as it has both a numerator and a denominator for the x and ya values.
We can then convert these fractions to decimal form as shown :
x - value : 3 ÷ 4 = 0.75
y - value : 5 ÷ 6 = 0.83
In decimals, it is:
(0.75, 0.83)
In conclusion, as a fraction, point P is ( 3 / 4, 5 / 6 ), and as a decimal, point P is ( 0.75, 0.83 ).
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You are walking from home to a shoe store. You stop for a rest after 1/3 miles. The shoe store is actually 3/4 miles from home. How much farther do you have to walk? Write your answer as a fraction in simplest form.
Answer:
[tex]\frac{5}{12}[/tex]
Step-by-step explanation:
[tex]\frac{3}{4}[/tex] - [tex]\frac{1}{3}[/tex]
[tex]\frac{9}{12}[/tex] - [tex]\frac{4}{12}[/tex] = [tex]\frac{5}{12}[/tex]
Helping in the name of Jesus.
1. If the gross domestic product of a country is significantly higher in one year than in another, what
might account for the difference
a. population growth
Ob.
b. greater available resources and technological advances
Oc. inflation
C.
Od. all of these
2. The Lorenz Curve for the United States indicates that the richest 20 percent of households have
what percentage of the nation's income
a. 20 percent
b. 3.8 percent
c. 90 percent
d. 46.8 percent
3. The economic condition most likely to be caused by a war affecting oil production in the
Mid East would be
a. demand-pull inflation
b. cost-push inflation
c. deflation
Od.
d. cost of living inflation
The difference is accounted for by d. all of these
The percentage of the nation is 46.8 percent
The economic condition most likely to be caused by a war affecting oil production in the Mid East would be cost-push inflation
How to answer the questionsThe accurate response is (d) all of these. An overflow in population can influence Gross Domestic Product (GDP) by enlarging the labor force, potentially promoting productivity and efficiency as well as heightening output through more accessible assets and advanced technology. Inflation might also affect GDP by escalating prices and reducing buying capability.
Therefore, the precise answer is (d) 46.8 percent. The Lorenz Curve is a pictorial rendering of income inequality and the Gini coefficient estimates the severity of disparity. According to fresh records, the most affluent 20 percent of households in the United States keep virtually 46.8 percent of the national income.
The economic state maybe instigated by a conflict impacting oil production in the Middle East would be (b) cost-push inflation. A disruption in the offering of petroleum may consequence in elevated construction costs for businesses, which could then pass on such augmented charges to customers via higher rates. This manner of inflation is referred to as cost-push inflation.
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Determine the five-number summary for the data set. 20, 26, 18, 31, 22, 28, 30
The five-number summary for the given data set is 18, 22, 26, 30, 31.
What is five-number summary?The five-number summary is a set of descriptive statistics that provides information about a dataset by summarizing the data's five most important features. It includes the minimum data point, the first quartile, the median, the third quartile, and the maximum data point.
In order to calculate the five-number summary for the given data set (20, 26, 18, 31, 22, 28, 30), we first need to arrange the data in ascending order: 18, 20, 22, 26, 28, 30, 31.
The minimum data point is 18, the first quartile is 22, the median is 26, the third quartile is 30, and the maximum data point is 31.
So, the five-number summary for the given data set is 18, 22, 26, 30, 31.
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ines a and b are parallel and lines e and f are parallel.
Horizontal lines e and f are intersected by lines a and b. At the intersection of lines a and e, the uppercase left angle is 82 degrees, and the bottom left angle is 98 degrees. At the intersection of lines b and e, the bottom right angle is x degrees.
What is the value of x?
Given that lines a and b are parallel, lines e and f are parallel and the angles formed by their intersection is x at the intersection of lines b and e. The value of x is 82 degrees. So, the correct answer is B).
We are given that Lines a and b are parallel and Lines e and f are parallel. Horizontal lines e and f are intersected by lines a and b.
At the intersection of lines a and e, the upper left angle is 82 degrees, and the bottom left angle is 98 degrees.
We need to find the value of x, which is the bottom right angle at the intersection of lines b and e. Here are the steps to solve the problem:
Since lines a and b are parallel, the angle at the top left of the intersection between b and f is also 98 degrees. This is because alternate interior angles are congruent.
We know that the angle at the top left of the intersection between a and e is 82 degrees.
