Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
The formation of faults in Earth's crust is an effect. What causes faults to form in the crust? Global Positioning System sensors beds shaking across New York City the movement of tectonic plates landslides across the Midwest
Answer: The movement of tectonic plates
Explanation:
Tectonic plates are the part of the earth's crust that both the ocean and land rest on. These plates are constantly moving as a result of currents in the mantle.
These movements cause stress on the surface which has the effect of fracturing rocks and thereby creating/ forming faults in the earth's crust. Sometimes faults form when these plates move away from each other and sometimes they are formed when they push into each other.
The larger the displacement of an engine, the less power it produces true or false
Answer: False
Explanation:
How much computer memory (in bytes) in minimum would be required to store 10 seconds of a sensor signal sampled by a 12-bit A/D converter operating at a sampling rate of 5 kHz?
Answer:
73.24 K byte
Explanation:
Assuming that
N = total number of samples
N = 10 * 5kHz
N = 50*10^3
Also, the total number of bits, T
T = 12 * N
T = 12 * 50*10^3
T = 600 * 10^3
And then, finally, the total number of byte,
B = 600*10^(3/8)
B = 75*10^3 byte
75*10^3 byte = 75*10^3/1024 kilo byte
And on converting to decimal, we will have
= 73.24 K byte
Therefore, the memory required = 73.24 K byte
For a RC Low Pass filter, what is the approximate amplitude (as a decimal proportion of input amplitude) at 1/4 the cutoff frequency?
Answer:
Explanation:
RC low Pass Filter is an electronic circuit that comprises of a resistor and capacitor and it functions to permit low-frequency signals depending on the design and reject the high-frequency signals above a given frequency known as the cutoff frequency.
From the diagram attached below:
[tex]V_{in[/tex] = the input signal
[tex]V_o[/tex] = the output signal
Since; [tex]V_o[/tex] is used across the capacitor C,
By using the potential divider equation we have:
[tex]V_o =V_{in} \times \dfrac{X_C}{\sqrt{ R^2+X_C^2} }[/tex]
From above; [tex]X_C[/tex] = capacitive reactance ;
and The total impedance Z is illustrated as [tex]Z = \sqrt{R^2+X_C^2}[/tex]
Thus;
[tex]V_o =V_{in} \times \dfrac{X_C}{Z}[/tex]
Recall that;
[tex]X_C = \dfrac{1}{2 \pi fC}[/tex]
Here; f denotes the frequency of the input signal
Since the cutoff frequency is related to the frequency at which the capacitive reactance and resistance are said to be the same, then:
The Cutoff frequency can be expressed as:
[tex]F_C = \dfrac{1}{2 \pi RC}[/tex]
Also;
the frequency of input signal [tex]f = \dfrac{F_c}{4}[/tex]
[tex]f = \dfrac{1}{8 \pi RC}[/tex]
Hence;
[tex]X_C = \dfrac{1}{2 \pi fC}[/tex]
[tex]X_C = \dfrac{1}{2 \pi \times \dfrac{1}{8 \pi RC} \times C}[/tex]
[tex]X_C = 4R[/tex]
Finally;
From [tex]Z = \sqrt{R^2+X_C^2}[/tex]
[tex]Z = \sqrt{R^2+(4R)^2}[/tex]
[tex]Z = \sqrt{17R^2}[/tex]
Z [tex]\simeq[/tex] 4.12R
As such, the output will be:
[tex]V_o =V_{in} \times \dfrac{X_C}{\sqrt{ R^2+X_C^2} }[/tex]
[tex]V_o =V_{in} \times \dfrac{4R}{4.12R^2} }[/tex]
[tex]V_o =0.97V_{in}[/tex]
So, if we regard [tex]A_{in}[/tex] to be the input amplitude, then [tex]A_{out}[/tex] i.e the output amplitude will also be [tex]A_{out}[/tex] = [tex]0.97 A_{in}[/tex]
which term describes how a mineral looks when it breaks apart in an irregular way
Answer:
Fracture.
Explanation:
Fracture describes how a mineral looks when it breaks apart in an irregular way.
Answer:
Fracture.
Explanation:Fracture describes how a mineral looks when it breaks apart in an irregular way.
In the NiTi system, there are a number of invariant transformations and solid state phases. How many degrees of freedom are there in the two phase regions and at the invariant points?
