The volume of this cylinder is 6480π cm3.
Find the length of the radius,
The sides are equal to 180cm.

Answer:

y=1.75 that’s the unit or you can say the constant so I can do 1.75+1.75 and I would get 3.50

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Find and classify the global extrema of the following function:

f(x) = -x^3 + 5 x^2 + x

Find the critical points of f(x):

Compute the critical points of -x^3 + 5 x^2 + x

To find all critical points, first compute f'(x):

d/(dx) (-x^3 + 5 x^2 + x) = -3 x^2 + 10 x + 1:

f'(x) = -3 x^2 + 10 x + 1

Solving -3 x^2 + 10 x + 1 = 0 yields x = 1/3 (5 - 2 sqrt(7)) or x = 1/3 (5 + 2 sqrt(7)):

x = 1/3 (5 - 2 sqrt(7)), x = 1/3 (5 + 2 sqrt(7))

f'(x) exists everywhere:

-3 x^2 + 10 x + 1 exists everywhere

The critical points of -x^3 + 5 x^2 + x occur at x = 1/3 (5 - 2 sqrt(7)) and x = 1/3 (5 + 2 sqrt(7)):

x = 1/3 (5 - 2 sqrt(7)), x = 1/3 (5 + 2 sqrt(7))

The domain of -x^3 + 5 x^2 + x is R:

The endpoints of R are x = -∞ and ∞

Evaluate -x^3 + 5 x^2 + x at x = -∞, 1/3 (5 - 2 sqrt(7)), 1/3 (5 + 2 sqrt(7)) and ∞:

The open endpoints of the domain are marked in gray

x | f(x)

-∞ | ∞

1/3 (5 - 2 sqrt(7)) | -0.0490425

1/3 (5 + 2 sqrt(7)) | 21.9009

∞ | -∞

The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:

The open endpoints of the domain are marked in gray

x | f(x) | extrema type

-∞ | ∞ | global max

1/3 (5 - 2 sqrt(7)) | -0.0490425 | neither

1/3 (5 + 2 sqrt(7)) | 21.9009 | neither

∞ | -∞ | global min

Remove the points x = -∞ and ∞ from the table

These cannot be global extrema, as the value of f(x) here is never achieved:

x | f(x) | extrema type

1/3 (5 - 2 sqrt(7)) | -0.0490425 | neither

1/3 (5 + 2 sqrt(7)) | 21.9009 | neither

f(x) = -x^3 + 5 x^2 + x has no global extrema:

Answer: -x^3 + 5 x^2 + x has no global extrema

The scale factor that Noah apply to Polygon P to create Polygon Q is 3

An equation is an expression that shows the relationship between two or more numbers and variables.

Equations are classified based on degree (value of highest exponents) as linear, quadratic, cubic and so on. Variables can be dependent or independent. Dependent variables depend on other variable while an independent variable do not depend.

Area of polygon Q = (6 unit * 9 units) - (3 units * 3 units) = 45 unit²

Area of polygon P * scale factor² = area of polygon Q

5 * scale² = 45

Scale factor = 3

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The average rate of change per minute in the amount downloaded is 11.5 megabytes per minute

File size: 1400 megabytes

Start time of download: 7:00 pm

File size remaining to be downloaded: 825 megabytes

Time after one has done homework: 7:50 pm

Time elapsed: 50 minutes

File size downloaded: Total file size - File size remaining to be downloaded

= 1400 - 825 = 575 megabytes

Average rate of change per minute = File size downloaded/Time elapsed in minutes

= 575/50

= 11.5 megabytes per minute

So, the average rate of change per minute in the amount of download is 11.5 megabytes per minute

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Answer:

2 + 2 is 5

Step-by-step explanation:

everyone knows that

Answer:

Obviously its 22

Step-by-step explanation:

Answer:

I believe so but I'm nor 100% sure

The ratios 5:3 and 6:4 are not equivalent.

A ratio in mathematics illustrates how many times one number contains another. For example, if a dish of fruit contains eight oranges and six lemons, the orange-to-lemon ratio is eight to six. Similarly, the lemon to orange ratio is 6:8, while the orange to total fruit ratio is 8:14.

