True or false Condensation occurs with the removal of thermal energy.

The force exerted by the parachutist on the ground is 471.24 N when she comes to rest at a distance of 0.660 m

Let t = Time taken

u = Initial velocity , v = Final velocity

s = Displacement, a = Acceleration

As given in the problem initial velocity u = 3.85 m/s

Final velocity v = 0 (rest)

s = 0.660 m

From the equation of motion v² = u² + 2as

we have a = v²-u² / 2s

⇒a = 0-3.85² / (2* 0.660)

⇒a = -11.22 m/s²    (negative sign shows deceleration)

we know force F = mass m * acceleration a

Given mass of parachutist m = 42 kg

∴Force exerted by parachutist on ground

F = 42 * 11.22 = 471.24 N

If the distance is shorter, acceleration increases in magnitude and so does the force exerted by the parachutist.

The question is incomplete and the full question is probably " A 42.0-kg parachutist is moving straight downward with a speed of 3.85 m/s. (a) If the parachutist comes to rest with constant acceleration over a distance of 0.660 m, what force does the ground exert on her? "

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A rocket with 200kgs is loaded extra 100kgs then the  Rocket maximum altitude is 93005 m and total Time-of-Flight is 294 s

The Time-of-Flight concept (ToF) is a technique for determining distances between sensors and objects based on the amount of time that passes between a signal being sent and returning to the sensor after being reflected by an object. The Time-of-Flight principle can be employed with a variety of signals (also known as carriers), with sound and light being the most popular ones. The time it takes for photons to travel between two points—from the sensor's emitter to a target and back—in order to calculate distance for all Time-of-Flight (ToF) sensors.

Direct and indirect ToF both have unique advantages in particular situations. Each pixel in a scene can be simultaneously measured for distance and intensity.

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Flow rate and velocity are physically connected but very different quantities. The flow rate of the river increases with increasing water velocity. However, river size also affects flow rate.

[v*π*(2/2)^2] *60 = 20*1000 [1 L = 1000 cm^3]

(22*60/7)*v = 20000,

or,  v = 7*20000/22/60or  

v = 106.06 cm/s = 1.06 m/s.

Hence, velocity of the water when its in the hose is 1.06 m/s.

Consider the rate at which a river flows to understand the difference. The flow rate of the river increases with increasing water velocity. However, river size also affects flow rate. For instance, the Amazon River in Brazil carries much more water than a swift alpine stream. The exact formula for the link between flow rate Q and velocity is

A is the cross-sectional area, and

V is the average velocity, therefore Q = A v.

This equation makes sense to me. According to the relationship, the size of a river, pipe, or other conduit, as well as the magnitude of the average velocity (hereinafter referred to as the speed), directly affect the flow rate. The cross-sectional area of a conduit increases with its size.

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When two small ball collide elastically in which first ball is moving with velocity, v with second ball which is in rest than after collision the second ball will move with velocity, v and first ball will come to rest.

An elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of the collision. In elastic collisions, momentum and kinetic energy are both conserved.

An elastic collision is one in which the momentum, p and the kinetic energy, KE are both conserved.

[tex]p_{i} =p_{f}[/tex]

[tex]KE_{i} = KE_{f}[/tex]

Given in the question two identical steel ball that means have same mass and one is moving with velocity, v another is in the rest initially, after collision the momentum of first ball will transfer to second ball so second ball will move with velocity, v and first ball will come to rest.

So final velocity of first ball is zero and second ball is v.

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1.7 m/s is the horizontal velocity that is required to clear the rocks.

As the jumper runs off a 15 m high cliff.

And according to the question,  starts with 0 velocities in the start direction thus he covers 15 m.

Given,

x = 15 m

a = g = 9.8 m, which is the acceleration due to gravity.

iv is the initial velocity which is 0, vo = 0

vf is the final velocity,

Using 2nd equations of motion,

x = iv × t + (1 ÷ 2) a × t²

15 = 0 + ((1 ÷ 2) × ( 9.8) × t²)

t = 1.75

Thus, the time is 1.75 seconds.

