These two images show pairs of oppositely charged plates that create uniform electric fields. The strength of the field on the right is twice as strong as that of the field on the left. In the field on the left, a positive charge changes position as shown. In the field on the right, a negative charge that has twice the magnitude of the positive charge is placed midway between the plates.

Two drawings with horizontal parallel plates. The top plates are positive and the bottom plates are negative. The distance between the plates are 0.1 m. On the left drawing there is a positive charge 0.04 m from the negative plate and a second positive charge a distance 0.08 m above the negative plate. There is a vector pointing from the bottom positive charge to the top positive charge. The drawing on the right has a charge of negative 2 q a distance of 0.05 m away from the negative plate.

How can the negative charge be moved in order to cause both charges to have the same change in electric potential energy?

It can be moved 0.04 m toward the positive plate.
It can be moved 0.04 m toward the negative plate.
It can be moved 0.01 m toward the positive plate.
It can be moved 0.01 m toward the negative plate

The centripetal force that a child with a mass of 45 kg feel when standing 1.0 m from the outer edge of the carousel is 127.9 N.

The centripetal force of the child is the inward force that must maintain the circular motion of the child at the given point in the circular axis without falling.

Mathematically, the formula for centripetal force is given as;

Fc = ma

where;

The centripetal acceleration of the child is calculated as;

a = v²/r

where;

a = (ω²r²) / r

a = ω²r

where;

ω = 7.2 rev/min = 7.2 rev/min x 2π rad/rev x 1 min/60s = 0.754 rad/s

Fc = ma

Fc = m(ω²r)

Fc = 45(0.754² x 5)

Fc = 127.9 N

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Answer:

Centripetal acceleration: [tex]1250\; {\rm m\cdot s^{-2}}[/tex].

Resultant force on the object should be [tex]12500\; {\rm N}[/tex].

(Assuming that the speed of the object is [tex]50\; {\rm m\cdot s^{-1}}[/tex].)

Explanation:

For an object that travels along a circle path of radius [tex]r[/tex] at a speed of [tex]v[/tex], (centripetal) acceleration will be [tex]a = (v^{2} / r)[/tex].

In this example, speed is [tex]v = 50\; {\rm m\cdot s^{-1}}[/tex] while the radius of the circular path is [tex]r = 2\; {\rm m}[/tex]. The (centripetal) acceleration of this object will be:

[tex]\begin{aligned}a &= \frac{v^{2}}{r} \\ &= \frac{(50\; {\rm m\cdot s^{-1}})^{2}}{(2\; {\rm m})} \\ &= 1250\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].

For an object of mass [tex]m[/tex], the resultant force to achieve acceleration [tex]a[/tex] is [tex]F(\text{net}) = m\, a[/tex]. In this example, [tex]m = 10\; {\rm kg}[/tex] while [tex]a = 1250\; {\rm m\cdot s^{-2}}[/tex]. The required resultant force will be:

[tex]\begin{aligned}F(\text{net}) &= m\, a \\ &= (10\; {\rm kg})\, (1250\; {\rm m\cdot s^{-2}}) \\ &= 12500\; {\rm kg \cdot m\cdot s^{-2}} \\ &= 12500\; {\rm N} \end{aligned}[/tex].

The initial vertical velocity of the object is 2.5 m/s .

Initial Velocity, denoted as u, is the velocity at time period t = 0. It is the speed at which motion first occurs. There are four equations for starting velocity: (1) The starting velocity is expressed as u = v - at if time, acceleration, and final velocity are given.

Keep in mind that the INITIAL VERTICAL VELOCITY of the projectile is equal to ZERO because it is launched horizontally.

Given,

base  =1m

height = 2.5

vertical velocity =2.5/1

The initial vertical velocity of the object is 2.5 m/s .

A projectile's initial velocity has both a horizontal component and a vertical component if it is thrown at an angle to the horizontal. The projectile's displacement horizontally as a result of velocity is shown by the horizontal velocity component (vx).

