If the resultant force acting on the van is 1500 Newtons, then the magnitude of Force X would be 1500 Newtons as X is the only horizontal force opposing the motion of the van.
What is Newton's second law?Newton's Second Law states that the resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem statement If the resultant force acting on the van is 1500 Newtons, then we have to find the magnitude of Force X,
The magnitude of the Force X = 1500 Newtons
Thus, the magnitude of the force X would be 1500 as it is the only force acting on the van.
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List the factors that affect gravitational potential energy.
There are three factors that affect gravitational potential energy:
MassHeight (distance)GravityGravitational potential energy is potential energy an object holds when falls towards another object due to gravity.
for instance, if we lift a stone and try to throw it from a height, it will have gravitational potential energy whereas stones in the ground have no gravitational potential energy.
Height is directly proportional to the gravitational potential energy(GPE). The higher the height, the more GPE it will have. Mass is also directly proportional to GPE and so gravity does.the formula of GPE: E = mgh where
m = mass, g = gravity and h = height
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Which variable is the Dependent Variable in that situation?
How do you know it's the Dependent Variable?
Answer: The time it takes for the cart to roll down the ramp is dependent on the height of the ramp. This makes the time dependent on the height.
Which law motion explains why a ball hit softly doesn’t travel as far as one that is it hard?
you have too high of a spin rate with your driver and irons.
The faster the swing speed the longer the distance from the tee. Therefore, to get the ball as far down the fairway as possible, you need to swing as hard as possible without losing balance posture, or control of the club. A softer ball provides more control on off-center shots and more distance on low-impact shots. I downgraded it a bit due to the high price.
These Titleist Tour golf balls are perfect for the beginner golfer who needs a lot of forgiveness on their shots. All in all the Pro is a seasoned athlete who hits the ball so far because he plays on the courts in the best possible conditions. Athletic golf skill maximizes swing speed, thereby maximizing distance. Fairway agronomy, on the other hand, pushes the ball farther. The reason taller golfers hit longer is primarily that their size provides a framework for greater leverage with more muscles and joints.
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a rock is thrown off a cliff with a initial velocity of 5 m/s in the horizontal direction. if the rock takes 5 seconds to hit the ground, how far does the rock go horizontally? How high is the cliff?
The rock will travel 25m horizontally with an initial velocity of 5m/s.
The height of the cliff is 125 meters.
Let 'x' be the horizontal distance travelled by the rock when thrown from the cliff.
Vₕ = horizontal velocity of the rock
T = total time of flight of the rock
Therefore, we know x = Vₕ × T
x = 5 × 5
x = 25
So, the horizontal distance travelled by the rock is 25 meters.
Now to find the height of the cliff, we can use one of the equations of motion,
H = uT+ ½gt²
Therefore equating all the given values in the above equation;
H = 0 + ½gt² (since u=0, initial vertical speed)
H = ½×10×(5)²
H = 5 × 25
H = 125m
So, the height of the cliff is 125 meters.
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A sand bag is dropped from a hot air balloon. It reached the ground 13 seconds later. What was the final velocity of the sand bag? (neglect air resistance)
a=
vf=
vi=
t=
Answer:
V = 127.4 m/s
Explanation:
Using the following expression:
V = V₀ + a * t
Applying to vertical movement:
V = 0 + g * t (Start at rest and a = g = 9.8 m/s²)
V = g * t
V = 9.8 * (13)
V = 127.4 m/s
A basketball with a mass of 2.2 kg weighs 19.6 N on Venus. What is
the acceleration due to gravity on Venus? (show work)
Im not sure but no one can kek lskhd. akshd
Mary pushes a crate by applying force of 18 newtons. unable to push it alone, she gets help from her friend, anne. together they apply a force of 43 newtons, and the crate just starts moving. if the coefficient of static friction is 0.11, what is the value of the normal force? a. 2.0 × 102 newtons b. 2.6 × 102 newtons c. 3.9 × 102 newtons d. 4.0 × 102 newtons e. 4.3 × 102 newtons
The value of the normal force is 3.9x10^2
Using the formula for friction,
Ff = UsN
Where
Us is the coefficient of static friction.
