Answer:
The photon or quantum of light
Explanation:
explain why the moon orbits the earth while the earth orbits the sun
Which phrase is best described as the energy of motion?
Answer:
The energy of motion is known as kinetic energy.
Explanation:
A car starts from rest and for 15.0 s its wheels has a constant linear acceleration of 0.800 m/s^2 to the right. What is the angle through which each wheel rotated in 20.0 s interval if the radius of the tires is 0.330 m?
What is the total amount of potential and kinetic energy in a system? *
1 point
A: Electrical energy
B: Heat energy
C: Mechanical energy
D: Nuclear energy
Answer:
C. Mechanical Energy
Explanation:
The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.
2. Un niño hace girar con la mano una pelota de hule que se encuentra sujeta mediante un cordón de
0.75 m de longitud. Si la pelota da 0.7 vueltas a cada segundo, entonces,
a) ¿Cuál es el periodo de la pelota?
b) ¿Cuál es la velocidad lineal de la pelota?
Cuando el niño hace girar 0.7 vueltas por segundo una pelota de hule que se encuentra sujeta mediante un cordón de 0.75 m de longitud, tenemos que:
a) El periodo de la pelota es 1.43 segundos.
b) La velocidad lineal de la pelota es 3.3 m/s.
a) El periodo de la pelota está dado por:
[tex] T = \frac{2\pi}{\omega} [/tex]
En donde:
ω: es la velocidad angular
Dado que la pelota da 0.7 vueltas (revoluciones) cada segundo, la velocidad angular es:
[tex] \omega = \frac{0.7 \:rev}{s}*\frac{2\pi rad}{1 \:rev} = 4.40 rad/s [/tex]
Entonces, el periodo es:
[tex]T = \frac{2\pi}{\omega} = \frac{2\pi}{4.40 rad/s} = 1.43 s[/tex]
b) La velocidad lineal de la pelota se puede calcular usando la siguiente ecuación:
[tex] v = \omega r [/tex]
En donde:
r: es el radio de la circunferencia = longitud del cordón = 0.75 m
[tex]v = \omega r =4.40 rad/s*0.75 m = 3.3 m/s[/tex]
Por lo tanto, la velocidad lineal de la pelota es 3.3 m/s.
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(2) A 800 g block is pushed up an inclined plane (angled at 18°) with a velocity of 11.8 m/s. The first block slides up the
incline a distance of 2.2 m and strikes a second block with a mass of 300 g also moving at 3.4 m/s up the incline.
The two blocks hit and stick together. Determine the following:
(i) The maximum vertical height of the two blocks when they stop.
(ii) The time needed for the blocks to reach the bottom of the incline after the moment of impact.
(u = 0.19)
this is my attachment answer hope it's helpful to you
what is the purpose of delivering medical aid through drones
If the ball has a positive electric charge, what should the charge of the coilgun be to push the ball away?
A)positive
B) negative
C)neutral
Answer:
A
Explanation:if the things have the same charge they will repel makeing the ball move away form its positively charged guy = that the coil gun works.
Find the gravitational potential energy of a body of mass 25kg,kept at a height of 4m If g=10m/s'.
Answer:
1000 JExplanation:
The gravitational potential energy of a body can be found by using the formula
GPE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
GPE = 25 × 10 × 4 = 1000
We have the final answer as
1000 JHope this helps you
Kichelle enjoys balloon animals from the carnival. She just received a balloon giraffe that has an initial temperature of 39.0°C and a volume of 1.28 L. If Preston plays a trick on Kichelle, and puts her balloon giraffe into the freezer, what would be the new volume of the balloon if the temperature drops down to 8.0°C?
39°C=1.28L
8°C=? Less
=8°C/39°C×1.28L
=8/39×1.28L
=10.24/39
=512/195
=2.6L
Who is the author "talking” to in the third stanza of Flanders field
Answer:
One of Canada's best-known poems, “In Flanders Fields” was written on May 2, 1915, when Canadian serviceman John McCrae was stationed at an army hospital in Flanders, Belgium, during World War I.
Explanation:
______is the rate of change of velocity. A,speed. B,distance. C,acceleration. D,force
Explanation:
c) aceleración
Which explains why scientists often prefer to measure mass rather than weight?
It is always the same.
It is affected by gravity.
Answer:
scientists often prefer to measure mass rather than weight because weight is affected by gravity while mass is not. Mass is always the same.
Explanation:
Weight is a force rather than a measure of the amount of matter something contains. The same amount of matter can have different weights depending on where it is. Mass directly measures the amount of matter present and remains the same no matter where it's measured.
1. A stone is thrown vertically upward with velocity of 15 m/s at the same time, 10 m vertically above a second stone is allowed to fall. After what time and at what height do they collide (take g = 10 ms^-2)
Let the ball at the ground be A and that at the top be B.
Assume that you see the motion of A while sitting at B.
You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.
Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.
Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.
Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.
Since B falls freely, he covers a distance of 1/2(g)(1²)=5 (assuming g = 10m/s²)
Thus, they meet at a height of (20–5)m = 15m from the ground.
a soccer ball is kicked at an angle of 35° and it lands on even ground.