Therefore, the angle at the bottom left of the intersection between f and b is
angle at the bottom left of the intersection between f and b = 180 - (82 + 98) = 0
This means that line f and line b are collinear, and therefore, they do not intersect.
Since line e intersects both lines a and b, the angle at the bottom right of the intersection between b and e is 180 degrees (a straight line).
Therefore, x = 180 - the angle at the bottom left of the intersection between b and e, which is 98 degrees.
x= 180 - 98 = 82
Hence, x = 82 degrees.
So, the correct option is B).
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--The given question is incomplete, the complete question is given
" Lines a and b are parallel and lines e and f are parallel.
Horizontal lines e and f are intersected by lines a and b. At the intersection of lines a and e, the uppercase left angle is 82 degrees, and the bottom left angle is 98 degrees. At the intersection of lines b and e, the bottom right angle is x degrees.
What is the value of x?
8
82
98
172 "--
ASAP Dr. Rollins is both an anthropologist and archeologist. While excavating some ruins in South America, he discovered a scale drawing of a replica of a Mayan pyramid.
-The scale for the drawing to the replica was 1 inch : 2 feet.
- The scale for the replica to the actual pyramid was 1 foot : 14 feet.
If the height of the pyramid on the drawing was 3 1/2 inches, what was the height of the actual pyramid?
A. 98 feet
B. 49 feet
C. 91 feet
D. 196 feet
The height of the actual pyramid is 98 feet.
How to find the height of the actual pyramid?
To find the height of the actual pyramid, we need to use the two scales given to us and convert the height on the drawing to the height of the actual pyramid. Here are the steps to follow,
Use the scale for the drawing to the replica to convert the height on the drawing to the height of the replica,
[tex]3 \frac{1}{2} \: inches \: \times \frac{2 \: feet}{ 1 \: inch}= 7 \: feet[/tex]
Use the scale for the replica to the actual pyramid to convert the height of the replica to the height of the actual pyramid,
[tex]7 \: feet \times \frac{ 14 \: feet }{1 \: foot}= 98 \: feet[/tex]
Therefore, the height of the actual pyramid is 98 feet. The answer is A. 98 feet.
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Please help me answer this I will give you brainliest!!!!
Answer:
8) ]-infinity ,1]
9) ]-infinity,-2[
Answer:
8) x ≤ 1 9) x < -2
Hope this helps.
Jonathan makes two handcrafted
wooden boxes. The volume of the
oak box is 2x³ + 5x²-3x cm³. The
volume of the maple box is 2x3 + 9x²
2x 24 cm³. In both expressions,
x represents the width of the box in
centimeters.
Which of the following is a true
statement?
statement B and D are true. to determine which of the statements is true, we need to perform the indicated operations and simplify the expressions for the volumes of the boxes.
what is expressions ?
In computer programming, an expression is a combination of values, variables, and operators that produces a result or value. Expressions can be simple or complex, and they can be used in a variety of contexts, such as assigning values to variables, performing calculations, and making logical decisions.
In the given question,
To determine which of the statements is true, we need to perform the indicated operations and simplify the expressions for the volumes of the boxes.
The volume of the oak box is 2x³ + 5x² - 3xc*m³.
The volume of the maple box is 2x³ + 9x² - 2x - 24c*m³.
A. The oak box has a volume 4x² + x 24c*m³ greater than the maple box.
To compare the volumes, we need to subtract the volume of the maple box from the volume of the oak box:
(2x³ + 5x² - 3xcm³) - (2x³ + 9x² - 2x - 24cm³)
= 2x³ - 4x² + 2x + 24c*m³
Therefore, statement A is not true.
B. The maple box has a volume 4x² + x - 24c*m³ greater than the oak box.
To compare the volumes, we need to subtract the volume of the oak box from the volume of the maple box:
(2x³ + 9x² - 2x - 24cm³) - (2x³ + 5x² - 3xcm³)
= 4x² + x - 24c*m³
Therefore, statement B is true.
C. The total volume of 1 oak box and 1 maple box is 4x³ + 14x² + 5x + 24c*m³.
To find the total volume, we need to add the volumes of the oak and maple boxes:
(2x³ + 5x² - 3xcm³) + (2x³ + 9x² - 2x - 24cm³)
= 4x³ + 14x² - x - 27c*m³
Therefore, statement C is not true.
