the statement from which investigation is an example of repetition? *answer choices in picture*

Answer:

A

Explanation:

2800 sq m of cross-sectional area raised 6 m,  mass therefore 2800 x 7.5 = 21,000

Numerous structural computation techniques make use of the cross-sectional area. Navier's formula is arguably the one that uses the cross-sectional area the most frequently.

We only need to compute the volume because we already know the ship's horizontal cross-sectional area, which is 2800 m2, and we will learn that this figure remains constant for the entire 9.5 of the ship's height from the waterline to the new waterline after unloading: V is for volume, A is for area, and H is for height. V= 2,800 * 7.5 = 21000 m3 Therefore, the volume of freshwater delivered in this year was 21,000 cubic metres mass.

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When a large truck and a small car have a head-on collision, B: "the car has the greater acceleration because it has the smaller mass".

Acceleration refers to the rate of change of velocity, reflecting that acceleration means the speed is changing. Based on the scenario when a large truck and a small car have a head-on collision, the car will exert a higger acceleration in comparison to the acceleration of the truck because the car has smaller mass.

It is because the acceleration is far greater for the lighter or smaller vehicles which would be subjected to a far greater velocity/speed change at the same time (duration of collision).

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Option B.   feelings of i A child's worry caused by a stranger is known as "stranger anxiety."

Answer. Strangers or strange environments are frequently what cause stranger anxiety. Therefore, given that the setting is familiar and there is no perceived threat from outsiders, it is less likely to emerge in a multiple-choice context.

When a stranger approaches, sobbing is a sign of stranger anxiety. It is typical when it begins at around 8 to 9 months of age and typically goes away by age 2. The infant's developmental process of separating the familiar from the unknown is linked to stranger dread. A infant has separation anxiety when they are separated from the person who loves them the most, usually their mother. When: Stranger anxiety

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Answer:  B

Explanation:

A 0.28 kg stone you throw rises 34.3 m in the air. The impulse our hand receives from the stone while it throws the stone is 7.3 N.s

What is Impulse?

Impulse can be defined as the sudden force acting on an object for a short interval of time. Conventionally represented by “J”. Sometimes by “imp” and expressed in “N.s”.

Impulse = change in momentum

the stone rises to a height of 34.3m

final velocity of the stone is 0m/s

so applying equation of motion:

V2 - U2 = 2gS ( where S is the height, g is value of gravity )

0 - U2 = 2(-9.8)×34.3

U2 = 672.3

U = √672.3

= 26m/s

so initial velocity is 26m/s.

Impulse = change in momentum

Impulse = mv - mu

= 0 - (0.28× 26)

= - 7.3 N.s

So the impulse our hand receives from the stone while it thrown the stone is 7.3 N.s

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Young readers are the target audience for some of the best realistic fiction publications. Consider the novels The Outsiders by S.E. Hinton, The Hate U Give by Angie Thomas, or Wonder by R.J. Palacio.

As Auggie makes friends, copes with bullying, and demonstrates to the school what a wonder he truly is, the novel follows him through his fifth-grade year. It exemplifies how kids adapt, in the words of my friend who teaches elementary school.

Contemporary/Realistic: Fiction that is realistic depicts our world and society through the use of fictional characters and settings. Growing up and facing personal and societal issues are the main themes. Characters in this genre are shown learning to understand one another and themselves.

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Expressive aphasia is also known as broca aphasia. Broca's aphasia patients have difficulty speaking, although they are able to understand language.

They can organise their thoughts and decide what to say. they are unable to construct sentences. You speak incomprehensibly to other people when you have Wernicke's aphasia. Reading comprehension was consistently weaker in three patients with Wernicke's aphasia than it was in the other two. The paraphasia of speech, repetition, and naming highlight the aphasic aspect of the condition even if this syndrome mimics alexia with agraphia. Furthermore, prior... Wernicke's aphasia can be treated, however some patients completely recover on their own. Even after serious loss, linguistic capacity often returns in children under the age of eight. Speech therapy is typically necessary. Recovery often occurs in three

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Explanation:

To calculate the radius of curvature of a concave makeup mirror that produces an upright image at a distance of 50 cm behind the mirror when an object is placed 25 cm in front of it, you can use the formula:

R = 2f

where R is the radius of curvature and f is the focal length of the mirror.

