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The velocity of the car after 8 seconds of the drive will be 20.0066 miles/hr.

Acceleration is defined as the rate of change of velocity with respect to time.

Given that you are driving your car at 20 miles per hour and then accelerate at a rate of 3 miles per hour every second.

We can calculate the acceleration using the formula -

a = Δv/Δt

a = (v - u)/t

Now -

t = 8 seconds = 0.0022 hrs

Then -

3 = (v - 20)/0.0022

3 x 0.0022 = v - 20

v = 20.0066 miles/hr

Therefore, the velocity of the car after 8 seconds of the drive will be 20.0066 miles/hr.

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Because momentum will be conserved, their common speed after impact will be 5 m/s

The third Newton's law of motion states that in any action, there will be equal and opposite reaction.

Given that a toy train with a mass of 2 kg moving at 10 m/s collides with a 2-kg toy train that is stationary. If the two trains move together after the collision, their speed V after impact can be calculated through the formula

M1U1 + M2U2 = (M1 + M2)V

The given parameters are

Substitute all the parameters into the formula

2 × 10 + 2 × 0 = (2 + 2)V

20 = 4V

V = 20/4

V = 5 m/s

Therefore, their speed after impact is 5 m/s

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According to air masses classification, we can assume that to the west of the stationary front in northwestern Canada there is a maritime Polar (mP) air mass which is likely to be warmer than the air mass to the east. Option B) mP, warmer.

Air masses are horizontal extensions of moving air in which humidity, temperature, and physical properties are homogeneous.

Air masses can be classified according to their temperature (Cold or Warm), nature (continental -c- or maritime -m-), Origin region (Polar -P-, Artic -A-, Antarctic -AA-, Tropical -T-, Equatorial -E-)

Joining the previous classifications, we can identify different air masses

Maritime Polar air masses (mP)

Looking at the image, we will focus on the superior left area near the A. This is a red line with semicircles that represents a warmer front.

This red line comes from the west and moves forward to the northeast. Since this point is located near the coast, we can assume this is a maritime air mass.

These red lines, which represent worm fronts, suggest that to the west, the air is warmer than to the east.

The likely air mass to the west of the stationary front is a maritime Polar (mP) air mass which is likely to be warmer than the air mass to the east.

Option B) mP, warmer.

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Complete question

Find the stationary front located in northwesterm Canada.

The likely air mass to the west of the stationary front is ______ a air mass that is likely to be _____ than the air mass to the east.

A) cP: cooler

B) mP: warmer

C) cP: warmer

D) ml: warmer

Answer:

answer= lithium

Explanation:

electronic configuration

C. doing bicep curls.

Explanation:

why? A. is considered thermal energy.

B. is considered solar energy to chemical energy.

The push magnitude and the tension of the cord is 5.4 × 10^-4

What is cord ?

cord is the slender flexible material usually consisting of several stands or twisted together.

It is wired coverd in rubber or plastic which connects electrical equipment to an electricity supply.

The free body diagram as per the question with the tension of string T .

The force of gravity ~mg

The force of air ~f

Since the sphere is motionless the net force on it is 0.

And the x and y are the components of the equation are zero

Tsin + 0 = F

Tcos - mg= 0

Where ¥ = 32°

Thus we get

T= (3.9×10^-4 kg ) (9.8m/s^2)/cos32°

= 2.1×3.2×10^-4

Solving T

We can get the F =

(3.2×10^-4)sin 32° =

5.4 ×10^-4

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The net force of the lawn mower is 32.5 N and acceleration is 1.62 m/s^2.

The student pushes the lawn mower with 15.5 force and the lawn mower's motor provides 20.0 N force. The grass has a resistance force 3.0 N which is in opposite direction to the student's and lawn mower's forces. So, the net force is given,

F = 15.5 N + 20.0 N - 3.0 N = 32.5 N

According to Newton's second law, we know the relation between acceleration and force applied. Force is equal to mass times acceleration. The mass of the lawn mower is 25.0 kg.