N is the normal force.
To get the crate moving, enough force must be applied to overcome the static friction:
Fapplied = Ff
Since Fapplied = 43 Newtons:
43 = UsN
Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11
43/0.11 = N = 390.9 which is approximately 391 = 3.9x10^2
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Answer:
See image
Explanation:
Plato
5) A rocket accelerates straight up from the ground at 22m / (s ^ 2) After rising for 5.0 s a piece of the rocket breaks of and falls back to earth. How fast does the piece hit the ground?
The final velocity of the rocket when it hits the ground is 71 m/s.
What is the final speed of the rocket?The final speed of the rocket will help us to determine how fast it is falling when it hits the ground.
Apply the following kinematic equation to determine the final velocity of the rocket
v = u + gt
where;
v is the final velocity of the rocketu is the initial velocity of the rocketg is acceleration due to gravityt is time of motionv = 22 m/s + (9.8 m/s²) x (5 s)
v = 22 m/s + 49 m/s
v = 71 m/s
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Marina is trying to pay more attention to her health, and she has been monitoring her heart rate using a fitness tracker. Yesterday, she got into her first-choice college. When she checked her tracker, she noticed that her heart rate was higher for most of the afternoon. What BEST explains this?
A. Strong emotions can impact the heart rate. B. She probably exercised and forgot about it.
C. If she was sitting most of the afternoon, it would be high.
D. Heart rates are unpredictable and don't generally follow patterns.
A. "Strong emotions can impact the heart rate."
An elevated heart rate, or tachycardia, can occur for any reason.
Exercise-induced or stress-related heart rate increases are two possible causes (sinus tachycardia).
Sinus tachycardia is not seen as an illness but rather a symptom.
Another factor contributing to tachycardia is an unsteady heartbeat (arrhythmia).
Heart problems and stress
Adrenaline and cortisol are two of these hormones. They get your body ready to handle stress. To help move blood to the body's center, they make your heart beat more quickly and your blood arteries shrink. Your blood pressure and blood sugar levels are also elevated by the hormones.
Heart palpitations and anxiousness are common side effects. The autonomic nervous system's "fight or flight" reaction is triggered by anxiety (ANS). Your ANS engages when you feel concerned about a circumstance, raising your heart rate.
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- A dog runs and jumps from one roof top to another which is 10 meters away and 3 meters
below. Calculate the minimum horizontal speed with which the cat must jump off the
first roof in order to make it to the other.
The minimum horizontal speed with which the cat must jump off the first roof in order to make it to the other is 12.82 m/s.
What is time of motion?The time of motion of the dog's jump is calculated as follows;
Apply the following kinematic equation and determine the time of motion of the cat's Jump.
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity of the cat = 0h is the height jumped by the catt is time of motion g is acceleration due to gravityh = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
t = √(2 x 3 / 9.8)
t = 0.78 second
The minimum horizontal distance traveled by the cat is calculated as follows;
x = Vt
where;
x is the maximum horizontal distance traveled by the catV is the horizontal velocity of the catt is the time of motion of the catV = x/t
V = (10 m) / (0.78 s)
V = 12.82 m/s
Thus, the minimum horizontal speed with which the cat must jump off the first roof in order to make it to the other is determined by applying the formula for range of a projectile.
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A car starts at rest and accelerates at a constant rate for 12 seconds to a speed of 30 m/s. a) What is the acceleration
Answer:
use the equations of motion
If an object has a mass of 4 kg and an acceleration of 8 m/s2, what is the force this object exerts?
The force acting on the object will be 32 N.
Newton's second law of motion states that, "the force is equal to the change in momentum per change in the time". The mathematical form of the law is given below.
[tex]F = \frac{dP}{dt}=\frac{d(mv)}{dt}=m\frac{dv}{dt}=ma[/tex]
Where P = momentum, t = time, m =mass, v = velocity, a = acceleration and F = force.
The mass of the object is 4 kg and acceleration is 8 m/s^2. Substitute the values in the equation and we will get the force.