Equivalent ratios are those that are the same when compared. Two or more ratios can be compared to determine whether they are equal. For example, the ratios 1:2 and 2:4 are equal.

The given two ratios are 5:3 and 6:4. We can write them as 5/3 and 6/4

Let us apply subtraction, if we get 0 then these are equivalent.

6/4-5/3

The LCM of 4 and 3 is 12

=(18-20)/12

The value of 18-20 is -2

=-2/12

We have to divide 2 by 12 we get -1/6.

=-1/6 not equal to 0

Therefore, it can be concluded that the ratios 5:3 and 6:4 are not equivalent.

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The Probability that 2 or fewer will withdraw without completing the introductory statistics course is 0.4547  .

The Binomial  Distribution formula is

P(X=x) = C(n,x)*pˣ*qⁿ⁻ˣ

where ,

n is the number of trials

x is the number of times success occurs

p is the probability of success

q is the probability of failure .

In the given question ;

it is given that

students that are registered for the course = 20

so , n=20

Let x denote the number of students that withdraw without completing the course .

given that 14 % students  withdraw without completing the course ,

hence p = 14% = 0.14

So , q= 1-p = 1-0.14 = 0.86

the probability that 2 or fewer will withdraw from the course is denoted by P(X ≤ 2) and  is calculated using

the formula , P(X≤2)=P(X=0)+P(X=1)+P(X=2)        ...(i)

using Binomial Probability we get

P(X=x) = C(n,x)*pˣ*qⁿ⁻ˣ

P(X=0) = C(20,0)*(0.14)⁰*(0.86)²⁰⁻⁰

= C(20,0)*(0.14)⁰*(0.86)²⁰

= 1*1*(0.0489)

= 0.0489

So , P(X=0)=0.0489        ...(ii)

P(X=1) = C(20,1)*(0.14)¹*(0.86)¹⁹

= 20*0.14*0.0569

= 0.1593

So , P(X=1)=0.1593        ...(iii)

P(X=2) = C(20,2)*(0.14)²*(0.86)¹⁸

= 190*0.0196*0.0662

= 0.2465    

So , P(X=2)=0.2465        ...(iv)

Substituting the values of (ii) , (iii) and (iv) in (i) , we get

P(X≤2)=P(X=0)+P(X=1)+P(X=2)

P(X ≤ 2) = 0.0489 + 0.1593 + 0.2465

= 0.4547

Therefore , the Probability that 2 or fewer will withdraw without completing the introductory statistics course is 0.4547   .

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The quotient [8a squared b]/[2ab squared] is simplified to 16/b

Algebraic expressions are simply known as arithmetic expressions which are made up of constants, variables, terms, factors and coefficients.

They are also made up of certain operations, arithmetic, mathematical which includes;

Given the expression;

[8a squared b] = x

[2ab squared] = y

Take the quotient of the values

(8a)²b/(2ab)²

Expand the bracket

64a²b/4a²b²

Now, divide the common terms, we have

16/b

Hence, the value is 16/b

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The relative maximum point is point D.

The relative maximum point is determined by the slope.

Here the slope is represented by tan theta.

If we draw a tangent at every point of the curve then we observe that A has a positive curse and point D has a increasing curve which is almost equal to 90° and tan 90 is 1.  Point B and C however have a steady curve and tan 0 is 0.

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The expression two hundred and fifty six x^4 minus one thousand two hundred and ninety six y⁴ will be 16(4²x⁴ - 9²y⁴)

It should be noted that expressions simply means one or more number or variables that are used to represent a data or a particular information.