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Answer:

Below

Explanation:

V = IR

V/R = I  

    Now you can see that if you decrease R, you will need to decrease V to have the same value of I

Poor circulation is not a benefit of stretching.

How many minutes of stretching should a person perform before participating in physical activities?

Stretching for 5 to 10 minutes is probably enough for most activities. It's important, however, to adequately stretch all the muscles you'll be using. Three benefits of stretching before a workout include increased blood flow.

What are the 5 benefits of stretching?

Which benefit comes with flexibility?

Activities that lengthen and stretch muscles can help you prevent injuries, back pain, and balance problems. A well-stretched muscle more easily achieves its full range of motion.

Thus, poor circulation is the correct option.

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0.017 is the probability that tab A won’t fit into slot B

Probability is related to possibility. Random event generation is the subject of this branch of mathematics. Values ​​range from 0 to 1. Probabilities are built into mathematics to predict the likelihood of certain events.

P(tab A won't fit into slot B) = P (A>B)

                                                = P( A-B > 0)

Given that, A ≈ N(30,0.5)   B ≈ N(32, 0.8)

Here,

E (A-B) = 30-32 = -2

V(A-B) = V(A) + V(B) = (0.5)² + (0,8)²

                                   = 0.89

SD (A-B) = [tex]\sqrt{0.89}[/tex]

So, (A-B) ≈ N (-2, 0.9433)

P( A-B > 0) = 1 - P(A-B ≤ 0)

= 1 - P [(A - B +2 / 0.9433) ≤ (+2 / 0.9433)]

= 1 - P (Z₁ ≤ 2.12)

= 1 - 0.98300

= 0.017

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Both stars A and B will have the same brightness to the earth because luminosity is dependent on the temperature and size where A is hotter but smaller and B is bigger but colder.

There are several factors that determine the luminosity of a star namely, the size, temperature, distance and magnitude. The two main factors that determine luminosity of a star when the distance is the same are temperature and size.

When the temperature of a Star is higher than the other with equal distance from the earth the star is brighter than that with lower temperature. Also, when the size of a star is bigger, it possesses a higher surface area to absorb light and energy. This makes A and B as bright as the other.

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The reflected pulse will be equal to or less than incident pulse when wave pulse on a string reflects from a boundary.

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According to sect 110.12 (A) in the NEC, unused knockouts and other openings in electrical boxes and cabinets are required to be closed.

What do you understand by national electrical code?

A United States standard for the secure installation of electrical wiring and equipment is the National Electrical Code (NEC), also known as NFPA 70. It is a component of the National Fire Protection Association's National Fire Codes series (NFPA). While the NEC does not represents a U.S. law, NEC use is typically mandated by state or municipal legislation, as well as in many jurisdictions outside of the United States. The NEC standardizes and codifies the specifications for secure electrical installations. The "authority having jurisdiction" checks to see if these minimum requirements have been met.

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The force required to extend or compress a spring, divided by the lengthening or shortening of the spring, is known as the spring constant.

A vertical spring with mass M that is attached steadily lowers to its equilibrium position. This causes the spring x to lengthen. Suppose the same thing was still tied to the same vertical spring, but it was allowed to fall suddenly instead.

The maximum velocity is equal to the amplitude times the angular frequency, or v max=A v max = A, since the sine function oscillates between -1 and +1. The mass is travelling toward x=+A when the maximum velocity occurs at the equilibrium location (x=0).

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Answer:

[tex] \huge{\boxed{68,738.99 \: J}} [/tex]

Explanation:

The kinetic energy of the car can be found by using the formula

[tex] \bold{k = \frac{1}{2} \times m \times {v}^{2} \\ }[/tex]

m is the mass in kg

v is the velocity in m/s

From the question

m = 1854.5 kg

v = 8.61 m/s

[tex]k = \frac{1}{2} \times 1854.5 \times {8.61}^{2} \\ k = 927.25 \times 74.1321 \\ \\ k = 68738.989[/tex]

We have the final answer as

Given the

Half the weight of an SUV

If the mass of the SUV is 2m, the mass of the car is m

An SUV can produce twice as much power as a car, or 2 F.

