True or False - Water changing between states of matter is an example of a physical change.

Each electron has a charge of :

[tex]1.6 \times 10 {}^{ - 19} \: C[/tex]

For producing 1 Cuolomb charge we need :

Now, for producing 0.009 C of charge, the number of electrons required is :

_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

[tex] \mathrm{5.616 \times 10 {}^{16} \: \: electrons} [/tex]

Number of electrons passing through it in 1 Second is :

Now, in 10 seconds the number of electrons passing through it is :

_____________________________

[tex]\mathrm{ \#TeeNForeveR}[/tex]

Answer:

Isotopic dating of meteor fragments

Explanation:

Earth is so old that its age can only be determined using isotopic dating. The oldest measurement of Earth's age was determined using isotopic dating of meteor fragments.

Answer: Isotopic dating of meteor fragments

Explanation:

Answer:

The fifth harmonic frequency is 2.9 KHz.

Explanation:

For a closed tube, the fifth harmonic frequency is also the second overtone. So that;

fifth harmonic frequency = [tex]\frac{5V}{4L}[/tex]

where V is the velocity of the sound in air, and L is the length of the tube.

But L = 0.15 m and V = 343 m/s, then:

fifth harmonic frequency = [tex]\frac{5*343}{4*0.15}[/tex]

                                     = [tex]\frac{1715}{0.6}[/tex]

                                     = 2858.33 Hertz

fifth harmonic frequency = 2.9 KHz

The fifth harmonic frequency of the soda bottle is approximately 2.9 KHz.

Answer:

2828.33

Explanation:

answer for acellus

The best demonstration that applies to Newton's Third Law of motion would be D) When you walk your foot pushes down on the ground while the ground pushes back on your foot.

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Newton's Third Law states that for every action, there is an equal and opposite reaction. This is actually explains that forces come in pairs and forces are an interaction between two objects. As per the correct option given in the question explains Newton’s Third Law.  

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When you walk your foot (say object A) pushes down on the ground while the ground (say object Q) pushes back on your foot with the same force but in the opposite direction.

Answer:

The Wilson cloud chamber is used to study the direction, speed, and distance of charged particles. Explanation; ... The Wilson cloud chamber works by producing a super-saturated vapor, as explained by florin.

Explanation:

I hope it's help u

Answer:

A practical activity about the study of the structure of the natural and physical world that can be shown thorough experiments and study's.

Explanation:

The question is incomplete. The complete question is :

Consider a composite cube made of epoxy with fibers aligned along one axis of the cube (the fibers are parallel to four of the twelve cube edges). If the cube can only be loaded in axial tension such that the force is uniformly applied over - and is normal to - a cube face, what is the lowest possible positive length change the cube can experience under this tension? The applied tensile force is 102 KN. The unloaded cube edge length is 56 mm. The glass fibers have an elastic modulus of 200 GPa. The epoxy has an elastic modulus of 38 GPa. The cube is comprised of 18 vol% epoxy (the balancing vol % is glass fiber). Hint: The loading axis is intentionally unspecified. Answer Format: Lowest possible length increase (change of length) under tension.

Solution :

Given :

[tex]$E_{glass fibre}$[/tex] = 200 GPa

[tex]$V_{glass fibre} = 82\%$[/tex]

[tex]$E_{epoxy}$[/tex] = 38 GPa

[tex]$V_{epoxy} = 82\%$[/tex]

Edge length = 56 mm

Cube is loaded in axial tension such that the force is uniformly applied over a cube face.

[tex]$E_{\text{composite}}=\frac{E_{glass fibre} \times E_{epoxy}}{(E_{glass fibre .E_{epoxy}})+(E_{fibre}.V_{glass fibre})}$[/tex]

[tex]$E_{composite} = \frac{200 \times 38}{(200 \times 0.18)+(38\times 0.82)}$[/tex]

               [tex]$=113.16 $[/tex]  GPa

Applied stress [tex]$=\frac{\text{applied load}}{\text{area}}$[/tex]

                    [tex]$\sigma=\frac{102 \times 10^3 \ N}{56 \times 56 \times 10^{-6} \ m^2}$[/tex]

                       = 32.5 MPa

By Hooke's law

[tex]$\sigma = E . \epsilon$[/tex]

[tex]$\sigma = E. \frac{\Delta l}{l}$[/tex]

[tex]$\Delta l = \frac{\sigma}{E}\times l$[/tex]

Length change, [tex]$\Delta l =\frac{32.5 \times 10^6 \ Pa}{113.16 \times 10^9 \ Pa}\times 56 \times 10^{-2} \ m$[/tex]

