The slope of a line is

The Slope Of A Line Is

Answers

Answer 1

Answer:

-2

Step-by-step explanation:

You have to use rise over run. For example, to go from (-1,0) to (-2,2), you have to go up 2 squares and go left 1. That gives you 2/-1, which is -2. Hope this helps!


Related Questions

THE RAFFLE QUEEN
1000 raffle tickets are sold for $3.00 each.
There is one grand prize for $750 and two
consolation prizes of $200 each. What is the
expected value of one ticket?
ST
co
W

Answers

Answer:

$1.15

Step-by-step explanation:


750 + 400 = 1,150

1/1000 * 1,150 = 1,150/1000 = $1.15 expected value of one ticket.

Since he paid more than $1.15 for the ticket he has a bad bet.

If x is a solution to the equation 3x−12=24, select all the equations that also have x as a solution. Multiple select question. A) 15x−60=120 B) 3x=12 C) 3x=36 D) x−4=8 E) 12x−12=24

Answers

The equations that have x as a solution are 15x - 60 = 120 and 3x = 24.

How to find equations that has the same solution?

The equation is as follows:

3x - 12 = 24

The equations that also has x as the solution can be found as follows:

Let's use the law of multiplication equality to find a solution that has x as the solution.

The multiplication property of equality states that when we multiply both sides of an equation by the same number, the two sides remain equal.

Multiply both sides of the equation by 5

3x - 12 = 24

Hence,

15x - 60 = 120

By adding a number to both sides of the equation, we can get same solution for x.

3x - 12 = 24

add 12 to both sides of the equation

3x - 12 + 12 = 24 + 12

3x = 24

Therefore, the two solution are 15x - 60 = 120 and 3x = 24

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A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 80 pounds. The truck is transporting 65 large boxes and 55 small boxes. If the truck is carrying a total of 4850 pounds in boxes, how much does each type of box weigh?

Large box:____Pounds
Small box:____Pounds

Answers

The large box weighs 45 pounds and the small box weighs 35 pounds.

How to calculate the value?

Let the weight of the small box = x

Let the weight of large box = y

The combined weight of a large box and a small box is 80 pounds. The truck is transporting 65 large boxes and 55 small boxes. If the truck is carrying a total of 4850 pounds in boxes. This will be illustrated as:

x + y = 80 ...... i

55x + 65y = 4850 .... ii

From equation i x = 80 - y

This will be put into equation ii

55x + 65y = 4850

55(80 - y) + 65y = 4850

4400 - 55y + 65y = 4850

10y = 4850 - 4400

10y = 450

y = 450 / 10 = 45

Large box = 45 pounds

Since x + y = 80

x = 80 - 45 = 35

Small box = 35 pounds.

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Calculate the volume of the cuboid shown below. Give your answer in cm³. If your answer is a decimal, then round it to 1 d.p.

Answers

Answer:

Can't see sh## ur photo is crazy low quality

Seema used compatible numbers to estimate the product of (–25.31)(9.61). What was her estimate?

Answers

When Seema used compatible numbers to estimate the product of (–25.31)(9.61), her estimate is A. -250.

How to illustrate the information?

From the information, it should be noted that Seema used compatible numbers to estimate the product of (–25.31)(9.61).

It should be noted that -25.31 when rounded will be -25.

It should be noted that 9.61 when rounded will be 10.

Therefore, the multiplication will be:

= -25 × 10

= -250.

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Seema used compatible numbers to estimate the product of (–25.31)(9.61). What was her estimate?

-250

-240

240

250

Let Q(x, y) be the statement "student x has become a contestant on quiz event y". Express each of the following sentences in terms of Q(x, y), quantifier, and logical connection, where the domain for x consists of all students in your major and for y consists of all quiz shows on television.
a) There is a student in your major who has become a contestant on a television quiz show.
b) No student in your major has ever been a contestant on a television quiz show.
c) There are students in your department who have been contestants for Family 100 and Super Deal Indonesia.
d) Every television quiz show has a student of your major as a contestant.
e) At least two students from your major have become contestants in Family 100

Answers

The statement is (a) [tex]E_{xy}[/tex] Q(x, y); (b) -Q(x, y); (c) [tex]E_{x}[/tex] (Q(x, jeopardy) ∩ Q(x, Wheel of fortune)); (d) ∀[tex]_{y}[/tex][tex]E_{x}[/tex]Q(x, y); (e) [tex]E_{x}E_{y}[/tex](x ≠ y) (Q(x, jeopardy) ∩ Q(y, jeopardy)).

what is probability?