Experience acceleration in an SUV

;SUV=2F/2m

;SUV=F/m

car acceleration

; car = F/m

They both start with an initial velocity of zero, so after a few seconds they have the same velocity and share the same position.

speed-

Velocity is a vector representation of the displacement an object or particle experiences with respect to time. The standard unit for velocity magnitude (also called velocity) is meters per second (m/s). Alternatively, centimeters per second (cm/s) can be used to express velocity magnitude. The direction of the velocity vector can be expressed in different ways depending on the number of dimensions involved. speed

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Area T represents the distance travelled by the object whilst moving at a constant speed. Option (C) is correct.

The distance an object travels in a unit of time is its speed. Speed is a scalar quantity since it has simply magnitude and no direction. SI unit of speed is meter per second.

Hence, mathematically:

Speed = distance travelled/time interval.

Distance travelled = speed × time interval.

In the given graph, area T represents  constant speed × time interval. Hence, area T is equal to the distance travelled by the object moving at a constant speed.

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Answer:

As little as 10 percent of the energy at any trophic level is transferred to the next level; the rest is lost largely through metabolic processes as heat.

Explanation:

Answer:

Heat Loss = Heat Gain

(60 - T) K1 M1 = (T - 10) K2 M2

M1 = metal        M2 = liquid

K1 = metal         K2 = liquid

(60 - T) K1 * 1 = (T - 60) K2 * 5

60 K1 - T K1 = 5 T K2 - 300 K2

T (5 K2 + K1) = 300 K2 + 60 K1

T = (300 K2 + 60 K1) / (5 K2 + K1)

Need to find largest T

(probably ethanol and iron - you will need to check)

The acceleration of the luggage across the airport is 0.42 m/s².

The acceleration of the luggage across the airport is calculated by applying Newton's second law of motion as follows;

Mathematically, the Newton's second law of motion is given as;

F(net) = ma

where;

F - Ff = ma

where;

33.3  - 12.3  = 50a

21 = 50a

a = 21/50

a = 0.42 m/s²

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The complete question is below:

Jadee pulls a piece of luggage across the airport, notices that she is lagging behind her parents and wants to catch up for a short amount of time. She pulls with a horizontal force of 33.3 N. The force due to friction for the luggage is 12.3 N and the mass of the luggage is 50.0 kg. find the acceleration of the luggage.

The peak out of phase voltage also becomes doubled with increase in frequency .

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The magnitude of the gravitational force is 7×10⁻⁷ N

Baby weighs (m₁) 4.20 kg.

Father weighs (m₂)  100 Kg.

The gravitational force (F) between the body and the earth has a magnitude of 6.67×10⁻

The separation between them is: 0.200 m

The gravitational constant is

F=Gm₁×m₂÷ R²

F= 6.67×10⁻¹¹×4.20×100÷ (0.200)²

F= 7×10⁻⁷ N

Gravitational force: The gravitational force between any two mass-containing objects causes them to be drawn together. The gravitational force is said to as attractive because it continually seeks to unite masses rather than to drive them away. In truth, you and everything else in the universe are being pulled in different directions. It is referred to as Newton's Universal Law of Gravitation.

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The action that best describes the camera motion in the scenes directly prior to the Old Man's Defiant hand gesture is: "Zooming in and out" (Option C)

Some interesting camera motions are:

Note that the different camera motions described above are important because they allow filmmakers to convey mood and emotion, create visual interest, and guide the audience's attention within a scene.

For example, a static shot can create a sense of calm or stability, while a handheld shot can create a sense of intimacy or instability. A panning shot can follow the action and keep the audience engaged, while a zoom shot can draw attention to a specific part of the scene.

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Full Question:

What best describes the camera motion in the scenes directly prior to the old man's defiant hand gesture?

