the thermodynamic processes that occur in nature ____________.

Answers

Answer 1

Answer:

The thermodynamic processes that occur in nature convert thermal energy into mechanical energy.

Answer 2

The thermodynamic processes that occur in nature are according to the law of thermodynamics.

The thermodynamics processes seen in nature are guided by the law of thermodynamics. The role of energy and heat transmission in physical systems is guided by these laws.

The laws are:

(1) Energy cannot be created nor destroyed in a system, according to the first law of thermodynamics, Also, referred to as the law of energy conservation. Only from one form to another, the energy can be transmitted or altered. Energy is conserved through natural processes, keeping the overall amount constant.

(2) Second law of thermodynamics: states that the overall entropy of an isolated system tends to increase over time in any natural process. This suggests that processes progress towards a state of increasing disorder.

Hence, the thermodynamic processes are guided by the law of thermodynamics.

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Related Questions

The total power input to the leaf blower is 750 W. The useful power outlet of the leaf blower is 360 W. Calculate the efficiency of the leaf blower.

Answers

H = Pu / P x 100% = 360/750 x 100% = 48%

P/s: Pu is the useful power outlet of the leaf blower

P is the total power input to the leaf blower

ok done. Thank to me :>

A 3.00 kg toy falls from a height of 10.0 m. Just before hitting the ground, what will its kinetic energy be? (Disregard air resistance; g = 9.81 m/s2.)

Answers

The kinetic energy of the toy before hitting the ground is 294.3 J

From the question given above, the following data were obtained:

Mass (m) = 3 Kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.81 m/s²

Kinetic energy (KE) =?

Before the toy will hit the ground, the potential and kinetic energy of the toy will be the same.

KE = PE = mgh

KE = 3 × 9.81 × 10

KE = 294.3 J

Therefore, the kinetic energy of the toy is 294.3 J

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a dragster accelerate to a speed of 112m/s over a distance of 398m/s. determine the acceleration (assume uniform) of the dragster

Answers

457 is the absolute correct answer I got my teacher to help hope this helps

what is the relationship of physics and technology ​

Answers

Answer:

Physics explains and describes natural phenomena. It tells us how different parts of nature work and react to different situations. Technology helps us solve problems and complete tasks by using the world around us.

It is observed that technology gives rise to new physics and at other times physics generates new technology. Physics Generating New Technology: Newton's law of motion helped in the development of rockets.

Explanation:

Hope this helps you! :)

Explain why we draw straight lines to show rays of light?

Answers

Answer:

Because light always travels in  straight line.

Explanation:

The fact that light travels can be demonstrated by putting an object in its path. If the object is opaque the result is a degree of blackness on the other side of it which is due to the absence of the light. ... As light does appear to travel in straight lines then light is usually modelled as straight lines in drawings.

Hope this helps :)

#Followformore

how can the motion of an object that is already moving change?

Answers

Answer: A force can change the direction in which an object is moving

Explanation: A bigger force of an object will produce a bigger change in motion

a force acting on 25kg mass produces an acceleration of 4m/square what would this the same force produce on a 12kg mass​

Answers

Answer:8.3m/s

Explanation:

from F=ma, f=25*4=100N. since the force is 100, 100=12a. acceleration= 8.3m/s

Please Help

A car travels on a straight road with velocity components of 20 m/s west and 70 m/s south. What is the total distance the car travels in 50 s?

Answers

I know I don’t know what the problem

PLz help--- What's happening here?
This object is not moving
This object is not changing speeds.
This object is changing speeds; it's getting faster.
This object is changing speeds; it's getting slower.

Answers

Answer:

getting faster

Explanation:

the curve gets more steeper, and steeper line shows more distance for less time, meaning faster.

What is the weight, on Earth, of a book with a mass of 1. 5 kg? 1. 5 N 6. 5 N 11. 3 N 14. 7 N.

Answers

Answer:

The weight, on Earth, of a book with a mass of 1.5kg is 14.7N.

Explanation:

Hi there!

Weight of an object = mass (kg) × acceleration due to gravity (N/kg)

Plug in the given values using the g constant g = 9.8 N/kg:

W = 1.5 × 9.8 = 14.7 N


What mass M will cause this system accelerate e 0.75 m/s²?

Answers

Answer:

5.54 [kg].

Explanation:

1) if m₁=6; g=9.81; a=0.75 and m₂ - reqired mass, then

2) it is possible to write: m₁*a=m₁*g-m₂*g, and

3) [tex]m_2=\frac{m_1(g-a)}{g}; \ => \ m_2=\frac{6*(9.81-0.75)}{9.81}=5.54[kg].[/tex]

What is its time interval between the release of the ball and the time it reaches its maximum height? Its initial vertical speed is 9 m/s and the acceleration of gravity is 9.8 m/s 2 . Neglect air resistance.