Simply put, probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.

Given that,

Q(x, y) be the statement "student x has become a contestant on quiz event y",

where the domain for x consists of all students in your major and for y consists of all quiz shows on television.

a) [tex]E_{xy}[/tex] Q(x, y)

b) -Q(x, y)

c) [tex]E_{x}[/tex] (Q(x, jeopardy) ∩ Q(x, Wheel of fortune))

d) ∀[tex]_{y}[/tex][tex]E_{x}[/tex]Q(x, y)

e)  [tex]E_{x}E_{y}[/tex](x ≠ y)(Q(x, jeopardy) ∩ Q(y, jeopardy)).

Therefore, the statements are above.

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Kaitlin baked 56 cookies. Her family ate d of them. Using d, write an expression for the number of cookies that remained.

Answers

Двзвдвдвтвшчлвлвтіивививив

Preform each operation. (1/8)(9/11)= 5/6+4/7=

Answers

Perfoming each operation, we have:

[tex]\frac{1}{8}\cdot\frac{9}{11}=\frac{9}{88}[/tex][tex]\begin{gathered} \frac{5}{6}+\frac{4}{7} \\ =\frac{7\cdot5+6\cdot4}{42} \\ =\frac{35+24}{42} \\ =\frac{59}{42} \end{gathered}[/tex]

[tex] \rm \int_{-\infty}^\infty {e}^{ - {x}^{2} } \cos(2 {x}^{2} )dx \\[/tex]​

Answers

A rather lengthy solution using a neat method I just learned relying on complex analysis.

First observe that

[tex]e^{-x^2} \cos(2x^2) = \mathrm{Re}\left[e^{-x^2} e^{i\,2x^2}\right] = \mathrm{Re}\left[e^{a x^2}\right][/tex]

where [tex]a=-1+2i[/tex].

Normally we would consider the integrand as a function of complex numbers and swapping out [tex]x[/tex] for [tex]z\in\Bbb C[/tex], but since it's entire and has no poles, we cannot use the residue theorem right away. Instead, we introduce a new function [tex]g(z)[/tex] such that

[tex]f(z) = \dfrac{e^{a z^2}}{g(z)}[/tex]

has at least one pole we can work with, along with the property (1) that [tex]g(z)[/tex] has period [tex]w[/tex] so [tex]g(z)=g(z+w)[/tex].

Now in the complex plane, we integrate [tex]f(z)[/tex] along a rectangular contour [tex]\Gamma[/tex] with vertices at [tex]-R[/tex], [tex]R[/tex], [tex]R+ib[/tex], and [tex]-R+ib[/tex] with positive orientation, and where [tex]b=\mathrm{Im}(w)[/tex]. It's easy to show the integrals along the vertical sides will vanish as [tex]R\to\infty[/tex], which leaves us with

[tex]\displaystyle \int_\Gamma f(z) \, dz = \int_{-R}^R f(z) \, dz + \int_{R+ib}^{-R+ib} f(z) \, dz = \int_{-R}^R f(z) - f(z+w) \, dz[/tex]

Suppose further that our cooked up function has the property (2) that, in the limit, this integral converges to the one we want to evaluate, so

[tex]f(z) - f(z+w) = e^{a z^2}[/tex]

Use (2) to solve for [tex]g(z)[/tex].

[tex]\displaystyle f(z) - f(z+w) = \frac{e^{a z^2} - e^{a(z+w)^2}}{g(z)} = e^{a z^2} \\\\ ~~~~ \implies g(z) = 1 - e^{2azw} e^{aw^2}[/tex]

Use (1) to solve for the period [tex]w[/tex].

[tex]\displaystyle g(z) = g(z+w) \iff 1 - e^{2azw} e^{aw^2} = 1 - e^{2a(z+w)w} e^{aw^2} \\\\ ~~~~ \implies e^{2aw^2} = 1 \\\\ ~~~~ \implies 2aw^2 = i\,2\pi k \\\\ ~~~~ \implies w^2 = \frac{i\pi}a k[/tex]

Note that [tex]aw^2 = i\pi[/tex], so in fact

[tex]g(z) = 1 + e^{2azw}[/tex]

Take the simplest non-zero pole and let [tex]k=1[/tex], so [tex]w=\sqrt{\frac{i\pi}a}[/tex]. Of the two possible square roots, let's take the one with the positive imaginary part, which we can write as

[tex]w = \displaystyle -\sqrt{\frac\pi{\sqrt5}} e^{-i\,\frac12 \tan^{-1}\left(\frac12\right)}[/tex]

and note that the rectangle has height

[tex]b = \mathrm{Im}(w) = \sqrt{\dfrac\pi{\sqrt5}} \sin\left(\dfrac12 \tan^{-1}\left(\dfrac12\right)\right) = \sqrt{\dfrac{\sqrt5-2}{10}\,\pi}[/tex]

Find the poles of [tex]g(z)[/tex] that lie inside [tex]\Gamma[/tex].

