Three 1.83 in. diameter bolts are used to connect the axial member to the support in a double shear connection. The ultimate shear strength of the bolts is 60 ksi, and a factor of safety of 3.9 is required with respect to fracture. Determine the allowable load P that can be applied to the axial member based on the shear strength of the bolts. Give your answer in kips. Enter a positive number.

Answers

Answer 1

Answer: the allowable load P is 242.7877 kips

Explanation:

Given that;

diameter bolts d = 1.83 in

ultimate shear strength of the bolts = 60 ksi

we know that

shear area = 2×(π/4)d²

= 2×(π/4)×(1.83)² = 5.2604 in²

so

p/3(5.2604) = 60000/3.9

p/15.7812 = 15384.6153

p = 15.7812 × 15384.6153

p = 242787.691 lb

p = 242.7877 kips

therefore the allowable load P is 242.7877 kips


Related Questions

A good attitude toward blank means believing that the proper attitude and habits are extremely important

Answers

Answer:

the blank = life

Explanation:

:) happy holidays!

the water depths upstream and downstream of a hydraulic jump is 0.3 m and 1.2 m. Determine flow rate

Answers

This question is incomplete, the complete question is;

the water depths upstream and downstream of a hydraulic jump is 0.3 m and 1.2 m. Determine flow rate  ( in m³ ) if the rectangular channel is 20 m wide.

Answer:

the flow rate is 32.549 m³/sec

Explanation:

Given that

y₁ = 0.3 m

y₂ = 1.2 m

β = 20 m

Now for Rectangular Channel, we know that;

2q²/g = y₁y₂( y₁ + y₂)

where g = 9.81 m/s²

and q = Q/β

so

2(Q/β)²/g = y₁y₂( y₁ + y₂)

we substitute our given values

2(Q/20)²/9.81 = 0.3 × 1.2( 0.3 + 1.2)

2(Q²/400)/9.81 = 0.36(1.5)

2(Q²/400) = 0.54 × 9.81

Q²/400 = 5.2974 / 2

Q²/400 = 2.6587

Q² = 1059.48

Q = √1059.48

Q = 32.549 m³/sec

Therefore the flow rate is 32.549 m³/sec

An ECG has a scalar magnitude of 1 mV on lead II and a scalar magnitude of 0.5 mV on lead III. Calculate the scalar magnitude on lead I.

Answers

Answer: the scalar magnitude on lead I is 0.5 mV

Explanation:

Given that;

scalar magnitude on lead II = 1 mV

scalar magnitude on lead III = 0.5 mV

the scalar magnitude on lead I = ?

we know that;

Lead I Voltage = LA - RA -----------let this be equation 1

where LA is left arm electrode and RA is right am electrode

Also

Lead II = LL - RA

where LL is the left leg of electrode

we substitute

1 mV = LL - RA ---------------------let this be equation 2

Again

Lead III = LL - LA

we substitute

0.5 mV = LL - LA ------------------let this be equation 3

now subtract equation 3 and 2

1 mV - 0.5 mv = LL - RA - (LL - LA)

0.5 mV = LL - RA - LL + LA

0.5 mV = -RA + LA

0.5 mV = LA - RA

now taking a look at our equation 1 ( Lead I Voltage = LA - RA )

hence, Lead I Voltage = LA - RA = 0.5 mV

Therefore the scalar magnitude on lead I is 0.5 mV

A _________ is interesting only if the statistics computed from transactions covered by the rule are different than those computed from transactions not covered by the rule.

Answers

Answer: Quantitative association rule.

Explanation:

The quantitative rules of association apply to the basic type of rules of association which exists as X and Y, with X and Y consisting of a collection of numerical and/or categorical attributes. Unlike general association laws, where both the left and right sides of the law should have categorical (nominal or discrete) attributes, a numerical attribute must be included in at least one attribute of the quantitative association rule (left or right).

While examining the color of an engine's coolant: Technician A says that because it is orange, the cooling system should be flushed and new coolant put into the system. Technician B says that if the coolant looks rusty, the cooling system should be flushed and new coolant put into the system. Who is correct?