[tex]$\Delta l = \frac{32.5 \times 56}{113.16} \times 10^{-3} \ mm$[/tex]

   = 0.016 mm

This question is incomplete, the complete question is;

A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second. (a) What is the velocity of the top of the ladder when the base is given below

7 feet away from the wall

15 feet away from the wall

20 feet away from the wall

Answer:

- When x is 7 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -7/12 ft/s

- When x is 15 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -3/2 ft/s

- When x is 20 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -8/3 ft/s

Explanation:

Given the data in the question;

Let [tex]r[/tex]ft and [tex]x[/tex]ft represent the distance of the top of ladder from the ground and the distance of the bottom of ladder from the wall respectively.

Now using the Pythagoras Theorem ( right angled triangle ).

(hypotenuse)² = ( adjacent )² + ( opposite )²

so

r² = ( 25 )² - x²

r² = 625 - x² ------- let this be equation 1

now, we differentiate with respect to t

2r [tex]\frac{dr}{dt}[/tex] = 0 - 2x [tex]\frac{dx}{dt}[/tex]

r [tex]\frac{dr}{dt}[/tex] = -x [tex]\frac{dx}{dt}[/tex]

[tex]\frac{dr}{dt}[/tex] = -x [tex]\frac{dx}{dt}[/tex] × 1/r

[tex]\frac{dr}{dt}[/tex] = -x/r [tex]\frac{dx}{dt}[/tex]

Now, from equation, r² = 625 - x²

r = √( 625 - x² )

Then

[tex]\frac{dr}{dt}[/tex] = -x / √( 625 - x² ) [tex]\frac{dx}{dt}[/tex]

given that, The base of the ladder is pulled away from the wall at a rate of 2 feet per second i.e [tex]\frac{dx}{dt}[/tex] = 2 ft/s

so;

[tex]\frac{dr}{dt}[/tex] = ( -x / √( 625 - x² ) ) × 2

[tex]\frac{dr}{dt}[/tex] = -2x / √( 625 - x² )

∴

When x is 7 feet away from the wall;

[tex]\frac{dr}{dt}[/tex] = -2(7) / √( 625 - (7)² )

[tex]\frac{dr}{dt}[/tex] = -14 / √( 625 - 49 )

[tex]\frac{dr}{dt}[/tex] = -14 / √576

[tex]\frac{dr}{dt}[/tex] = -14 / 24

we simplify

[tex]\frac{dr}{dt}[/tex] = -7/12 ft/s

Therefore, When x is 7 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -7/12 ft/s

When x is 15 feet away from the wall

[tex]\frac{dr}{dt}[/tex] = -2(15) / √( 625 - (15)² )

[tex]\frac{dr}{dt}[/tex] = -30 / √( 625 - 225 )

[tex]\frac{dr}{dt}[/tex] = -30 / √400

[tex]\frac{dr}{dt}[/tex] = -30 / 20

we simplify

[tex]\frac{dr}{dt}[/tex] = -3/2 ft/s

Therefore, When x is 15 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -3/2 ft/s

When x is 20 feet away from the wall

[tex]\frac{dr}{dt}[/tex] = -2(20) / √( 625 - (20)² )

[tex]\frac{dr}{dt}[/tex] = -40 / √( 625 - 400 )

[tex]\frac{dr}{dt}[/tex] = -40 / √225

[tex]\frac{dr}{dt}[/tex] = -40 / 15

we simplify

[tex]\frac{dr}{dt}[/tex] = -8/3 ft/s

Therefore, When x is 20 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -8/3 ft/s

Answer:

Fc = 123 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

[tex] Fnet = Fapp + Fg[/tex]

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

Given the following data;

Normal force = 25N

Mass = 10kg

To find the centripetal force;

From the net force, we have the following formula;

Fc = N + mg

Where;

Fc is the centripetal force.

N is the normal force.

mg is the the weight of the object.

Substituting into the formula, we have;

Fc = 25 + 10(9.8)

Fc = 25 + 98

Fc = 123 Newton

Answer:

In addition to the sun's angle, atmospheric conditions can affect radiation levels. Cloud cover, air pollution and the hole in the ozone layer all alter the amount of solar radiation that can reach the surface. These factors all cause typical radiation levels to differ.

hope it helps

To solve this, we must be knowing each and every concept behind solar radiation. Therefore, cloud cover, air pollution, and the ozone hole all reduce the quantity of solar energy that reaches the earth's surface.