Answer:
we have zero degree of freedom (F = 0) at the first phase region and one degree of freedom (F = 1) at the second phase region
Explanation:
given the diagram;
C = 2 { Ti and Ni}, N = 1 {Pr is constant}, P = 3 { L and B}
For degree of freedom,
Gibbs phase rule is applied for invariant point (ex.A)
P + F = C + N
3 + F = 2 + 1
F = 3 - 3
F = 0
For the second phase region ( ex.B)
C = 2, N = 1, P = 2
P + F = C + N
2 + F = 2 + 1
F = 3 - 2
F = 1
Therefore we have zero degrees of freedom (F = 0) at the first phase region and one degrees of freedom (F = 1) at the second phase region
A semiconductor, in thermal equilibrium, has a hole concentration of p0 = 2x1016 cm-3. The minority carrier life time = 3x10-7 s. (Assume, ni = 1010 cm-3)
(a) Determine the thermal equilibrium recombination rate of electrons.
(b) Determine the recombination rate of electrons if an excess electron concentration of În = 1013 cm-3 exists.
(c) Calculate the change in the recombination rate when excess electron concentration exists (compared to thermal equilibrium).
Answer:
[tex]1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
[tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
[tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
Explanation:
[tex]p_0[/tex] = Hole concentration = [tex]2\times 10^{16}\ \text{cm}^{-3}[/tex]
[tex]n_i[/tex] = Intrinsic concentration = [tex]10^{10}\ \text{cm}^{-3}[/tex]
[tex]\tau_{n0}[/tex] = Minority carrier life time = [tex]3\times 10^{-6}\ \text{s}[/tex]
[tex]\delta n[/tex] = Excess concentration of electrons = [tex]10^{13}\ \text{cm}^{-3}[/tex]
Majority carrier electron concentration is given by
[tex]n_0=\dfrac{n_i^2}{p_0}\\\Rightarrow n_0=\dfrac{(10^{10})^2}{2\times 10^{16}}\\\Rightarrow n_0=5000\ \text{cm}^{-3}[/tex]
Recombination rate is given by
[tex]R_{n0}=\dfrac{n_0}{\tau_{n0}}\\\Rightarrow R_{n0}=\dfrac{5000}{3\times 10^{-6}}\\\Rightarrow R_{n0}=1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
The recombination rate is [tex]1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
Recombination rate is given by
[tex]R_n=\dfrac{\delta_n}{\tau_{n0}}\\\Rightarrow R_n=\dfrac{10^{13}}{3\times 10^{-7}}\\\Rightarrow R_n=3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
The recombination rate is [tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
Change in the recombination rate is
[tex]\Delta R_n=3.33\times 10^{19}-1.67\times 10^{9}\\\Rightarrow \Delta R_n=3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
The change in the recombination rate is [tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
What do engineers spend up to 25 percent of their design process formulating and analyzing?
the team that will work on the project
if a material is malleable
if a design will need a functional or superficial improvement
the perfect material for their design
Answer:
Engineers spend up to 25 percent of their design process formulating and analyzing
the team that will work on the project.
Explanation:
During the design engineering stage of a project, the team is a very important decision item because determining the required team also determines the cost and the technical skill requirements of the project. The cost depends, to a large extent, on the technical skills of those that will work on the project. When the technical skill requirements are not met, the project will be massively jeopardized.
Answer:
the team that will work on the project.
Explanation:
What is the first step to cutting internal threads on an engine lathe?
Answer:
zero off your workpiece so you can work from a datum, usually the centre of your work on a lathe. change your tool to a drill and drill a hole to a size smaller than your thread diameter, change out your tool for a threaded tap and away you go.
I'm not sure which part they want but I'd say ensure your tool is set to the right height, you have the tool lines up where you want to cut and that you have calculated the speed you need to cut at safety. Drill a hole before you tap though.
If you have a CNC lathe you just set the programme to do the processes and tool change for you.
The first step to cutting internal threads on an engine lathe is to make calculations so that the thread will have proper dimensions.
What is lathe threading?The technique of thread cutting on the lathe results in a helical ridge with a consistent section on the workpiece.
To work from a datum, often the center of your work on a lathe, zero off your workpiece. Use a drill to create a hole that is less in diameter than the thread, then switch to a threaded tap and carry on.