F = ma
F = 4 kg * 8 m/s^2
F = 32 kg.m/s^2
F = 32 N
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suppose that you are climbing a hill whose shape is given by , and that you are at the point in which direction should you proceed initially in order to reach the top of the hill fastest?
If you walk due south from (60,40,966), we will ascend at the rate of 0.8. The location of something in relation to another is referred to as its direction.
To create the resulting vector, two vectors facing the opposite direction are subtracted from one another. Here, the vector B runs counterclockwise to the vector A, and the resulting vector R is
Consider,
z=1000−0.005x2−0.01y2∇f(x,y)
=⟨fx,fy⟩fx
=∂/∂x(1000−0.005x2−0.01y2)
=−0.01xfx
=∂/∂y(1000−0.005x2−0.01y2)
=−0.02y
Therefore,
∇f(x,y)
=⟨−0.01x,−0.02y⟩
At (60,40),∇f(60,40)
=⟨−0.01(60),−0.02(40)
=⟨−0.6,−0.8⟩
If you walk due south, the unit vector in the direction is
u=−j or ⟨1,−1⟩
Du(60,80)
=∇f(60,40)⋅⟨1, −1⟩
=⟨−0.6,−0.8⟩.⟨1,−1⟩=0.8
Therefore, if you walk due south from (60,40,966), we will ascend at the rate of0.8
The complete question is- Suppose that you are climbing a hill whose shape is given by z=934−0.06x2−0.1y2, and that you are at the point (80,50,300) In which direction (unit vector) should you proceed initially in order to reach the top of the hill fastest?
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a proton beam in an accelerator carries a current of 126 ????a. if the beam is incident on a target, how many protons strike the target in a period of 22.0 s?
The number of protons that strikes the target is 1.7325 x 10²² protons.
What is quantity of charge?
The quantity of a charge is the amount of charge or electron flowing over a given period of time.
Mathematically, the quantity of a charge is given as;
Q = It
where;
Q is the quantity of charge of the protonI is the current t is the time of current flowQ = (126 A) x (22 s)
Q = 2,772 C
The charge of the proton is 2,772 C.
The number of protons in a 2,772 C charge is calculated as follows;
1.6 x 10⁻¹⁹ C ---------> 1 proton
2,772 C ---------------> ?
= (2,772 x proton) / (1.6 x 10⁻¹⁹)
= 1.7325 x 10²² protons
Thus, we can conclude that during a period of 22 seconds, a total of .7325 x 10²² protons struck the target.
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a ball is being twirled in a circle at the end of a string. the string provides the centripetal force needed to keep the ball moving in the circle at a constant speed. does the force exerted by the string on the ball do work on the ball in this situation? explain.
The force exerted by the string on the ball does not do work on the ball if a ball is twirled in a circle at the end of a string.
W = F d cos θ
F = Force
d = Displacement
θ = Angle between applied force and displacement
If the string provides centripetal force, the force is acting towards the end of string that is constant. The direction is always tangential to the circular motion.
θ = 90°
W = 0
The work done is maximum when the force vector and displacement act in the same direction. Because if they both act in same direction, θ = 0° and W = F d cos 0° = F * d
Therefore, the force exerted by the string on the ball does not do work on the ball in this situation.
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7. If a graph is showing a positive slope, and the graph itself is a straight line, what must be the x and y axis if the straight
line is showing a constant acceleration?
An object has positive acceleration if it is accelerating and travelling in the right direction.
What does it signify if a position time graph has a straight line with a positive slope? A straight line with a positive slope will appear on the Position vs. Time graph of an item travelling forward at a constant speed. It shows that the object's velocity is constant and that it is travelling ahead.The y-axis of this sort of graph denotes position in relation to the starting point, while the x-axis denotes time. An object's distance from its beginning position at any given moment since it began moving is displayed on a position-time graph.In a distance-time graph, the object's speed is equal to the slope or gradient of the line. The line becomes steeper as the thing goes more quickly (and the greater the gradient).The starting point of the item is indicated by the y-intercept. An object's y-intercept is zero if it begins at the measuring instrument. Its y-intercept is 3 meters if it begins at a distance of 3 meters. When two items are in the same position, you may tell by where two lines intersect.To Learn more About Positive acceleration, Refer:
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Do automobiles rust quicker in hotter or colder climates? Explain.
