To estimate the height of a building, two students find the angle of elevation from a point (at ground level) down the street from the building to the top of the building is 35∘. From a point that is 150 feet closer to the building, the angle of elevation (at ground level) to the top of the building is 51∘. Assume that the street is level. What is the height of the building?

Round your answer to the nearest hundredth. Don't include the "h=" or any units - your answer should just be a number

Answer:

Lucy has ridden 25% of the course so far. This means she has completed a quarter of the total distance.

Step-by-step explanation:

To determine the percentage of the course Lucy has ridden so far, we can use the following formula:

Percentage = (Distance ridden / Total distance) * 100

Given that the total distance of the bike course is 88 miles and Lucy has

ridden 22 miles, we can substitute these values into the formula:

Percentage = (22 miles / 88 miles) * 100

Simplifying the equation:

Percentage = (1/4) * 100

Percentage = 25

Therefore, Lucy has ridden 25% of the course so far. This means she has completed a quarter of the total distance.

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The given data set: 4, 5, 6, 6, 7, 7, 7, 7, 8, 8, 9, 10 is skewed right or positively skewed due to a cluster of values towards the center and a gradual increase on the right side. The correct answer is A) Skewed Right.

The given data set is: 4, 5, 6, 6, 7, 7, 7, 7, 8, 8, 9, 10.

To determine the shape of the data set, we can analyze its distribution.

Looking at the data set, we can observe that the values are gradually increasing from 4 to 10. However, there are multiple occurrences of the numbers 6, 7, and 8. This indicates that the data set has a cluster or mode around these values.

Since the data set has a cluster of values towards the center and a gradual increase on the right side, it suggests that the data set is skewed right or positively skewed.

Therefore, the correct answer is A) Skewed Right.

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The solution is: 0.003 area of of the room's area is, covered by one sheet of newspaper.

Here, we have,

given that,

60 cm * 50 cm what is the area covered by one sheet of newspaper if the area of the room is 79.2 m square​.

we know, that,

area of one sheet of newspaper = 60 cm * 50 cm

                                                      = 3000 cm^2

we know that,

100 cm = 1 m

so, 3000 cm^2 = 0.3 m^2

now, we have,

the area of the room is 79.2 m square​.

so, we get,

the area covered by one sheet of newspaper = 0.3/ 79.2

                                                                            = 0.003

Hence, The solution is: 0.003 area of of the room's area is, covered by one sheet of newspaper.

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We cannot determine the exact number of complex zeros for the given polynomial.

We have,

To determine the number of complex zeros of the polynomial

f(x) = 6x^6 - 5x^4 + 2x^3 - x^2 + 12

We need to analyze the degree and sign changes of the polynomial.

The degree of the polynomial is 6, which means it is a polynomial of degree 6.

According to the Fundamental Theorem of Algebra, a polynomial of degree n can have at most n complex zeros (counting multiplicity).

To analyze the sign changes, we can write down the coefficients of the polynomial in a row:

6, -5, 2, -1, 0, 0, 12

By observing the sign changes in the row of coefficients, we see that there are no sign changes.

This indicates that the polynomial has either zero or an even number of positive real zeros.

Since we are interested in complex zeros, this information alone does not provide conclusive evidence.

To determine the number of complex zeros, we would need more information or further analysis.

It is possible that some of the zeros are complex or imaginary, but without more details or a complete factorization of the polynomial, we cannot determine the exact number of complex zeros.

Thus,

We cannot determine the exact number of complex zeros.

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The sequence of transformations that transform the the pre-image and the congruence of the pre-image and image are indicated by the option D.

D. Reflection, then rotation results in an image that is congruent to the original

A transformation is the performance of a rotation, reflection, translation, or dilation, that produces an image with a different size, location, orientation or shape.

The coordinates of the points on the triangle ABC are laterally equidistant from the vertical line in the middle between the triangles ABC and triangle DEF, such that the line in the middle is the line of reflection.