One would advise making sure your tool is adjusted to the appropriate height, that it is lined up where you want to cut, and that you have determined the speed you must cut in order to be safe. Before you tap, drill a hole.
With a CNC lathe, you can simply program the machine to perform the processes and tool changes for you.
Therefore, to do this, make a series of cuts with a threading toolkit that matches the needed thread form.
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25points and brainliest if correct A, B, C, D
Which option distinguishes the most appropriate action to take next in the following scenario?
Lisa is a new worker on a farm. She needs to access an area of the farm at the top of the hill on a tractor. She tries backing the tractor up the slant and finds that it will not make the ascent.
A. Lisa should drive across the hill at an angle to get to the top.
B. Lisa should reach the top of the hill by finding a less steep path.
C. Lisa should drive forward up the hill at a slow pace to get to the top.
D. Lisa should reach the top of the hill by finding a more experienced driver.
Answer:A
Explanation:
B - it never talked about a steep path or not.
C- it never stated the speed.
d- more experienced driver makes a little bit of sence since she is new but she is new at the farm not driving.
thats my guess.
Answer:
b is the answer
Explanation:
Pure aluminum is poured into a sand mold. The metal level in the pouring basin is 10 in. above the metal level in the mold, and the runner is circular with a 0.4-in. diameter. What are the velocity and rate of the flow of the metal into the mold? Is the flow turbulent or laminar? 10.44 A cylinder with a diameter of 1.5 in. and height of 3 in. solidifies in 3 minutes in a sand casting operation. What is the solidification time if the cylinder height is doubled? What is the time if the diameter is doubled?
Solution :
Given :
Height at which the metal is poured, h = 10 in
Diameter of the runner , d = 0.4 in
Assume viscosity, μ = 0.004 Pa-s
Now considering Bernoulli's equation to find velocity,
As there is no loss in energy, Δ Pressure energy ≅ 0
So,
[tex]$\frac{v^2_1}{2g}+z_1=\frac{v^2_2}{2g}+z_2$[/tex]
Here 1 and 2 represents top and bottom section of the sprue.
[tex]$\frac{v^2_1}{2g}+z_1=\frac{v^2_2}{2g}+z_2 \ \ \ (v_1=0)$[/tex]
[tex]$v_2=\sqrt{2g \Delta z}$[/tex]
Now substituting [tex]$32.20 \ ft/s^2 = 386.4 \ in/s^2$[/tex] for g and 10 in for Δz in velocity equation,
[tex]$v_2=\sqrt{2 \times 386.4 \times 10}$[/tex]
[tex]$v_2= 87.91 \ in\s = 7.32 \ ft/s$[/tex]
Calculating the area of the basin
[tex]$A=\frac{\pi}{4}d^2$[/tex]
Substitute .04 in for d in the above equation
[tex]$A =\frac{\pi}{4} \times (0.4)^2$[/tex]
[tex]$A= 0.1256 \ in^2$[/tex]
Calculating the flow rate
Q = 0.1256 x 87.91
[tex]$ Q= 11 .04 \ in^3/s $[/tex]
Hence the viscosity is [tex]$v_2 = 87.91 \ in/s$[/tex] and the flow rate is [tex]$Q=11.04 \ in^3/s$[/tex]
Calculating the Reynolds number of the flow,
[tex]$Re = \frac{\rho v d}{\mu}$[/tex]
[tex]$Re = \frac{0.097544 \times 87.91 \times 0.40}{5.8 \times 10^{-7}}$[/tex]
[tex]$Re=5.9 \times 10^6$[/tex]
Therefore, the flow is turbulent.
Now considering the solidification time,
[tex]$t=c \times \left(\frac{V}{A}\right)^2$[/tex]
[tex]$t=c \times \left(\frac{\frac{\pi}{4}d^2h}{2\left(\frac{\pi}{4}d^2\right)+ \pi dh}\right)^2$[/tex]
[tex]$t=c\left(\frac{dh}{2d+4h}\right)^2$[/tex]
Substituting 1.5 for d and 3 for h and 3 min for t to calculate the value of c is
[tex]$3=c\left(\frac{1.5 \times 3}{2 \times 1.5 + 4 \times 3} \right)^2$[/tex]
c = 33.33
For case when height is double i.e. h = 6 in
[tex]$t_h = 33.33 \times \left(\frac{1.5 \times 6}{2 \times 1.5 + 4 \times 6} \right)^2$[/tex]
[tex]$t_h= 3.70 \ min$[/tex]
For case when the diameter is doubled i.e. 3 in for d and 3 in for h,
[tex]$t_d = 33.33 \times \left(\frac{3 \times 3}{2 \times 3 + 4 \times 3} \right)^2$[/tex]
[tex]$t_d= 8.3325 \ min$[/tex]
Engineering economics deals with
Answer:
It is a branch of engineering that deals with the formulation, estimation and evaluation of economic outcomes when there are alternatives to accomplish a defined purpose.