[tex]a=\frac{F}{m}[/tex]

a = 32.5/20 = 1.62 m/s^2

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The time required by the truck moving with speed 25.0 m/s and covering the distance 48.0 m is 3.84 seconds.

What is speed?

The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity.

As given in the question,

the initial speed of the truck when brakes are applied (u) = 25 m/s.

Final speed (v) = 0 m/s

The distance covered after brakes are applied (s) = 48 m.

By the Newton's equation of motion

[tex]v^2 = u^2 + 2as[/tex]

Putting values from the question from the question.

0 = (25)^2 + 2a(48)

a = -6.51 m/s^2

Now by the equation,

v = u + at

Putting value from question

0 = 25 - 6.51 t

t = 25/6.5

t = 3.84 seconds

Therefore, time taken is 3.84 seconds.

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Answer:

the Vernier caliper

Explanation:

Answer:

Vernier caliper

PLSS MARK AS BRAINLIEST

The centripetal acceleration of the bike is 2.65 m/s².

Centripetal acceleration is the acceleration of an object moving in a circular track. This acceleration describes the rate of change of tangential velocity with time in the circular track.

The magnitude of the centripetal acceleration, can be determined by applying the formula for net force.

At constant speed, the centripetal acceleration of the bike is given as;

μmg = ma

μg = a

a = μg

where;

a = (0.27) x (9.8 m/s²)

a = 2.65 m/s²

Thus, the centripetal acceleration of the bike increases with increase in velocity.

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When a negatively charged conductor is brought in contact with a neutral conductor, then both objects become charged negatively.

Conductors are substances through which electrons flow freely. When a conducting material has a charge, the charges repel and move away from each other, distributing themselves evenly about the outer surface .

Charging by conduction involves the contact between a charged and a neutral object. Therefore, when an uncharged conductor is brought in contact with a charged conductor, charge is shared between the two conductors and hence the uncharged conductor also gets charged.

Both objects have the same type of charge, during charging by conduction. If a negative object is used to charge a neutral object, then both objects become negatively charged.

Any charged object whether positively or negatively charged have an attractive interaction with a neutral object. Positively charged and neutral objects attract each other and similarly negatively charged and neutral objects attract each other.

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It is a multistep plan or strategy that allows you to achieve your goals.

1.

(a) The ball cleared the crossbar by 10.23 m.

(b) The ball approaches the crossbar while falling.

The maximum height reached by the ball is calculated by applying the following kinematic equation as shown below;

H = u² sin²θ / 2g

where;

H = (20.2² x (sin 53)²) / (2 x 9.8)

H = 13.28 m

ΔH = 13.28 m - 3.05 m = 10.23 m

The horizontal distance travelled by the ball is calculated as follows;

R = u² sin(2θ) / g

R = (20.2² sin(2 x 53) ) / (9.8)

R = 40 m

Thus, the ball cleared the crossbar and since the maximum height travelled by the ball is far greater than the height of the crossbar, the ball will approach the crossbar while falling.

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Answer:

time is 3 seconds.

Explanation:

formula is given in the picture

"The direction of the current."

A solenoid's north and south poles are determined by two variables. two factors: the winding direction and the direction in which the stream flows (clockwise or counter-clockwise). The positive pole of the power source (such as a battery) should be determined first, followed by the end of the solenoid that will be connected to it.

Now, determine which way the winding is going by peering down the solenoid tube. The south pole is present if the positive wire is rotated clockwise, and the north pole is present if it is rotated counterclockwise. In conclusion, the magnetic south pole is always in reference to the positive wire clockwise.

The magnet's poles will be created as a result of current flowing through the solenoid, and the clock face rule in a solenoid is used to predict their positions. According to the rule, the south pole will be formed if you gaze through a solenoid at a location where the current runs in a clockwise direction. On the other hand, the north pole will be visible if viewed from the side where the current is flowing counterclockwise.

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When A1 and -A1 are of the same magnitude but the opposite direction, their total will be zero.

what is vector?

A quantity or phenom with independent property for the both magnitude and direction is called a vector. The term may also refer to a quantity's mathematical or geometrical representation. Velocity, electromagnetic fields, and weight are just a few examples of vectors in nature.