Answer:
colder because of moisture
fred moves past alice at a constant speed c and alice notes that fred's clock is running at a rate eight-elevenths that of her clock. what is fred's speed (in terms of c) relative to alice?
Fred's speed as relative to alice is V = 0.6873c.
Speed is defined as the distance covered in a unit of time. It is the rate of a moving object. The scalar quantity, or speed, is the size of the velocity vector. There is no direction to speed. When an object moves more slowly, it is thought to be traveling at a lower speed; when it moves more quickly, it is thought to be traveling at a higher speed.
Explanation
The formula below mentions the traditional way to determine an object's constant velocity while it is traveling straight.
r = d / t
where r stands for rate or speed (sometimes denoted as v, for velocity)
The distance traveled is d.
The motion's execution time is measured in t.
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53-20 you normally drive on the freeway between san diego and irvine at an average speed of 105 km/h, and the trip takes 2 h and 20 min. on a friday afternoon, however, heavy traffic slows you down and you drive the same distance at an average speed of only 74.0 km/h .
Assuming that average speed are in kilo-metres per hour, the typical trip takes 2 hours and 20 minutes to complete.
Apply the following formula to this issue:
Total distance travelled minus total time taken equals average speed.
You must first determine the length of the trip travelled.
Total distance travelled minus total time taken equals average speed.
Therefore : d = average speed x time spent overall - rearranging
In other words, d = vt = 105 km/hr x 2.3333... hrs = 245 km
Find out how long the typical journey takes on Friday afternoon.
t = d/v - equation rearranged equals 245 km/67 km/h = 3.6567164.
18 hours equals 3 hours, 39 minutes (rounded to nearest whole minute)
You must now determine how much longer the Friday trip takes.
Duration: (3 hours and 39 minutes) - (2 hours and 20 minutes)
= 1 hour and 19 minutes
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a 11.8-m-long wire of mass 152 g is stretched under a tension of 266 n . a pulse is generated at one end, and 22.0 ms later a second pulse is generated at the opposite end.
First, with m = 0.123 kg, pressure force, T = 255N, and length = 10 m, Using the formula V = ?, we've haste of 144 m/s.
After 20 milli alternate = 0.02 s, the first palpitation would have run along the line for
This means that it only left 10m-2.88 m = 7.12 m for the 2 pulsesto run.
therefore, the distance which the 2 beats will first meet would be
from the position where the first pulse is transferred.
exactly the same as the answer at the reverse)
remaining distance is divided by 2 as the 2 pulse are moving with the same speed towards each other.
Mass
Mass is the volume of matter in a physical body. It's also a measure of the body's indolence, the resistance to acceleration( change of haste) when a net force is applied. An object's mass also determines the strength of its gravitational magnet to other bodies.
The SI base unit of mass is the kilogram( kg). In drugs, mass isn't the same as weight, indeed though mass is frequently determined by measuring the object's weight using a spring scale, rather than balance scale comparing it directly with known millions. An object on the Moon would weigh lower than it does on Earth because of the lower graveness, but it would still have the same mass. This is because weight is a force, while mass is the property that( along with graveness) determines the strength of this force.
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6. If a graph is showing a positive slope, and the graph itself is a straight line, what must be the x and y axis if the straight
line is showing a constant velocity?
Answer:
See below
Explanation:
x = time y = position (displacemet)
while running a marathon, a long-distance runner uses a stopwatch to time herself over a distance of 100 m. she finds that she runs this distance in 21 s. answer the following by considering ratios, without computing her velocity.
The time is defined as Delta X, or 1600 meters, because the speed is 5.55 meters per second. 288 seconds have now elapsed.
In this activity, we'll discuss uniform motion with constant speed. Keep in mind that the velocity is the same as the delta X. This is the distance divided by the time component, Delta T. And what we have is a runner who completes a 100-meter run in 18 seconds.
