The volume of a water walking ball is $\frac{4}{3}\pi$
cubic meters. Find the diameter of
the water walking ball.

A photo shows a small boy inside a water walking ball in a pool.

The diameter is
meters.

Using the given proportions, it is found that the joint relative frequency of high school students who ride the bus is of 0.28.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The proportions relative to riding the bus in this problem are of 0.15 for middle school and 0.13 for high school, for a total of 0.28, hence, the joint relative frequency of high school students who ride the bus is of 0.28.

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Answer: 10 Howdy cupcakes

Step-by-step explanation:

   A percent divided by 100 becomes a decimal.

[tex]20\%\; / \;100 = 0.2[/tex]

   Now, we will multiply the total by 0.2 to find 20%.

[tex]50 * 0.2 = 10[/tex]

        You will be ordering 10 cupcakes.

Answer:

Below in bold.

Step-by-step explanation:

a = 16, b = 19 and c = 14.

By the Cosine Rule:

cos A = (a^2 - b^2 - c^2) / -2bc, so:

cos A  = ( 16^2  - 19^2 - 14^2) / (-2*19*14)

             =   -301 / - 532

             =  0.565789

m < A = 55.54 degrees.

Now Using the Sine Rule:

a / sin A = b / sin B

16 / sin 55.54 = 19/sin B

sin B = 19 * sin 55.54 / 16

         = 15.666 / 16

         = 0.979125

m < B = 78.27 degrees.

Finally

m < C = 180 - 55.54 - 78.27 = 46.19 degrees.

Alone, this shape cannot have the area solved in one step.  So, you must break it up into multiple pieces.

For this, we can break it up into a rectangle, and a right triangle.

The area formula for a rectangle is [tex]area = l*w[/tex]

The area formula for a right triangle is [tex]area = \frac{1}2} b*h[/tex]

To find the area of the rectangle, multiply 14 * 18 = 252 m^2

To find the length of the triangle, subtract 20 - 14 = 6

To find the height of the triangle, subtract 18 - 11 = 7

So, it is [tex]\frac{1}{2} 6*7[/tex] = 21 m^2

21 + 252 = 273 meters squared

Hope this helps, feel free to ask any questions

- Jeron    :)

Answer:

[tex]\pi * 9[/tex] or 28.28

Step-by-step explanation:

With the equation of [tex]A = \pi * r^2[/tex], We find that the r - (radius) = 3, so it would be [tex]\pi *3^2\\[/tex] or [tex]\pi * 9[/tex]

Hope This Helps!

Answer:

A relation between two sets is a collection of ordered pairs containing one object from each set. If the object x is from the first set and the object y is from the second set, then the objects are said to be related if the ordered pair (x,y) is in the relation.

Step-by-step explanation:

The products of powers formula when multiplying a number having exponents is suggest that in the multiplication of a number with different powers, the power are added.

The products of powers formula is used to find the product of two exponent numbers.

The products of powers formula when multiplying a number having exponents can be given as,

[tex]a^m\times a^n=a^{(m+n)}[/tex]

Here, (a,m and n) are the number real numbers. In this formula, m and n is the power of the common number a.

Hence, the products of powers formula when multiplying a number having exponents is suggest that in the multiplication of a number with different powers, the power are added.

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Hey there!

ASSUMING….

4 * 3^c

= 4 * 3^2

= 4 * 3 * 3

= 12 * 3

≈ 12 + 12 + 12

≈ 24 + 12

= 36

Therefore, the answer should be: 36

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

In the observation of Rachel the experimental probability of the next car which comes in is red is 5/12 and the experimental probability of the next car which comes in is not red is 7/12.

Experimental probability of an event is the ratio of number of favorable outcome which appeared while conducting an event to the total number of outcome of that event is occurred.

Rachel found that 20 out of 48 cars that entered a parking lot were red. In this observation, the probability of a car to be red is,

[tex]P=\dfrac{20}{48}\\P=\dfrac{5}{12}[/tex]

Thus, the experimental probability that the next car that comes in is red is 5/12.

The experimental probability that the next car that comes in is not red is,

[tex]P^{-1}=1-\dfrac{5}{12}\\P^{-1}=\dfrac{12-5}{12}\\P^{-1}=\dfrac{7}{12}[/tex]

Hence, In the observation of Rachel, the experimental probability of the next car which comes in is red is 5/12 and the experimental probability of the next car which comes in is not red is 7/12.

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Step-by-step explanation:

a trapezoid.

the 2 sides on the left and the right are equal (congruent), and so are the diagonals.

but these diagonals are usually not perpendicular (perpendicular = intersecting each other at 90°).