Answers

Answer:

Technician B is correct.

Explanation:

In every vehicles, coolants are very important as it keeps the engine cool and keep it running. The coolant serves the purpose of dissipating away the heat that is generated when the engine runs.

When the engine runs, the coolant passes all over the heating surfaces in the engine thus carrying away the heat along with it. With time the color of the coolant changes to rusty brown color when the coolant serves its purpose . It also washes away all the dirt particles from the engine part along with it. Thus the color changes and it is now can be flushed from the engine sump and fresh coolant can be put in to the engine.

Thus in the context, technician B is correct.

who is the strongest avenger i say hulk but who knows at this point

Answers

Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

All of these are part of the seat belt assembly EXCEPT the:
O latch plate
O D-ring
O retractor.
O cushion

Answers

Answer: Cushion
Explanation: All parts going together to form a seat belt except the cushion
The answer is the last one: cushion

A rectangular bar has a edge crack at the bottom and is subjected to a pure bending moment. The crack length is a = 1 mm. The height of the bar is b = 12.5 cm. Knowing that the failure strength of the material is Sigma = 1,400 MPa, what is the fracture toughness of the material, K_ic.

Answers

Answer:

The answer is "[tex]\bold{87.3906 \ MPa \sqrt{m}}[/tex]".

Explanation:

Given value:

[tex]\sigma = 1400 \ MPa \ \ \ \ \ \ \ \ where \ \sigma = failure \ strength\\\\a = 1 \ mm = 1 \times 10^{-3} \ m \ \ \ \ \ \ \ \ \ \ where\ a = crack\ length\\\\b= 12.5 \ cm = 125 \ mm = 0.125 \ m\\\\[/tex]

[tex]\to \alpha = \frac{a}{b} =\frac{1}{125} = 8 \times 10^{-3}\\\\[/tex]

[tex]k_{b} = \frac{1.12 + \alpha (2.62 \alpha -1.59)}{1-0.7 \alpha}\\[/tex]

    [tex]= \frac{1.12 + (8\times 10^{-3}(2.62(8\times 10^{-3}) -1.59))}{1-(0.7 \times 8\times 10^{-3})}\\\\= \frac{1.12 + (8\times 10^{-3}(0.02096 -1.59))}{1-(0.7 \times 8\times 10^{-3})}\\\\= \frac{1.12 + (8\times 10^{-3}(-1.56904))}{1-(0.0056)}\\\\= \frac{1.12 + (-0.01255232)}{0.9944}\\\\= \frac{-1.10744768}{0.9944}\\\\= -1.11368431\\\\[/tex]

[tex]k_{ic} = \sigma \sqrt{\pi a} \ y_b[/tex]

     [tex]=1400 \times \sqrt{\pi \times 1 \times 10^{-3} } \times -1.11368431\\\\=1400 \times 0.00177200451 \times -1.11368431\\\\=87.3906 \ MPa \sqrt{m}[/tex]

A site is underlain by a soil that has a unit weight of 118 lb/ft3. From laboratory shear strength tests that closely simulated the field conditions, the total stress parameters were measured to be C total = 250 lb/ft2 and φ total = 29°. Estimate the shear strength on a horizontal plane at a depth of 12 ft below the ground surface at this site in lbs/ sq ft

Answers

Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Explanation:

Given that;

Weight of soil r = 118 lb/ft³

stress parameter C = 250 lb/ft²

φ total = 29°

depth Z = 12 ft

The shear strength on a horizontal plane at a depth of 12ft

ζ = C + δtanφ

where δ = normal stress

normal stress δ = r × z = 118 × 12 = 1416

so

ζ = C + δtanφ

ζ = 250 + 1416(tan29°)

ζ = 250 + 1416(tan29°)

ζ = 250 + 784.9016

ζ = 1034.9015 lb/ft²

Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

5.5.1 Dual-edge detector A dual-edge detector is similar to a rising-edge detector except that the output is asserted for one clock cycle when the input changes from 0 to 1 (i.e., rising edge) and 1 to 0 (i.e falling edge). 1. Design a circuit based on the Moore machine and draw the state diagram and ASM chart. 2. Derive the HDL code based on the state diagram of the ASM chart. 3. Derive a testbench and use simulation to verify operation of the code.