O Static and secured on a tripod

O Moving chaotically

O Zooming in and out

O Filming at 96 frames a second

According to the given statement [tex]\sqrt{2h}[/tex] and [tex]2\sqrt{3h}[/tex] and is the angular momentum of a hydrogen atom.

Momentum may be viewed as a body's "power" while it is moving, or the amount of force it can exert on another body. For instance, a slow-moving bowling ball might have the same acceleration as a baseball being thrown fast.

Briefing:

The angular momentum of a hydrogen atom can be defined as:

[tex]L=\sqrt{l(l+1)}h,[/tex]

where l represents the orbital quantum number which defines the subshells s, p, d, f.

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surface gravity formula

[tex]g=\frac{GM}{r^{2} }[/tex]

[tex]g[/tex] is the surface gravity in m/s²

[tex]G[/tex] is the gravitational constant 6.67408x10⁻¹¹ m³/kgs²

[tex]M[/tex]  is the mass of the object in kg

[tex]r[/tex] is the radius of the object in  m

The Earth’s mass is 5.972x10²⁴kg,

Jupiter’s mass is 1.898x10²⁷ kg,

the Earth’s radius is 6371 km,

Jupiter’s radius is 69911 km

[tex]g=\frac{6.67408X10^{-11}X5.972X10^{24} }{(6.371X10^{6} )^{2} }[/tex]

[tex]g=9.82 m/s^{2}[/tex]

[tex]g=\frac{6.67408X10^{-11}X1.898X10^{27} }{(6.9911X10^{7} )^{2} }[/tex]

[tex]g=25.92 m/s^{2}[/tex]

conclusion

[tex]\frac{25.92}{9.82} = 2.63[/tex]

the surface gravity of Jupiter is 2.63 times that of Earth.

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It is true that when weights is normally distributed, students who weigh between 60 kg and 75 kg is 476.

Mean is the average of given observations and we can calculate mean by dividing sum of observation by the total number of observation.

A standard deviation shows how much data is dispersed in relation to mean. Low deviation indicates that data are clustered and high deviation means data are scattered.

Mean weight is 70 kg and standard deviation is given 3 kg.

α1 = 75 - 70 / 3 = 1.67

α2 = 60- 70/3 = 3.33

So, P( α2- α1) = 0.9375- (1- 0.9666)

                      = 0.9371

The number = 500 ×0.9371

                     = 467

So, the statement is true.

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After doing the equation the total mass is 1.53×10^-3kg .

What is the magnetic force of attraction?

Similar poles or charges will typically repel one another. Thus, the two magnets will push against one another. Repulsion is the name given to a force that causes objects to move apart from one another.

between two or more comparable or similar charges there is a force. Similar charges are attracted to one another. Charges that share a similar appearance separate. Chemical bonding is characterized by repulsive forces.

Create a formula for the magnetic force to equal the normal force, and then enter the necessary values into the expression to obtain the mass.

FN=F

mg=µo I1 I2 L÷2πr

m=µo I1 I2 L÷2πrg

 = 4π×10^-7T-m/A (15A) (15A)(0.50m)÷2π(0.0015m)(9.8m/s²)

= 1413÷0.0923×10^-7

= 1.53×10^-3kg

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The center of mass must be found in order to analyze issues involving the flow of matter when subjected to forces, or dynamics.

Motion is the alteration of a skin's position or orientation over time. The movements of people and animals is just one illustration of how everything in the cosmos is always moving. In addition, the fundamental building block of matter, the atom, is likewise constantly in motion.

Motion is the free flow of a body in relation to time. For instance, the fan, the carpet's dust blowing off of it, the water running from the faucet, a ball rolling about, a moving car, etc. Even just the universe is always changing.

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Train must move with equal speed as of platform in opposite direction i order to maintain zero relative velocity.

Velocity is the speed in which something move in a paticular Direction.

From the question it is given that

relative velocity between platform and train = 0

since relative velocity of train with respect to platform is given by

where,  is the velocity of train and  is the velocity of platform

⇒ vt = vp

since platform is always at stationary i.e.,

thus train velocity  = 0

Therefore, train does not move

If, Platform is moving then train must move with equal speed as of platform in opposite direction.