Answer:

yes it represents it because the linear equation

The quadratic expression cannot be factorized, because the discriminant is less than 0

The expression is given as:

x²+12x+180

Calculate the discriminant of the expresison using:

D = B² - 4AC

So, we have:

D = 12² - 4* 1 * 180

Evaluate

D = -576

Because the discriminant is less than 0, then the expression cannot be factorized

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Answer:   The answer is (d) ⇒ cscx = √3

Step-by-step explanation:

∵ sinx + (cotx)(cosx) = √3

∵ sinx + (cosx/sinx)(cosx) = √3

∴ sinx + cos²x/sinx = √3

∵ cos²x = 1 - sin²x

∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M

∴ (sin²x + 1 - sin²x)/sinx = √3

∴ 1/sinx = √3

∵ 1/sinx = cscx

∴ cscx = √3

Answer:

19 %

Step-by-step explanation:

589 is what percetage of 3100?

589 / 3100  * 100 % = 19%

Answer:

19%

Step-by-step explanation:

589 = x% of 3100?

589 / 3100  * x/100= 19%

Hopefully this helped you, and have a good day!

Answer:

  h(j+1) = 4j² +11j +5

Step-by-step explanation:

A function is evaluated for a specific argument by substituting that argument for the variable in the function's expression. Then the expression is simplified.

__

For function ...

  h(x) = 4x² +3x -2

The value of h(j+1) is ...

  [tex]h(j+1)=4(j+1)^2 +3(j+1)-2\\\\= (4(j+1)+3)(j+1)-2=(4j+7)(j+1)-2=4j^2+11j+7-2\\\\\boxed{h(j+1)=4j^2+11j+5}[/tex]

Answer:

18 region

Step-by-step explanation:

step 1. 11+11+1=23

step 2. 23-41= -18 region

Given,

ABCD is a cyclic quadrilateral in which AC and BD are its diagonals.

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \sf∠DBC= 55° and ∠BAC = 45°[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \sf∠CAD = ∠DBC= 55° (Angles \: in \: the \: same \: segment)[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

Thus,

[tex] \sf∠DAB=∠CAD + ∠BAC[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \sf= 55° + 45° [/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \sf= 100°[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

We know that the opposite angles of a cyclic quadrilateral are supplimentary.

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \sf ∠DAB +∠BCD = 180°[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \sf∠BCD = 180°-100° =80°[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \pink{\boxed{\sf{∠BCD = 80°}}}[/tex]

Answer:

∠BCD = 80°

Step-by-step explanation:

ABCD is a cyclic Quadrilateral.

∠DBC = 55°

∠BAC = 45°

∠BDC

=> ∠BAC = ∠BDC

=> 45° = ∠BAC { Angles of same segment BC}

In Triangle BCD

=> ∠BDC + ∠DBS + ∠BCD = 180°

=> 45° + 55° + ∠BCD = 180°

=> 100° + ∠BDC = 180°

=> ∠BDC = 180-100

=> 80° ans.

Answer:

[tex]25 \: or \: {5}^{2} [/tex]

Step-by-step explanation:

Simplify It

[tex]20 + 2 + 3[/tex]

Then calculate it.

[tex]20 + 2 + 3 = 25[/tex]

Answer:

25

Step-by-step explanation:

Given:

20+(5 × 2/5 )+ 3

Solve:

Using the PEMDAS

Which is:

P- Parentheses

E- Exponents

M- Multiplication

D- Division

A- Addition

S- Subtraction

Thus we have:

20+(5 × 2/5 )+ 3                               {5 × 2/5 = 2}

= 20 + 2 + 3

= 22 + 3

= 25

Kavinsky

The height of the parallelogram whose area is 72 mm² with a base of 9 mm is calculated as: 8 mm.

The area of a parallelogram = base × height of the parallelogram.

Given the following:

9 × height = 72

Height of parallelogram = 72/9

Height of parallelogram = 8 mm.

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Answer:

22.62 degrees

Step-by-step explanation:

Right triangle

  you can pick cosine or sine to calculate angle r

        sin r = opposite leg/ hypotenuse = 5/13

                arcsin(5/13) = 22.62 degrees

         cos r =  12/13  

                r = arccos(12/13) =  22.62 degrees

Answer: 7/40x + 19

Step-by-step explanation:

---Distribute the negative sign

4/5x + 13 - 5/8x + 6

---Get common denominators on the fractions

32/40x + 13 - 25/40x + 6

---Combine like terms

(32/40x - 25/40x) + (13 + 6)

7/40x + 19

Answer: 7/40x + 19

Hope this helps!

Yes..