Answers

Give an example of a counterargument for an essay on why waffles are better than pancakes.

The resistance of a 1,000-foot length of #6 AWG wire at a temperature of 25 degrees C is  0.4028 ohm. Thus, option B is correct.

What is prototype?

It is a term used in a variety of contexts, including semantics, design, electronics, and software programming.A prototype is an early sample, model, or release of a product built to test a concept or process or to act as a thing to be replicated or learned from.

The statement that defines a prototype is a prototype is a working model of the proposed system. Say for instance a programmer creates a flowchart or an algorithm of an actual program. The flowchart or the algorithm is the prototype of the actual program. This in other words means that prototypes are models of a system. Hence, the statement that defines a prototype.

Therefore, The resistance of a 1,000-foot length of #6 AWG wire at a temperature of 25 degrees C is  0.4028 ohm. Thus, option B is correct.

Learn more about prototype on:

https://brainly.com/question/7509258

#SPJ2

In urban area you can except

Answers

Answer:

eoidnfoejsdncodsnc

Explanation:

dfdjsncojnsdjcnsdojnvjsdvkjsdkjvnsdjvnskjnvkjdvkjnsdcjndkjndskjndskjndskjnsdvkjnvsdkjvsdkjnvskdjnvkjdsvkjsdnvkjsdnkjsvnkj

Thermodynamics fill in the blanks The swimming pool at the local YMCA holds roughly 749511.5 L (749511.5 kg) of water and is kept at a temperature of 80.6 °F year round using a natural gas heater. If you were to completely drain the pool and refill the pool with 50°F water, (blank) GJ (giga-Joules) of energy are required to to heat the water back to 80.6 °F. Note: The specific heat capacity of water is 4182 J/kg ⋅°C. The cost of natural gas per GJ is $2.844. It costs $ (blank) to heat the pool (to the nearest dollar).

Answers

Answer:

[tex]95.914\ \text{GJ}[/tex]

[tex]\$272.78[/tex]

Explanation:

m = Mass of water = 749511.5 kg

c = Specific heat of water = 4182 J/kg ⋅°C

[tex]\Delta T[/tex] = Change in temperature = [tex]80.6-50=30.6^{\circ}\text{F}[/tex]

Cost of 1 GJ of energy = $2.844

Heat required is given by

[tex]Q=mc\Delta T\\\Rightarrow Q=749511.5\times 4182\times 30.6\\\Rightarrow Q=95.914\times 10^9\ \text{J}=95.914\ \text{GJ}[/tex]

Amount of heat required to heat the water is [tex]95.914\ \text{GJ}[/tex].

Cost of heating the water is

[tex]95.914\times 2.844=\$272.78[/tex]

Cost of heating the water to the required temperature is [tex]\$272.78[/tex].

A garden hose fills a 2-gallon bucket in 5 seconds. The number of gallons, g (y), is proportional to the number of seconds, t (x), that the water is running. What is the constant of proportionality?

Answers

Answer:

0.4 gallons per second

Explanation:

A function shows the relationship between an independent variable and a dependent variable.

The independent variable (x values) are input variables i.e. they don't depend on other variables while the dependent variable (y values) are output variables i.e. they depend on other variables.

The rate of change or slope or constant of proportionality is the ratio of the dependent variable (y value) to the independent variable (x value).

Given that the garden hose fills a 2-gallon bucket in 5 seconds. The dependent variable = g = number of gallons, the independent variable = t = number of seconds.

Constant of proportionality = g / t = 2 / 5 = 0.4 gallons per second

Given that the skin depth of graphite at 100 (MHz) is 0.16 (mm), determine (a) the conductivity of graphite, and (b) the distance that a 1 (GHz) wave travels in graphite such that its field intensity is reduced by 30 (dB).