D. The total volume of 2 maple boxes is 4x³ + 18x² + 4x + 48c*m³.
To find the total volume of 2 maple boxes, we need to multiply the volume of 1 maple box by 2:
2(2x³ + 9x² - 2x - 24cm³) = 4x³ + 18x² - 4x - 48cm³
Therefore, statement D is true.
In summary, the correct statements are:
B. The maple box has a volume 4x² + x - 24c*m³ greater than the oak box.
D. The total volume of 2 maple boxes is 4x³ + 18x² + 4x + 48c*m³.
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The amount of snowfall in December was 5 7/8 feet. The amount of snowball in October was 1/4 feet. How much more snowfall was there in December? Write your answer as a mixed number in simplest form.
Answer:
5 3/8 ft
Step-by-step explanation:
5 7/8 - 1/4 = 5 7/8 - 4/8 = 5 3/8
An initial amount of money is placed in an account at an interest rate of 4% per year, compounded continuously. After four years, there is $1255.66 in the account. Find the initial amount placed in the account. Round your answer to the nearest cent.
Answer:
We can use the continuous compounding formula to solve this problem:
A = Pe^(rt)
where A is the final amount, P is the initial amount, r is the interest rate, and t is the time in years.
In this problem, we know the final amount (A = $1255.66), the interest rate (r = 4% = 0.04), and the time (t = 4 years). We want to find the initial amount (P).
Substituting the known values into the formula, we get:
1255.66 = Pe^(0.04*4)
Simplifying the exponent:
1255.66 = Pe^0.16
Dividing both sides by e^0.16:
1255.66 / e^0.16 = P
Using a calculator to evaluate e^0.16, we get:
1255.66 / 1.17351087099 = P
Simplifying:
P = $1069.44
Therefore, the initial amount placed in the account was $1069.44 (rounded to the nearest cent).
Step-by-step explanation:
compounded continuously, given that there is $1255.66 in the account after four years, we can use the formula:
A = Pe^(rt)
where A is the final amount, P is the initial amount, r is the interest rate, and t is the time in years.
Substituting the known values into the formula, we get:
1255.66 = Pe^(0.04*4)
Simplifying the exponent:
1255.66 = Pe^0.16
Dividing both sides by e^0.16:
P = 1255.66 / e^0.16
Using a calculator to evaluate e^0.16, we get:
P = 1069.44
Therefore, the initial amount placed in the account was $1069.44 (rounded to the nearest cent).
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Answer:
We can use the continuous compounding formula to solve this problem:
A = Pe^(rt)
where A is the final amount, P is the initial amount, r is the interest rate, and t is the time in years.
In this problem, we know the final amount (A = $1255.66), the interest rate (r = 4% = 0.04), and the time (t = 4 years). We want to find the initial amount (P).
Substituting the known values into the formula, we get:
1255.66 = Pe^(0.04*4)
Simplifying the exponent:
1255.66 = Pe^0.16
Dividing both sides by e^0.16:
1255.66 / e^0.16 = P
Using a calculator to evaluate e^0.16, we get:
1255.66 / 1.17351087099 = P
Simplifying:
P = $1069.44
Therefore, the initial amount placed in the account was $1069.44 (rounded to the nearest cent).
Step-by-step explanation:
compounded continuously, given that there is $1255.66 in the account after four years, we can use the formula:
A = Pe^(rt)
where A is the final amount, P is the initial amount, r is the interest rate, and t is the time in years.
Substituting the known values into the formula, we get:
1255.66 = Pe^(0.04*4)
Simplifying the exponent:
1255.66 = Pe^0.16
Dividing both sides by e^0.16:
P = 1255.66 / e^0.16
Using a calculator to evaluate e^0.16, we get:
P = 1069.44
Therefore, the initial amount placed in the account was $1069.44 (rounded to the nearest cent).
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The probability that a city bus is ready for service when needed is 84%. The probability that a city bus is ready for service and has a working radio is 67%. Find the probability that a bus chosen at random has a working radio given that it is ready for service. Round to the nearest tenth of a percent.
The probability that a bus chosen at random has a working radio given that it is ready for service is approximately 85.3%
How to find the probability of a bus having a working radio given that it is ready for service?