It should be noted that two hundred and fifty six x⁴ minus one thousand two hundred and ninety six y^4 will be expressed as:

256x⁴ - 1096y⁴

In this case, there's a common factor between 256 and 1096. This will give a result as:

= 16(16x⁴ - 81y⁴)

= 16(4²x⁴ - 9²y⁴)

= 16[(4x)² - (9y²)²][(4x²)² + (9y²)²]

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Answer:

An is A and E

Plsss mark as brainliest

The equation of the line of best fit for the points is y = -2x + 3

The distance between two points is referred to as a line. The standard equation of a line in slope-intercept form is expressed according to the equation

y = mx + b

where:

m is the slope

b is the intercept

Using the coordinate points (-1, 5) and. (5, -7)

Slope = -7-5/5-(-1)

Slope = -12/6

Slope = -2

Find the y-intercept

-7 = -2(5) + b

-7 = -10 + b

b. = 3

Determine the equation

y = mx + b

y = -2x + 3

This gives the required equation of line of best fit.

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Ratios  equivalent to 1:2 9:18 12:24 5:10​ are 13: 26, 4:8, 7:14, 15: 30 and many more.

A ratio in mathematics demonstrates how many times one number is present in another. For instance, if a dish of fruit contains eight oranges and six lemons, the ratio of oranges to lemons is eight to six. The ratio of oranges to the overall amount of fruit is 8:14, and the ratio of lemons to oranges is 6:8. An ordered pair of numbers a and b, represented as a / b, is a ratio if b is not equal to 0. A proportion is an equation that sets two ratios at the same value.

Given Data

ratios  equivalent to 1:2 9:18 12:24 5:10​ are

13:26

as [tex]\frac{13}{26}[/tex] = [tex]\frac{1}{2}[/tex]

4:8

7:14

15:30

and many more.

Ratios  equivalent to 1:2 9:18 12:24 5:10​ are 13: 26, 4:8, 7:14, 15: 30 and many more.

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[tex]m = \frac{y - y1}{x2 - x1} \\ m = \frac{ - 7 - ( - 1)}{ - 8 - 1} \\ m = \frac{ - 7 + 1}{ - 9} \\ m = \frac{ - 6}{ - 9} \\ m = \frac{2}{3} [/tex]

I ALSO PROVIDED THE FORMULA TO USE.

HOPE THIS HELPS

Answer:total cost= 20x+50 x= number of hours

Step-by-step explanation: Gooooooooooooogle

After dilation, the length of line segment A'B' is 6 units.

So, the length of line segment AB:

After dilation:

Therefore, after dilation, the length of line segment A'B' is 6 units.

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Answer:

0.0533

Step-by-step explanation:

first remove the decimal points, then add a zero to the end.

205*

260  0*5,0*0,0*2=0. 6*5=30, but you carry the 3, so its another 0.

6*0+3=3

6*2=12

2*5=10, but you carry the one, so it is 0. 2*0+1=1

2*2=4

1230

4100=

5330, but we moved 0.26 2 spaces forward, and we moved 0.205 3 spaces forward too. in total, that makes 6 spaces, so now we have to move it back. 533-1 space

53.3-2 spaces           5.33-3 spaces          0.533-4   0.0533-5 spaces

Answer:

Quadrant I

Step-by-step explanation:

Time and height must both be positive.

The volume of the box is 287 and the height of the box is 3

The figure that completes the question is added as an attachment

On the figure, we have

So, the base area is

Base area = Number of squares x Length of square^2

The volume becomes

Volume = Height x Base area

This gives

Volume = Height x Number of squares x Length of square^2

Substitute the known values in the above equation

Volume = 7 x 41 x 1^2

Evaluate

Volume = 287

The base area is

Base area = Number of squares x Length of square^2

The volume becomes

Volume = Height x Base area

This gives

Volume = Height x Number of squares x Length of square^2

Substitute the known values in the above equation

123 = Height  x 41 x 1^2

Evaluate

123 = Height  x 41

Divide by 41

Height  = 3

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Use the horizontal number line, the statements which are true include the following:

A. –9 < –7

C. –1 > –3

A number line can be defined as a type of graph with a graduated straight line which is composed of both positive and negative numbers that are placed at equal intervals along its length.

In Mathematics, a number line typically increases in numerical value towards the right from zero (0) and decreases in numerical value towards the left from zero (0).

In this context, we can reasonably and logically deduce that the following inequalities on a number line are either true or false:

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Complete Question:

Use the horizontal number line shown to answer the question. Which statements are true?