0 is the intersection of line A1 and -A1.

Both the matrices A1 and A2 have the same magnitude, which itself is A

|A1| = A , |A2| = A

the result of A1 and A2 is 3 A

Hence, 3 A = (A2 + A2 + 2A2 cos x)

3A2 = 2A2 + 2A2 cos x

=> 1/2 = cos x

x = 60°

A1 and A2 are at an angle of 60 °.

Now, we must find the product of A1 and -A1. These vectors create a 180° angle.

the product of A1 and -A1 is (A2 + A2 + 2A2 cos 180°

=> √(2A²-2A²)

=> 0

When A1 and -A1 are of the same magnitude but the opposite direction, their total will be zero.

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The intensity of sound in each hall will not be doubled.

The intensity of sound may  be defined as, the power carried by sound waves per unit area in a direction perpendicular to that area. The intensity of sound is measured in decibel i.e. the unit is written as (dB).

It can be formulated as ,

I = pv

Where, I is the intensity of the sound, p is the pressure of sound, v is the velocity of the particle. And here, I and v are vectors, therefore they both have a magnitude and a direction. The average direction of energy flow is represented by the direction of sound intensity.

Therefore, due to the fact that our hearing is not linear and dB is a logarithmic scale, even though the energy may have doubled, the perceived intensity has not. In actuality, one of the singers' voices may both hide the other's and have the potential to improve it.

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Answer: Force required to 25 joule work when the force causes a displacement of 0.5m is 50N

Explanation: To calculate the work done we use the formula

W=F.s                               (1)

W= work done

F=  force applied               s= displacement

Given, work done W= 25 joules= 25 J

displacement s= 0.5m

∴From equation (1) we get the force required when work is done and displacement is given, that is

F[tex]=\frac{W}{s}[/tex]                                (2)

∴Force required [tex]F=\frac{W}{s}= \frac{25J}{0.5m}=50N[/tex]            

(1 J is the work done by a force of 1 N acting over a displacement of 1 m and so 1 J= 1 Nm⇒ 1 N = 1 J/m)

ANS: Force required to do 25 J work when a force causes displacement of 0.5m = 50 N

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The least magnitude of the normal force on the rafter from each thumb or opposite fingers is 276.5 Newtons.

As we know, henry is suspended by using his hands.

If he not going upward or downwards. we can conclude that the magnitude of all forces should be cancelling each other.

The force that is stopping the thumbs and the finger is frictional force.

Friction force f is a kind of force that comes into play when their is an actual slipping or the tendency to slip between any two contacted surface.

f = μN

where N is the normal force.

The net friction force should be equal to the total weight if the body,

Frictional force f by the fingers can be distributed equally in four parts,

mg = 4f

mg = 4μN

Mass is 79 Kg. g is 9.8m/s² and the value of μ is 0.7.

79 x 9.8 = 4 x 0.7 x N

N = 276.5 newtons.

So the least normal force on the each thumb and fingers is 276.5 N.

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Consider the following system, where F = 120 N, m = 1 kg, and M = 5 kg. Force exerted by the lighter block on the heavier block is F_2=20N

F = 120N

m = 1kg

M = 5kg

Generally, the equation for acceleration is mathematically given as

[tex]a=\frac{F}{m+M} \\\\a=\frac{120}{1+5} \\[/tex]

a=20m/s^2

Let's formulate the heavier block's equation of motion.

F_1=F-F_2

Ma=F-F_2

It is estimated that the lighter block will exert the following force on the heavier block:

[tex]&F_2=\mathrm{F}-\mathrm{Ma} \\&F_2=120-(5 *20) \\[/tex]

F_2=20N

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There are four aspects of waves that only pertain to specific types of waves. Peaks and troughs are used to describe transverse waves. Compressions and rarefactions are used to describe longitudinal waves. Medium, wavelength, amplitude, and frequency are the four qualities that both types of waves have in common.