Using the same equation, horizontal velocity will be:

x = iv × t + (1 ÷ 2) a × t²

3 = vf × (1.75) + 1 ÷ 2 × (0) × (1.75)

vf = 1.7

Therefore, The horizontal velocity required to cover the rocks is 1.7 m/s.

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No, its fake the instant of inertia of the machine decreases and the angular pace will increase.

A merry-go-spherical spins freely while janice actions fast to the middle alongside a radius of the merry-go-spherical. Moment of inertia is a amount withinside the rotational movement which performs a position analogous to position performed with the aid of using mass withinside the linear movement. Hence, it's also referred to as angular mass or the rotational momentum.

Janice decreases her contribution to the instant of inertia of the machine with the aid of using transferring towards the rotation axis. This decreases the whole second of inertia of the machine. The angular momentum L of the machine does now no longer extrade seeing that no outside torque is applied. The angular pace ω will increase sinceω = L/I.

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There were 1647 before liftoff. 38 m moving planes.

An object is considered to be in motion if its location throughout time changes in relation to its surroundings. It is the gradual change in an object's location. The only kind of motion that exists is linear motion.

The three equations are as follows: S = ut + 12at2, v = u + at, v2 = u + 2as.

The airplane's initial speed is U=0 m/s.

The plane accelerates at a 4 m/s rate.

with a time stamp of 28.7 seconds.

Distance traveled using the formula S=ut+a

⇒ S=0(28.7)+0.5(4) (4)

=1647.38 ~ 1647m

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A runner jack 12km north then turns and runs 16km in 3hours Therefore his average velocity is 1.3 km/h.

What is average velocity?

The change in position or displacement (x) divided by the time intervals (t) during which the displacement happens is the definition of average velocity. Based on the direction of the displacement, the average velocity might either be positive or negative. Meters per second (m/s or ms-1) is the SI measure for average velocity.

Given:

A runner jack 12km north then turns and runs 16km in 3hours .

Therefore average velocity= (16 - 12)/ 3 km/h

=1.3 km/h

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The block will incline up with projectile motion until 0.085 m before sliding down.

We need to know about the projectile motion to solve this problem. The projectile motion is known as parabolic motion and the velocity is divided by 2 axes.

vox = vo cosA

voy = vo sinA

where vox is initial velocity of x axis, voy is initial velocity of y axis, vo is initial velocity and A is the angle.

From the question above, the given parameters are

vo = 5 m/s

A = 20⁰

By using the uniform motion, where vty = 0 m/s. Hence,

vty² = voy² - 2gh

0 = 5.sinA - 2 . 10 . h

20h = 5 . sin20⁰

h = 1/4 . 0.34

h = 0.085 m

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The magnitude and direction of Clare's resultant displacement is 26.4 m and  37.3⁰ respectively.

The magnitude of Clare's resultant displacement is calculated as follows;

her initial position, a = 16 m north

Final position, b = 21 m east

Resultant displacement, d = √a² + b²

d = √(16² + 21²)

d = 26.4 m

The direction of the resultant displacement is calculated as follows;

tan θ = 16 / 21

where;

tan θ = 0.762

θ  = arc tan(0.762)

θ  = 37.3⁰

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The Acceleration of the system as depicted in the diagram is 1.38 m/s².

Acceleration is the rate of change of velocity. The S.I unit of acceleration is m/s²

To calculate the acceleration of the system, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the acceleration of the system is 1.38 m/s².

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The impulse of the two skaters is the same but the speed of Jason is only half that of Megan.

We define the impulse as the product of the force and the time. We know that two objects are taking of at the same time. Given the fact the they are taking off from the same kind of surface at the same time, the impulse of the two are the same.

We know that the speed of the object would depend on the mass of the object. The greater the mass, the lesser the speed of the object hence Jason would have a lesser speed than Mason.

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Answer:

5437.5

Explanation:

I took the quiz.

W is the work done by charge from A to B and from C to B then the potential difference  (vc−va)=552.62V.

The difference between the energy levels that charge carriers have at two places in a circuit is known as the potential difference.

