The weight of a 1,000 kg car is ______________ (pick best answer)

Group of answer choices

9800 N

102.4 N

1000 N

10000 N​

Answers

Answer 1

What is the weight of a car with the mass of 1000 kg?

Answer: it is 9800 N.


Related Questions

answer with proper explanation

Answers

Answer:

B

Explanation:

Moment = force * perpendicular distance

Since the beam is balanced(equilibrium), the 2 moments will be equal.

30 * P = 70 * Q

The 2 combinations which achieve this equality is P = 21 and Q = 9

You increase your walking speed from 1 m/s to 3 m/s in a period of 1 s.

What is your acceleration?

5 m/s2
3 m/s2
2 m/s2
4 m/s2

Answers

Answer:

2 m/s2

Explanation:

the answer is 2 m/s2

A ____ is a region where jets of gas from young stars impact and heat the gas surrounding the young star.

Answers

Bipolar outflow is the blank

Mention the methods of census and explain each of them in brief​

Answers

Answer:

Census includes the total process of collecting, compiling, analyzing, evaluating, publishing and disseminating statistical data regarding the population and housing and their geographical location. Population characteristics include demographic, social and economic data and are provided as of a particular date (reference period).

Census Methods:

Population censuses typically use one of two approaches:

De facto – meaning enumeration of individuals as of where they are found in the census, regardless of where they normally reside.

De jure - meaning enumeration of individuals as of where they usually reside, regardless of where they are on census day.

the following can increase the amount of friction in the surface, except ______.
a. glue
b. paper
c. lubricant
d. foil​

Answers

Answer:

c. lubricant..........

Do you think humans will ever walk on the sun?

Answers

[tex] \: \: \: \: \: [/tex]

yes

because sun have a super nova and if someone get it there that person definitely get burn

hope it helps

[tex] \: \: \: \: \: [/tex]

Plate movements on Earth’s crust create ______

Answers

Answer: earthquakes and volcanoes

Explanation:

3. What happens if an object has a negative acceleration?​

Answers

Answer:

They will go backwards?

Explanation:

If positive they go forward but is negative they go backwards.

- A cylinder of volume 5.0 x 103 cm3 contains air at a pressure of 8.0 x 105 Pa.
A leak develops so that air gradually escapes from the cylinder until the air in the cylinder
is at atmospheric pressure. The pressure of the atmosphere is 1.0 x 105 Pa.
Calculate the volume of the escaped air, now at atmospheric pressure. Assume that the
temperature stays constant.

Answers

Answer:

10

Explanation:

if you put 10 your right

Imagine you have a ball tied to the end of a string. You hold the other end of the string and swing it around. Suppose the string breaks, what direction will the ball travel

Answers

It will move in a curving motion starting in the direction where it snapped from. In the end it goes down :D

According to the table, what was the hiker's average speed for
the entire hike?
A: 2.0 km/h B: 5.7 km/h C: 6.7 km/h D: 10 km/h

Answers

Answer:

6.7 km/h (C)

Explanation:

According to the table, the hiker's average speed for the entire hike would be 6.7 kilometers/hour.

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.

The total distance traveled by the hiker = 4 kilometers  + 6 kilometers + 4 kilometers west + 6 kilometers north

                                                                  = 20 kilometers

The total time is taken by the hiker = 45 min + 60 min + 30 min+ 45 min

                                                           = 180 min

                                                           =3 hours

                                               

The average speed of the hiker = 20 kilometers / 3 hours

                                                     = 6.7 kilometers / hours

Thus, the hiker's average speed for the entire hike would be 6.7 kilometers/hour.

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The initial temperature of the mixture was +20 °C. The mixture froze at -1.5 °C.
A total of 165 kJ of internal energy was transferred from the mixture to cool and
freeze it.
specific heat capacity of the mixture = 3500 J/kg °C
specific latent heat of fusion of the mixture = 255 000 J/kg
Calculate the mass of the mixture.
Give your answer to 2 significant figures.
[6
M

Answers

Answe16000/3500(-1.5-2-)225000= 1.1

Explanation:

The mass of the mixture will be 2.19 ×10⁻³ kg. The unit of mass is kg and it is a scalar quantity.

What is mass?

Mass is a numerical measure of inertia, which is a basic feature of all matter. It is, in effect, a body of matter's resistance to a change in speed or position caused by the application of a force.

In the International System of Units (SI), the kilogram is the unit of mass.