The vertical height of the coordinates of the triangle ABC and DEF, which are the same indicates that the transformation from triangle ABC to EFD is a reflection across the line in the middle between the two triangles. The side GH in triangle IGH corresponds to the side EF in the triangle EFD,

The length of GH = EF = 4 units

Similarly, IH = DE, and IG = DF, therefore;

Triangle EFD and triangle HGI are congruent by SSS congruence rule

The orientation of the side EF of the triangle EFD which is vertical and the side HG which is horizontal indicates a rotation of the triangle EFD by 90 degrees to obtain the triangle HGI

The correct option is therefore, the option D.

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To find a particular solution of the non-homogeneous equation and the general solution of the equation, we can use the method of variation of parameters.

First, let's find the Wronskian of the homogeneous solutions y1(x) and y2(x):

W(y1, y2) = | y1 y2 |

| y1' y2' |

We have y1(x) = sin(x) / √x and y2(x) = cos(x) / √x. Differentiating these functions, we get:

y1'(x) = (cos(x) / √x - sin(x) / (2√x^3))

y2'(x) = (-sin(x) / √x - cos(x) / (2√x^3))

Substituting these values into the Wronskian:

W(y1, y2) = | sin(x) / √x cos(x) / √x |

| (cos(x) / √x - sin(x) / (2√x^3)) (-sin(x) / √x - cos(x) / (2√x^3)) |

Expanding the determinant:

W(y1, y2) = (sin(x) / √x) * (-sin(x) / √x - cos(x) / (2√x^3)) - (cos(x) / √x) * (cos(x) / √x - sin(x) / (2√x^3))

Simplifying:

W(y1, y2) = -1 / (2√x)

Now, we can find the particular solution using the variation of parameters formula:

y_p(x) = -y1(x) * ∫(y2(x) * g(x)) / W(y1, y2) dx + y2(x) * ∫(y1(x) * g(x)) / W(y1, y2) dx

Here, g(x) = 3x√xsin(x). Substituting the values:

y_p(x) = -((sin(x) / √x) * ∫((3x√xsin(x)) * (-1 / (2√x))) dx + (cos(x) / √x) * ∫((3x√xsin(x)) / (2√x)) dx

Simplifying the integrals:

y_p(x) = -(∫(-3sin^2(x)) dx) + (∫(3xcos(x)sin(x)) dx)

Integrating:

y_p(x) = 3/2 (xsin^2(x) - cos^2(x)) - 3/2 (xcos^2(x) + sin^2(x)) + C

Simplifying:

y_p(x) = 3x(sin^2(x) - cos^2(x)) + C

The general solution of the equation is given by the sum of the homogeneous solutions and the particular solution:

y(x) = C1 * (sin(x) / √x) + C2 * (cos(x) / √x) + 3x(sin^2(x) - cos^2(x)) + C

where C1, C2, and C are arbitrary constants.

The number of adult tickets sold were 80.

Let's denote the number of adult tickets sold as A and the number of student tickets sold as S.

The number of student tickets sold was two times the number of adult tickets sold:

S = 2A

We also know that the total number of tickets sold was 240:

A + S = 240

Substituting the value of S from the first equation into the second equation, we have:

A + 2A = 240

Combining like terms:

3A = 240

Divide both sides of the equation by 3:

A = 80

Therefore, 80 adult tickets were sold.

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The coordinates of one of the points in Carlos' pattern would be (2, 3).

To determine the coordinates of the points in Carlos' pattern, we can assign the term number as the x-coordinate and the corresponding term value as the y-coordinate. Let's go through each term:

Term 1: 1

The first term is 1. So, the coordinate for this term is (1, 1).

Term 2: 3

The second term is obtained by adding 2 to the previous term. The previous term had the coordinate (1, 1). Therefore, the coordinate for this term is (2, 3).

Term 3: 5

The third term is obtained by adding 2 to the previous term. The previous term had the coordinate (2, 3). Therefore, the coordinate for this term is (3, 5).

Term 4: 7

The fourth term is obtained by adding 2 to the previous term. The previous term had the coordinate (3, 5). Therefore, the coordinate for this term is (4, 7).

From the given options, we can see that the coordinates (2, 3) match one of the points in Carlos' pattern. Therefore, the correct answer is B) (2, 3).

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Answer: I WOULD SAY 45%

Step-by-step explanation:

The percentage increase in miles per gallon from Toyota city driving to highway driving is 33.33%.

The percentage increase in miles per gallon from Toyota city driving to highway driving can be calculated using the formula:

Percentage increase = ((new value - old value) / old value) x 100

Let's say the old miles per gallon for city driving is 30 and the new miles per gallon for highway driving is 40:

Therefore, there is a 33.33% increase in miles per gallon from Toyota city driving to highway driving.

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Clearer image, please!

Check the picture below.

The length of one side of the square is 36 meters.In general, the perimeter of a rectangle can be found by adding up the lengths of all four sides.

If we know the length and width of the rectangle, we can use the formula:

Perimeter = 2(length + width)

To find the length of the rectangle using the Pythagorean Theorem, we would need to be given some additional information, such as the width and the length of one of the sides or one of the diagonals. Once we have the length and width of the rectangle, we can use the formula above to find its perimeter.

If the diagonals of a square measure 36 meters, what is the length of a side of the square?(Use Pythagorean Theorem to find the side of the square)

Let s be the length of one side of the square. Since the diagonals of a square are equal in length, we have:

s² + s² = 36²

Simplifying the left-hand side:

2s² = 1296

Dividing both sides by 2:

s² = 648

Taking the square root of both sides:

s = √648 = 18√4 = 36.

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The coefficient of variation or CV of the given numbers is 45.64%.

Given numbers are,

5, 8, 9, 2, 6

We have to find Coefficient of variation.

CV = (Standard deviation / sample mean ) × 100

Sample mean = Sum of the values / total number of values

                       = (5 + 8 + 9 + 2 + 6) / 5

                       = 6

Standard deviation = √[(Σ(x - mean)² / (n - 1)]

Σ(x - mean)² = (5 - 6)² + (8 - 6)² + (9 - 6)² + (2 - 6)² + (6 - 6)²

                    = 30

Standard deviation = √(30 / (5 - 1) = 2.7386

CV = (2.7386 / 6) × 100

     = 45.64%

Hence CV is 45.64%.

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The approximate x-values for the local maximum and the local minimum are given as follows:

D) max ≈ -0.3 , min ≈ 2.3.

Hence the critical points of the graphed function are given as follows:

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Answer:2nd one

Step-by-step explanation:

Answer:

43.98

Step-by-step explanation:

43.98 to nearest hundredth

1. The of jigsaw puzzles is 216 and crossword puzzle is 261.

2. 22 table lamps were left in the warehouse.

1. Crossword Puzzle Books and Jigsaw Puzzles:

Let's the number of jigsaw puzzles as "x".

then, the number of crossword puzzle books will be "x + 45"

Now, Number of sold crossword puzzle books = (5/9) (x + 45)

= (25/100) x

= x/4

It is also given that there were 91 more crossword puzzle books sold than jigsaw puzzles. Therefore, we can set up the equation:

(5/9) (x + 45) - (x/4) = 91

(5/9)x + 25 - (x/4) = 91

(20/36)x + 25 - (9/36)x = 91

(11/36)x = 91 - 25

(11/36)x = 66

x = (36/11)  66

x ≈ 216

So, the number of jigsaw puzzles is 216 and the number of crossword puzzle books is 216 + 45 = 261.

2. Table Lamps and Standing Lamps:

Let's the number of table lamps as "x".

then, the number of standing lamps will be "155 - x"

So, Number of table lamps = (60/100) x = 0.6x

and, Number of standing lamps

= (80/100) (155 - x)

= 0.8(155 - x)

= 124 - 0.8x

Therefore, the number of table lamps left will be:

Remaining table lamps = (70/100) * 0.6x = 0.42x

To find the value of x, we can set up the equation:

0.42x = x - 30

Simplifying the equation:

x - 0.42x = 30

0.58x = 30

x = 30 / 0.58

x ≈ 51.72

So, the number of table lamps left is 0.42 x 51.72 ≈ 21.68.

Thus, 22 table lamps were left in the warehouse.

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The blanket's width is determined by adding up the widths of each individual stripe, resulting in a total width of 104 inches.

To find the width of Alyssa's blanket, we need to calculate the total width of all the pink and white stripes combined.

Given that there are 7 pink stripes and 6 white stripes, and each stripe is 8 inches wide, we can calculate the total width as follows:

Total width = (Number of pink stripes [tex]\times[/tex] Width of each pink stripe) + (Number of white stripes [tex]\times[/tex] Width of each white stripe)

Substituting the values into the equation:

Total width [tex]= (7 \times 8) + (6 \times 8)[/tex]

= 56 + 48

= 104 inches.

Therefore, Alyssa's blanket is 104 inches wide.

In this case, we multiply the number of pink stripes by the width of each pink stripe (7 [tex]\times[/tex] 8) and add it to the product of the number of white stripes and the width of each white stripe (6 [tex]\times[/tex] 8) to obtain the total width of the blanket.

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The required, general solution for x that satisfies the equation cos(x + 30) = -1 is x = (2n + 1)π - 30.

To find the general solution for the equation cos(x + 30) = -1, we can start by considering the general form of the cosine function. The cosine function has a period of 2π, meaning it repeats every 2π radians.

In this equation, we have cos(x + 30) = -1. Since the cosine function has a maximum value of 1 and a minimum value of -1, the only way for cos(x + 30) to equal -1 is if x + 30 is an odd multiple of π. We can write this as:

x + 30 = (2n + 1)π

Here, n is an integer representing the number of periods of the cosine function. To find the general solution, we can solve for x by subtracting 30 from both sides:

x = (2n + 1)π - 30

This equation gives us the general solution for x that satisfies the equation cos(x + 30) = -1. We can see that for each integer value of n, we have a different solution.

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All six trigonometric ratios of the triangle are :

sin (θ) = 3/5, cos (θ) = 4/5, tan (θ) = 3/4

cosec (θ) = 5/3, sec (θ) = 5/4, cot (θ) = 4/3

Given a triangle, which is right angled.

Length of hypotenuse = √(20² + 15²) = 25

Given an angle θ.

We have to find the six trigonometric ratios which are sin, cos, tan, cosec, sec and cot.

sin (θ) = opposite side / hypotenuse = 15/25 = 3/5

cos (θ) = adjacent side / hypotenuse = 20/25 = 4/5

tan (θ) = opposite side / adjacent side = 15/20 = 3/4

cosec (θ) = 1 / sin (θ) = 5/3

sec (θ) = 1 / cos (θ) = 5/4

cot (θ) = 1 / tan (θ) = 4/3

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Answer:

area= 39 square meters

Step-by-step explanation:

10×6=60m²

60m²÷2=30m² is the area of the bigger triangle

6×3=18m²

18m²÷2=9m²

9m²+30m²=39m²

In the given diagram, we have a triangle with one angle labeled as 2x + 10° and another angle labeled as 3x - 5°. To solve for x, we can set up an equation using the sum of angles in a triangle, which is 180°.

The sum of the angles in a triangle is given by the equation:

Angle1 + Angle2 + Angle3 = 180°

Substituting the given angle measurements, we have:

(2x + 10°) + (3x - 5°) + 95° = 180°

Combining like terms, we get:

5x + 100° = 180°

Next, we can isolate the variable x by subtracting 100° from both sides:

5x = 180° - 100°

5x = 80°

Finally, we can solve for x by dividing both sides by 5:

x = 80° / 5

x = 16°

Therefore, the value of x is 16°.

[tex]u=(\sqrt{3}~~,~-1)\hspace{5em}v=(3~~,~-4) \\\\\\ u\cdot v\implies (\sqrt{3}\cdot 3)~~ + ~~(-1\cdot -4)\implies \stackrel{ \textit{dot product} }{3\sqrt{3}+4}[/tex]

To find the average velocity of the ball between t = 1 and t = 2, we need to calculate the displacement of the ball during that time interval and divide it by the duration.

The displacement of an object can be determined by finding the difference in its position at the beginning and end of the interval. In this case, we can find the height of the ball at t = 1 and t = 2 using the given equation:

h(1) = -5(1)² + 30(1) + 5

= -5 + 30 + 5

= 30 meters

h(2) = -5(2)² + 30(2) + 5

= -20 + 60 + 5

= 45 meters

The displacement of the ball between t = 1 and t = 2 is:

Displacement = h(2) - h(1)

= 45 - 30

= 15 meters

The duration of the interval is 2 - 1 = 1 second.

Finally, we can calculate the average velocity using the formula:

Average velocity = Displacement / Duration

= 15 meters / 1 second

= 15 m/s

Therefore, the average velocity of the ball between t = 1 and t = 2 is 15 m/s.

Answer:

dy/dx = 2x + 2

Step-by-step explanation:

the slope (gradient) is given by differentiating y = x² + 2x.

dy/dx = 2x + 2

Answer:

To solve for x, we need to isolate x on one side of the equation.

First, we can start by subtracting 2 1/4 from both sides of the equation:

5 1/6x = 10 - 2 1/4

5 1/6x = 7 3/4

Next, we can simplify the left side of the equation by multiplying the whole equation by the reciprocal of 5 1/6, which is 6/31:

(6/31) * 5 1/6x = (6/31) * 7 3/4

x = 3/2

Therefore, the value of x in the equation is 3/2.

Answer:

  a. x = licensed riders; y = junior racers

  b. x + y = 321; 25x +15y = 6935

  c. see attached. (x, y) = (212, 109); 212 licensed riders; 109 junior racers

Step-by-step explanation:

You want to determine the number of racers of each type, given 321 racers total paid $6935 in fees. Licensed racers paid $25 each, and junior racers paid $15 each. You want a system of equations and a graphical solution.

In general, the variables represent the values the question is asking for. In part (b), we see that we want to find the number of racers of each type. Since our graphing program prefers the variables x and y, we will assign those in the same order the descriptions of the types of racers appear in the problem statement. (Keeping the order can avoid confusion later.)

  x = the number of licensed riders

  y = the number of junior racers

The relations given in the problem statement give rise to two equations:

The attached graph shows the solution to these equations is (x, y) = (212, 109). There were 212 licensed riders and 109 junior racers.

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The critical value of the given data set is 3.42.

The two-way chi-square analysis is used to determine if there is a relationship between two categorical variables. In this case, the two variables are shiftwork availability and the union-management relationship.

To conduct the analysis, we need to calculate the expected frequencies for each cell in the table. We can do this by multiplying the row and column totals and dividing by the total number of observations.

For the cell in the top left corner (No Shiftwork/Good Relationship):

Expected Frequency = (36 × 33) / 100 = 11.88

We can then calculate the expected frequencies for the other cells in the same way.

Once we have calculated the expected frequencies, we can then calculate the chi-square statistic using the following formula:

Chi-square = Σ [(Observed Frequency - Expected Frequency)² / Expected Frequency]

Using this formula, we can calculate the chi-square statistic for the above example as follows:

Chi-square = (11 - 11.88)²/11.88 + (22 - 21.12)²/21.12 + (25 - 23.12)²/23.12 + (42 - 40.88)²/40.88 = 3.42

Finally, we can compare the chi-square statistic to the critical value of 3.84 at α = 0.05 (df = 1). Since our chi-square statistic is less than the critical value, we can conclude that there is no relationship between shiftwork availability and the union-management relationship.

Therefore, the critical value of the given data set is 3.42.

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