To find the focal length of the mirror, you can use the formula:

1/di + 1/do = 1/f

where di is the distance of the image from the mirror, do is the distance of the object from the mirror, and f is the focal length of the mirror.

In this case, do is equal to 25 cm, and di is equal to 50 cm. Plugging these values into the formula gives:

1/50 cm + 1/25 cm = 1/f

Solving for f gives:

f = (50 cm * 25 cm) / (25 cm - 50 cm) = -25 cm

Since the focal length is negative, this indicates that the mirror is concave.

Plugging the value for f into the formula for the radius of curvature gives:

R = 2 * (-25 cm) = -50 cm

This means that the radius of curvature of the mirror is 50 cm.

To calculate the magnification of the image, you can use the formula:

m = -di/do

Plugging in the values for di and do gives:

m = (-50 cm)/(25 cm) = -2

This means that the magnification of the image is -2.

Since the magnification is negative, the image is virtual and is located on the same side of the mirror as the object. Additionally, since the magnification is less than 1, the image is inverted relative to the object.

The product of 1.24 and 107 kilograms expressed in standard form is 1.3268 x 10² kg.

A standard form is a form of writing equations, numbers, or expressions using a certain set of rules.

Standard form is a method often used by scientists to express large number into a more condensed form, usually in power of ten.

The product of 1.24 and 107 kilograms expressed in standard form is calculated as;

1.24 x 107 kg = 132.68 kg

in standard form = 1.3268 x 10² kg

Thus, numbers expressed in standard forms makes it very easy to represent and recall the number.

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A decimal point is a point or a dot that is used to distinguish between a whole number and its fractional component.

It also goes by the name Decimal Mark. The decimal point's symbol is (.). Decimals are also used frequently in everyday life. The symbol of decimal point is (.).

The place value of a decimal number is recognised according to the position of the dot or decimal point. The first digit to the right of the decimal point indicates the number of tenths and the second digit to the right indicates the number of hundreths. For example, 0.8 can be written as 8/10 as a fraction.

Note that an overview was given as the information is incomplete.

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1. Zygote 2.  2ry oocyte (egg)  3. Morula 4. 4-cell stage 5. Blastocyst  6. Blastomeres 7. Inner cell mass - terms with the correct numbers.

The process by which a parent cell divides into two daughter cells is known as cell division. Cell growth and chromosome replication precede cell division, which often happens as part of a longer cell cycle.

Meiosis is a type of cell division that produces haploid gametes for sexual reproduction by reducing the number of chromosomes from two of each type in the diploid parent cell to one of each type in the daughter cells. Mitosis is a type of cell division that produces daughter cells that are genetically identical to the parent cell.

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Explanation:

1. 19.6m/s

2. 274.4 m/s²

3. 28

After being fired vertically upward into the block at a speed of 403.4 m/s, a 10 g bullet stops inside the block and the block starts to oscillate, with its highest point rising 45 cm above the beginning level.

Mu+0=(m+M)V

V=mu/m+M= velocity of system after collision

1/2(m+M)V² = 1/2kx²

(m+M)*m²u²/(m+M)² = kx²

u²=(2+10^-2)*40*0.45^2

u=√16.28 *10²

u=403.4  m/s

Speed is the rate of movement along a path, whereas velocity is the speed and direction of an object's motion. In other words, speed is a scalar value, but velocity is a vector. Velocity has magnitude and direction because it is a vector quantity. The distance (d) traveled over the change in time is the definition of speed (t).

Speed is a unit of measurement for how swiftly a body moves. The rate at which an object's location changes in any direction is referred to as speed. The distance traveled divided by the trip time is how speed is calculated.

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The system's steady-state response is 0.05 m for F(t) = 200 cos(10t) N. The steady-state response of the system is 0.10 m for F(t) = 200 cos(20t) N.

Part A's excitation frequency is 10 rad/s, while the system response frequency is 20 rad/s. According to the frequency response function, the steady-state response has a magnitude of 0.25 m.

Therefore, the steady-state response is 0.25 m cos (10t + 0.8 radians), where 0.8 radians is the phase angle of the system response.

Both the system response frequency and the excitation frequency for part b are 20 rad/s. According to the frequency response function, the steady-state response has a magnitude of 0.5 m.

The question is incomplete I answered it in general way.