We can use Bayes' theorem to find the probability of a bus having a working radio given that it is ready for service,
P(radio | ready) = P(ready | radio) * P(radio) / P(ready)
where
P(radio | ready) is the probability that a bus has a working radio given that it is ready for service.
P(ready | radio) is the probability that a bus is ready for service given that it has a working radio.
P(radio) is the probability that a bus has a working radio.
P(ready) is the probability that a bus is ready for service.
From the given information, we know that:
P(ready) = 0.84
P(radio | ready) = 0.67
To find P(ready | radio), we can use the formula:
P(ready | radio) = P(ready and radio) / P(radio)
From the given information, we know that:
P(ready and radio) = P(radio | ready) × P(ready) = 0.67 × 0.84 = 0.5628
To find P(radio), we can use the law of total probability:
P(radio) = P(radio | ready) × P(ready) + P(radio | not ready) × P(not ready)
We can assume that if a bus is not ready for service, it doesn't matter if it has a working radio or not. So we can simplify the equation to:
P(radio) = P(radio | ready) × P(ready) + P(radio | not ready) × (1 - P(ready))
From the given information, we know that:
P(radio | ready) = 0.67
P(ready) = 0.84
We don't have information about P(radio | not ready), but we can assume that it is lower than P(radio | ready) since a bus that is not ready for service is more likely to have a broken radio. Let's assume P(radio | not ready) = 0.3.
Then, we can calculate,
P(radio) = 0.67 × 0.84 + 0.3 × (1 - 0.84) = 0.6596
Now, we want to find P(radio | ready),
P(radio | ready) = P(ready | radio) × P(radio) / P(ready)
P(ready | radio) = P(ready and radio) / P(radio) = 0.5628 / 0.6596 = 0.853
Therefore, the probability that a bus chosen at random has a working radio given that it is ready for service is approximately 85.3% (rounded to the nearest tenth of a percent).
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The probability that a bus chosen at random has a working radio given that it is ready for service is approximately 85.3%
How to find the probability of a bus having a working radio given that it is ready for service?
We can use Bayes' theorem to find the probability of a bus having a working radio given that it is ready for service,
P(radio | ready) = P(ready | radio) * P(radio) / P(ready)
where
P(radio | ready) is the probability that a bus has a working radio given that it is ready for service.
P(ready | radio) is the probability that a bus is ready for service given that it has a working radio.
P(radio) is the probability that a bus has a working radio.
P(ready) is the probability that a bus is ready for service.
From the given information, we know that:
P(ready) = 0.84
P(radio | ready) = 0.67
To find P(ready | radio), we can use the formula:
P(ready | radio) = P(ready and radio) / P(radio)
From the given information, we know that:
P(ready and radio) = P(radio | ready) × P(ready) = 0.67 × 0.84 = 0.5628
To find P(radio), we can use the law of total probability:
P(radio) = P(radio | ready) × P(ready) + P(radio | not ready) × P(not ready)
We can assume that if a bus is not ready for service, it doesn't matter if it has a working radio or not. So we can simplify the equation to:
P(radio) = P(radio | ready) × P(ready) + P(radio | not ready) × (1 - P(ready))
From the given information, we know that:
P(radio | ready) = 0.67
P(ready) = 0.84
We don't have information about P(radio | not ready), but we can assume that it is lower than P(radio | ready) since a bus that is not ready for service is more likely to have a broken radio. Let's assume P(radio | not ready) = 0.3.
Then, we can calculate,
P(radio) = 0.67 × 0.84 + 0.3 × (1 - 0.84) = 0.6596
Now, we want to find P(radio | ready),
P(radio | ready) = P(ready | radio) × P(radio) / P(ready)
P(ready | radio) = P(ready and radio) / P(radio) = 0.5628 / 0.6596 = 0.853
Therefore, the probability that a bus chosen at random has a working radio given that it is ready for service is approximately 85.3% (rounded to the nearest tenth of a percent).
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Determine the rate of change of the function given by the table.
The rate of change of the function given by the table is 1.
What is the rate of change?The rate of change represents the ratio of one quantity compared to another.
The rate of change is also known as the slope (the Rise/the Run), the gradient, unit rate, or constant rate of proportionality.
The rate of change is computed as the quotient between the Change in the Rise and the Change in the Run.
x y Rate of Change
5 3
6 4 1 (1/1)
7 5 1 (1/1)
8 6 1 (1/1)
Thus, for the function represented by the table, the rate of change or unit rate is 1.