The given data in the problem is;

The initial temperature of the mixture was, [tex]\rm T_i = 20 ^0 \ C[/tex]

The mixture froze at the temperature of, [tex]\rm T_F = -1.5 ^0 \ C[/tex]

The internal energy is,[tex]\rm E = \rm 165 \ kJ[/tex]

The specific heat capacity of the mixture is,[tex]\rm C = 3500 J/kg ^0C[/tex]

The specific latent heat of fusion of the mixture is,[tex]\rm l = 255 000 J/kg[/tex]

m is the mass of the mixture,

The latent heat is equal to the heat transfer. Because the net work done is zero.

The formula for the heat transfer is found as;

[tex]\rm Q = mCdt \\\\ m = \frac{Q}{Cdt} \\\\ m = \frac{165 }{3500(20-(-1.5)} \\\\ m = 2.19 \times 10^{-3} \ kg[/tex]

Hence the mass of the mixture will be 2.19 ×10⁻³ kg.

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Copper is a type of metal.
A block of copper has a mass of 2.0kg.
The block of copper absorbs 12000J of thermal energy.
The specific heat capacity of copper is 385J /(kg°C).
What is the temperature rise of the copper?
A 15.6°C B 31.2°C C 46.8°C D 62.4°C

Answers

The temperature rise in the copper is. I think its 0.393

The temperature rise in the copper is. I think its 0.393. Copper is a chemical element with the symbol Cu (from Latin: cuprum) and atomic number 29.

What is Capacity of copper?

The chemical element copper (Cu) is a reddish, incredibly ductile metal belonging to Periodic Group 11 (Ib) that has an exceptional ability to conduct heat and electricity.

In nature, copper can be found in its free metallic state. Neolithic (New Stone Age) humans originally utilised this local copper (about 8000 BCE) as a substitute for stone.

Around 4000 BCE, Mesopotamia saw the beginning of metallurgy as copper was cast into molds, reduced to metal from ores with fire and charcoal, and purposefully alloyed with tin to form bronze (c. 3500 BCE).

Therefore, The temperature rise in the copper is. I think its 0.393. Copper is a chemical element with the symbol Cu (from Latin: cuprum) and atomic number 29.

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A car approaches you at 50 km/h. A fly inside the car is flying toward the back of the car at 7 km/h. From your point of view by the side of the road, the fly is moving at ______________km/h. Group of answer choices 57

Answers

Answer:

43 km/h

Explanation:

If the car is going past you at 50 km/h, then all the objects inside appear to be going 50 km/h. The fly is flying 7km/h in the opposite direction, and would appear to be going 7 km/h slower. Therefore, as 50 - 7 is 43, the fly would appear to be going 43 km/h. Hope this helps :D

how much of the light that reaches the earth from the sun is used for photosynthesis

Answers

Answer:

Less than one percent of the total energy that reaches Earth is used by plants for photosynthesis

what is the medium for the sound waves for whales to communicate with each other?

Answers

Answer:

SONGS CLICKS AND WHISTLE

Explanation:

how do mechanical waves compare with electromagnetic waves?

Answers

Answer:

Electromagnetic waves are waves that have no medium to travel whereas mechanical waves need a medium for its transmission. Electromagnetic waves travel in a vacuum whereas mechanical waves do not. The mechanical waves need a medium like water, air, or anything for it to travel.

Explanation:

Does the volume of a gas affect the rate of diffusion in a porous material​

Answers

Answer:

No

Explanation:

The rate of diffusion defines the gas that passes through some area over the course of time.

the small lightweight particles outside the nucleus of an atom are called___.​

Answers

The neutron has no charge, and a mass of slightly over 1 amu. Some scientists propose the neutron is made up of a proton and electron-like particle. The electron is a very small particle located outside the nucleus.

Electron: -1

Neutron: 0

Proton: +1

Energy a substance or system has because of its motion Is what?

light energy
chemical energy
sound energy
electrical energy
thermal energy
mechanical energy

Answers

Answer:

Mechanical energy is the energy a substance or system has because of its motion. For example machines use mechanical energy to do work.

Calculate the force applied if 100 N/m² pressure is exerted over the area of 0.2m²​

Answers

Answer: 100 pascals times 0.2 m^2= 20 N force is applied.

Explanation:

A 100 kg roller coaster comes over the first hill at 2 m/sec (vo). The height of the first hill (h) is 20 meters. See roller diagram below.

1) Find the total energy for the roller coaster at the initial point.

2) Find the potential energy at point A using the PE formula.

3) Use the conservation of energy to find the kinetic energy (KE) at point B.