Answers

Answer:

the answer is below

Explanation:

a) The conductivity of graphite (σ) is calculated using the formula:

[tex]\delta=\frac{1}{\sqrt{\pi f \mu \sigma} }\\\\\sigma =\frac{1}{\pi f \mu \delta^2}[/tex]

where f = frequency = 100 MHz, δ = skin depth = 0.16 mm = 0.00016 m, μ = 0.0000012

Substituting:

[tex]\sigma =\frac{1}{\pi *10^6* 0.0000012*0.00016^2}=0.99*10^4\ S/m[/tex]

b) f = 1 GHz = 10⁹ Hz.

[tex]\alpha=\sqrt{\pi f \mu \sigma} = \sqrt{0.0000012*10^9*\pi*0.99*10^5}=1.98*10^4\ Np/m\\\\20log_{10} e^{-\alpha z}=-30\ dB\\\\(-\alpha z)log_{10} e=-1.5 \\\\z=\frac{-1.5}{log_{10} e*-\alpha} =1.75*10^{-4}\ m=0.175\ mm[/tex]

1. The construction process begins with which of the following stages?
a) establishing the foundation
b) enclosing the building
c) site preparation
d) installing underground utilities

Answers

Answer:

c) site preparation

Explanation:

A construction process can be defined as a series of important physical events (processes) that must be accomplished during the execution of a construction project.

Generally, in the construction of any physical asset such as offices, hospitals, schools, stadiums etc, the first step of the construction process is site preparation. Site preparation refers to processes such as clearing, blasting, levelling, landfilling, surveying, cutting, excavating and demolition of all unwanted objects on a piece of land, so as to make it ready for use.

This ultimately implies that, site preparation should be the first task to be accomplished in the construction process.

Hence, the construction process typically begins with site preparation before other activities such as the laying of foundation can be done.

Additionally, construction costs can be defined as the overall costs associated with the development of a built asset, project or property. The construction costs is classified into two (2) main categories and these are; capital and operational costs.

A commercial facility has a three-phase, 277 volt, 1200 Amp service. What is the required nominal transformer size needed for this building?
a. 750 kVA
b. 500 kVA
c. 575 kVA
d. 633 kVA
e. 1,000 kVA

Answers

Answer:

The answer is "Option e".

Explanation:

Given value:

[tex]\to v_{ph}=277 \ \ \ \ \ \ \ I_{ph} =1200\\\\[/tex]

[tex]vA= v_{Ph} I_{ph} \ \ \ \to for \ single \ phase\\\\=3v_{ph} I_{ph} \ \ \ \ \ \to for \ 3 - \phi \\\\s = 3\times 277 \times 1200 \\\\[/tex]

  [tex]=997.200 \ K VA\\\\= 1000 \ k VA[/tex]

Assume there exists some hypothetical metal that exhibits ferromagnetic behavior and that has (1) a simple cubic crystal structure, (2) an atomic radius of 0.154 nm, and (3) a saturation flux density of 0.83 tesla. Determine the number of Bohr magnetons per atom for this material. A: What is the volume, in m3, for this unit cell?B: How many atoms are there per m3 in this material?C: What is the number of Bohr magentons per atom for this material?

Answers

Answer:

a. 2.9218x10^(-29) m^3

b. 7.1230x10^(28) atoms/m^3

c. 2.0812 BM/atom

Explanation:

Atomic radius r = 0.154 nm

saturation flux density Bs = 0.83 tesla

- the formula for the volume of the simple cubic crystal (Vc) = a^3 = (2r)^3

= (2 x 0.154x10^-9)^3

= 2.9218x10^-29 m^3

- The formula for the Bohr magneton per atom with respect to VC, Bs, permeability of the vacuum Uo and magnetic moment per Bohr magneton Ub is;

Bohr magneton per atom nb = (Bs x VC) / (Ub x Uo)

                                    = (0.83 x 2.9218x10^-29) / (9.27x10^-24) x(1.257x10^-6)

                                    = 2.4251x10^-29 / 1.1652x10^-29

                                    = 2.0812 BM/atom

- Number of atoms per Vc, N = nb / Vc

                                              = 2.0812 / 2.9218x10^-29 = 7.1230x10^28 atoms

A brine solution is 26% salt with 70.0 kg of water evaporated per hour. To produce 195 kg of pure salt (0% moisture) per day, how long should the process operate each day and how much brine must be fed to the evaporator per hour?
The process should operate each day for ___ hours.
The amount of brine that must be fed to the evaporator is ___ kg/h.