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Supplementary angles
Answer: ∠HDG
Step-by-step explanation:
Starting Angle: ∠HDE
Possible Supplement: ∠HDG
Can someone please help me
If tan(a) > 1 where could angle a be on the unit circle?
Option B is correct because the tangent of angle a is greater than 1 when a is between 0 and pi/4. Option G is correct because the tangent of angle a is also greater than 1 when a is between 3pi/4 and pi.
When tan(a) > 1, this means that the tangent of angle a is greater than the length of the adjacent side divided by the length of the opposite side in a right triangle. Since the adjacent and opposite sides of a unit circle have a length of 1, this means that the opposite side of angle a is less than 1.
To determine where angle a could be on the unit circle, we need to find the angles whose tangent is greater than 1. Since tangent is positive in the first and third quadrants, the angles we need to consider are in the first and third quadrants.
In the first quadrant, the angle whose tangent is 1 is pi/4, and the tangent increases as the angle increases. Therefore, angle a could be between 0 and pi/4 (option B).
In the third quadrant, the angle whose tangent is 1 is 5pi/4, and the tangent decreases as the angle increases. Therefore, angle a could also be between 3pi/4 and pi (option G).
Therefore, options B and G are correct, and angles a could be located in the regions described by these options on the unit circle.
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what is the lowest depth the diver reaches using the function d(t)=3t^2-12t+0
Answer:
12 units.
Step-by-step explanation:
Convert the expression to vertex form:
d(t)=3t^2-12t+0
= 3(t^2 - 4t)
= 3[(t - 2)^2 - 4]
= 3(t-2)^2 - 12.
Minimum value = 12.
Round to the nearest tenth, then find the difference. 13.56 − 10.02 = ___ pleas help I need help im in a test im sorry if 10 points is not enough.
what is the solution to the system of equations below?
y= 1/2x + 6 and y= - 3/4x - 4
(-8,2)
(-8,-1)
(8,-10)
(8,10)
Answer:
(- 8, 2 )
Step-by-step explanation:
y = [tex]\frac{1}{2}[/tex] x + 6 → (1)
y = - [tex]\frac{3}{4}[/tex] x - 4 → (2)
substitute y = [tex]\frac{1}{2}[/tex] x + 6 into (2)
[tex]\frac{1}{2}[/tex] x + 6 = - [tex]\frac{3}{4}[/tex]x - 4
multiply through by 4 ( the LCM of 2 and 4 ) to clear the fractions
2x + 24 = - 3x - 16 ( add 3x to both sides )
5x + 24 = - 16 ( subtract 24 from both sides )
5x = - 40 ( divide both sides by 5 )
x = - 8
substitute x = - 8 into either of the 2 equations and evaluate for y
substituting into (1)
y = [tex]\frac{1}{2}[/tex] (- 8) + 6 = - 4 + 6 = 2
solution is (- 8, 2 )
HELP
Which expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign?
A square shaped traffic sign is shown with the length of one side labeled as x plus 1.
x2 + 2x + 1
x2 + x + 1
x2 + 2x
x2 + 1
The expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign is A) [tex]x^2+2x+1[/tex].
What is area?
The region that an object's shape defines as its area. The area of a figure or any other two-dimensional geometric shape in a plane is how much space it occupies.
Here the given square shaped traffic sign side length a = x+1
We know that, area of square = [tex]a^2[/tex] square unit.
Then, area of the square shaped traffic sign is
=> A = [tex](x+1)^2[/tex]
=> A = [tex]x^2+2x+1[/tex]
Hence the expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign is A) [tex]x^2+2x+1[/tex].
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PQ
is tangent to OR at point P. Is each statement true for OR? Drag "true" or "false" below each statement.
R
50 °
P
40°
true
ST is tangent to OR at point 7.
mZRST=mZSRT
false
mZSTR=mZQPR
The answer to each statement are:
a. ST is tangent to circle R at point T - True
b. m<RST ≅ m<SRT - False
c. m<STR ≅ m<QPR - True
What is a tangent to a circle?A tangent is a straight line drawn in such a way that it intersects externally a point on the circumference of a circle. Thus it touches a circle externally at a point on its boundary.