4) Find the potential energy at point C.

5) Use the conservation of energy to find the Kinetic Energy (KE) of the roller coaster at point C.

6) Use the Kinetic Energy from C, find velocity of the roller coaster at point C.

Answers

For the 100 kg roller coaster that comes over the first hill of height 20 meters at 2 m/s, we have:

1) The total energy for the roller coaster at the initial point is 19820 J

2) The potential energy at point A is 19620 J

3) The kinetic energy at point B is 10010 J

4) The potential energy at point C is zero

5) The kinetic energy at point C is 19820 J

6) The velocity of the roller coaster at point C is 19.91 m/s

1) The total energy for the roller coaster at the initial point can be found as follows:

[tex] E_{t} = KE_{i} + PE_{i} [/tex]

Where:

KE: is the kinetic energy = (1/2)mv₀²

m: is the mass of the roller coaster = 100 kg

v₀: is the initial velocity = 2 m/s

PE: is the potential energy = mgh

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 20 m

The total energy is:

[tex] E_{t} = KE_{i} + PE_{i} = \frac{1}{2}mv_{0}^{2} + mgh = \frac{1}{2}*100 kg*(2 m/s)^{2} + 100 kg*9.81 m/s^{2}*20 m = 19820 J [/tex]

Hence, the total energy for the roller coaster at the initial point is 19820 J.

   

2) The potential energy at point A is:

[tex] PE_{A} = mgh_{A} = 100 kg*9.81 m/s^{2}*20 m = 19620 J [/tex]

Then, the potential energy at point A is 19620 J.

3) The kinetic energy at point B is the following:

[tex] KE_{A} + PE_{A} = KE_{B} + PE_{B} [/tex]

[tex] KE_{B} = KE_{A} + PE_{A} - PE_{B} [/tex]

Since

[tex] KE_{A} + PE_{A} = KE_{i} + PE_{i} [/tex]

we have:

[tex] KE_{B} = KE_{i} + PE_{i} - PE_{B} =  19820 J - mgh_{B} = 19820 J - 100kg*9.81m/s^{2}*10 m = 10010 J [/tex]

Hence, the kinetic energy at point B is 10010 J.

4) The potential energy at point C is zero because h = 0 meters.

[tex] PE_{C} = mgh = 100 kg*9.81 m/s^{2}*0 m = 0 J [/tex]

5) The kinetic energy of the roller coaster at point C is:

[tex] KE_{i} + PE_{i} = KE_{C} + PE_{C} [/tex]            

[tex] KE_{C} = KE_{i} + PE_{i} = 19820 J [/tex]      

Therefore, the kinetic energy at point C is 19820 J.

6) The velocity of the roller coaster at point C is given by:

[tex] KE_{C} = \frac{1}{2}mv_{C}^{2} [/tex]

[tex] v_{C} = \sqrt{\frac{2KE_{C}}{m}} = \sqrt{\frac{2*19820 J}{100 kg}} = 19.91 m/s [/tex]

Hence, the velocity of the roller coaster at point C is 19.91 m/s.

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A wrecking ball has a mass of 650 kg. It swings from a cable that is 21 m long. The centripetal force on the ball is 56 N. What is the tangential speed of the wrecking ball? 1. 3 m/s 1. 8 m/s 46 m/s 870 m/s.

Answers

Hi there!

For an object moving in a circle:

Centripetal force = ∑F = mv²/r

Thus:

56 = mv²/r

Rearrange to solve for velocity:

√(56r/m) = v

√(56 × 21)/650 = 1.345 m/s

Answer:

A

Explanation:

have a good day

please no irrelevant answers!
Light enters a glass block at an angle of incidence of 46°. The light refracts at an angle of refraction of 26°. What is the refractive index of the glass?
A 0.57
B 0.61
C 1.64
D 1.77​

Answers

Answer:

Choice C: Approximately [tex]1.64[/tex].

(Assuming that light entered into this glass block from air.)  

Explanation:

Let [tex]n_{1}[/tex] denote the refractive index of the first medium (in this example, air.) Let [tex]\theta_{1}[/tex] denote the angle of incidence.

Let [tex]n_{2}[/tex] denote the refractive index of the second medium (in this example, the glass block.) Let [tex]\theta_{2}[/tex] denote the angle of refraction.

By Snell's Law:

[tex]n_{1} \, \sin(\theta_{1}) = n_{2}\, \sin(\theta_{2})[/tex].