Answers

Answer:

The time to reach max height is    h = 1/2 g t^2  

The time to fall is the same as that for an equivalent rise

m g h = 1/2 m v^2       KE vs PE

Here:   (Vf - VI) / g = t = -9  / -9.8 = .92 s


[tex] \huge \mathcal{Question}[/tex]


Can someone Help me with this question ?

(I need proper Explanation if possible)

Thanks for Answering ~ ​

Answers

Answer:

c. Force applied is 75 N

EDITED

tan 37 = a/g

a = 3g/4

a in equation

t× 3/5 = 2 × 3g/4

t = 5× 10/2

t = 25n

f = ma

f = ( mt + mb )a

F = 10 × 3× 10/4

F = 75 n

• Correct option is (C).

We know that the angle made by string is θ=

[tex]tan {}^{ - 1} ( \frac{a}{g} )[/tex]

where a is the acceleration of the frame in which the string is hanging in our case it is a trolley.

[tex]putting  \: θ=37° \: or \: tan \: 37° = \frac{3}{4} [/tex]

[tex]we \: get \: a \: \frac{3g}{4} = \frac{30}{4} = 7.5 \: m/s^2[/tex]

[tex] \boxed{Force \:  F=total  \: mass \:  of \:  the  \: system \:  on  \: which  \: force  \: is  \: acting ×acceleration  \: of  \: the  \: system=(8+2)×7.5=75 }[/tex]

[tex] \boxed{ so \: force \: is \: 75 \:N. }[/tex]

A man on the moon with a mass of 90 kilograms weighs 146 newtons. The radius of the moon is 1.74 x 10^6
meters. Find the mass of the moon

equation- F= G m1 m2/ d^2

Answers

Answer:

7.36 × 10^22 kg

Explanation:

Answer:

D

Explanation:

As a speaker, I should know my purpose and method of delivery before giving my speech so...​

Answers

Explanation:

I will prepare my speech first and then I will give a speech on it.

A large solar farm has 21 700 solar panels and generates 5.0 MW of power.

1.0 MW = 1.0 × 106 W

Calculate the average power each panel produces.

Answers

Answer:

answer is

Explanation:

average power each panel produces = 21700/ 5×10^6

4340 ×10^-6

that's mean 4340 micro Watt

How would the gravity between two objects change if one object got bigger?

Answers

The correct answer is the 3rd answer, gravity would increase its pull on the small object

hope this helps! :)

Lợi ích của lực ma sát và cách làm tăng

Answers

Ma sát có lợi và cách tăng ma sát: Ma sát giữa bánh xe với mặt đường, giữa đế giày với mặt đất, ma sát khi ta cầm một vật là ma sát có lợi. Làm tăng ma sát bằng cách tăng áp lực, tăng độ nhám của mặt tiếp xúc ( cắt nhiều khía ở vỏ xe, đế giày, rải cát trên đường trơn)

4. A force of 50 Newtons is applied to a mass resulting in an acceleration of 8 m/s2. What force would need to be applied to this mass to cause an acceleration of 25 m/s??​

Answers

Answer:

125N

Explanation:

force =mass×acceleration

50 =mass×8m/s2

mass=6.25kg

A bus speeds up from 5 m/s to 15 m/s in 20 seconds. How far did it go during the 20 seconds? (use KE1 to find a, then use that to find xf)

Answers

The distance the bus travelled in 20 seconds is 12.75 m

The first step is to write out parameters given in the question

Final velocity= 15

Initial velocity= 5

Time= 20

Distance= ?

V² + U²= 2as

15² + 5²= 2(9.8)s

225+25= 19.6s

250= 19.6s

s= 250/19.6

= 12.75

Hence the distance the bus travelled in 20 seconds is 12.75 m

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What do these two changes have in common

a slice of banana turning brown

bleaching clothes

Answers

Answer:

They get air inside

Explanation:

bananas turn brown when air is inside

I need help making a chart (preferably a line graph) with this data. I'm not sure how to show that it will be a linear line in a graph. If you don't have excel can you explain to me how to do it.


note: these datasets are separate and arent related

Spring Constant (N/m) Displacement (m)
100 0.5m
300 0.167m
500 0.1m
700 0.071m

Applied force (N) Displacement (m)
20 0.2m
30 0.3m
50 0.5m
70 0.7m

Answers

Answer:

the graph plotted based on your data, you did not mention what are the variables on the x-axis and y- axis . and the graphs can be three small graphs of different material of one quality i.e. thickness or length

hope it helps

Explanation:

A rock on the moon has 0.5kg. It is brought to Earth where the gravitational field is stronger. On Earth, the rock will have:
a) Less mass and same weight
b) The same mass and more weight
c) Less mass and less weight
d) The same mass and same weight

Answers

Answer:

Explanation:

It will be B.

The correct answer is the same mass and less weight.