The energy generated by the sun as just a consequence of vast internal processes is known as solar radiation. In a word, the sun's capacity to generate intense nuclear fusion within and around the core enables it to radiate such vast amounts of energy inside the form of both heat and light. The entire process begins at the core of the sun.

Aside from the sun's angle, meteorological variables can influence radiation levels. Cloud cover, air pollution, and the ozone hole all reduce the quantity of solar energy that reaches the earth's surface. All of these variables contribute to variations in normal radiation levels.

Therefore, cloud cover, air pollution, and the ozone hole all reduce the quantity of solar energy that reaches the earth's surface.

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Answer:

Im sorry I do not know how to do this, I hope you will be able to figure it out

Explanation:

Combined energy of the two sleds will be conserved when they collides.

Energy is nothing but the ability to do work. there are different energies in different form which are thermal energy, mechanical energy, electric energy and sound energy etc.

According to first law of thermodynamic, Energy neither be created nor be destroyed. it can only be transferred from one form into another form. Energy is expressed in joule (J). its dimensions are [M¹ L² T⁻²].

Energy is conserved throughout the motion,

according to conservation law of energy, initial energy is equal to final energy.

When two sleds coming in opposite direction, it is having mass as well as velocity. hence it has kinetic energy, when they get collide with each other some of total energy gets converted into sound energy as collision cause sound(boom). some of the energy will use to break the material which made the sled and remaining energy will convert in kinetic energy of broken sleds it can be moved in opposite direction or in same direction depending initial energies.

in this collision combined kinetic energy can be converted into sound energy, mechanical energy and again kinetic energy but totally energy is conserved.

Hence combined energy will be conserved.

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Answer:

https://www.slader.com/discussion/question/an-electron-is-accelerated-through-240-times-103-v-from-rest-and-then-enters-a-uniform-170-t-magnetic-field-what-are-a-the-maximum-and-b-the-9e425fbd/

( Here is solution)

Answer:

length

Explanation:

Legth is derived physical quantity

Answer:

Explanation:

For fundamental frequency in a vibrating string , the formula is

n = 1 / 2L  x  √ ( T /m₁ )

n is frequency , L is length , T is tension and m₁ is mass per unit length .

For first string ,

293 =  1 / 2L  x  √ ( 49 N  /m₁ )

For second string , let mass per unit length be m₂ .

196 =  1 / 2L  x  √ ( 49 N  /m₂ ) ------ ( 1 )

To bring its frequency back to previous one let tension be T

293  =  1 / 2L  x  √ ( T  /m₂ ) ------- ( 2 )

Dividing

293 / 196 = √ ( T  /49  )

1.4948 = √ ( T  /49  )

2.2344 = T  /49

T = 109.48 N .

Answer:

4.16×103 m/s

Explanation:

Answer:

The angular width is "[tex]1.575\times 10^{-3} \ rad[/tex]" and the linear width is "[tex]2.835\times 10^{-3} \ m[/tex]".

Explanation:

Given:

Wavelength,

[tex]\lambda = 630 \ nm[/tex]

or,

  [tex]=630\times 10^{-9} \ m[/tex]

Slit width,

[tex]a = 0.8 \ mm[/tex]

or,

  [tex]=0.8\times 10^{-3} \ m[/tex]

Distance between slit and screen,

[tex]D = 1.8 \ m[/tex]

As we know,

The central bright fringe's angular height,

⇒ [tex]\theta = \frac{2 \lambda}{a}[/tex]

       [tex]= \frac{2\times 630\times 10^{-9}}{0.8\times 10^{-3}}[/tex]

       [tex]=1.575\times 10^{-3} \ rad[/tex]

and,

The linear width will be:

⇒ [tex]x_o=\frac{2D \lambda}{a}[/tex]

By substituting the values, we get

        [tex]=\frac{3\times 1.8\times 630\times 10^{-9}}{0.8\times 10^{-3}}[/tex]

        [tex]=2.835\times 10^{-3} \ m[/tex]

Answer:

a) -3.267 m/s

b) 2.227 m/s

Explanation:

As per the conservation of momentum

m1v1 + m2v2=0

m1= mass of log

m2 = mass of lumber jack

v1 = velocity of log

v2 = velocity of lumber jack

a) Velocity of first log

[tex]-\frac{70*7}{150} = -3.267[/tex] m/s

b) m1v1 + m2v2 = m3v3

Velocity of log

= [tex]\frac{70*7}{150+70} \\2.227[/tex]

Answer: [tex]7.96\ \mu C[/tex]

Explanation:

Given

The dimension of the plate is [tex]1\ cm\times 6\ cm[/tex]