Explanation:
Engineers are able to evaluate the cost and benefits of projects that involve engineering designs and analysis through systematic approach. This process quantifies the costs and benefits of the projects to see enough money is saved to allow capital investments.
Suppose the working pressure for a boiler is 10 psig, then what is the corresponding absolute pressure?
Answer:
The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.
Explanation:
From Fluid Mechanics, we remember that absolute pressure ([tex]p_{abs}[/tex]), measured in pounds per square inch, is the sum of the atmospheric pressure and the working pressure (gauge pressure). That is:
[tex]p_{abs} = p_{atm}+p_{g}[/tex] (1)
Where:
[tex]p_{atm}[/tex] - Atmospheric pressure, measured in pounds per square inch.
[tex]p_{g}[/tex] - Working pressured of the boiler (gauge pressure), measured in pounds per square inch.
If we suppose that [tex]p_{atm} = 14.696\,psi[/tex] and [tex]p_{g} = 10\,psi[/tex], then the absolute pressure is:
[tex]p_{abs} = 14.696\,psi+10\,psi[/tex]
[tex]p_{abs} = 24.696\,psi[/tex]
The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.
A steel rod of circular cross section will be used to carry an axial load of 89 kips. The maximum stresses in the rod must be limited to 31 ksi in tension and 14 ksi in shear. Determine the required diameter for the rod.
Answer:
d = 1.9 in
Explanation:
Since, the tension force is greater than the shear force. Hence, the area of cross-section shall be limited by the tension:
Tension = Force/Area
Area = Force/Tension
Area = 89 kips/31 ksi
Area = 2.87 in²
but,
Area = πd²/4
2.87 in² = πd²/4
(2.87 in²)(4)/π = d²
d = √(3.65 in²)
d = 1.9 in
Define ways in which you would go about networking to explore opportunities in your career field and obtain more information for yourself. If applicable, explain ways in which you have already done that and how you will expand going forward. Choose one person in your career field that you would like to have a conversation with. What do you think you can learn from this person?
Answer:
mmmmmm
Explanation:
ffmfmfmmfmfmmfmfmfmfmfmffmfmfmfmfmfmfmfmfmfmfmfmfffmmfmffmmmfmfmfmfmfmfmfmfffmfmfmfmfmfmmfmfmmfmfmfmfmfmfffmfmfffmfmfmfmffmmfmfmffmfmfmfmfffmfmfmfmfmmmmfmfmfmfmfmfmfmmmfmfmfmfmfmfmfmfmmfmfmfmfmfmfmfmfmfmfmffmfmfmfmfmfmmfmfmmmmmfmfmfmffmfmfmfmffmffmfm
What is the output? for num in range(3): print (num + 5)
Answer: 5 6 7
Explanation:
you can run this in python and get this result
The output for the given program is: 5 6 7
What is Python Programming Language?This refers to the high-level language that was created and is used for data structures due to its OOP (object-oriented programming).
Hence, this python code asks for an array of numbers in the range of 3 and when that is found, it should make a display of the number and increment it.
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Which reference source may be consulted to answer questions regarding the Professional Engineers Act?
(a) The Business and Professions Code
(b) The California Code of Regulations
(c) The Professional Engineers Act and Board Rules
(d) All of the above
The reference source that can be consulted is C. The Professional Engineers Act and Board Rules
The reference source that may be consulted to answer questions regarding the Professional Engineers Act is the Professional Engineers Act and Board Rules.
The Professional Engineers Act and Board Rules is an Act that was established in order to regulate the qualifications for professional engineers, register them and also make sure that their conducts and behavior are looked into.