As a result, our objective is to assume that they want to maintain the same speed as she did in the first 100 meters and in question A. We must ascertain the runner's time requirement as well. We have traveled 400 meters. So let's figure out the speed first. The runner's speed v.
The attacks are comparable to this. The body is 100 m without a T, there are no taxes, and tea is served in 18 seconds. We therefore equal 72. I apologize. Yes, to reach a speed of 5.56 m/s.
That's not to imply that the T is prime. What we are trying to determine is what is equivalent to Delta X Prime divided by V. This distance, 400 meters, is calculated by dividing it by the assumed speed of 5.56 meters per second, which is the same as before. So, 72 seconds passed. Any inquiries? I have to wait to see how long the runner needs. True on, say, one mile away. Recall that 1600 meters make up one mile.
Since the speed is 5.55 meters per second, the time is defined as Delta X, or 1600 meters. So, 288 seconds have passed. You finish their exercise, I see.
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Answer:t = 1603/(100/21)
= 337.89 sec
Explanation:
t1 = 21 sec, x1=100m
speed= x/t1 = 100/21
x2= 300 m.
t2= x2/(x1/t)
=300/(100/21)
=63 sec
1 mile = 1603 m
t = 1603/(100/21)
= 337.89 sec
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Please help will give brainiest.
Answer:
Potential Energy.
Explanation:
Kinetic Energy is when an object is moving and it's the speed when it's released but Potential Energy is when the object is stand still/at rest, like the arrow, as the archer holds the arrow back.
Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
The meter stick is the center of mass of the three mass system is at 83cm.
What is center of mass?The center of mass is a location determined in respect to an object or group of things. It represents the average location of the system, weighted by the mass of each component.
Briefing:The center of mass of the three mass system is at 83cm
The mass of the meter stick is:
M = 0.5kg.
Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.
Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.
Now a mass m2 = 1kg is attached at 50cm mark.
So the distance of m2 from 0cm is x2 = 50cm = 0.5m.
Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.
Now the position of the three mass system from 0cm is given by,
[tex]$X_{C M}=\frac{M x_1+m_2 x_2+m_3 x_3}{M+m_2+m_3}$[/tex]
[tex]$X_{C M}=\frac{0.5 \times 0.5+1 \times 0.5+3 \times 1}{0.5+1+3}$[/tex]
[tex]$X_{C M}$[/tex] = 3.75/4.5 =0.83 = 83cm
So the center of mass of the three mass system is at 83cm.
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two iceboats, one of mass m and the other of mass 2m, are racing on a frictionless horizontal frozen pond. both iceboats start from rest at the starting line, and the wind applies the same constant force to both iceboats.
When both boats have the same kinetic energy and are traveling at the same speed, the iceboat reaches the finish line first.
Since the kinetic energy saved will be the same for both icebergs in this situation,
This: F *x
F is equal to force due to the wind.
where x is the same for the two icebergs as the distance to the goal. Consequently, even if the velocities may differ, the kinetic energy in the end will be the same.
The square speed of the heavier boat must be equal to the square speed of the lighter boat for the kinetic relation to hold true, and both boats will reach the finish line with the same kinetic energy.
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a carnot engine has an efficiency of 22.0%. it operates between constant-temperature reservoirs differing in temperature by 75.0 degrees celsius. what is the temperature of the (a) lower temperature and (b) higher temperature reservoir?
The temperature of the lower-temperature reservoir in the Carnot engine is 266 K, while the temperature of the higher-temperature reservoir is 341 K.
This is basically a two unknowns problem. If we mark the temperature of the higher-temperature reservoir as H (for hot) and the temperature of the lower-temperature reservoir as C (for cold), we know the following:
H - C = 75.0 °C = 75 K,
and the efficiency of Carnot engine is calculated in the following manner:
0.22 = 1 - C/H ⇒ C/H = 1 - 0.22 = 0.78 ⇒ C = 0.78H
Now we use that in the first equation:
H - 0.78H = 75.0 K = 0.22H ⇒ H = 75.0 K / 0.22 = 341 K
C = 0.78H = 0.78 * 341 K = 266 K
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Which part(s) of the electromagnetic spectrum are able to be seen by the human eye? question 2 options: radio waves microwaves infrared waves visible light ultraviolet rays x-rays gamma rays
Visible light is known as the fragment which is the part of electromagnetic spectrum that can be seen by humans.