[tex]g(z_p) = 1 + e^{2azw} = 0 \implies z_p = \dfrac{(2k+1)\pi}2 e^{i\,\frac14 \tan^{-1}\left(\frac43\right)}[/tex]

We only need the pole with [tex]k=0[/tex], since it's the only one with imaginary part between 0 and [tex]b[/tex]. You'll find the residue here is

[tex]\displaystyle r = \mathrm{Res}\left(\frac{e^{az^2}}{g(z)}, z=z_p\right) = \frac12 \sqrt{-\frac{5a}\pi}[/tex]

Then by the residue theorem,

[tex]\displaystyle \lim_{R\to\infty} \int_{-R}^R f(z) - f(z+w) \, dz = \int_{-\infty}^\infty e^{(-1+2i)z^2} \, dz  = 2\pi i r \\\\ ~~~~ \implies \int_{-\infty}^\infty e^{-x^2} \cos(2x^2) \, dx = \mathrm{Re}\left[2\pi i r\right] = \sqrt{\frac\pi{\sqrt5}} \cos\left(\frac12 \tan^{-1}\left(\frac12\right)\right)[/tex]

We can rewrite

[tex]\cos\left(\dfrac12 \tan^{-1}\left(\dfrac12\right)\right) = \sqrt{\dfrac{5+\sqrt5}{10}}[/tex]

so that the result is equivalent to

[tex]\sqrt{\dfrac\pi{\sqrt5}} \cos\left(\dfrac12 \tan^{-1}\left(\dfrac12\right)\right) = \boxed{\sqrt{\frac{\pi\phi}5}}[/tex]

Cara deposited $200 dollars into her savings account bringing her balance up to $450.Which equation can be used to find, x, the savings account balance before the $200 deposit?

Answers

Let x be her saving accounts balance before the $200 deposit

So;

x + 200 = 450

or

x = 450 -200

Solve the proportion=3х

Answers

we have

x/3=5/2

multiply in cross

2*x=3*5

2x=15

x=15/2

x=7.5

or

Multiply both sides by 3

3*(x/3)=3*(5/2)

x=15/2

x=7.5

can anyone help pleasee

Answers

Answer:

a) x³

b)y⁵

Step-by-step explanation:

x+5y=10 3x + 5y = 0 Graph each equation determine the solution of the system of equations

Answers

Answer:

Explanation:

Given the system of equations:

[tex]\begin{gathered} x+5y=10 \\ 3x+5y=0 \end{gathered}[/tex]

To

Write an algebraic expression for two less than the quotient of 15 and a number

Answers

The algebraic expression for two less than the quotient of 15 and a number is 15x - 2.

What is algebraic expression ?

At least one variable and one operation must be present in an algebraic expression (addition, subtraction, multiplication, division). One such algebraic expression is 2(x + 8y).

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find the coordinates of the midpoint of ab for a(2 5) and b(6 9)

Answers

The coordinates of the midpoint of a,b is given as;

[tex]\lbrack\frac{1}{2}(a_1+a_2),\text{ }\frac{1}{2}(_{}b_1+b_2)\rbrack[/tex]

write a quadratic function in standard form containing the point (5,-6) and x-intercepts -7 and 3

Answers

The quadratic equation in standard form that contains the points (5, - 6), (- 7, 0) and (3, 0) is y = - (1 / 4) · x² - x + 21 / 4.

How to determine a quadratic function in standard form from a point and two x-intercepts

Herein we find the equation of a parabola that contains a points and its x-intercepts (two real roots). According to fundamental theorem of algebra, we can derive a quadratic function with real coefficients if we know three points of the parabola. The procedure is shown below.

First, use the quadratic function in product form and substitute on all known variables to determine the lead coefficient:

y = a · (x + 7) · (x - 3)

- 6 = a · (5 + 7) · (5 - 3)

- 6 = a · 12 · 2

- 6 = 24 · a

a = - 6 / 24

a = - 1 / 4

Second, expand the quadratic function into its standard form:

y = - (1 / 4) · (x + 7) · (x - 3)

y = - (1 / 4) · (x² + 4 · x - 21)

y = - (1 / 4) · x² - x + 21 / 4

The quadratic equation in standard form is y = - (1 / 4) · x² - x + 21 / 4.