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20 points and brainliest is it A, B, C, D
Using your Greek roots and context clues, figure out the meaning of “fissures” in this sentence and select the best definition:
“Look at these recent fissures in the granite roof”
A. an opening made by splitting
B. a crack made from crushing
C. a line made from evaporation
D. a line made from sediment deposits
Answer:
B
Explanation:
Consider fully developed flow in a circular pipe with negligible entrance effects. If the length of the pipe is doubled, the head loss will:_________
(a) double,
(b) more than double,
(c) less than double,
(d) reduce by half, or
(e) remain constant.
Fully developed flow in a circular pipe with negligible entrance effects. If the length of the pipe is doubled, the head loss will double.
What is Negligible entrance?The amount of piping head loss is computed by equating the lengths and distances of all fittings to a particular inner pipe diameter. The length of a flow through a conduit before it completely develops is referred to as the entry length in fluid dynamics.
Entrance length is the length of the entry zone, which is the area immediately following the pipe entrance where effects from the inner wall of the pipe disseminate into the flow as an expanding boundary layer.
As the boundary layer completely fills the pipe and the flow characteristics stop changing as the pipe's length rises, the emerging flow becomes fully formed.
Therefore, Fully developed flow in a circular pipe with negligible entrance effects. If the length of the pipe is doubled, the head loss will double.
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.................................................
Answer:
................................................
Explanation:
plz mark B R A I N L I E S T
lol
Answer the following questions about your own experience in the labor force.
a. When you or one of your friends is looking for a part-time job, how many weeks does it typically take? After you find a job, how many weeks does it typically take?
b. From your estimates, calculate (in a rate per week) your rate of job finding, f, and your rate of job separation, s. (Hint: If f is the rate of job finding, then the average spell of unemployment is 1/f.)
c. What is the natural rate of unemployment for the population you represent?
Answer:
Following are the solution to this question:
Explanation:
In point a:
This takes me six weeks for both the took ideas that I was searching for but it continued for 3 years (12 weeks) as it's an intern.
In point b:
Finding job:
[tex]\to f = \frac{1}{6} = 0.166[/tex] jobs weekly
Separation of jobs:
[tex]\to \frac{ 1}{12}=0.083[/tex] employment per week.
In point c:
Its natural rate of unemployment is: [tex]\frac{U}{L} = s+(s \times f)[/tex].
The normal level of employment for that community I represent, once we add up from that preceding section, is as follows:
[tex]\to \frac{U}{L} = 0.083+ (0.083\times 0.166) = 0.096[/tex]
If on average, it requires six weeks to find another job or the work lasted 12 weeks, the group's unemployment level is [tex]0.096 \ \%[/tex].
A rigid tank contains 2 kg of N2 and 4 kg of Co2 at temperature of 25 C and 1 MPa. Find the partial pressure of each gas respectively?
Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.
Explanation: Dalton's Law of Partial Pressure states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:
[tex]P_{total} = P_{1}+P_{2}+...[/tex]
The proportion of each individual gas in the total pressure is expressed in terms of mole fraction:
[tex]X_{i}[/tex] = moles of a gas / total number moles of gas
The rigid tank has total pressure of 1MPa.
Nitrogen gas:molar mass = 14g/mol
mass in the tank = 2000g
number of moles in the tank: [tex]n=\frac{2000}{14}[/tex] = 142.85mols
Carbon Dioxide:molar mass = 44g/mol
mass in the tank = 4000g
number of moles in the tank: [tex]n=\frac{4000}{44}[/tex] = 90.91mols
Total number of moles: 142.85 + 90.91 = 233.76 mols
To calculate partial pressure:
[tex]P_{i}=P_{total}.X_{i}[/tex]
For Nitrogen gas:
[tex]P_{N_{2}}=1.\frac{142.85}{233.76}[/tex]
[tex]P_{N_{2}}[/tex] = 0.6
For Carbon Dioxide:
[tex]P_{total}=P_{N_{2}}+P_{CO_{2}}[/tex]
[tex]P_{CO_{2}} = P_{total}-P_{N_{2}}[/tex]
[tex]P_{CO_{2}}=1-0.6[/tex]
[tex]P_{CO_{2}}=[/tex] 0.4
Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.
Ground effect is felt at a height that is equal to the plane's wingspan.
True or False
Answer:
True
Explanation:
A 18-ft thick clay layer in the field (drained on one side) is normally consolidated. When the pressure is increase from 0.75 ton/ft^2 to 1.5 ton/ft^2, the void ratio decreases from 1.12 to 0.98. The hydraulic conductivity, k, of the clay during the above loading range was found to be 4.3 times 10^-7 cm/sec. a. How long (in days) will it take for the clay layer to reach 70% reach 70% consolidation? b. What is the settlement at that time (that is, at 70% consolidation)?