In addition to longitudinal waves, which also move in the direction of the medium, there is another type of wave that does so: the transverse wave. While longitudinal waves are made up of compressions and rarefactions, transverse waves are made up of crests and troughs.

In longitudinal waves, localized compression and rarefaction are observed. Compressions are regions of extremely high pressure because of the near proximity of the particles. Rarefactions are regions of low pressure because to the particles' enhanced dispersion.

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The speed of the cat when it slide off the table is 2.27 m/s

To obtain the answer to the given question, we'll begin by obtainig the time taken for the cat to strike the floor. This can be obtained as follow:

h = ½gt²

0.94 = ½ × 9.81 × t²

0.94 = 4.905 × t²

Divide both side by 4.905

t² = 0.94 / 4.905

Take the square root of both side

t = √(0.94 / 4.905)

t = 0.44 s

The speed of the cat can be obatined as illustrated below:

s = ut

1 = u × 0.44

Divide both sides by 0.44

u = 1 / 0.44

u = 2.27 m/s

Thus, we can conclude that the speed of the cat is 2.27 m/s

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Due to the principle of energy conservation, the sled's initial potential and kinetic energy are identical to its ultimate kinetic energy. So the correct answer is vf =21.71 m/s.

According to no 12th law, additional forces are equal to M. A. Therefore, in this instance, MG sine data equals M. A. This will give us A. equals theta in the G symbol It will be the first equation at A. equals D B divided by D T. By using dx by DT, or D X by D T, we can multiply and divide. D X's indu D D. As a result, we shall obtain V D V by D X equals a. The second equation will be this.

The result of equation 192 is then that D V by D X equals G sign theta. Therefore, V D V is G scientology to be X equal. Now that D V equals integral energy, we can integrate this integral. G sign to D X to D. that we will receive G scientific data is equivalent to energy We Squire divided by two. X. We'll see. At X=0, nothing happens. We will have a speed of 9.2 m/s. 9.2 squared divided by two will equal C. 42.32 is what that comes to.

Then we divide Squire by two to get theta in the G sign. X + 42.32. Then, using this information, we can determine that we are equivalent to the root energy of two indu G sine theta into X plus 42.32. The numbers that are route off two can be changed to 9.8 m/s. Nine degree Squire In is 0.156. surplus food industry 1 40 m less 42.32. We shall therefore arrive at a quanto of 21.71 m/s by solving this.

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​

​

The sideways acceleration is required to deflect an ion 2. 0 cm to one side is [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex].

Velocity =  5. 5 × [tex]10^{6}[/tex] m/s

acceleration region = L1 = 5.0 cm = 0.05 m

Ends of the acceleration plates = L2 1. 5 m

D = 0.02 m

a = [tex]\frac{2v^{2}d }{2L1L2+L1^{2}}[/tex]

Putting the values

a = 2×( 5. 5 × [tex]10^{6}[/tex])^2  × 0.02 m / 2 × 0.05m × 1.5m + (0.05m)^2

a = 1×10^12 m^2/s / 0.15m^2+2.5×10^-3m^2

a = 2 ×10^5 m^2/s / 0.1525 m^2

a = [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex]

The sideways acceleration is required to deflect an ion 2. 0 cm to one side is [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex].

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The sideways acceleration required to deflect an ion 2.0cm to one side is [tex]7.9*10^{12} m/s^{2}[/tex]  expressed to 2 significant figures

Given the following:

V = 5.5 X10 m/s

Acceleration region (L[tex]^{1}[/tex]) = 5.0 cm long

Ends of the acceleration plates are L[tex]_{2}[/tex] = 1.5m from the patient

Now determine the sideways acceleration to deflect anion

d=2.0cm to one side.

Sideway acceleration is:

[tex]a=\frac{2V^{2}d }{2L_{1}L_{2}+L_{1} ^{2} }[/tex]

[tex]a=\frac{2*(5.5*10^{6})^{2}*0.02 }{(2*0.05*1.5)+0.05^{2} }[/tex]

[tex]a=7.9344*10^{12}m/s^{2} \\[/tex]

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The gravitational force between them will change by a factor 1/9.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

R2 = 3R1

By substituting the following parameters, we get

F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²

F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²

F2/F1 = 1/9

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0.56 A is the current of the secondary coil.

transformer is the device that transfer electric energy from one AC circuit to another.

we know that ;

I ∝ 1/n;

where I IS CURRENT and n is NUMBER OF TURNS.