Voltage, commonly known as potential difference (p.d. ), is a unit of electrical potential. The charge carriers in a circuit pass through the electrical components, transferring energy to them. We gauge the potential difference using a voltmeter (or voltage).

V = I x, the potential difference formula

The quantity of current times the resistance equals the potential difference (also known as voltage), which is equal to that. When a charge travels between two locations in a circuit, a potential difference of one Volt is equivalent to one Joule of energy being used by that charge.

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Answer:

Move at the same velocity

Explanation:

According to newton's 1st law of motion, an object at rest remains at rest or if in motion, it will remain in motion at constant velocity unless acted upon by a net external force

In 1912 Wertheimer discovered the phi phenomenon, an optical illusion in which stationary objects shown in rapid succession, transcending the threshold at which they can be perceived separately, appear to move.

When two neighbouring optical stimuli are presented in alternation with a relatively high frequency, an apparent motion is seen that is known as the phi phenomenon. At higher frequencies, beta movement is visible, but the stimuli themselves don't seem to move.

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A. The speed of the elevator after it has moved downward 1.00 m from the point where it first contacts a spring is 3.65m/s

B. The acceleration when the elevator is 1.00 {\rm m} below point where it first contacts a spring is 4m/s²

In calculating the speed of the elevator and acceleration, first we have to find the force of gravity F on the elevator, which is the force pulling the elevator in downward direction. Using the equation for force of gravity which is:

F = mg

Where:

Mass of the elevator; m= 2000kg

Acceleration due to gravity; g = 9.8m/s

2000kg × 9.8m/s²= 19600N

F = 19600

Force of opposing friction clamp of gravity = 17000N

Net force on the elevator = force of gravity - Force of opposing friction clamp

Net force on the elevator = 19600 - 17000

Net force on the elevator = 2600 N

We will also find the kinetic energy K.E; of the elevator at the point of contact with the spring using:

K.E = 1/2 mv²

Where

Mass of the elevator; m = 2000kg

Velocity of the elevator = 4.00m/s

K.E = (1/2)*2000kg*(4m/s)²

K.E = 16000J

The kinetic energy and energy gained will be absorbed by the spring across the next 2m

Therefore,

Energy; E = K.E + P.E

Where:

Kinetic energy K.E = 16000J

Potential Energy P.E = ?

P.E of spring = net force absorbed × distance at compression

Where:

Net force absorbed = 2600N

Distance at compression = 2.0m

P.E = 2600*2

P.E = 5200J

E = 16000J + 5200J

E = 21200J

Spring constant = k

To find k

Using:

E = (1/2)*k*(x)²

Where:

E = 21200J

k = ?

x = 2m

21200J = (1/2)*k*(2m)²

21200J*2 = (4m)k

K = 42400J/4m

K = 10600N/m

Therefore,

Acceleration at 1m compression = ?

Using:

F = K*X

Where

F is force provided by the spring = 10600N/m,

K = 10600 N/m

X = 1m

F = 10600N/m * 1m

F = 10600N (upward)

A. The speed of the elevator after it has moved downward 1.00 {\rm m} from the point where it first contacts a spring?

Using:

Original Kinetic energy + net force on the elevator = final kinetic energy + spring energy

16000N + 2600N = (1/2)mv² + (1/2)k x²

18600 = (1/2)(2000)(v²) + (1/2)(10600N)(1²)

18600 = 1000(v²) + 5300

18600 - 5300 = 1000(v²)

13300 = 1000(v²)

V² = 13.300

V =3.65m/s

B. The acceleration of the elevator is 1.00m below point where it first contacts a spring

Spring constant = net force on the elevator + resultant force

Where:

Spring constant = 10600N

Net force on the elevator = 2600N

Resultant force = ?

10600N = 2600N + resultant force

Resultant force = 10600N - 2600N

Resultant force = 8000N

Using the equation for Newton's 2nd law where F = ma,

a = F/m

Where:

Resultant force; F =8000N

Mass of the elevator; m =2000kg)

a = 8000 / 2000

a = 4m/s²

Here's the complete question:

In a "worst-case" design scenario, a 2000kg elevator with broken cables is falling at 4.00m/s when it first contacts a cushioning spring at thebottom of the shaft. The spring is supposed to stop the elevator,compressing 2.00m as it does so. During the motion a safety clampapplies a constant 17000N frictional force to the elevator.