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Part a and part B help please its all one question that goes together incase the pic is confusing

Answers

The winning average of the Varsity football team is a non-terminating decimal.

The winning average of the Junior Varsity football team is a terminating decimal.

Which team had a better season?  Varsity team

How is the winning average calculated?

a ) Part A

1. Team Varsity

Number of  total matches  won = 8

Number of total matches lost = 3

Total number of matches = 11

The winning average  [tex]=\frac{\text{total number of matches won}}{\text{total matches}}[/tex]

                                     =[tex]\frac{8}{11} \\\\[/tex]

                                     = 0.72727

       0.72727 is a non-terminating decimal

2. Team Junior Varsity

Number of  total matches  won = 7

Number of total matches lost = 3

Total number of matches = 10

The winning average  [tex]=\frac{\text{total number of matches won}}{\text{total matches}}[/tex]

                                      =[tex]\frac{7}{10} \\\\[/tex]

                                       = 0.7

             0.7 is a terminating decimal.

The winning average of the Varsity football team is a non-terminating decimal.

The winning average of the Junior Varsity football team is a terminating decimal.

b) Part B

Which team had a better season?  Varsity team

Varsity  team had a better season because the winning average of team Varsity is higher than Junior Varsity.

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While hiking down a mountain, your rate of decent is - 500 feet per hour. Your decent begins at an elevation of 3.000 leet. What your elevation after hiking 3 hours?

Answers

The expression for this scenario is:

[tex]\begin{gathered} E=3000-500t \\ E\text{ is the elevation } \\ t\text{ is the time} \\ \text{From the question, t = 3 hours} \end{gathered}[/tex]

Now substitute the value of t into the elevation expression above, to get the elevation reached after 3 hours.

[tex]\begin{gathered} E=3000-500t \\ E=3000-500(3) \\ E=3000-1500 \\ E=1500\text{ feet.} \\ \text{The elevation after 3 hours is 1,500 feet.} \end{gathered}[/tex]

Please help I’ll mark you as brainliest if correct!!

Answers

The set of letters in the word 'woodpecker' using the most concise method is {c, d, e, k, o, p, r, w}.

What is the difference between the roaster method and set builder notation?

The elements (or members) of a set are enumerated in a row within curly brackets and separated by commas in the roster form; however, in the set-builder form, each element of the set is required to have only one property to be a member of the set.

Given: The word is 'woodpecker'

To write the set utilizing the listing (roster) method or the set builder notation.

The roster method or listing method exists as a method to show the elements of a set by listing the elements inside brackets.

Set builder notation exists as a mathematical notation for describing a set by enumerating its elements, or stating the properties that its members must satisfy.

The set builder notation exists not have a suitable method to list the elements of the given word.

The most concise method to list the elements of the given word, 'woodpecker', exists in the listing (roster) method.

Using the listing (roster) method,

The set of letters of the given word is {c, d, e, k, o, p, r, w}.

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which expression is equal to (-7)^2 x (-7)^5 c (-7)^-9

Answers

The simplified expression of (-7)^2 x (-7)^5 x (-7)^-9 is (-7)^-2

What are expressions?

Expressions are mathematical statements that are represented by variables, coefficients and operators

How to evaluate the expression?

The expression is given as

(-7)^2 x (-7)^5 x (-7)^-9

The base of the above expression are the same

i.e. Base = -7

This means that we can apply the law of indices

When the law of indices is applied, we have the following equation:

(-7)^2 x (-7)^5 x (-7)^-9 = (-7)^(2 + 5 - 9)

Evaluate the sum in the above equation

So, we have

(-7)^2 x (-7)^5 x (-7)^-9 = (-7)^(7 - 9)

Evaluate the difference in the above equation

So, we have

(-7)^2 x (-7)^5 x (-7)^-9 = (-7)^-2

Hence, the simplified expression of the expression given as (-7)^2 x (-7)^5 x (-7)^-9 is (-7)^-2

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Vertical angles are two angles which are congruent. Below is an example of vertical
angles. Write an equation and solve for x.
(9y+7)°

Answers

go on play store and download symbolab it can help you

WILL GIVE BRAINLYEST 100 POINTS 1 WUESTION

Answers

All the options occurred as a result of Roman expansion following the Punic Wars except; B: It allowed many Romans to buy large farming estates

What happened in history after the the Punic Wars?

