This line is parallel to the line 2x + 6y = 12.

Answer:

a = 0

Step-by-step explanation:

4(a-2) = 2(a-4) + 2a

4a - 8 = 2a - 8 + 2a

4a - 2a - 2a = -8 + 8

    0             =    0

This has infinitely many solutions.

Step-by-step explanation:

Any number you put for a would work to make them equal. Feel free to try it.

Answer:

false

Step-by-step explanation:

hope it helps and sorry if it's wrong i wish you luck

Answer:

bb

Step-by-step explanation:

Answer:

The answer for this question is 240 yd

Answer:

b

Step-by-step explanation:

Answer:

9 days before only 8 mg is still emitting radiation.

Step-by-step explanation:

The exponential model is:

[tex]y(t) = a(0.5)^{\frac{t}{28}}[/tex]

In which a is y(0), that is, the initial quantity.

10 mg is ingested by a patient

This means that [tex]a = 10[/tex], and thus:

[tex]y(t) = 10(0.5)^{\frac{t}{28}}[/tex]

How many days before only 8 mg is still emitting radiation?

This is t for which y(t) = 8. So

[tex]y(t) = 10(0.5)^{\frac{t}{28}}[/tex]

[tex]8 = 10(0.5)^{\frac{t}{28}}[/tex]

[tex](0.5)^{\frac{t}{28}} = \frac{8}{10}[/tex]

[tex](0.5)^{\frac{t}{28}} = 0.8[/tex]

[tex]\log{(0.5)^{\frac{t}{28}}} = \log{0.8}[/tex]

[tex](\frac{t}{28})\log{0.5} = \log{0.8}[/tex]

[tex]\frac{t}{28} = \frac{\log{0.8}}{\log{0.5}}[/tex]

[tex]t = 28\frac{\log{0.8}}{\log{0.5}}[/tex]

[tex]t = 9[/tex]

9 days before only 8 mg is still emitting radiation.

Answer:

3.3

Step-by-step explanation:

7lb 3oz

3oz/16oz=.1875lb

7lb+.1875lb=7.1875lb

7.1875lb/2.2kg=3.27kg

Answer:

Step-by-step explanation:

250x^3-16

2(125x^3-8)

2[(5x)^3-(2)^3]

2(5x-3)[(5x)^2+5x*3+(2)^2]

2(5x-3)(25x^2+15x+4)

Answer:

Not 100 percent sure about this one.

Answer: The answer is 800

that’s all you type in 800.

Step-by-step explanation:

Y=1. Cause both land on one bht ones positive and neagitive

Answer:

67.7

Step-by-step explanation:

Because it is the exact same as 67.7 angle n is. So it is 67.7 I went over this recently so I understand your pain!

Answer:

option A

Step-by-step explanation:

f(x) = 3x + 2

g(x) = 2x - 2

(f - g)(x) = f(x) - g(x)

           = (3x + 2) - (2x - 2)

           =3x + 2 - 2x + 2

           = x + 4

The value of function (f - g)(x) is,

⇒ (f - g)(x) = x + 4

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

Function are,

f(x) = 3x + 2 and g(x) = 2x - 2

Hence, The value of function (f - g)(x) is,

⇒ (f - g)(x) = (3x + 2) - (2x - 2)

⇒ (f - g)(x) = 3x + 2 - 2x + 2

⇒ (f - g)(x) = x + 4

Thus, The value of function (f - g)(x) is,

⇒ (f - g)(x) = x + 4

Learn more about the function visit:

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Answer:

B) 8330.66

Step-by-step explanation:

Answer:

1. 3/6

2.12/24

3. 6/12

4. 6/12

5.8/16

6. 9/18

7. 12/24

8. 12/24

im not sure if everything is correct

Answer:  

To see the shaded regions, check out the attached image below. The shaded regions are in red.

The fractional values for each figure are:

The fractional answers are in bold. All of those fractions reduce to 1/2. Make sure that you don't reduce any of those fractions.

========================================================

Explanation:

We count out the number of squares for each figure. Then we shade half of them. For problem 1, we just shade the left half (or you can shade the right half, but you can only pick one side). This is because 3 is half of 6.

Problem 2 is a similar story, but we'll shade the first two columns out of the four total columns. You could shade the last two columns if you wanted, but you can't shade everything.

Problem 3 has an odd number of columns, but an even number of rows. I'm shading the first two rows to represent half of the blocks.

The rest are handled in a similar manner.

------------

To form the fractional results, you basically count the number of shaded smaller squares out of the number of squares total.

For example, the answer for problem 1 is 3/6 because we have 3 shaded red squares out of 6 squares total. The rest are handled the same way.

Answer:

x = -4, 4

Step-by-step explanation:

Hi there!