Add 2 sides together and if it’s larger than the 3rd side it’s possible

6 + 3 = 9, which is larger than 5

3 + 5 =8 which is larger than 6

6 + 5 = 11 which is larger than 3

Answer:

Step-by-step explanation:

The sides of a triangle rule asserts that the sum of the lengths of any two sides of a triangle has to be greater than the length of the third side.

so

6+3=9

6+5=11

3+5=8

yes it is possible

Answer:

x= -4/3

Step-by-step explanation:

Steps

7x +8 = 4X + 4

Subtract 8 from both sides

7x+ 8-8= 4x + 4-8

Simplify

7x=4x-4

Subtract 4x from both sides

7x-4x=4x-4-4x

Simplify

3X = -4

Divide both sides by 3

3X/3 = -4/3

Simplify

x= -4/3

Answer:

Step-by-step explanation:

Solution

7x+8=4x+4                          Subtract 4x from both sides

7x - 4x + 8 = 4                     Combine

3x + 8 = 4                            Subtract 8 from both sides

3x + 8 - 8 = 4 - 8                 Combine

3x = - 4                                Divide by 3

3x/3 = -4/3  

Answer: x = -4/3

The measure of the third angle in a triangle will be 112°.

Your information is incomplete. Therefore, an overview will be given.

Let's assume the the angles given in a triangle are 23° and 59°. The third angle will be:

= 180° - (23° + 59°)

= 180° - 82°

= 112°

It should be noted that a triangle has three angles.

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hope this helps :)

............

Answer:

[tex]4 \sqrt{2}[/tex]

Step-by-step explanation:

Rewrite 32 as the product of 16 and 2:

[tex]\implies \sqrt{32}=\sqrt{16 \cdot 2[/tex]

Apply exponent rule [tex]\sqrt{a \cdot b}=\sqrt{a}\sqrt{b}[/tex]

[tex]\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}[/tex]

Rewrite 16 as 4²:

[tex]\implies \sqrt{16}\sqrt{2}=\sqrt{4^2}\sqrt{2}[/tex]

Apply exponent rule [tex]\sqrt{a^2}=a[/tex]

[tex]\implies \sqrt{4^2}\sqrt{2}=4 \sqrt{2}[/tex]

Answer:

4[tex]\sqrt{2}[/tex]

Step-by-step explanation:

using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]

[tex]\sqrt{32}[/tex]

= [tex]\sqrt{16(2)}[/tex]

= [tex]\sqrt{16}[/tex] × [tex]\sqrt{2}[/tex]

= 4[tex]\sqrt{2}[/tex]

Expression: 5z² - 2z + 1 = 0

Discriminant formula: b²- 4ac

Identify: a = 5, b = -2, c = 1

Solve for discriminant: (-2)²- 4(5)(1) = 4 - 20 = -16

p = 1 also can be rewritten as 2nd equation: 0m + 1p = 1

Build Augment Matrices by taking coefficient's:

[tex]\left[\begin{array}{ccc}1&-1&|| \ \ 2\\0&1&|| \ \ 1\end{array}\right][/tex]

Solve:

Add row 2 to row 1 : R₁ = R₁ + R₂ and restore it back

[tex]\rightarrow \ \left[\begin{array}{ccc}1+0&-1+1& \ \ \ \ || \ 2+1\\0&1&|| \ \ 1\end{array}\right][/tex]

[tex]\rightarrow \ \left[\begin{array}{ccc}1&0& || \ \ 3\\0&1&|| \ \ 1\end{array}\right] \ \ \ = The \quad reduced \quad matrix[/tex]

Solution = (m, p) = (3, 1)

Answer:

14.  -16

15.  m = 3  and  p = 1

Step-by-step explanation:

Discriminant

[tex]b^2-4ac\quad\textsf{when}\quad ax^2+bx+c=0[/tex]

Given equation:   [tex]5z^2-2z+1=0[/tex]

Therefore:

Substituting the values into the discriminant:

[tex]\begin{aligned}\implies b^2-4ac & = (-2)^2-4(5)(1)\\& = 4-20\\& = -16\end{aligned}[/tex]

As the discriminant is negative, this implies there are no real roots.

Augmented Matrices

[tex]\begin{array}{c}ax+by=p \\cx+dy=q\end{array} \implies \left[\begin{array}{r r | r}a & b & p \\ c & d & q\end{array}\right][/tex]    

Use elementary row operations to convert into:

[tex]\left[\begin{array}{r r | r}1 & 0 & h \\ 0 & 1 & k\end{array}\right] \implies \begin{array}{r}x=h\\y=k\end{array}[/tex]

Given:

[tex]\begin{aligned}m-p & =2\\ p & = 1\end{aligned} \implies \left[\begin{array}{r r | r}1 & -1 & 2 \\ 0 & 1 & 1\end{array}\right][/tex]

[tex]\left[\begin{array}{r r | r}1 & -1 & 2 \\ 0 & 1 & 1\end{array}\right] \begin{array}{c}R_1 + R_2 \rightarrow R_1 \\\rightarrow\end{array} \left[\begin{array}{r r | r}1 & 0 & 3 \\ 0 & 1 & 1\end{array}\right][/tex]

Therefore:  

[tex]m=3[/tex]

[tex]p=1[/tex]