-10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1

Check all that apply.

A. –9 < –7

B. –6 = 6

C. –1 > –3

D. 0 < –3

Answer: A & C

Step-by-step explanation:

Part (a)

A = {prime numbers between 10 and 16}

A = {11, 13}

B = {multiples of 3 between 10 and 16}

B = {12, 15}

A U B = union of set A with set B

A U B = {set of stuff from A or B or both}

A U B = {11, 12, 13, 15}

=================================================

Part (b)

I'm assuming that you meant to write [tex]A \cap B[/tex]

If so, then this is the set of values inside set A and set B at the same time.

Since there is no common overlap between the sets A and B, we say that the answer is the empty set. We write the empty set as a pair of curly braces with nothing inside. Not even zero is a member of the empty set.

[tex]A \cap B = \{ \ \}[/tex]

we could also write the empty set using the symbol [tex]\varnothing[/tex]

So,

[tex]A \cap B = \varnothing[/tex]

=================================================

Part (c)

Reason:

The weird looking E symbol in this context means "is inside" or "is part of"

In other words, a statement like [tex]11 \in B[/tex] translates to "11 is part of set B", which is a false statement. Recall that B = {12, 15}

If we said [tex]11 \in A[/tex], then it would be true since A = {11, 13} which shows 11 as one of the values of set A.

Answer:

(1-5420)

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997, 1009, 1013, 1019, 1021, 1031, 1033, 1039, 1049, 1051, 1061, 1063, 1069, 1087, 1091, 1093, 1097, 1103, 1109, 1117, 1123, 1129, 1151, 1153, 1163, 1171, 1181, 1187, 1193, 1201, 1213, 1217, 1223, 1229, 1231, 1237, 1249, 1259, 1277, 1279, 1283, 1289, 1291, 1297, 1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, 1399, 1409, 1423, 1427, 1429, 1433, 1439, 1447, 1451, 1453, 1459, 1471, 1481, 1483, 1487, 1489, 1493, 1499, 1511, 1523, 1531, 1543, 1549, 1553, 1559, 1567, 1571, 1579, 1583, 1597, 1601, 1607, 1609, 1613, 1619, 1621, 1627, 1637, 1657, 1663, 1667, 1669, 1693, 1697, 1699, 1709, 1721, 1723, 1733, 1741, 1747, 1753, 1759, 1777, 1783, 1787, 1789, 1801, 1811, 1823, 1831, 1847, 1861, 1867, 1871, 1873, 1877, 1879, 1889, 1901, 1907, 1913, 1931, 1933, 1949, 1951, 1973, 1979, 1987, 1993, 1997, 1999, 2003, 2011, 2017, 2027, 2029, 2039, 2053, 2063, 2069, 2081, 2083, 2087, 2089, 2099, 2111, 2113, 2129, 2131, 2137, 2141, 2143, 2153, 2161, 2179, 2203, 2207, 2213, 2221, 2237, 2239, 2243, 2251, 2267, 2269, 2273, 2281, 2287, 2293, 2297, 2309, 2311, 2333, 2339, 2341, 2347, 2351, 2357, 2371, 2377, 2381, 2383, 2389, 2393, 2399, 2411, 2417, 2423, 2437, 2441, 2447, 2459, 2467, 2473, 2477, 2503, 2521, 2531, 2539, 2543, 2549, 2551, 2557, 2579, 2591, 2593, 2609, 2617, 2621, 2633, 2647, 2657, 2659, 2663, 2671, 2677, 2683, 2687, 2689, 2693, 2699, 2707, 2711, 2713, 2719, 2729, 2731, 2741, 2749, 2753, 2767, 2777, 2789, 2791, 2797, 2801, 2803, 2819, 2833, 2837, 2843, 2851, 2857, 2861, 2879, 2887, 2897, 2903, 2909, 2917, 2927, 2939, 2953, 2957, 2963, 2969, 2971, 2999, 3001, 3011, 3019, 3023, 3037, 3041, 3049, 3061, 3067, 3079, 3083, 3089, 3109, 3119, 3121, 3137, 3163, 3167, 3169, 3181, 3187, 3191, 3203, 3209, 3217, 3221, 3229, 3251, 3253, 3257, 3259, 3271, 3299, 3301, 3307, 3313, 3319, 3323, 3329, 3331, 3343, 3347, 3359, 3361, 3371, 3373, 3389, 3391, 3407, 3413, 3433, 3449, 3457, 3461, 3463, 3467, 3469, 3491, 3499, 3511, 3517, 3527, 3529, 3533, 3539, 3541, 3547, 3557, 3559, 3571, 3581, 3583, 3593, 3607, 3613, 3617, 3623, 3631, 3637, 3643, 3659, 3671, 3673, 3677, 3691, 3697, 3701, 3709, 3719, 3727, 3733, 3739, 3761, 3767, 3769, 3779, 3793, 3797, 3803, 3821, 3823, 3833, 3847, 3851, 3853, 3863, 3877, 3881, 3889, 3907, 3911, 3917, 3919, 3923, 3929, 3931, 3943, 3947, 3967, 3989, 4001, 4003, 4007, 4013, 4019, 4021, 4027, 4049, 4051, 4057, 4073, 4079, 4091, 4093, 4099, 4111, 4127, 4129, 4133, 4139, 4153, 4157, 4159, 4177, 4201, 4211, 4217, 4219, 4229, 4231, 4241, 4243, 4253, 4259, 4261, 4271, 4273, 4283, 4289, 4297, 4327, 4337, 4339, 4349, 4357, 4363, 4373, 4391, 4397, 4409, 4421, 4423, 4441, 4447, 4451, 4457, 4463, 4481, 4483, 4493, 4507, 4513, 4517, 4519, 4523, 4547, 4549, 4561, 4567, 4583, 4591, 4597, 4603, 4621, 4637, 4639, 4643, 4649, 4651, 4657, 4663, 4673, 4679, 4691, 4703, 4721, 4723, 4729, 4733, 4751, 4759, 4783, 4787, 4789, 4793, 4799, 4801, 4813, 4817, 4831, 4861, 4871, 4877, 4889, 4903, 4909, 4919, 4931, 4933, 4937, 4943, 4951, 4957, 4967, 4969, 4973, 4987, 4993, 4999, 5003, 5009, 5011, 5021, 5023, 5039, 5051, 5059, 5077, 5081, 5087, 5099, 5101, 5107, 5113, 5119, 5147, 5153, 5167, 5171, 5179, 5189, 5197, 5209, 5227, 5231, 5233, 5237, 5261, 5273, 5279, 5281, 5297, 5303, 5309, 5323, 5333, 5347, 5351, 5381, 5387, 5393, 5399, 5407, 5413, 5417, 5419