[tex]x^2-16=0[/tex]

Rewrite 16:

[tex]x^2-4^2=0[/tex]

The difference of squares rule states that [tex]a^2-b^2=(a+b)(a-b)[/tex]. With this, apply the difference of squares to the equation:

[tex](x+4)(x-4)=0[/tex]

The zero-product property states that if the product of two numbers is 0, then one of the numbers must be equal to zero. Set each term equal to 0 and find the solutions:

[tex]x+4=0\\x=-4[/tex]

[tex]x-4=0\\x=4[/tex]

Therefore, the solutions are -4 and 4.

I hope this helps!

Answer:

The p-value of the test is 0.001 < 0.05, which means that there is evidence at the 0.05 level of significance that the mean one-time gift donation is greater than $70.

Step-by-step explanation:

Test if the mean one-time gift donation is greater than $70:

At the null hypothesis, we test if it is 70 or less, that is:

[tex]H_0: \mu \leq 70[/tex]

At the alternate hypothesis, we test if it is greater than 70, that is:

[tex]H_1: \mu > 70[/tex]

The test statistic is:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

70 is tested at the null hypothesis:

This means that [tex]\mu = 70[/tex]

Based on a random sample of 60 nonprofit organizations, the mean one-time gift donation in the past year was $75, with a standard deviation of $12.

This means that [tex]n = 60, X = 75, s = 12[/tex].

Test statistic:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{75 - 70}{\frac{12}{\sqrt{60}}}[/tex]

[tex]t = 3.23[/tex]

P-value of the test:

The p-value of the test is the probability of finding a sample mean above 75, which is a right-tailed test with t = 3.23 and 60 - 1 = 59 degrees of freedom.

Using a t-distribution calculator, this p-value is of 0.001.

The p-value of the test is 0.001 < 0.05, which means that there is evidence at the 0.05 level of significance that the mean one-time gift donation is greater than $70.

Answer:

Ahh I did this about a year ago but try math-way (without -) it gives the correct answers sorry I couldn't help more.

Answer:

The graph of function f is shifted 3 units to the right.

Step-by-step explanation:

Sample Answer from Edmentum

Answer:

The graph of function f is shifted 3 units to the right.

Step-by-step explanation:

Plato/Edmentum

Answer:

3×22+3×54

as there's bracket, so c is the answer

Answer:

C

Step-by-step explanation:

Answer:

It doesn't show the statements so I'll create some.

Step-by-step explanation:

ABCD make a shape with 2 pairs of parallel lines.

ABCD when broken apart can create 4 triangles

Answer:

5 rides.

Step-by-step explanation:

$28 - $6.50 = $21.50

$21.50 - $4 = $17.5

$17.5 ÷ $3 = 5.83

Answer:

look at the explanations

Step-by-step explanation:

part a: the zeros are the two points on the x-axis

           - looks like (0,10) and (0,60)

part b: the zeros represent her minimum profit where she makes 0 dollars

part c: the vertex is the very top of the parabola

          - looks like (35, 12000)

part d: the vertex represents the max amount of profits she makes

13.52 fluid were drunk by Andre

Answer:

The answer is C or the third option. "g(x) has a greater maximum value than f(x)"

Step-by-step explanation:

I took the test and got it correct.

The statement that best compares the maximum value of the two functions is g(x) has a greater maximum value than f(x).

The function f is given as:

f(x) = -2x^2 + 9

Differentiate the function

f'(x) = -4x

Set to 0

-4x = 0

Divide both sides by -4

x = 0

Substitute x = 0 in f(x)

f(0) = -2(0)^2 + 9

f(0) = 9

This means that the maximum value of function f(x) is 9

From the table of function g(x), the maximum is 11

11 is greater than 9

Hence, g(x) has a greater maximum value than f(x).

Read more about maximum values at:

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Answer:

translation then rotation

Answer:

7

Step-by-step explanation:

3RD MAN: 1

2ND MAN: 2

1ST MAN: 4

3rd Man = 1/2+1/2 = 1

2nd Man = 1+1 = 2

1st Man = 2*2 = 4

There are two pieces we need to find here: the area of the section of the circle, and the area of the triangle.

Area of the section of the circle:

A = pi * r^2

A = pi * 15^2

A = 225pi * 72/360 || We only need this part of the circle, not the whole thing.

A = 45pi

Area of the triangle:

A = 1/2 * a * b * sin(c)

A = 1/2 * 15 * 15 * sin(72)

A = 112.5 * sin(72)

Next, we need to subtract the area of the triangle from the area of the section of the circle.

A = 45pi - (112.5 * sin(72))

A = 112.8165 units^2 -- Feel free to round off wherever you need!

Hope this helps!! :)

Answer:

She started at 8:34 and finished at 9:21, with some simple math.. the answer is 47 minutes