The wavelength and frequency of light that is visible are 400nm to 700nm and 400THz to 800THz respectively. As we know, living beings are blind to a number of wavelengths of light, but it can be detected by specific instruments. But we can perceive easily that our world is aligned around this light.
For example, the sun is natural visible light. Everything around us that we’re able to see is a reflection of sunlight falling off the objects. Colour of any object that we’re able to see is actually just a reflection of light and other than that, all other colours get absorbed.
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DeWayne meets a potential employer at a restaurant, who gives him a phone number. Because he doesn't have anything to write with, he repeats the number several times to himself as a way of remembering the phone number. He is not very likely to remember this phone number later in the evening because of this strategy. True False
Based on the fact that he didn't write the number down, the statement "He is not very likely to remember this phone number later in the evening because of this strategy. " is True
This is further explained below.
What is DeWayne's strategy?Generally, While DeWayne's strategy is eating at a restaurant, he meets a potential employer who provides him with his phone number.
Because he does not have anything with which to write, he must recite the telephone number to himself many times in order to commit it to memory.
In conclusion, It is quite improbable that he will remember this phone number later on in the evening if you use this strategy.
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6.when trying to stop a car on icy pavement in as short a distance as possible, is it better to slam on the brakes and skid to a stop or apply the brakes more gently and roll to a stop? (hint: what type of friction is acting between your tires and the roadway if your tires are sliding along the road? what if your tires are rolling along the road?) briefly explain.
So there are two types of friction one is kinetic friction which acts when car skid on icy pavement and other is rolling friction which acts which helps tire to roll along the surface now as we know that coefficient of rolling friction μr is greater than coefficient of kinetic friction μk .
So due to which friction force will be more effective when tire rolls along the surface not skid so in order to stop car in minimum distance possible on icy pavement should apply brakes more gently.
Kinetic friction is defined as a force that acts between shifting surfaces. A body moving at the floor reviews a force in the opposite direction of its motion. The importance of the force will rely on the coefficient of kinetic friction among the two materials.
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a receiver in a football game is standing still, having just caught a pass. before he can move, a tackler, running at a velocity of 4.4 m/s, grabs him. the tackler holds onto the receiver, and the two move off together with a velocity of 3 m/s. the mass of the tackler is 120 kg. assuming that momentum is conserved, find the mass of the receiver.
115 kilos are given to us as m r, so m r equals m t. T is stated as 115 kilos when T is 4.5 meters per second divided by the combined velocity, which is 2.6 meters per second. This now weighs 84.04 kilos. As a result, the receiver's mass, m r, is determined to be 84 kilograms.
We are provided the tackler's mass, m, which is 120 kilos. A tackle moves at a speed of 4.4 meters per second. The combined velocity of the tackler and the receiver, designated as b r, is now given as 0 meters per second.
Let's say it's indicated as 3 m/sec since, based on the principle of momentum conservation, we know that the system's initial and end linear moments should be equal. The initial momentum is now m r v, r plus m t v, t equals m r plus m t, which is the combined mass into v, and this term now goes to zero since we are as zero, which is the initial velocity of the receiver. This phrase ends at 0. Now that t = m r + m t into v, we obtain m t v.
Now, if we rearrange this, we obtain m r = m t v, t by v, and m t less. Sorry, minus m t, so m r equals m t v, t by v minus m t, and now enter all the given values into v. For example, 115 kilos are given to us as m r, so m r equals m t. T is stated as 115 kilos when T is 4.5 meters per second divided by the combined velocity, which is 2.6 meters per second. This now weighs 84.04 kilos. As a result, the receiver's mass, m r, is determined to be 84 kilograms.
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