1. What is the speed of the elevator after it has moved downward 1.00m from the point where it first contacts aspring?

2. When the elevator is 1.00m below point where it first contacts a spring, what is its acceleration?

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The new voltage value of parallel-plate capacitor is 800 V.

We need to know about the capacitance of the parallel-plate capacitor to solve this problem. The capacitance of the parallel-plate capacitor depends on the charge and voltage. It can be written as

C = Q/V

where C is capacitance, Q is charge and V is voltage.

Capacitance also can be calculated by the area and distance between capacitor plate

C = εo . A / d

where εo is vacuum permittivity (8.85 x 10¯¹² F/m), A is area of plate and d is distance.

From the question above, we know that

V1 = 200 V

d1 = d

d2 = 4 d

By substituting the given parameters, we can calculate the voltage

εo . A / d = Q/V

The voltage is proportional to the distance of plate. Hence, the ratio of voltage will be

V1 / V2 = d1 / d2

200 / V2 = d / 4d

V2 = 4 x 200

V = 800 N

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Answer:

c

Explanation:

because whenever you push g box into h box and then h displaces according to third law of motion h box will apply the force on g box so that's why

The action of volleying a ball straight up and down comes under the free-fall motion of the ball. Free-fall is defined as the motion of a body which falls freely due to the gravitational pull of the earth.

The velocity (v) of the ball undergoing free-fall can be calculated using the free-fall formula,

[tex]v^{2}[/tex] = 2gh

where, g is the acceleration due to gravity and h is the height of the freely falling body.

Given that, the height to which ball rises, h = 3.6m. (g = 9.8 m/[tex]s^{2}[/tex])

Substituting h and g in the velocity formula,

 [tex]v^{2}[/tex] = 2 × 9.8 m/[tex]s^{2}[/tex] × 3.6m

 [tex]v^{2}[/tex] = 70.56 [tex]m^{2}/s^{2}[/tex]

The velocity of volley ball is,

v =  [tex]\sqrt{70.56m^{2}/s^{2} }[/tex]

∴ v = 8.4 m/s

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0.19362 rad/s is the angular speed and 8.8096 m/s2 is car's acceleration.

[tex]angular speed=\omega=v/r=45.5m/s/235m=0.19362rad/sec[/tex]

[tex]car acceleration =a=v^2/r=45.5^2m/s^2/235m=8.8096m/s^2[/tex]

The definition of angular speed is the rate of change of angular displacement, which is the angle a body travels along a circular route. The ratio of the number of rotations or revolutions performed by a body to the time taken is used to compute angular speed. The Greek letter Omega, stands for angular speed. Rad/s is the angular speed unit in the SI.

As is common knowledge, angular speed is defined as the rate of change of displacement divided by the time. Therefore, the equation for angular speed is = /t. Despite the aforementioned method, there is a different and more popular formula for calculating angular speed when it comes to competitive tests. As ω = θ/t

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Polar jet streams are formed because of the warm and cold air masses.

Polar front jet stream, also called polar front jet or mid-latitude jet stream stream, a belt of powerful upper level winds that sits at top the polar front.

The winds are strongest in the troposphere, which is the upper boundary of the troposphere, and move in a generally westerly direction in mid-latitudes.

The vertical wind shear which extends below the core of this jet stream is associated with horizontal temperature gradients that extend to the surface. As a consequence, this jet manifests itself as a front that marks the division between colder air over a deep layer and warmer air over a deep layer.

Polar jet streams are formed due to warm and cold air masses.

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Answer:

C

Explanation:

Answer:

ans a

Explanation:

The acceleration when a 44.7 N net force is applied to 7.7 kg object is 5.8 m / s²

According to Newton's second law of motion,

F = m a

F = Force

m = Mass

a = Acceleration

m = 7.7 kg

F = 44.7 N

a = F / m

a = 44.7 / 7.7

a = 5.8 m / s²

Newton's second law of motion states that the force is equal to the rate of change of momentum. It can also be said as acceleration of an object is directly proportional to the net force acting on the object.