What happens to the weight of an object when it is brought from the moon to the Earth?

The weight decreases. Your weight will be 1/6 of the weight on the moon that you had on Earth. This is because the mass of the moon is less hence the gravitational pull is very low compared to Earth.

What happens to the mass of an object when you take it to the moon?

Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.

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A 29000-kg open railroad car, initially coasting at 0.825 m/s with negligible friction, passes under a hopper that dumps 117500 kg of scrap metal into it.

a)What is the final speed, in meters per second, of the loaded freight car?
b)How much kinetic energy is lost, in joules, when the freight car receives this scrap metal? Ignore the free-fall kinetic energy of the scrap metal.

Answers

Answer:

a) Answer: 0.16331 m/s

b) Answer: 8522.66 joules

Explanation:

The final speed is  0.1633 m/s.

When the freight car receives this scrap metal, 7915.72 Joule kinetic energy is lost.

What is momentum?

A body has momentum while it is moving, according to our understanding. It is said that a body's momentum is equal to the sum of its mass and speed. A body's direction is important when discussing momentum. Its direction belongs to the body's direction of motion.

(a) Given parameter:

Mass of the railroad car, M = 2900 Kg.

Mass of the scrap metal, m= 11750 Kg.

Initial speed of the car, u = 0.0825 m/s.

Initial speed of the scrap metal = 0 m/s.

Final speed of the system, v = ?

Then, initial momentum of the  system = initial momentum of the car +  initial momentum of the scrap metal .

= (29000×0.825 + 117500×0) kg.m/s.

= 23925 kg.m/s.

Final momentum of the system = total mass of the system× final speed

= (29000 + 117500)× v kg.m/s

= 146500v kg.m/s.

Hence, from principle of conservation of momentum,

initial momentum of the  system = Final momentum of the system

⇒ 23925 = 146500v

⇒ v = 0.1633 m/s.

The final speed of the  loaded freight car is 0.1633 m/s.

(b) Lost in kinetic energy = initial kinetic energy of the car - final kinetic energy of the loaded car.

= 1/2*29000*0.825² -1/2*(29000 + 117500)* 0.1633² Joule.

= 7915.72 Joule.

Hence, 7915.72 Joule kinetic energy is lost in this process.

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According to the principle of regularity, it is recommended that an individual exercise.

A 3-4 days per week at the beginning and progress to 4 or 5 days a week as your fitness improves.

B 7 days per week at the beginning and progress to 4 or 5 days a week as your fitness improves.

C 3-4 days per week at the beginning and progress to 7 days a week as your fitness improves.

D 1-2 days per week at the beginning and progress to 5 or 6 days a week as your fitness improves.

Answers

Answer:

Socratic app

Explanation:

it will help you

John carries a 5 kg bag horizontally to the checkout line. How much work must he
do to move it 8 m at a constant velocity of 1 m/s to the right?

Answers

The work John must do to move the bad horizontally to given distance is 2.5 J.

The given parameters;

mass of the  bag, m = 5 kgdistance moved by the bad, d = 8 mvelocity of bag, v = 1 m/s

The acceleration of the bag at the given distance and velocity is calculated as follows;

[tex]v^2 = u^2 + 2as\\\\1^2 = 0 + 2(a)(8)\\\\1 = 16 a\\\\a = \frac{1}{16} \\\\a = 0.0625 \ m/s^2[/tex]

The work done in moving the bag to 8m is calculated as follows;

[tex]W = F \times d\\\\W = ma \times d\\\\W = 5 \times 0.0625 \times 8 \\\\W = 2.5 \ J[/tex]

Thus, the work John must do to move the bad horizontally to given distance is 2.5 J.

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When an electron falls from one energy level to a lower energy level, the result is the emission of:

Answers

Answer:

fsdfbfsdhfsfiic,dsiwe

Explanation:

which of the following changes will result in a weaker electromagnet

Answers

Answer:

Changing the metal core for a different metal will make the electromagnet stronger or weaker.

Explanation:

Hope this helped, nya~ :3

How do you change an object's motion?

Answers

Forces cause all motions. Every time the motion of an object changes, it's because a force has been applied to it. Force can cause a stationary object to start moving or a moving object to change its speed or direction or both. A change in the speed or direction of an object is called acceleration.

2. Summarize how to use a spring scale to measure a pull and how to use it to apply a push with
a specific force.

Answers

If the spring constant is known, the extension or compression of the spring can be used to calculate the applied force (pull or push) on the spring.

According to Hook's law, the force applied to an elastic material is directly proportional to the extension of the material.

The force applied;

F = kx

where;

k is the spring

The applied force can be in form of push or pull. A push force can result in compression of the spring while a pull force can result in extension of the spring.

If the spring constant is known, the extension or compression of the spring can be used to calculate the applied force (pull or push) on the spring.

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