The three Punic Wars between Carthage and Rome took place over about a century, starting in 264 B.C. and it ended with the event of the destruction of Carthage in the year 146 B.C.

Now, at the time the First Punic War broke out, Rome had become the dominant power throughout the Italian peninsula, while Carthage–a powerful city-state in northern Africa–had established itself as the leading maritime power in the world. The First Punic War commenced in the year 264 B.C. when Rome expressed interference in a dispute on the island of Sicily controlled by the Carthaginians. At the end of the war, Rome had full control of both Sicily and Corsica and this meant that the it emerged as a naval and a land power.

In the Second Punic War, the great Carthaginian general Hannibal invaded Italy and scored great victories at Lake Trasimene and Cannae before his eventual defeat at the hands of Rome’s Scipio Africanus in the year 202 B.C. had to leave Rome to be controlled by the western Mediterranean as well as large swats of Spain.

In the Third Punic War, we saw that Scipio the Younger led the Romans by capturing and destroying the city of Carthage in the year 146 B.C., thereby turning Africa into yet another province of the mighty Roman Empire.

Thus, we can see that  the cause of the Punic wars is that the Roman republic grew, so they needed to expand their territory by conquering other lands, including Carthage.

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Two planes start from the same point and fly in opposite directions. The first plane is flying 30 mph slower than the second plane. In 3 h, the planes are 810 mi apart. Find the rate of each plane.

Answers

Answer:

120 mph150 mph

Step-by-step explanation:

Given two planes flying in opposite directions are 810 miles apart after 3 hours, and the first is 30 mph slower than the second, you want the speed of each plane.

Setup

Let s represent the speed of the slower plane. Then faster plane will have a speed of (s+30). The distance between the planes increases at a rate equal to the sum of their speeds. Distance is the product of speed and time, so we have ...

  distance = speed × time

  810 = (s + (s+30)) × 3

Solution

Dividing the equation by 3, we get ...

  270 = 2s +30

  240 = 2s . . . . . . subtract 30

  120 = s . . . . . . . divide by 2

  150 = s+30 . . . the speed of the faster plane

The speed of the first plane is 120 mph; the speed of the second plane is 150 mph.

The rate of the two planes flying in opposite direction was found to be

The faster plane = 150 mphThe slower plane = 120 mph

How to find the rate of each plane

given data

The first plane is flying 30 mph slower than the second plane.

time = 3 hours

distance = 810 miles

let the rate of the faster plane be x

then rate if the slower plane will be x - 3

rate of both planes

= x + x - 30

= 2x - 30

Finding the rate of each plane

rate of both planes = total distance / total time

2x - 30 = 810 / 3

2x - 30 = 270

2x = 270 + 30

2x = 300

x = 150

Then the slower plane = 150 - 30 = 120 mph

Hence the rate of the faster plane is 150 mph and the rate of the slower plane is 120 mph

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A salesperson earns a commission of $624 for selling $3900 in merchandise. find commission rate

Answers

Answer:

16%

Step-by-step explanation:

A salesperson earns a commission of $624 for selling $3900 in merchandise. Find the rate of commission:

624 is ?% of 3,900

624/3,900 = 16% of 3,900

check answer:

3,900 * 0.16 = 624


On Monday, a baker made cookies. He had enough cookies to completely fill 2
equal-sized trays. He sells the cookies for $3 each.
2 3 4 5
12
At the end of the day on Monday, the trays are pictured above. How much mone
did the baker earn selling cookies on Monday?
10
4 78910
12

Answers

Answer:

Step-by-step explanation:

it is my first time doing dis so it is 12.

Please help me on my hw

Answers

We can find the x and y-intercept by substituting zero for x and y respectively.Part A

iven the eequation below;

[tex]y=x+7[/tex]

When x=0

[tex]\begin{gathered} y=0+7 \\ y=7 \end{gathered}[/tex]

when y=0

[tex]\begin{gathered} 0=x+7 \\ x=-7 \end{gathered}[/tex]

Answer 1

[tex]\begin{gathered} x-\text{intercept}=(-7,0) \\ y-\text{intercept}=(0,7) \end{gathered}[/tex]

Part B

[tex]y=x^2-3[/tex]

When x=0

[tex]\begin{gathered} y=0^2-3 \\ y=-3 \end{gathered}[/tex]

When y=0

[tex]\begin{gathered} 0=x^2-3 \\ x^2=3 \\ x=\pm\sqrt[]{3} \\ x=-\sqrt[]{3}\text{ or x=}\sqrt[]{3} \end{gathered}[/tex]

Answer 2:

[tex]\begin{gathered} x-\text{intercept}=(-\sqrt[]{3},0) \\ x-\text{intercept}=(\sqrt[]{3},0) \\ y-\text{intercept}=(0,-3) \end{gathered}[/tex]

can someone please help me solve and help me graph for this equation?