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The propagation speed of the waves is v = 1.1009 m/s

Waves' progression and transformation through space and time. The article will examine several definitions in addition to the usual one for wave propagation.

There are numerous crests and troughs that sound waves travel over. II Sound waves need a physical medium to travel through. III The movement of particles is thought to be responsible for the propagation of sound waves.

Transverse waves include electromagnetic waves like X-rays, radio waves, and visible light. Electric and magnetic fields moving in a perpendicular direction make up these waves. The best examples of longitudinal waves, which vibrate parallel to the direction of the wave, are sound waves.

The formula is

v = fλ

given distance is 5.45 m

and the number of times the bridge is shaken is 3 times

this implies

v = 3 / 5.45 × 2

v = 1.1009 m/s

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acceleration during the constant speed is the  friction acceleration which is 3 ms^-2.

Accelaration is the eate of the change of the velocity of an object with respect by time.

Accelaration (a) id the reason that change in velocity over to the change in time.

Represented by the equation to a= ∆v/∆t. This is allowa you to measure how fast velocity by the changes in meters per second squars (m/s^2).

Here mass is 14 KG box

Here friction force applied by the  because of rough place so that it stopped in 2 seconds

So acceleration by friction is negative sense and 6/2 or 3 ms^-2

So static frictional force is = 14×3 or 54 which is greater  than the  applied force

So the acceleration during the constant speed is the  friction acceleration which is 3 ms^-2.

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if 5ev of energy is supplied to an electron with a binding energy of 2.3ev, with what kinetic energy is [tex]\Rightarrow \mathrm{KE}=5-2.3=\mathbf{2 . 7} \mathrm{eV}[/tex]

What is kinetic energy?

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Photoelectric effect: The photoelectric effect is a phenomenon where electrons are ejected from a metal surface when the light of sufficient frequency is incident on it. These ejected electrons are called photoelectrons.

- When a photon falls on the metal surface, the photon's energy is transferred to the electron.

- Some part of the energy gets utilized in removing the electron from the metal surface, and the remaining goes into giving kinetic energy for the ejected electron.

- Work function [tex](\phi)[/tex]: It is the minimum amount of energy required to cause photo-emission of electrons from a metal surface when light is incident on it.

- Einstein's Photoelectric Equation gives the relationship between work function[tex](\phi)[/tex], the kinetic energy of the emitted electron, and the energy of the photon [tex](E)[/tex]

[tex]$$E=\phi+K E$$[/tex]

Given that:

Energy of incident light, [tex]E=5 \mathrm{eV}[/tex]

Work function,[tex]$\phi=2.3 \mathrm{eV}$[/tex]

Using Einstein's Photoelectric Equation,

[tex]$$\begin{aligned}& \mathrm{E}=\phi+\mathrm{KE} \\& 5=2.3+\mathrm{KE} \\& \Rightarrow \mathrm{KE}=5-2.3=\mathbf{2 . 7} \mathrm{eV}\end{aligned}$$[/tex]

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The temperature rise of the iron is 13.33°C

Calorimetry is the science of measuring the heat absorbed or evolved during the course of a chemical reaction or change of state.

The heat gained or released during a calorimetry procedure can be calculated as follows:

Q = mc∆T

Where;

According to this question, a 5kg block of iron with a specific heat capacity of 450 J/kg °C recieves 0.03 MJ of energy. The change in temperature can be calculated as follows:

30,000J = 5 × 450 × ∆T

30000 = 2250∆T

∆T = 30000 ÷ 2250

∆T = 13.33°C

Therefore, 13.33°C is the temperature rise.

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Answer:hope this helps

pleasee i need the brainliest

Explanation: Warm air rises and is replaced by cooler air from the surrounding area. The warm air eventually cools off, falling down and replacing more warm air. This causes a constant upward flow sometimes called a thermal that allows large birds to soar without effort.