Given ωn= 20 rad/s and δst = 0.05 m, the frequency response function of the vibration system is given. If the excitation function is a. F(t) = 200 cos(10t) N, b. F(t) = 200 cos(20t) N, Using the figures above to obtain the steady-state responses of the system.

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Type I error, for a particular test is reduced. There will be an increase in Type II error. Regarding Type I and Type II errors of a significance test, the following statements are accurate:

P(Type II mistake) = P - 1 (Type I error). This is untrue; the likelihood of making a Type II error is and is related to the test's power by P = 1 -. The significance level (the parameter) defines the likelihood of making a Type I error.

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Answer:

mass 3.67 kg, density 600 kg/m3) is fitted

with lead (density 1.14 * 10^4 kg/m3) so that it floats in water with

0.900 of its volume submerged. Find the lead mass if the lead is fitted

to the block’s (a) top and (b) bottom.

The landing velocity of a pole vaulter who cleared a height of 6.00 m is 10.8m/s.

To determine the landing velocity of a pole vaulter, you will need to know the initial velocity of the vaulter at the time of takeoff and the height of the pole vault. Using these two pieces of information, you can use the equation for kinetic energy to determine the landing velocity.

The equation for kinetic energy is:

KE = (1/2) * m * v^2

where KE is the kinetic energy, m is the mass of the object, and v is the velocity.

In this case, you can use the given height of 6.00 m and the kinetic energy equation to solve for the vaulter's landing velocity. Since the vaulter starts from rest at the ground, their initial velocity is zero. The mass of the vaulter can be assumed to be constant, so it can be treated as a constant in the equation.

Plugging in the values, you get:

KE = (1/2) * m * v^2

(1/2) * m * v^2 = m * g * h

where g is the acceleration due to gravity (9.8 m/s^2) and h is the height of the pole vault.

Solving for v, you get:

v = sqrt(2 * g * h)

Plugging in the values, you get:

v = sqrt(2 * 9.8 m/s^2 * 6.00 m)

v = sqrt(118.8)

v = 10.8 m/s

So, the landing velocity of the pole vaulter who cleared a height of 6.00 m is 10.8 m/s.

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Emissions from the biological decomposition of the waste during waste water treatment. Due to the fact that the organization does not run or regulate these emissions, they are categorized as Scope 3: Category 5 Waste Generated in Operations.

Nearly 290 million metric tonnes of CO2 are produced annually in the US by the energy required to transfer, purify, and consume water for both residential and commercial purposes, which is equal to 5% of the country's overall carbon emissions.

Although they occur from sources that the corporation does not own or control, scope emissions are a byproduct of company activity. Scope 3 activities include, for instance, the extraction and manufacturing of bought materials.

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The resultant reaction P (Newton) acting on the body is determined as 14.7 N.

Limiting equilibrium means that an object is just on the threshold of motion. In other words, a slight application of force will result in the motion of the body.

The resultant reaction P (Newton) acting on the body is calculated by applying Newton's second law of motion as follows;

∑F = ma

where;

F - Ff = ma

where;

If the body is in equilibrium, the acceleration of the body is zero.

F - Ff = m(0)

F - Ff = 0

F = Ff

F = Ff = 14.7 N

Thus, the resultant reaction acting on the body is a function of the applied force and the direction of the force as shown in the above calculation.

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For the auto now no longer to strike the deer, the minimal deceleration ought to be eight m / (s ^ 2) with a blended immediately drivers response took at the distance of 15 metres.

The given parameters are;

The distance farfar from the deer the auto turned into while the motive force notices the deer = 25 m

The velocity of the auto = 20m / s

Therefore, for the auto now no longer to strike the deer, the minimal deceleration of the auto ought to be from 20 ^ 2 / (2 * 25) = eight m/s² for a direct motive force response time

For a motive force response time of 0.five seconds, we have

Distance moved with the aid of using car = 0.five * 20 = 10 metersDistance moved with the aid of using car = 0.five * 20 = 10 meters

Minimum deceleration of the auto required = 20 ^ 2 / (2 * 15) =13. overline three m/s^ 2

Distance of the auto from the deer on the begin of deceleration = 25 - 10 = 15 meters.

Therefore, climate the deer is struck with the aid of using the auto relies upon at the drivers response time and deceleration of the auto.

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The force of sliding is the force required to keep an object moving at a constant velocity while it is sliding on a surface.