Answer:
a) 294.34 days
b) Δh = 25.361 cm
Explanation:
Given data:
Thickness of clay layer = 18 ft
initial pressure = 0.75 ton/ft^2
final pressure = 1.5 ton/ft^2
Δp = 0.75 ton/ft^2
eo = 1.12
e1 = 0.98
k = 4.3 * 10^-7 cm/sec
A ) determine how long it will take to reach 70% consolidation
attached below is the detailed solution
T( time in days ) = 294.34 days
B) determine settlement at 70%
attached below is the detailed solution
Δh = 25.361 cm
A cylinder with a height-to-diameter ratio of unity solidifies in 10 minutes in a sand casting operation. What is the solidification time if the cylinder height is doubled? What is the time if the diameter is doubled? Use n=1.5.
Answer:
a) 13 mins
b) 18 mins
Explanation:
solidification time = 10 minutes
height-to-diameter ratio = 1
applying the expression for calculating solidification time
t = B [tex](\frac{V}{A} ) ^n[/tex] --------- ( 1 )
n = 1.5
B = ?
t = 10 minutes
V = [tex]\frac{\pi d^2}{4} H[/tex]
A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex]
back to equation 1
making B subject of the formula ; B = [tex]\frac{147}{d^{1.5} }[/tex]
a) Determine the solidification time if the cylinder height is doubled
t = B [tex](\frac{V}{A} ) ^n[/tex]
substitute : B = [tex]\frac{147}{d^{1.5} }[/tex] , H = 2D , V = [tex]\frac{\pi d^2}{4} H[/tex] , A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex] , n = 1.5
therefore ; t ( solidification time when height is doubled ) ≈ 13 mins
b) Determine the time if the diameter is doubled
t = B [tex](\frac{V}{A} ) ^n[/tex]
substitute ; B = [tex]\frac{147}{h^{1.5} }[/tex] , D = 2H , n = 1.5 , V = [tex]\frac{\pi d^2}{4} H[/tex], A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex]
therefore ; t ( solidification time when diameter is doubled ) ≈ 18 mins
Estimate the luminosity of a 3 -solar-mass main-sequence star; of a 9 -solar-mass main-sequence star. Can you easily estimate the luminosity of a 3 -solar-massred giant star?
Answer:
a) 46.76 Lsun
b) 2187 Lsun
c ) You can easily estimate the luminosity of a 3-solar massed giant star because its luminosity is close to the luminosity of the sun
Explanation:
To estimate the luminosity of a celestial body in terms of solar luminosity we use the expression below
= [tex]\frac{L}{Lsun} = (\frac{M}{Msun} )^{3.5}[/tex]
a) Estimate the luminosity of a 3 solar mass main sequence star
= [tex]\frac{L}{Lsun} = (\frac{3M}{Msun} )^{3.5}[/tex]
Hence ; L(luminosity of a 3 solar mass star ) = 46.76 Lsun
b) Estimate the luminosity of a 9-solar-mass main sequence star
= [tex]\frac{L}{Lsun} = (\frac{9M}{Msun} )^{3.5}[/tex]
hence L( luminosity of a 9-solar mass star ) = 2187 Lsun
c ) You can easily estimate the luminosity of a 3-solar massed giant star because its luminosity is close to the luminosity of the sun
A) The luminosity of a 3 -solar-mass main-sequence star is; L = 46.765L_sun
B) The luminosity of a 9 -solar-mass main-sequence star is; L = 2187L_sun
C) Yes, we can easily estimate the luminosity of a 3 -solar-mass main-sequence star.
We want to find luminosity of a solar body which in this case is a main sequence star. The formula in terms of solar luminosity is;
L/L_sun = (M/M_sun)^(3.5)
Where;
L is luminosity of the solar body
L_sun is luminosity of the sun
M is mass of the solar body
M_sun is mass of the sun
A) Thus;
For a 3 -solar-mass main-sequence star;
M = 3M_sun
Therefore;
L/L_sun = (3M_sun/M_sun)^(3.5)
L/L_sun = 3^(3.5)
L/L_sun = 46.765
L = 46.765L_sun
B) For a 9-solar-mass main-sequence star;
L/L_sun = (9M_sun/M_sun)^(3.5)
L/L_sun = 9^(3.5)
L/L_sun = 2187
L = 2187L_sun
C) We can see from answer A above that the luminosity of a 3 solar mass body is 46.765 times of the luminosity of sun. Since it's not so much bigger than the luminosity of sun, then it is easy to estimate.