A) What angle will produce the same range?
B) Which angle of the two will produce the highest ball?
C) Which angle of the two will produce the ball that is in the air the longest?
D) What angle in this situation would produce the furthest range?
Hi there!
A)
The angle that will produce the same range is the compliment of 35°.
Thus, kicking the ball at 55° will result in the same range.
We can prove this by using the derived range equation:
[tex]R = \frac{v^2sin2\theta}{g}[/tex]
An angle of 35° yields:
[tex]R = \frac{v^2sin(2*35)}{g} = .939R[/tex]
An angle of 55° yields:
[tex]R = \frac{v^2sin(2*55)}{g} = .939R[/tex]
Both are the same, thus indicating that 55° produces the same range.
B)
The angle of 55° will produce the higher ball because the VERTICAL component of the ball's velocity is greater compared to kicking the ball at 35° degree.
sin(55) > sin(35)
C)
The angle of 55° will result in the ball being in the air the longest because when a ball is in the air (assuming no air resistance), the ball experiences an acceleration due to gravity of -9.8 m/s², causing the vertical velocity to decrease until it eventually reaches 0 m/s at the top of its path. A greater initial vertical velocity means that it will take longer for the ball to fall.
We can prove this using:
vf = vi + at
0 = vy - 9.8t
vy/9.8 = t
Greater vy (vertical component of velocity) ⇒ greater time taken.
D)
The angle that would result in the furthest range is 45°.
We can prove this using calculus. Recall the above range equation:
[tex]R = \frac{v^2sin2\theta}{g}[/tex]
We can take the derivative and use the first-derivative test to find its critical point:
[tex]\frac{dR}{d\theta} = \frac{v^22cos2\theta}{g} = 0[/tex]
Evaluate:
[tex]v^22cos2\theta = 0 \\\\cos2\theta = 0 \\\\2\theta = 90^o\\\\\boxed{\theta = 45^o}[/tex]
A. The angle that will produce the same range as a 35° kick is 53°.
B. The angle that produces the highest ball is 45°.
C. The angle that produces the ball that is in the air the longest is 45°.
D. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.
A. The range of a projectile is the horizontal distance it travels before it hits the ground. The range of a projectile is determined by the initial velocity, the angle of projection, and the acceleration due to gravity.
For a given initial velocity, the range of a projectile is maximized when the angle of projection is 45°. However, if the ground is not level, the range of a projectile can be maximized at other angles.
In the case of a soccer ball kicked at an angle of 35°, the range will be maximized at an angle of 53°. This is because the range of a projectile is maximized when the vertical component of the initial velocity is equal to the horizontal component of the initial velocity.
The angle of 53° is the angle that produces a vertical component of the initial velocity that is equal to the horizontal component of the initial velocity when the ball is kicked at an angle of 35°.
Therefore, the angle that will produce the same range as a 35° kick is 53°.
B. The angle that produces the highest ball is 45°.
C. The angle that produces the ball that is in the air the longest is 45°.
D. The angle that produces the furthest range depends on the initial velocity and the acceleration due to gravity. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.
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For a boiling kettle draw a sankey diagram to show where The energy goes
Answer:
draw the picture / (.) (.) \ Patrick star
When there is a temperature inversion, you would expect to experience Group of answer choices clouds with extensive vertical development above an inversion aloft. good visibility in the lower levels of the atmosphere and poor visibility above an inversion aloft. an increase in temperature as altitude increases.
Temperature inversion leads to an increase in temperature as altitude increases.
The term temperature inversion refers to a situation in which a layer of warm air lies over a layer of cool air. This is also referred to as thermal inversion. This occurs when the air below to loose heat rapidly.
One of the effects of temperature inversion is reduction in visibility. So, thermal inversion leads to an increase in temperature as altitude increases.
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A car goes from 60 m/s to 75 m/s in 10 seconds.calculate the car’s acceleration?
Explanation:
Uhhhh here is an example
a=vt. =27 m/s10 s. =2.7 m/s2.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Acceleration of the car is ~
[tex] \boxed{1.5 \: \: m/s}[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
We know that,
Acceleration = rate of change in velocity ~
that is ~
[tex]a = \dfrac{v - u}{t} [/tex]where,
v = final velocityu = initial velocity t = time taken ~now, let's solve ~
[tex]a = \dfrac{75 - 60}{10} [/tex][tex]a = \dfrac{15}{10} [/tex][tex]a = 1.5 \: \: m/s[/tex]A long-distance runner runs at a constant speed of 4.8 m/s. How long does it take them to run 1.5 km?
Convert km to meters:
1km = 1000 m
1.5 km x 1000 = 1500 m
1500m / 4.8 m/s = 312.5 seconds
312.5 seconds / 60 seconds per minute =5.2 minutes = 5 minutes 12.5 seconds
Solve this anyone please fast ..!