Considering the diagram and information given in the question, given a circle with center R and tangents PQ, ST. It can be deduce that the statements that are true or false are:
i. ST is tangent to circle R at point T - True
ii. m<RST ≅ m<SRT - False
ii. m<STR ≅ m<QPR - True
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Please help due in 1 hour
Answer:
Answer is B. 3x^2 +2x - 2.5
Step-by-step explanation:
Just factor out and simplify.
[tex]\frac{0.25x^2*(3x^2+2x-2.5)}{0.25x^2}[/tex]
x cannot be 0 or else the denominator is 0 making the function undefined.
Answer:
it is B
Step-by-step explanation:
Given the function f(x) =3x^2-6x-9 is the point (1,-12) on the graph of f?
Answer: Yes
Step-by-step explanation:
For questions like this, youve been given a value for x, and a value for y.
Plug in and see if it works out!
[tex]3x^2- 6x - 9 = y[/tex]
[tex]3(1)^2- 6(1) - 9 = -12[/tex] ----- Plugging in for x and y
[tex]3 - 6 - 9 = -12[/tex]
[tex]-12 = -12[/tex]
Since -12 is indeed equal to -12, we conclude the statement is true;
In terms of the graph, this translates to, "Yes, the point (1, -12) is on the graph of [tex]y = 3x^2- 6x - 9[/tex]
So your answer is Yes
4. How many combinations are possible on a 4 number computer cable lock. Each space can
be any number 0 - 9. The only exception is that all four numbers cannot be the same.
How many combinations are possible?
The possible number of combinations are 9,720.
What is combination?In mathematics, a combination is a way of selecting a subset of items from a larger set, where the order of selection does not matter. The number of combinations of size k that can be chosen from a set of n items is denoted by the symbol C(n,k) or sometimes by ⁿCk, and is given by the formula:
C(n,k) = n! / (k! ×(n - k)!)
Define number?A number is a mathematical concept used to represent quantity or value. It can be a whole number, such as 1, 2, 3, or a decimal, such as 1.5 or 3.14. Numbers are used in various mathematical operations, such as addition, subtraction, multiplication, and division. They are also used in everyday life for counting and measuring.
There are a total of 9,720 possible combinations for a 4-number computer cable lock where each space can be any number 0-9, except for the restriction that all four numbers cannot be the same. To arrive at this number, we can first calculate the total number of possible combinations without the restriction, which is 10⁴ = 10,000. Then we subtract the number of combinations where all four numbers are the same, which is simply 10 (i.e. 0000, 1111, 2222, etc.), to get 9,990. Finally, we subtract the number of combinations where all four numbers are the same and also subtract the number of combinations where three out of four numbers are the same (which is simply 10×4 = 40 since there are 10 possible values for the repeated number and 4 possible positions for it), which gives us a final count of 9,720.
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A substance with a half life is decaying exponentially. If there are initially 12 grams of the substance and after 2 hours there
are 7 grams, how many grams will remain after 3 hours? Round your answer to the nearest hundredth, and do not include
units.
Provide your answer below:
Answer:
5.35 grams
Step-by-step explanation:
Given that a 12 grams of a substance will decay exponentially to 7 grams in 2 hours, you want to know the amount remaining after 3 hours.
EquationThe amount remaining can be described by ...
remaining = (initial amount)·(decay factor)^(t/(decay interval))
remaining = 12(7/12)^(t/2) . . . . where t is in hours
ApplicationAfter 3 hours, the amount remaining is ...
remaining = 12(7/12)^(3/2) ≈ 5.35 . . . . grams
About 5.35 grams will remain after 3 hours.
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Additional comment
The half-life is about 2.572 hours.
what is 999.09344471 rounded to the nearest square kilometer?
The nearest kilometers to 999.09344471 km is 1000 km.
Given value is 999.09344471 Km.
We have to calculate the round off value to the nearest kilometers. we know that after the decimal if the value of tenth place is 5 or bigger than 5 then we add 1 to the tens place digit, this is the fundamental rule of rounding off.
Now on following this rule from the very right hand side up to the tenth place digit we come to the conclusion that only the value after the decimal (934) is to be rounded off which is (900).
So 999.09344471 km is finally becomes 999.900 km after rounding of to nearest hundredth value.
Again rounding off 999.900 km to nearest km so it becomes 1000 km.
The nearest kilometers to 999.09344471 km is 1000 km.