Therefore, the acceleration of the object is 5.8 m / s²

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High specific heat of the water. Option (c)

What is Specific heat?

The amount of heat required to increase the temperature of one gram of a substance by one degree Celsius is referred to as the substance's specific heat. Typically, calories or joules are used per gram and degree Celsius when referring to the units of specific heat.

The moderate temperature of islands has much to do with the water's high specific heat. The typical off-water is more significant than this clear land or soil. Due to this fact, water absorbs and releases eat more slowly. In comparison to the land.

Hence, the water has high specific heat.

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Given

60 kg of mass, 70 mm or 0.07 meters of gyroscopic radius, and 9 rad/sec2 of angular acceleration

Inertia, It is an object's resistance to any change in motion. The amount of inertia is directly related to an object's mass; in fact, as we frequently observe, the heavier an object is, the harder it is to change its direction of motion.

The moment of inertia must be identified. EM = I > I > MK2

I stands for inertia mass moment.

I = 60 kg/m2 M = I = 0.216 kg/m2 = 11 kg/m2 M = 2.376 nm

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Answer:

Explanation:

Given:

m = 60 kg

R = 70 mm = 0.070 m

ε = 9 rad/s²

__________________

M - ?

The moment:

M = J·ε = m·R²·ε

M = 60·0.070²·9 ≈ 2.65 N·m

The force that causes the water to leave the rocket compared to the force that causes the rocket to launch is that they are unequal and act in opposite directions.

According to Newton's third law of motion, every action has a corresponding and opposing response. In the instance of Bode's rocket, the pressured air in the bottle causes the water to rush downward out of the bottle, causing the rocket to fly upward into the air. The upward force on the rocket is equivalent to the force of the water streaming down. Thus, the two forces are equivalent and exert opposing forces.

When you pump, more air is pumped into the bottle while maintaining the same volume. By doing this, you raise the pressure inside the bottle, increasing the force acting on the interior of the bottle. Eventually, when the bottle can no longer withstand the pressure, the cork will be violently ejected from the bottle's bottom by the force of the pressure. 

The air will be forced out of the bottle as rapidly as possible by the abrupt pressure drop caused by the new opening. When the air leaves the bottle, the pressure that was previously holding it under pressure is used to drive all of the water out with it.

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Answer:

They are equal and act in opposite directions.

Explanation:

I just answered the question on study island and got it right :P

Answer:

W' = 287.55 N

Explanation:

We know that weight force is defined as follows:

W = m × g

So:

On Earth (W = 1775 N):

1775 = m × 9.8

m = 1775 / 9.8

m = 181.12 kg

On the Moon (g' = 1.62 m/s²):

W' = m × g'

W' = 181.12 × 1.62

W' = 293.42 N

The friction that is necessary to keep her from falling off the merry go round is 280.16N, the distance travelled in one revolution is 28.28 meters and the time period T after in revolution is 6.89 seconds.

The mass of the worker is 75 kg, the radius of merry go round is 4.5m and the linear velocity of the merry go round is 4.1m.s.

a) The diagram is attached below.

b) The friction force while rotation will be equal to the centrifugal force, this is the reason why he will be able to go round,

So, we can write,

Friction force Fr = Centrifugal force

Fr = MV²/R

Where Fr is the friction force,

M is the mass of the worker,

V is the velocity of the merry go round,

r is the distance at which the worker is standing.

Putting all the values,

Fr = 75 x 4.1 x 4.1/4.5

Fr = 280.16N.

The friction required is 280.16N.

c) The distance she travelled by her after the first round will be equal to the circumference of the circle,

Distance = 2Πr

D = 2 x 22 x 4.5/7

D = 28.28m

d) time period T after one revolution,

T = Distance/velocity

T = 28.28/4.1

T = 6.89 seconds.

The time period is 6.89 seconds.

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