Answers

Answer:

- the process should operate each day for 7.9286 hours

- the amount of brine that must be fed to the evaporator is 94.594 kg/hr

Explanation:

Given that;

concentration of brine = 26%

so water concentration will be 100% - 26% = 74%

for evaporation of 70kg water per hour, residual is pure salt( 0% moisture)

so mass flow rate of brine = 70/(74%) = 70/0.74 = 94.5945 kg/hr

Amount of pure dry salt produced(0%) = 94.5945 - 70 = 24.5945 kg/hr

Now for production of 195kg of pure dry salt, number of hours required will be

T = 195 / 24.5945 = 7.9286 hrs

Therefore the process should operate each day for 7.9286 hours.

Total brine solution required ( 26% salt conc.) = 195/0.26 = 750 kg

Feed rate of brine solution ( 26% salt conc.) = 750 / 7.9286 = 94.594 kg/hr

Therefore the amount of brine that must be fed to the evaporator is 94.594 kg/hr

A work element in a manual assembly task consists of the following MTM-1 elements: (1) R16C, (2) G4A, (3) M10B5, (4) RL1, (5) R14B, (6) G1B, (7) M8C3, (8) P1NSE, and (9) RL1.
(a) Determine the normal times in TMUs for these motion elements.
(b) What is the total time for this work element in sec

Answers

Answer:

a)

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b) 3.1 secs

Explanation:

a) Determine the normal times in TMUs for these motion elements

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b ) Determine the total time for this work element in seconds

first we have to determine the total TMU = ∑ TMU = 86.4 TMU

note ; 1 TMU = 0.036 seconds

hence the total time for the work in seconds = 86.4 * 0.036 = 3.1 seconds

1) I love to swim. 2) A few years ago, my new year's resolution was to become a faster swimmer. 3) First, I started eating better to improve my overall health. 4) Then, I created a training program and started swimming five days a week. 5) I went to the pool at my local gym. 6) To measure my improvement, I tried to count my laps as I was swimming, but I always got distracted and lost track! 7) It made it very hard for me to know if I was getting faster. 8) This is a common experience for swimmers everywhere. 9) We need a wearable device to count laps, calories burned, and other real-time data. Summarey of the story

Answers

Do you think you could help me on my latest question

sin x +√3 coax= √2

Answers

Answer:

The two values of x are 2n*pi + pi/12 and 2n*pi -5pi/12

Explanation:

The given equation is

Sin x +√3 Cosx= √2

Upon dividing the equation by 2 we get

 [tex]\frac{1}{2}Sinx + \frac{\sqrt{3} }{2}Cosx = \frac{\sqrt{2} }{2}[/tex]

Sin([tex]\frac{pi}{6}[/tex])*Sinx + Cos([tex]\frac{pi}{6}[/tex])*Cosx = [tex]\frac{1}{\sqrt{2} }[/tex]

This makes the formula of

CosACosB + SinASinB = Cos(A-B)

 Cos(x-[tex]\frac{pi}{6}[/tex]) = [tex]\frac{1}{\sqrt{2} }[/tex]

cos(x- pi/6) = cos(pi/4)

upon writing the general equation we get

x-pi/6 = 2n*pi ± pi/4

x = 2n*pi ± pi/4 -pi/6

so we will have two solutions

x = 2n*pi + pi/4 -pi/6

  = 2n*pi + pi/12

and

x = 2n*pi - pi/4 -pi/6

  = 2n*pi -5pi/12

Therefore the two values of x are 2n*pi + pi/12 and 2n*pi -5pi/12.

On a Test please help
When towing a trailer, you should consider all of the following except

the minimum speed limit on roadways.
your personal protective equipment.
the gross weight of the load.
the increased stopping distance

Answers

Answer:

I'm not 100%sure but I think it's the first one

lara sees her colleague taking a bribe from a customer. what should she do?