The gap between the plate is [tex]0.001\ cm[/tex]

Voltage applied [tex]V=15,000\ V[/tex]

The capacitance of the capacitor is

[tex]C=\dfrac{\epsilon_o A}{d}\\\\C=\dfrac{8.85\times 10^{-12}\times 1\times 6\times 10^{-4}}{10^{-5}}\\\\C=53.1\times 10^{-11}\ F[/tex]

Charge acquired by the capacitor

[tex]\Rightarrow Q=CV\\\Rightarrow Q=53.1\times 10^{-11}\times 15,000\\\Rightarrow Q=796.5\times 10^{-8}\\\Rightarrow Q=7.96\times 10^{-6}\ C[/tex]

Answer: Unsustainable wood harvesting can lead to deforestation, soil erosion, and desertification.

Explanation: you welcome

A drawback of burning biomass to produce electricity is that it is very costly to use. Option B is correct.

Biomass is a low-carbon fuel that is renewable, since a fresh crop can be planted after each harvest.

The chemical formula for biomass is about CHO. It's comparable to coal, except with the addition of an oxygen atom.

The drawbacks of biomass Energy

1. It's not quite clean.

2. High prices in comparison to other options.

3. Deforestation is a possibility.

4. Water is required.

5. It is inefficient.

A drawback of burning biomass to produce electricity is that it is very costly to use.

Hence, option B is correct.

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Answer:

I think its D, Does the wave travel In a Vaccum?

Answer:

It's C. Does the wave transfer energy?

Answer:

Entropy is typically defined as either the level of randomness (or disorder) of a system or a measure of the energy dispersal of the molecules in the system.

Answer:

entropy

Explanation:

edge2021

Answer:

A. The medium through which it travels

Answer:

d

Explanation:

The sphere is positively charged so that when it comes in contact with the rod, its positive charges will repel to the other end. Hence, Hold the sphere near each end of the block, because that will give experimental data about both ends of the block.

Polarization is the separation of charges into two poles due electrostatic repulsion. Two similar charges will repel and opposite charges attracts each other.

When a charged or polar substance get in contact with a non-polar substance, the nonpolar one will deform in such a way that the electrons from the polar one will repel the electrons of nonpolar and there occurs a temporary charge separation in non polar substance creating an induced polarity.

Here, when the positive sphere comes in contact with the charged rod, the positive charges will align to the opposite pole of the rod away from the sphere and the negative charges will align near the sphere.

Thus there occurs an attractive force at one end and repulsion at the other end. Thus, holding the sphere at each end will data about charge distribution.

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Answer:

a) 627840000 W

b) 0.9233

Explanation:

The rate at which energy flows through the dam for the generation of electricity is proportional to the volulme flow rate times the potential energy per unit volume.

Mathematically,

P = Q(ρgh)

Where, ρ is water density, g is accelaration due to gravity, h is height through which water falls over the turbine and Q is the discharge.

a) The power can be calculated as

P = 640(1000×9.81×221)

P = 627840000 W

b) The ratio = Calculated power / avarage power

= 62784×10^4/680×10^6

= 0.9233

[tex] \huge\fbox\red{Lean}\ [/tex]

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Answer:

[tex]lean \: is \: the \: measure \: of \: fat \\ you \: can \: remembar \: by \: using \\ \: the \: term \: lean \: meat \: usually \: used \: to \: \\ eat \\ thank \: you[/tex]

Answer:

The correct answer is a

Explanation:

The speed of a sound wave depends on the square root of the modulus of compressibility and the density of the medium.

For the same medium, the speed of sound depends on the temperature of the fora

           v = [tex]v_o \ \sqrt{1 + \frac{T}{273} }[/tex]

Therefore, the different results that are obtained are due to changes in temperature. The correct answer is a

since this way it has the values ​​of the speed of sound for each temperature, for which it can compare with the results obtained from the trip.

Answer:

The speed of sound in the argon is 340 m/s.

Explanation:

Given;

fundamental frequency, f₀ = 200 Hz

length of the pipe, L = 42.5 cm = 0.425 m

A pipe that is open at one end and closed at another end is known as a closed pipe.

The wavelength for the first harmonic is calculated as;

L = Node -------> Antinode

L = λ/4

λ = 4L

The speed of the sound is calculated as;

v = fλ

where;

v is the speed of the sound

v = f x 4L

v = 200 x (4 x 0.425)

v = 340 m/s

Therefore, the speed of sound in the argon is 340 m/s.

Answer:

Thank you so much! Have a great day!