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20 points and brainliest is it A, B, C, D
Which option identifies the informational resource that would be best to use in the following scenario?
When Daniel reached for a container of oil that someone had left on a high, hard-to-reach shelf, he accidently knocked over another container of liquid that spilled onto the floor. He was unsure of the second chemical's properties or how to clean it up.
A. the MSDS binder
B. the OSHA hotline
C. the poison control center
D. the machine shop manager
Answer:
c
Explanation:
A speed reducer is rated at a maximum input speed of 2609 rpm and a maximum input power of 8 horsepower. The speed reduction ratio is 1:25, and the service factor is 1.15. What is the maximum input power?
Answer:
9.2 hp
Explanation:
Service factor is the ratio of the gearbox rated horsepower (or torque) to the application's required horsepower (or torque)
SF = Pₒ / Pᵢ
Pᵢ = Pₒ × SF
Pᵢ = 8 hp × 1.15
Pᵢ = 9.2 hp
The beam below will be subjected to a live load of 600 lb/ft, a concentrated live load of 25 kip, and a dead load of 300 lb/ft. a) What is the maximum positive moment that can be produced at G? b) What is the maximum negative moment that can be produced at G?
Answer:
hello some part of your question is missing below is the complete question
answer :
A) 162750 Ib.ft
B) - 64950 Ib.ft
Explanation:
Applying Muller-Breslau's law
we will make assumptions which include assuming an imaginary hinge at G
therefore the height of I.LD for B.M at G = ( 12 * 8 ) / 20 = 4.8
height of I.L.D at C = 2.4 ( calculated )
height of I.L.D at F = 1.5 ( calculated )
A) Determine Maximum positive moment produced at G
[tex]M ^+[/tex] = [ (1/2 * 20 * 4.8 ) ( 600 + 300 ) ] + [ ( 25 * 4.8 * 10^3 ) ] - [ ( 1/2 *2.4*20 ) * 300 ] + [ (1/2 * 1.5 * 10 ) ( 600 + 300 ) ]
= 162750 Ib.ft
B) Determine the maximum negative moment produced at G
[tex]M ^-[/tex] = [ ( 1/2 * 20 * 4.8 ) * 300 ] - [ ( 1/2 * 2.4 * 20 ) ( 600 + 300 ) ] - [ (2.5 * 10^3 * 2.4 ) ] + [ ( 1/2 * 1.5 * 10) * 300 ]
= - 64950 Ib.ft
In powershell what commands do these:1. How can we find out the different membertypes (e.g. properties and methods) of the Get-Process cmdlet?2. How can we load the Storage module to the current session?3. How can we gather a list of only the SingularNoun for all the cmdlets currently available in our PS session? Please limit the list to only show the unique noun4. How can we display a list of all available modules that ends with the word "server"?
Answer:
Following are the solution to this question:
Explanation:
In question 1:
It Cmdlet gets the representatives of items, its features including their methods. Now use a variable (InputObject) and pipe the object to Even getting Member for both the purpose of specifying the object. It static variable utilizes their class members, not the case, to gather information regarding static members. Just use the (MemberType) parameter and receive only some forms of participants, such example NoteProperties.
In question 2:
Its Purchase cmdlet allows us to import components through our process. It can import components via remote sessions through the local client beginning with Window PowerShell 3.0.
In question 3:
The Syntax query to have all cmdlets lists it in the cmdlet title alphabetical order, but instead shows them in noun clauses.
Command:
[tex]\text{Type Cmdlet } | \text{Sort-Object -Property Noun} | \text{Format-Table -GroupBy Noun}[/tex]
In question 4:
Syntax:
[tex]\text{Get node} | \text{format list} | \text{Selection process, device forms, route group title all}[/tex]
[tex]| \text{Layout Table} | \text{Selection process}[/tex]
[tex]\$ s[/tex] = New-PSSession -ComputerName Server
Get-Module -PSSession [tex]\$ s[/tex] -ListAvailable