A. confront her colleague with a warning
B. tell her other colleagues and spread the news
C. ask for a stake in the bribe
D. gather evidence and approach a trusted supervisor​

Answers

Answer:

D. Gather evidence an approach a trusted supervisor

Explanation:

B and C are obviously not the answer, A will probably not be useful since the colleague will most likely continue what they are doing

Technician A says that a way to prevent galvanic corrosion is to duplicate the original installation method. Technician B says that a way to prevent galvanic corrosion is to reuse coated bolts. Who is right

Answers

Answer:

Technician A

Explanation:

Galvanic corrosion is not on only one metal alone but caused when two metals are interacting. Thus, Duplicating the original installation method is a better option because re-using a coated bolt doesn't prevent galvanic corrosion because both materials must be coated and not just the bolt and in technician B's case he is coating just the bolt. Thus, technician B's method will not achieve prevention of galvanic corrosion but technician A's method will achieve it.

Compare and contrast the roles of agricultural and environmental scientists.

Answers

Answer:

HUHHHHHH BE SPECIFIC CHILE

Explanation:

ERM IRDK SORRY BOUT THAT

If 1 inch equals 10 feet, what would the measured distance be if the line scaled 1 1/2 inches?
A. 10 feet
b. 15 feet
c. 2 feet
d. 25 feet​

Answers

Answer: B. 15 feet

Explanation:

A trapezoidal section has a 5.0-ft bed width, 2.5-ft depth, and 1:1 side slope. Evaluate its geometric elements (Area, water depth, wetted perimeter, top width, hydraulic radius, and hydraulic depth).

Answers

Answer:

a) 18.75 ft^2

b) 2.5 ft

c) 12.07 ft

d) 10 ft

e) 1.553 ft

f) 1.875 ft

Explanation:

Given data :

5.0-ft bed width, ( b )

2.5-ft depth ( y )

1 : 1 side slope

Evaluate

a) Area of trapezoidal section

A = by + my^2

we assume m = 1

A = [5 + (1 * 2.5 ) ] *2.5

   = ( 7.5 ) 2.5  = 18.75 ft^2

b) Calculate water depth

water depth = 2.5 ft

c) Calculate wetted perimeter

P = b + 2y √ 1 + m^2

  = 5 + (2.5*2) √ 1 + 1 ^2  =   12.07 ft

d) calculate top width

    T = b + 2my

       = 5 + 2 ( 1 * 2.5 ) = 10 ft

e) calculate hydraulic radius

R = A / P = 18.75 / 12.07

               = 1.553 ft

f) calculate hydraulic depth

 D = A / T = 18.75 / 10 = 1.875 ft

If the length of the arm were to increase, how would the required torque change? a. Required torque would increase b. Required torque would decrease c. Required torque would remain the same d. It is impossible to calculate required torque with the values given.

Answers

B.requires torque would decrease (I think)

GMA MIG weiding is a

Answers

Gas metal arc welding (GMAW), sometimes referred to by its subtypes metal inert gas (MIG) welding or metal active gas (MAG) welding, is a welding process in which an electric arc forms between a consumable MIG wire electrode and the workpiece metal(s), which heats the workpiece metal(s), causing them to melt and join.

Explanation:

GMA MIG weiding is aiejrjjrkdkff

What does Enter key do?

You cannot click Enter key to start a line if your current is blank?

This is spot to do today

Answers

Answer:

See below

Explanation:

Enter-key also called the "Return key," it is the keyboard key that is pressed to signal the computer to input the line of data or the command that has just been typed.It Was the Return KeyThe Enter key was originally the "Return key" on a typewriter, which caused the carriage to return to the beginning of the next line on the paper. In a word processing or text editing application, pressing Enter ends a paragraph. A character code for return/end-of-line, which is different in Windows than it is in the Mac, Linux or Unix, is inserted into the text at that point.

Answer:

True

Explanation:

Once there are two yellow lines having inner broken lines on the two sides of a center traffic lane, what this is trying to tell you is that you can use those lanes to start a left hand turn, or a U-turn from the both directions of traffic. However you cannot use it for passing. This is sometimes misunderstood by road users and drivers.

Other Questions
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