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Which of the following is true to the degree of freedom
Its value is always one greater than the sample size.
In statistics, the degree of freedom represents the number of values in the final calculation of a statistic that is open to varying. In other terms, it is the number of distinct data points used to calculate a statistic.
The degree of freedom (df) for a sample data set is equal to the sample size minus one (df = n - 1), where 'n' represents the sample size. This means that the sample size is always one less than the degree of freedom.
The answer choices do not accurately depict the concept of the degree of freedom. The sum of all differences between the data values and the sample mean may not equal zero. The value of the degree of freedom does not always equal the sample size; rather, it is always one less than the sample size. Therefore, the correct statement is always that its value exceeds the sample size by one.
Although part of your question is missing, you might be referring to the full question:
Which of the following is true with regard to the degree of freedom?
The sum of all the differences between the data value and the sample mean can be any number
The sum of all the differences between the data value and the sample mean is always zero
Its value is always one more than the sample size
Its value is the same as the sample size
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The principal P is borrowed at a simple interest rate r for a period of time t. Find the simple interest owed for the use of the money. Assume there are 360 days in a year.
P = $3000, r = 2.5%, t = 9 months
The simple interest owed for the use of the money is $56.25.
The following formula can be used to determine the simple interest due for the usage of the money:
Simple Interest = P x r x t ÷ 360
Where P is the principal amount borrowed, r is the annual interest rate as a decimal, and t is the time period in days.
In this case, the principal amount P is $3000, the interest rate r is 2.5% or 0.025 as a decimal, and the time period t is 9 months or 270 days (assuming 30 days per month).
Simple Interest (SI) = $3000 x 0.025 x 270 ÷ 360
SI = $56.25
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what is the leading coefficient of a third-degree function that has the output of -110 x=3 and has zeros of 14, I, -I
The leading coefficient of a third-degree function that has the output of -110 x=3 and has zeros of 14, I, -I is 10
How to find the leading coefficient of a third-degree functionIf a third-degree function has zeros 14, I, and -I, it can be factored as: f(x) = a(x - 14)(x - I)(x + I)
'a' denotes the leading coefficient.
We may use the knowledge that the function's output is -110 when x = 3 to calculate the value of 'a'.
Substituting x = 3 into the function's factored form yields:
f(3) = a(3 - 14)(3 - I)(3 + I) = -110
When we simplify this equation, we get:
a(-11)(3 - I)(3 + I) = -110
a(-11)(9 - I^2) = -110
a(-11)(9 + 1) = -110 (since I2 = -1)
a(-11)(10) = -110
-110a = -1100
a = 10
Hence , the third-degree function's leading coefficient is 10.
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find the mean median and mode of 12,9,17,15,10 after each data value increases my 20%
The mean of the new data set is 15.12. and the median of the new data set is 14.4.
To increase each data value by 20%, we can multiply each value by 1.20. So the new data set becomes:
12 x 1.20 = 14.4
9 x 1.20 = 10.8
17 x 1.20 = 20.4
15 x 1.20 = 18
10 x 1.20 = 12
New data set: 14.4, 10.8, 20.4, 18, 12
To find the mean, we add up all the values and divide by the total number of values:
Mean = (14.4 + 10.8 + 20.4 + 18 + 12) / 5 = 15.12
Therefore, the mean of the new data set is 15.12.
To find the median, we first need to order the data set from smallest to largest:
10.8, 12, 14.4, 18, 20.4
The median is the middle value in the ordered set, which is 14.4.
Therefore, the median of the new data set is 14.4.
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An architect is considering bidding for the design of a new museum. The cost of drawing plans and submitting a model is $11,000. The probability of being awarded the bid is 0.2. If the architect is awarded the bid, she will make $180000 minus the $55000 cost for plans and a model.
We can compute the expected value using the given values in the problem such as we have the cost of drawing and submitting the model amounting of $11,000.
We also know that once the project is awarded to them, the anticipated profit is $180,000. Therefore, the expected value is just $180,000 minus $55,000 and the answer is $125,000.
We can compute the expected value using the given values in the problem such as we have the cost of drawing and submitting the model amounting of $11,000.
We also know that once the project is awarded to them, the anticipated profit is $180,000. Therefore, the expected value is just $180,000 minus $55,000 and the answer is $125,000.