When an object is sliding on a surface, it experiences a force of friction that acts opposite to its direction of motion. This force of friction is what keeps the object moving at a constant velocity, rather than accelerating or decelerating.

The magnitude of the force of friction depends on the properties of the two surfaces in contact, such as their roughness and the type of material they are made of, as well as the normal force, which is the force exerted perpendicular to the surface. If the object is moving at a constant velocity, the force of friction is equal in magnitude to the force applied to the object, but opposite in direction.

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Answer:

The acceleration of the student-bicycle system is 3.52 m/s^2 toward the center of the circle.

Explanation:

The formula to calculate cutoff frequency and wavelength is hfc = Φ, λc = c/fc respectively.

The cutoff wavelength is the lowest wavelength at which light may dislodge electrons from a metal plate.

The cut-off wavelength, also known as the threshold wavelength, is the smallest wavelength of light that will not cause electrons to be emitted from a metal surface. The wavelength of the light must be less than the threshold wavelength if no electrons are expelled.

Where the signal is cut off is determined by the cutoff frequency. Lowpass filters are all that simpler synthesizers have. If the cutoff frequency is set at 2500 Hz and the signal comprises frequencies between 20 and 4000 Hz, frequencies over that frequency are filtered.

The formula to calculate cutoff frequency is hfc = Φ

where h = plank's constant

f = frequency

c = speed of the light

The formula to calculate cutoff wavelength is λ = c/f

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The force of gravity becomes greater than the force from internal pressure and the star begins to collapse.

What is star life cycle?

The gravity of a star holds a sphere of gas together. Our own Sun is the star that is nearest to Earth. A star's existence involves a perpetual fight with gravity. The star is continually being pushed toward collapse by gravity. However, the star's core is extremely hot, which exerts pressure on the gas. The star enters a state of equilibrium known as hydrostatic pressure when this pressure balances out the gravitational pull. As long as a star maintains this balance between pressure pushing it forth and gravity drawing it in, it will function normally. The majority of a star's lifespan is characterized by nuclear processes in the star's core, which provide the internal heat and radiation. The main sequence refers to this period of the star's existence.

A star is shrinking before it enters the main sequence, and its core isn't hot or dense enough to start nuclear reactions yet. Thus, the heat produced by the contraction serves as hydrostatic support until it reaches the main sequence.

Hence,  The force of gravity becomes greater than the force from internal pressure and the star begins to collapse.

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(a) The instantaneous velocity at 0 s is 10 m/s and at 3 s is -44 m/s.

(b) At time t = 1.29 s, the instantaneous velocity is zero.

Given that,

x = 34 + 10 t - 2 t³

v = dx/dt = 10 - 6 t²

v = 10 - 6 t² ----(1)

(a) Replacing t = 0 in (1)

v = 10 m/s

If t = 3 s, then

v = 10 - 6 (3)² = 10 - 54 = - 44 m/s

(b) Let us determine time from (1)

If v = 0, then

10 - 6 t² = 0

6 t² = 10

t² = 1.67

t = 1.29 s

The question is incomplete. The complete question is '(a) Find the instantaneous velocity of the object at 0 s, and at 3.0 s. (b) At what time between 0 and 3.0 s is the instantaneous velocity zero?'

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Answer:

Avg speed = 60 miles per hour

Explanation:

We generally know that,

→ Speed = Distance ÷ Time

Formula we use,

→ s = d/t

Now the average speed will be,

→ s = d/t

→ s = 180/3

→ [ s = 60 ]

Hence, average speed is 60.

Answer:

2.5 kg

Explanation:

Kinetic Energy = 1/2 m * v^2

2 * KE  / v^2 = m         2 * 2000 / ( 40^2) = 2.5 kg

For a distance of 5.0 meters, an object moving at an initial speed of 4.0 meters per second accelerates uniformly at 2.0 meters per second2. What is the object's final speed? Vi=4m/s

The object's final speed after uniformly accelerating in the direction of its motion is 6 m/s.

We apply the third equation of motion to calculate the object's final speed. Where u is the starting velocity, an is the acceleration, and s is the distance traveled, v is the end speed or velocity, a.

20 m/s is the final velocity.

Initial speed is equal to 16 m/s.

Equation 1 can be solved for by substituting these numbers above.

20² = 16²+2×a×36\s36a = 400-256

36a = 144\sa = 144/36\sa = 4

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