Rearrange the equation to find an expression for [tex]n_{2}[/tex], the refractive index of the second medium (the glass block.)

[tex]\begin{aligned}n_{2} = \left(\frac{\sin(\theta_{1})}{\sin(\theta_{2})}\right)\, n_{1}\end{aligned}[/tex].

The refractive index of air is approximately [tex]1.00[/tex]. Substitute in the values and solve for [tex]n_{2}[/tex], the refractive index of the glass block:

[tex]\begin{aligned}n_{2} &= \left(\frac{\sin(\theta_{1})}{\sin(\theta_{2})}\right)\, n_{1} \\ &= \left(\frac{\sin(46^{\circ})}{\sin(26^{\circ})}\right)\times 1.00 \\ &\approx 1.64\end{aligned}[/tex].

How much work must be done to stop a 925-kg car traveling at 95 km/h?

Answers

The amount of work done to stop the car is equal to 322,099.85 Joules.

Given the following data:

Mass = 925 kilogramsVelocity = 95 km/h

Conversion:

Velocity = 95 km/h = [tex]\frac{95 \times 1000}{60 \times 60} = 26.39 \;m/s^2[/tex]

To determine the amount of work done to stop the car, we would apply the work-energy theorem:

Note: The amount of work done must balance the kinetic energy possessed by the car due to its motion.

From the work-energy theorem, we have:

[tex]Work\done = \Delta K.E\\\\Work\done = \frac{1}{2} MV^2[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = \frac{1}{2} \times 925 \times (26.39)^2\\\\Work\;done =462.5 \times 696.4321[/tex]

Work done = 322,099.85 Joules

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help me solve please ​

Answers

Answer:

please check the image

Explanation:

I hope this image helps you please follow the steps. Thank you

Answer:

1kg/```````2

Explanation:

solution

Block 1, of mass m1, moves across a frictionless surface with speed ui. It collides elastically with block 2, of mass m2, which is at rest (vi=0). (Figure 1)After the collision, block 1 moves with speed uf, while block 2 moves with speed vf. Assume that m1>m2, so that after the collision, the two objects move off in the direction of the first object before the collision. What is the final speed vf of block 2?

Answers

The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]  

the momentum is defined by the product of the mass and the velocity of the body.

        p = mv

The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.

If the system is isolated, the forces during the collision are internal and the it  is conserved. Let's find the momentum is two instants.

Initial instant. Before crash.

      p₀ = m₁ u₀ + 0

Final moment. After crash.

      [tex]p_f = m_1 u_f + m_2 v_f[/tex]  

The momentum is preserved.

      p₀ = [tex]p_f[/tex]  

      [tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]  

Since the collision is elastic, the kinetic energy is conserved.

      K₀ = [tex]K_f[/tex]

      ½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex]  + ½ m₂  [tex]v_f^2[/tex]  

       

Let's write our system of equations.

       [tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]

       

Let's solve

       [tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]

       

       [tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]  

         

        [tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]

In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]  

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A car of mass 1500 kg is moving with a velocity of 30 m/s. If the velocity-time graph for this car
is a horizontal line parallel to the time axis, then the velocity of the car at the end of 25 s will be

Answers

Answer:

v=30m/s

Explanation:

m = 1500kg

v = 30m/s

t = 25s

The velocity time graph is parallel to the time axis,

that means The Velocity is constant. ('constant' means remains same).

Therefore, after 25s, v=30m/s

The energy transferred per unit electric charge in a circuit is .
A current
B charge
C power
D potential difference​

Answers

Answer:

(D)

E = V Q      energy of charge Q  thus V = E / Q

If a piece of glass permits light to pass through, then it is considered ___________. A. Transparent c. Transmitting b. Reflective d. Absorbent Please select the best answer from the choices provided A B C D.

Answers

Answer:

not sure, but I thinks it's either Transparent or Reflective

According to the concept of reflection, if  a piece of glass permits light to pass through, then it is considered to be reflective.

What is reflection?

Reflection of light is defined as a property of light ray that when it strikes a smooth surface it bounces back .Objects can be seen due to this property of light.Reflection is produced by all types of waves namely sound waves, light waves, electromagnetic waves.

Reflection of light is governed by laws of reflection which are also called as Snell's laws. According to laws of reflection, angle of incidence and angle of reflection are equal.The incident ray , reflected ray and normal all lie on the same side of the plane.Light travels in a straight line before, after and during the process of reflection.There are 3 types of reflection which are diffuse reflection,specular reflection and glossy reflection.

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