(I) secondary = X A

(n) secondary = 100

(I)  primary  = 0.04 A

(n)  primary  = 1400

USING THIS-----> I ∝ 1/n;

=>

0.04 A/X A =100/1400

=>X=0.56 A

as the current in the transformer is inversely proportional to the number of turns so 0.56 A is the current in the secondary coil.

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According to the given statement The kayaker has a resultant velocity is ||v + w|| ≈ 2.80 m/s.

An object's total vector velocity is the sum of its component vector velocities. The scalar product of an object's mass and acceleration vector equals the sum of the vector forces acting on it.

The kayaker has velocity vector

v = (2.50 m/s) (cos(45º) i + sin(45º) j )

v ≈ (1.77 m/s) (i + j )

and the current has velocity vector

w = (1.25 m/s) (cos(315º) i + sin(315º) j )

w ≈ (0.884 m/s) (i - j )

The kayaker's resultant velocity is the sum of these:

v + w ≈ (2.65 m/s) i + (0.884 m/s) j

The kayaker has a resultant velocity of  ||v + w|| ≈ 2.80 m/s in a direction θ such that

tan(θ) = (0.884 m/s) / (2.65 m/s)  

θ ≈ 18.4º

or about 18.4º north of east.

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The complete question is -

A kayaker paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast). What is the kayaker's resultant velocity?​

70 mmHg will convert to 9.333kpa pressure SI units while 20 mmHg will convert to 16kpa pressure SI units.

Absolute pressure for 70 mmHg is 110.658kpa

Absolute pressure for 120 mmHg is 117.325kpa

Converting 70 mmHg and 120 mmHg into SI pressure units:

If 760 mmHg=101.325kpa

      ∴ 70 mmHg=?

        = 70*101.325/760

         =9.333kpa

So 70 mmHg will be 9.333kpa

If 760 mmHg=101.325kpa

     ∴120 mmHg=?

      =120*101.325/760

      =16kpa

So 120 mmHg will be 16kpa

Blood pressure is generally measured in mmHg because mercury is used in the thermometers, so it is convenient to measure the pressure by rise in height of mercury in the thermometer.

However pressure measured by the thermometer is always gauge pressure, given by:

[tex]P_{gauge} =P_{abs} -P_{0}[/tex], where [tex]P_{0}[/tex] is atmospheric pressure and [tex]P_{abs}[/tex] is absolute pressure.

We now calculate absolute pressure for [tex]P_{1}[/tex] 70 mmHg and [tex]P_{2}[/tex] 120 mmHg,

[tex]P_{1} abs=P_{1} g+P_{0}[/tex]

         [tex]=101.325+9.333[/tex]

        =110.658kpa

[tex]P_{2} abs=P_{2} g+P_{0[/tex]

        =101.325+16

        =117.325kpa

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The cruising altitude of the plane of mass 40000 kg before its descent is 196 m

U = m g h

U = Gravitational potential energy

m = Mass

g = Acceleration due to gravity

h = Vertical height

U = 78400000 J

m = 40000 kg

g = 10 m / s²

h = U / m g

h = 78400000 / 40000 * 10

h = 196 m

Gravitational potential energy is a type of energy related to gravity. It is energy acquired by an object due to its change in position in the presence of gravitational field.

Therefore, the cruising altitude of the plane before its descent is 196 m

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The motion of one particle of a gas is unaffected by the motion of other particles of the gas unless the particles collide.

Heat is the primary cause of particle motion on Earth. The temperature of any substance is correlated with the energy of the atoms and molecules that comprise it. Energy is conserved, thus if one particle loses energy, another one acquires it.

The components of matter are also continually in motion. They are energetic in motion. The kinetic theory of matter states that all matter is made up of particles that are constantly moving.

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