Step-by-step explanation:

Together, Bob and John will need 10 hours to finish the computer program with the given rate of working.

We divide the change in y (output) by the change in x to determine the average rate of change (input).

The amount of work finished in a single day if a task takes x days to complete is equal to 1/x.

It is given that In 30 hours, Bob can write a computer program. John can write a computer program in half the time that Bob takes.

Bob's rate =  B

John 's rate = J

B × 30 = J × 15

Rate of Bob = 1/30 h

Rate of John = 1/15 h

Total time(1/30 + 1/15) = Computer Program

(1/30 + 1/15) = Computer Program/Total time

0.099 = Computer Program/Total time

So, total time = 1/0.099 = 10 hours/computer program

Therefore, Bob and John will finish the computer program in a total of 10 hours.

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800 people in the cinema are eating popcorn by probability.

What does math probability mean?

Total people in cinema = 200

probability of choosing a person eating popcorn is = 0.25

people in the cinema are eating popcorn = 200/0.25

people in the cinema are eating popcorn     = 800

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Answer:

<8=66°

Step-by-step explanation:

2 angles on a straight line will add up to 180° so

180-114=66.

<8,<4, <1, <5 all equal 66° since vertical angles are equal

answer; 6^8

explanations;

power rule for exponent; 2 x 4 = 8

Answer:

.............. ................

Answer:

8 dollars

Step-by-step explanation: