Answer:
Explanation:
Not in Genesis. The proposed sacrifice of Isaac was all Abraham's doing. Sarah was not present and could not, therefore offer any input. It might have been covered in other Jewish writings, but it is not recorded in Genesis.
Since the book most widely used by Everyone is the Bible, I would answer false.
Define the following units used for measuring distances in space.
a. Arcsecond
b. Astronomical unit
c. Parsec
d. Light year
Answer:
The astronomical unit is used primarily for measuring distances within the Solar System or around other stars.
1. An airplane flies with an airspeed (speed relative to the air) of 215
km/h. The wind is blowing at 45.0 km/h. Find the velocity of the
plane (relative to the ground) if the plane is pointed straight west and
the wind is:
A. blowing toward the
west (3 points)
B. blowing toward the east (3 points)
C. blowing toward the south (4 points)
(For part C be sure to calculate the angle as well.)
Answer:
Explanation:
A) 215 + 45.0 = 260 km/h West
B) 215 - 45.0 = 170 km/h West
C) √(215² + 45.0²) = 219.6588... 220 km/h
θ = arctan(45.0/215) = 11.8214... 11.8° S of W
The airplane's ground velocity is westward at 170 km/h regardless of wind direction. The south wind does not affect the plane's westward velocity in component C.
Vector addition will determine each scenario's plane velocity relative to the ground. We'll simplify by assuming a consistent horizontal breeze.
Let's divide the airplane's velocity and wind velocity into westward (negative) and eastward (positive) components.
Data: Plane airspeed = 215 km/h.
45 km/h wind.
A. West wind:
The airplane's westward (negative) ground velocity:
West aeroplane velocity = -215 km/h
-45 km/h west wind.
Find Vg when the wind blows west:
Vg (west) = Aeroplane velocity + Wind velocity (west)
Vg(west) = -215 km/h - (-45 km/h)
Vg (west)=-170 km/h
B. East wind: 2. Westward (negative) aeroplane velocity relative to the ground:
West aeroplane velocity = -215 km/h
Wind velocity (east) = 45 km/h (because the wind is blowing eastward)
Find Vg when the wind blows east:
Vg (west) = Aeroplane velocity (west) + Wind velocity (east).
Vg (west) = -215 + 45 km/h
Vg (west)=-170 km/h
C. Southerly wind: 3. Westward (negative) aeroplane velocity:
West aeroplane velocity = -215 km/h
Wind velocity (south) = 0 km/h (no effect since wind is not moving westward)
Find Vg when the wind blows south:
Vg (west) = Aeroplane velocity (west) + Wind velocity (south).
Vg (west) = -215 + 0 km/h.
Vg (west)=-215 km/h
All resultant velocities are westward and 170 km/h.
Part C's plane's westward velocity is unaffected by the south wind. The plane's ground velocity remains -215 km/h (westward). Since the heading is westward, no angle is needed.
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4. Protons and neutrons are held together to form this _________
Answer:
strong nuclear force.
Explanation:
hope this helps you!!
Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!
Which ball moved at the same speed as Ball 3?
Answer:
you forgot to attach the image
Two moles of an ideal monatomic gas go through the cycle abc. For the complete cycle, 800 J of heat flows out of the gas. Process ab is at constant pressure, and process bc is at constant volume. States a and b have temperatures Ta = 200 K and Tb = 300 K.
(a) Sketch the all possible pV-diagrarns for the cycle.
(b) What is the work W for the process ca?
a) Sketches of all possible pv-diagrams for the cycle are attached below
b) The work W[tex]_{ac}[/tex] for the process Ca is : 2462.8 J
Given data :
Amount of heat flowing out = 800 J
Ta = 200 K
Tb = 300 K
R = 800
B) Determine the work W for the process Ca
Wₐs = -pdv
= - [ pVb - pVa ] ---- ( 1 )
note : pVb = nRTb , pVa = nRTa
Equation ( 1 ) becomes
= -nR [ Tb - Ta ]
= - 2(8.314 ) [ 300 - 200 ]
= - 1662.87
given that W[tex]_{bs}[/tex] = 0 which is isochonic
dv = 0 ( cyclic process ) = d∅ - dw
∴ 0 = 800 - ( Wₐs + W[tex]_{ac}[/tex] )
Therefore : W[tex]_{ac}[/tex] = 800 + 1662.8 = 2462.8 J
Hence we can conclude that the work W for the process Ca = 2462.8 J
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Please help me! Some people have proposed a new way to build houses in areas that are likely to experience tsunamis. In this design, a house wouldn’t have solid walls on all four sides. Instead, some of the wall areas would be replaced by substances that water can travel through quickly, as shown in the diagram. How would this design help a house survive a tsunami? What drawbacks might there be to this design?
Answer:
I think some drawbacks are that since there are no solid walls meaning it is weak and if murphy's law is in place, the water will destroy the substance. Tsunami waves also happen very quickly so even if the water can travel thru the substance quickly, it probably won't be quick enough. This design could help if the wave is smaller because less destruction would occur.
Explanation:
yeah
using dimensional analysis find the relation between the velocities of transverse waves produced from the vibration of thin homogeneous string and between the tension in the string and mass per unit length of it.
Answer:
[tex]v^2=\frac{T}{M}[/tex]
where v = transverse wave velocity, T = tension in the string, M = mass per unit length.
Explanation:
Dimensional analysis is where you just look at the units and see how they fit within each other.
In this case, all relationships are made using the MLT comparisons, where M stands for Mass, L stands for Length, and T stands for time.
For example, for velocity, we know the SI unit for velocity is [ms⁻¹] which is L¹T⁻¹, we can do the same thing for tension = [N = Kgms⁻²] = M¹L¹S⁻², and for the mass per unit length which we can think of as [Kgm⁻¹] = M¹L⁻¹.
If you play around a little with the powers, you can find a relationship:
[tex]v^2=\frac{T}{M}[/tex]
since:
[L¹T⁻¹]² = L²T⁻² = M¹L¹T⁻² ÷ M¹L⁻¹ = M¹⁻¹L¹⁻⁽⁻¹⁾T⁻² = M⁰L²T⁻² = L²T⁻²
A change in momentum is also called:
a. Impact
b. Imput
c. Impulse
d. Impole
Answer:
c. Impulse
Explanation:
URGENTLY NEED HELP
This is a 2 part question
42) You pull downward with a force of 28 N on a rope that passes over a disk-shaped pulley of mass 1.2 kg and radius 0.075 m. The other end of the rope is attached to a 0.67-kg mass. (a) Is the tension in the rope the same on both sides of the pulley? If not, which side has the greater tension? (b) Find the tension in the rope on both sides of the pulley.
Answer:
The net force on the hanging mass is thus
2 T Mg 18 6.6 N 11.4 N
, enough to accelerate it upward at
17 m/s2
. The angular acceleration of the pulley is thus
2 2
Explanation:
The tension in the rope on both sides of the pulley 20.21N.
To solve this problem, we'll need to consider the forces acting on both sides of the pulley and apply Newton's second law of motion. Let's break it down step by step:
(a) Is the tension in the rope the same on both sides of the pulley?
No, the tension in the rope is not the same on both sides of the pulley. The side with the greater mass attached will experience a greater tension in the rope.
(b) Find the tension in the rope on both sides of the pulley:
Calculate the gravitational force on each mass:
Gravitational force on the pulley: Fpulley = mpulley * g, where mpulley is the mass of the pulley and g is the acceleration due to gravity (approximately 9.8 m/s²).
Gravitational force on the hanging mass: Fhanging = mhanging * g, where m_hanging is the mass of the hanging mass.
Calculate the net force on the pulley:
Net force on the pulley is the difference between the tension forces on either side: Fnet = TLeft - Tright.
Apply Newton's second law to the pulley:
For the pulley, Fnet = mpulley * a, where a is the acceleration of the pulley. Since the pulley is assumed to be massless, we can use the relationship a = α * r, where α is the angular acceleration and r is the radius of the pulley.
Use the relationship between linear acceleration and angular acceleration:
α = a / r.
Equate the torque due to the tension to the moment of inertia times the angular acceleration:
τ = I * α, where τ is the torque, I is the moment of inertia of the pulley, and α is the angular acceleration.
Substitute the expression for α and solve for the net tension:
Tnet = (τ / r) = (I * α) / r = (1/2 * mpulley * r² * α) / r = (1/2 * mpulley * r * a).
Now, substitute the expression for a from step 3 and solve for the net tension:
Tnet = (1/2 * mpulley * r * α) = (1/2 * mpulley * r * (a / r)) = (1/2 * mpulley * a).
Substitute the expression for a from step 2 (Fnet = mpulley * a) and solve for the net tension:
Tnet = (1/2 * Fnet).
Now, you can find the tensions on each side of the pulley:
Tleft = Tnet + Fhanging
Tright = Tnet - Fpulle
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Three people are trying to move a box. Which set of forces will result in a net
force on the box of 20 N to the left?
Answer: push force gravity tension and reverse force
Explanation: sense they are pushing the box there is a push force gravity because this is likely on earth tension because it is the reverse of gravity and the reverse force because you have to have the reverse of push
9. P waves move faster than S waves A. True B. False
Two positive charges of 1 mC and 10 mC are separated by a distance of 10 m. Find the
direction and the magnitude of electrostatic force between the charges. |Describe the
direction in terms of the charges attract each other," or "the charges repel each other."
mili C=1043 C
Answer:
900N, charges repel
Explanation:
F = KQq/d²
K = 9 × 10^9Nm²/C²
Q= 10mC = 10 × 10^-3C
q = 1mc = 1 × 10^-3C
d = 10m
F = ?
Force = (9 × 10^9 × 10 × 10^-3 × 1 × 10^-3)/10²
= 9 × 10²
= 900N
It will be an electrostatic force of repulsion since like charges(two positive charges) repel
The magnitude and the direction of the electrostatic force between the charges will be 900N and the charges will repel each other.
What is Coulomb's law of forces?Coulomb's law states that whenever the two charged particles are separated by a particular distance then there will be a force of attraction or repulsion acts between the charge.
The formula of coulomb's force will be given by
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
[tex]K=9\times 10^9\ \frac{Nm^2}{C^2}[/tex]
[tex]q_1= 10\times 10^{-3}\ C[/tex]
[tex]q_2=1\times 10^{-3}\ C[/tex]
[tex]\rm Distance \ d=10 \ m[/tex]
Now the force will be calculated as
[tex]F=(9\times 10^9)\dfrac{(10\times 10^{-3})\times (1\times 10^{-3})}{10}[/tex]
[tex]F= 900\ N[/tex]
The charges are positive in nature so they will repel each other
Hence the magnitude and the direction of the electrostatic force between the charges will be 900N and the charges will repel each other.
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In this image F1 is equal to 100 N and F2 is equal to 50 N. What is the net force?
Answer:
net force would be 50 N right
Explanation:
The amplitude of a lightly damped oscillator decreases by 4.2% during each cycle. What percentage of the mechanical energy of the oscillator is lost in each cycle?
Answer:
V= A ω maximum KE of object in SHM
V2 / V1 = .958 ratio of amplitudes since ω is constant
KE2 / KE1 = 1/2 m V2^2 / (1/2 m V1^2) = (V2 / V1)^2
KE2 / KE1 = .958^2 = .918
So KE2 = .918 KE1 and .082 = 8.2% of the energy is lost in one cycle
Which one is it??? The question and the choice are in the photo.
The answer is:
That they are switched on
Please answer the question in the picture, worth 25 points
I will report any links or false answers immediately
Answer:
Option C, increases and decreases
Explanation:
When an object making noise approaches you, the wave frequency increases leading to a higher pitch. Conversely, when it moves away from you or retreats, the wave frequency decreases leading to a lower pitch. This can be observed in ambulance sirens.
What is the weight of a 5kg object at the surface of the earth?
A. 49N
B. 49kg
C. 5.0kg
D. 25N
Answer: The answer is A) 49 N(Newtons).
The intensity of a sound wave increases as the wave spreads out from the source of the sound. True or false
Answer:False
Explanation:
the intensity of the sound wave decreases with increasing distance from the source.
13) What property of matter would be measured with this piece of equipment?
A) The mass of an apple
hing
)
By the temperature of a room
The volume of water in a glass.
D) The length of a piece of string.
Answer:
a
Explanation:
i took the test 100%
Look at the circuit given below. It consists of a cell, a bulb with two terminals X, Y and wires. P, Q, R and S are positions marked. What is the direction of the flow of current? a) PQXYRS b) SRYXQP c) SPQXYR d) PSRYXQ
The conventions for the current allow to find the result for which is the direction of the current the is circuit is:
It leaves the positive pole, goes to the blue cable, to the light bulb, from there to the red cable and reaches the negative pole.
Current is the movement of electrons in a circuit per unit time.
In an electrical circuit the electrons that have a negative charge leave the negative electrode towards the positive electrode, by convention the current goes in the opposite direction from the positive electrode towards the negative electrode.
When analyzing the given circuit, the current leaves the positive pole at the top of the battery and moves through the blue wire, reaches the light bulb and moves the red wire and reaches the negative pole of the battery.
In conclusion using the conventions for the current we can find the result for which is the direction of the current the is circuit is:
It leaves the positive pole, goes to the blue cable, to the light bulb, from there to the red cable and reaches the negative pole.
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13. In which of the following climates does chemical weathering generally occur most
rapidly?
A. Canda
B. Greenland
C. Brazil
D. Algeria
8th grade science !
can someone help me with trying to understand this question for my homework especially how to understand the graph and use that for my evidence and help me give an idea of how should I write the evidence and reasoning?
Answer:
for reasoning you could put -> the line is at the top at the left handed sided of the chart (also the beginning) slopes down towards the very bottom right handed side of the chart, symbolising less force as distance goes.
Would it be possible to direct the speeds that a coaster will reach before its ever placed on a track?How?
Yes, it is possible to determine the final speed of the rollercoaster if the initial speed and the height to be reached are known.
According the principle of conservation of energy, the total kinetic energy is equal to the total potential energy.
[tex]P.E _i + K.E_i = P.E_f + K.E_f \\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\g(0) + \frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\\frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\v_i^2 = 2gh_f + v_f^2\\\\v_i^2 - 2gh_f = v_f^2\\\\v_f = \sqrt{v_i^2 - 2gh_f}[/tex]
where;
[tex]v_i[/tex] is the initial velocity of the roller coaster[tex]v_f[/tex] is the final velocity of the roller coaster[tex]h_f[/tex] is maximum height reached by the roller coasterThus, it is possible to determine the final speed of the rollercoaster if the initial speed and the height to be reached are known.
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True or False. When Isaac’s father was a 100 God changed his name from Abram to Abraham.
explain how wind erosion changes land forms
Answer:
the wind carries abrasive materials
Explanation:
such as sand and salt over time theses small particles slowly strip way at the land form sculpting it by eroding the softer layers first
please help me !!
Gymnasts often practice on foam floors, which increase the collision time when a gymnast falls. What effect does this have on collisions?
A. The change in momentum needed to stop the gymnast is increased.
B. The change in momentum needed to stop the gymnast is decreased.
C. The force exerted by the floor on the gymnast decreases.
D. The force exerted by the floor on the gymnast increases.
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A satellite moves in a circular orbit around the Earth at a speed of 5.2 km/s. Determine the satellite’s altitude above the surface of the Earth. Assume the Earth is a homogeneous sphere of radius 6370 km and mass 5.98 × 1024 kg.
The value of the universal gravitational constant is 6.67259 × 10−11 N · m2/kg2
Answer:
The altitude of the satellite above the surface of the Earth is 1,528.48 km.
F=rmv2=R2GmMrv2=R2GMr=GMv2R2r=(6.67259×10−11)×(5.98×1024)(6900)2×(6,370,000)2r=4,841,516.6 mr=4,841.52 km
The work done by an electric force in moving a charge from point A to point B is 2.70 × 10‒3 J. The electric potential difference between the two points is VA ‒ VB = 50.0 V. What is the charge?
The charge moved by this electric force is [tex]5.4 \times 10^{-5} \; Coulombs[/tex].
Given the following data:
Work done = [tex]2.70 \times 10^{-3}\;Joules[/tex]Potential difference = 50.0 VoltsTo determine the charge:
Mathematically, the work done by an electric force in moving a charge from one point to another is given by the formula:
[tex]W = PQ[/tex]
Where:
W is the work done.P is the electric potential difference.Q is the charge.Making Q the subject of formula, we have:
[tex]Q =\frac{W}{P}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Q =\frac{2.70 \times 10^{-3}}{50}\\\\Q =5.4 \times 10^{-5} \; Coulombs[/tex]
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Một chất điểm khối lượng m=200g chuyển
động chậm dần với vận tốc biến đổi theo qui luật
v=30 – 0,4t2 (SI). Lực hãm tác dụng vào chất điểm
lúc t = 5 giây là
A. 8 N B. 0,8 N C. 4 N D. 0,4 N