The stem-and-leaf plot shows the weights (in pounds) of yellowfin tuna caught during a fishing contest.

Step-by-step explanation:

question 1

[tex]6 {x}^{4} - 36 {x}^{3} \\ 6 {x}^{3} (x - 6)[/tex]

question 2

[tex]64 {x}^{2} + 48x + 9 \\ {(8x + 3)}^{2} [/tex]

Answer:

I would say it's d (sorry if im wrong)

Answer:

946589196.155

Step-by-step explanation:

Hope that helps

Answer:

y=−25x+300

Step-by-step explanation:

have a good day/night

may i please have a branlliest

Answer:

x = 0.6

Step-by-step explanation:

We use tangent because the given numbers are opposite and adjacent from x

So, tangent (x) = opposite/adjacent

tan(x) = 8.78/12

[tex]tan^{-1}(\frac{8.78}{12}) = x[/tex]

x = 0.631664

Round to nearest tenth:

x ~ 0.6

0.59 h + 0.98 b = 1041.37 - 79.37

h + b = 1300

Answer: 95%

Step-by-step explanation:

Answer:

37.69911184

Step-by-step explanation:

because circumference is equal to pi multiplied by diameter, you will not get the circumference with the radius times pi. in order to get the diameter, you multiply the radius by 2, because the diameter is the length across the circle. So the diameter of this circle is equal to 12. so simply multiply that number by pi (3.14) and there is your answer. Hope i helped.

Answer:

A{-4,-2,1,4} is the domain of function.

Answer:

5M

Step-by-step explanation:

Answer:

See the attached

Step-by-step explanation:

I left last bits to you as it is about checking your understanding

Answer:

hope this will help you more

good luck...

Answer:

[tex] \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2} [/tex]

Answer C is correct

Step-by-step explanation:

[tex] \sqrt[3]{ \frac{ {x}^{2} }{8 {y}^{ - 1} } } \\ \frac{ {x}^{2 \times \frac{1}{3} } \times {y}^{1 \times \frac{1}{3} } }{ \sqrt[3]{8} } \\ = \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2} [/tex]

Answer:

x=-6, y=1

Step-by-step explanation:

Let's solve your system by substitution.

y=x+7;−2x−11=y

Step: Solve y=x+7 for y:

y=x+7

Step: Substitute x+7 for y in −2x−11=y:

−2x−11=y

−2x−11=x+7

−2x−11+−x=x+7+−x(Add -x to both sides)

−3x−11=7

−3x−11+11=7+11(Add 11 to both sides)

−3x=18

−3x/ −3 = 18/ −3  (Divide both sides by -3)

x=−6

Step: Substitute−6 for x in y=x+7:

y=x+7

y=−6+7

y=1  (Simplify both sides of the equation)

Answer:

x=−6 and y=1

Answer:

Solution given:

cotangent x=cot x=-1

now

x=cot -¹(-1)

x=180-45°

x=135°

So

ans is d. 135 degrees.

as cot is negative in 2nd quadrant.

Answer:

39

Step-by-step explanation:

Answer:

- 10 degrees Fahrenheit at 9:00 PM

Step-by-step explanation:

35 - 45 = -10

Answer:

I belive the answer for the first box is 9.67

I belive the answer for the second box is 71.

I hope I helped

Answer:log a - log b = log (a/b) than use this formula will get

log x^2 -log x = log (x^2 /x) = log x

so answer is log x

Step-by-step explanation:

Answer:

Vector (ordered pair - rectangular form)

[tex]\vec F = (27.189,12.679)\,[lbf][/tex]

Vector (ordered pair - polar form)

[tex]\vec F = (30\,lbf, 25^{\circ})[/tex]

Sum of vectorial components (linear combination)

[tex]\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N][/tex]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ([tex]\vec F[/tex]), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

[tex]\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)[/tex] (1)

Vector (ordered pair - polar form)

[tex]\vec F = \left(\|\vec F\|, \theta\right)[/tex]

Sum of vectorial components (linear combination)

[tex]\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}[/tex] (2)

Where:

[tex]\|\vec F\|[/tex] - Norm of the vector force, in newtons.

[tex]\theta[/tex] - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

[tex]\hat{i}[/tex], [tex]\hat{j}[/tex] - Orthogonal axes, no unit.

If we know that [tex]\|\vec F\| = 30\,lbf[/tex] and [tex]\theta = 25^{\circ}[/tex], then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

[tex]\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf][/tex]

[tex]\vec F = (27.189,12.679)\,[lbf][/tex]

Vector (ordered pair - polar form)

[tex]\vec F = (30\,lbf, 25^{\circ})[/tex]

Sum of vectorial components (linear combination)

[tex]\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N][/tex]

[tex]\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N][/tex]

Answer:

BOGO ko sa math

Step-by-step explanation:

hahaha sorryyyyy

Answer:

120 and 144

120÷24=5

144÷24=6

Answer:

x-intercept

Step-by-step explanation:

Answer:

[tex]x = \frac{50 + 92}{2} = 71[/tex]

Answer:

106°

Step-by-step explanation:

An isosceles triangle has 2 sides of the same length. All triangles add up to 180°

37 + 37 + x = 180

74 + x = 180

x = 106

Answer:

A) 28 7/12, or 343/12, or 28.583

B) 57.75

C) 86.3 or 86 1/3

Step-by-step explanation:

Answer:

Its an Obtuse angles

Step-by-step explanation:

x+79=2x-37

(x+79)+(-79)=(2x-37)+(-79)

x+79-79=(2x-37)-79

x=2x-37-79

x=116

An obtuse angle has a measurement greater than 90 degrees but less than 180 degrees.

Answer:

the data of the cubic

as it the distance between the two integers closed under addition