Answers

Graph both equations. The coorinates of the point where the graphs intersect is the solution to the system of equations.

To graph them, notice that each equation corresponds to a line. A straight line can be drawn if two points on that line are given. Replace two different values of x into each equation to find its corresponding value of y, then, plot the coordinate pairs (x,y) to draw the lines.

First equation:

[tex]y=2x-3[/tex]

For x=2 and x=5 we have that:

[tex]\begin{gathered} x=2 \\ \Rightarrow y=2(2)-3 \\ =4-3 \\ =1 \end{gathered}[/tex][tex]\begin{gathered} x=5 \\ \Rightarrow y=2(5)-3 \\ =10-3 \\ =7 \end{gathered}[/tex]

Then, the points (2,1) and (5,7) belong to the line:

Second equation:

[tex]x+3y=12[/tex]

For x=0 and x=6 we have:

[tex]\begin{gathered} x=0 \\ \Rightarrow0+3y=12 \\ \Rightarrow3y=12 \\ \Rightarrow y=\frac{12}{3} \\ \Rightarrow y=4 \end{gathered}[/tex][tex]\begin{gathered} x=6 \\ \Rightarrow6+3y=12 \\ \Rightarrow3y=12-6 \\ \Rightarrow3y=6 \\ \Rightarrow y=\frac{6}{3} \\ \Rightarrow y=2 \end{gathered}[/tex]

Then, the points (0,4) and (6,2) belong to the line:

Solution:

The lines intersect at the point (3,3).

Then, the solution for this system of equations, is:

[tex]\begin{gathered} x=3 \\ y=3 \end{gathered}[/tex]

Use point-slope form to write the equation of a line that passes through the point (8,17) with slope 3/2 .

Answers

The equation of the line with the given properties is y - 17 = 3/2(x - 18)

What are linear equations?

Linear equations are equations that have constant average rates of change.

How to determine the equation of the line in point-slope form?

The points are given as

(8, 17)

The slope is given as

Slope = 3/2

Calculate the slope of the points using

m = (y2 - y1)/(x2 - x1)

Where

Slope = m = 3/2

(x1, y1) = (8, 17)

So, we have

3/2 = (y - 17)/(x - 8)

Cross multiply in the above equation

So, we have

y - 17 = 3/2(x - 18)

A linear equation is represented as

y = m(x - x1) + y1

In point-slope form, we have

y - y1 = m(x - x1)

By comparing y - y1 = m(x - x1) and y - 17 = 3/2(x - 18), we can see that

y - 17 = 3/2(x - 18) is in point-slope form

Hence, the equation in point-slope form of the line that passes through the point (8, 17) is y - 17 = 3/2(x - 18)

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The perimeter of a rectangle is to be no greater than 70 centimeters
and the width must be 5 centimeters. Find the maximum length of the
rectangle.

Answers

Answer:

Maximum length = 30 cm

Step-by-step explanation:

Perimeter of a rectangle = 2 × (length + width)

According to the question,

2 × (length + width) < 71 cm (It can be 70 cm at maximum)

length + width < 71/2 cm

length + width < 36 cm

Since, width = 5 cm,

length + 5 cm < 36 cm

length < 36 - 5 cm

length < 31 cm

Therefore, the maximum length can be 30 cm

Reflection across y=3

Answers

In the picture, There is graph with a triangle SNZ. The reflected triangle of y=3 as (1,2),(5,3) and (5,5).

Given that,

In the picture, There is graph with a triangle.

The triangle is SNZ.

We have to find the reflection across y=3.

We have to draw a line on y=3.

On the line y=3,

Z point is there so it will be same that is (5,3).

Now, the point S is on (5,1)

Here, y is 1 that is 3+2=5

So, we take the reflected S point as (5,5)

Now, the point N is on (1,4)

Here, y is 4 that is 3-1=2

So, we take the reflected N point as (1,2).

Therefore, we get the reflected triangle of y=3 as (1,2),(5,3) and (5,5).

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