Answer:
Explanation:
Ax= 20*sin37
Ay =20*cos37
Bx=15*cos40
By = -15*sin40
Cx = -6*cos60
Cy = -6*sin60
Answer:
Ax = 12 cos 53
Ay = 12 sin 53
Bx = 15 cos 320 = 15 cos 40
By = 15 sin 320 = -15 sin 40
Cx = 6 cos 240 = -6 cos 60
Cy = 6 sin 240 = -6 sin 60
A small ball is attached to one end of a spring that has an unstrained length of 0.201 m. The spring is held by the other end, and the ball is whirled around in a horizontal circle at a speed of 3.41 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0176 m.
Required:
By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?
The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
The given parameters;
unstrained length, l₁ = 0.201 mextension of the string, x = 0.0176 mspeed of the ball, v = 3.41 m/sThe radius of the circular path when spring is stretched is calculated as;
R = l₁ + x
R = 0.201 + 0.0176
R = 0.2186 m
The spring constant is calculated as follows;
[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]
The extension of the spring when the ball is allowed to hang straight down, motionless;
[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]
Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
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Determine the work done by the force Fx=(6x-4)N as the object moves from x1=0 to x2=3 m.
Answer:
15J
Explanation:
Let's assume force and motion have the same direction, so the dot product between the two reduces to the product of magnitudes.
If you studied calculus: [tex]w= \int \limits^3_0 6x-4dx[/tex], by definition. Some "easy" math, that's [tex](3x^2-4x)\limits^3_0=27-12 - 0 = 15 J[/tex]
Else. we have to take the long way. if the force was constant, and you plotted magnitude of the force vs position in a graph, you would get an horizontal line, and your work would be the area between the line and the x axis. And there is no reason why it shouldn't be the same for a variable force - if you think about it, it's the same way they justify the position formula for an accelerated motion. Let's graph it and start debating - sorry for my paint skills. We can easily say that in the green triangle the force is opposing the motion, so its work is negative, while in the blue area force and displacement go in the same direction, thus work is positive. Now it's just to calculate the area of two triangles
For the green one, it's a right triangle with side lengths 4 and 2/3, whose area is [tex]\frac12(4)(\frac23) = \frac43[/tex].
For the blue triangle, it's again a right triangle with side lengths 14 and 3-2/3= 7/3, whose area is [tex]\frac12(14)(\frac73) = \frac{49}3[/tex]
Our total work is the difference between the two, or [tex]w= \frac{49}3-\frac43 = \frac{45}3 = 15[/tex]
The length of a road is 35.5cm what will be the length in meters?
안녕하세요
answer is 355 meters ...
Answer:
0.355m
Explanation:
To convert from cm to m, divide by 100
35.5÷100=0.355m
A 60 kg gorilla named Anthony Falcon is standing on his skateboard. This is on planet Erf,
where a = g = -10m/s2
If Anthony Falcon has a weight of 600 N, with what amount of force is their body pushing
down on the skateboard with?
The diagram shows what happened in the Rutherford and Marsden scattering experiment. Complete this sentence: The particle shown in red will come straight back from the foil because it is __________ by the charge in the gold nucleus.
From Rutherford and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.
Rutherford proposed Planetary model atom, which visualized an atom to consists of a positively charged heavy core called the nucleus around which negatively charged electrons circle in orbits much as planets move round the sun
Thus, from Rutherford and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.
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the answer is reflected or u can say repelled
When positive charges build up in an object, the net charge of that object becomes...
a. it stays the same
b. negative
c. positive
d. neutral
Answer:
c. postive
Explanation:
All physical objects are made up of atoms. Inside an atom are protons, electrons and neutrons. The protons are positively charged, the electrons are negatively charged, and the neutrons are neutral.
Therefore, all things are made up of charges. Opposite charges attract each other (negative to positive). Like charges repel each other (positive to positive or negative to negative). Most of the time positive and negative charges are balanced in an object, which makes that object neutral.
Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged. One way to discharge them is through a circuit.
Hope this helps, have a nice day/night! :D
Answer:
C
Explanation:
C because if you build anything up it remains the same.
Explain the relationship between the frequency, energy, and wavelength of a wave.
Answer:
Explanation:
The energy equation is E=hv
A runner slows down after completing a race. Her deceleration is 0.25 m/s2. After 5 s she is travelling at 4 m/s, determine her initial velocity.
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
The initial velocity of the runner is 5.25 m/s.
What is deceleration?
You've probably seen that when there's a lot of traffic and there are more bikes blocking us, we tend to slow down the speed of our bikes.
Therefore, deceleration is defined as a reduction in speed as the body moves away from the beginning location. The opposite of acceleration is deceleration.
Given parameters:
Deceleration of the runner: a = 0.25 m/s².
Time interval: t = 5 second.
Final velocity: v = 4 m/s.
We have to find initial velocity of the runner: u = ?
From definition of deceleration, it can be written that:
deceleration = (initial velocity - final velocity) time interval
0.25 = (u -4)/5
u = 5.25 m/s.
Hence, initial velocity of the runner is 5.25 m/s.
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A bowling ball and a ping-pong ball are each tied to a string and hung from the ceiling. The distance from the ceiling to the CM of each object is the same. Which object would have a longer period of motion if they were set swinging
What is the potential energy of a 50kg car on top of a 600m hill?
Answer:
294,000 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
PE = 50 × 9.8 × 600 = 294,000
We have the final answer as
294,000 JHope this helps you