Answer:
true answer this question
What is the approximate value of k when 30 = e^5k?
Answer:
Explanation:
30 = e^5k
ln30 = lne^5k
ln30 = 5k
k = ln30/5
k = 0.68023947...
round to your heart's content.
Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each other during the pouring process, one piece of grain picks up a charge of 6.0 E -10 C and another piece of grain picks up a charge of 2.3 E -15 C. What is the electric force between them if the pieces of grain are 2 cm apart?
Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.
Answer:
3.1×10⁻¹¹ N is
Explanation:
is the answer
Telescopes work by using optics with true or false
Answer: true
its making me add 20 word so here they are g g g g g g g gg g t
Answer: its FALSE
Explanation:
Telescopes work by using optics with light is false, just took the quiz.
half-life questionnnnn:
A 200-kg, 2.0-m-radius, merry-go-round in the shape of a flat, uniform, circular disk parallel to level ground is rotating at 1.2 cycles/second about an axis through its center of mass and perpendicular to the ground. A 50-kg boy jumps onto the edge of the merry-go round and lands at a fixed point. What is the angular velocity of the merry-go-round after the boy lands on it
Answer:
Explanation:
Conservation of angular momentum.
Disk I = ½MR²
Point mass I = mR² (boy)
Initial angular momentum
L₀ = Iω = ½MR²ω₀
Final angular momentum
L₁ = Iω = (½MR² + mR²)ω₁
as momentum is conserved, these are equal
(½MR² + mR²)ω₁ = ½MR²ω₀
ω₁ = ω₀(½MR²/ (½MR² + mR²))
ω₁ = ω₀(½M/ (½M + m))
ω₁ = 1.2(½(200)/ (½(200) + 50))
ω₁ = 1.2(⅔)
ω₁ = 0.8 cycles/second or 0.8(2π) = 1.6π rad/s
A gazelle is grazing while standing in a fixed location. When it's startled by a predator, the gazelle accelerates uniformly for 16.8 s until it reaches a speed of 21.9 m/s. The gazelle then runs in a straight line at constant speed for an additional 16.4 s. Finally, it uniformly slows to a stop at a rate of 1.8 m/s/s. What is the total distance traveled by the gazelle in meters
Answer:
Explanation:
acceleration phase
average speed was 21.9/2 = 10.95 m/s
distance covered is 10.95 m/s(16.8 s) = 183.96 m
distance at top speed 21.9 m/s(16.4 s) = 359.16 m
distance while decelerating (0² - 21.9²)/(2(-1.8)) = 133.225 m
total = 183.96 + 359.16 + 133.225 = 676.345 = 676 m
A wheel with radius 41.5 cm rotates 5.13 times every second.
Find the period of this motion.
What is the tangential speed of a wad of chewing gum stick to the rim of the wheel?
The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.
Let suppose that the wheel rotates at constant angular speed ([tex]\omega[/tex]), in radians per second, the tangential speed of a wad of chewing gum to the rim of the wheel ([tex]v[/tex]), in centimeters per second, is:
[tex]v = 2\pi\cdot r\cdot f[/tex] (1)
Where:
[tex]r[/tex] - Radius of the wheel, in centimeters[tex]f[/tex] - Frequency, in hertzIf we know that [tex]f = 5.13\,hz[/tex] and [tex]r = 41.5\,cm[/tex], then the tangential speed of the chewing gum is:
[tex]v = 2\pi\cdot (41.5\,cm)\cdot (5.13\,hz)[/tex]
[tex]v \approx 1337.659\,\frac{cm}{s}[/tex]
The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.
To learn more on angular speed, we kindly invite to check this verified question: https://brainly.com/question/9684874
what type of data do you need to collect in a ADI
3. A 1500 kg car moving at 30 m/s strikes a 6000 kg van initially at rest. If the car
comes to a complete stop after the collision, what is the final velocity of the van?
Answer:
7.5m/s
Explanation:
Force= mass × velocity
Energy is conserved, the car and van should have the same overall force.
1500kg × 30m/s= 6000kg × final velocity
Final velocity = 7.5m/s
halp me please i will give brainly
Answer: It should be the 3rd option down!
Explanation:
Answer: C
Explanation:
A child on ice skates is given a small push from behind by a parent. How are forces used to describe the resulting motion?(1 point)
Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move.
Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move.
There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
There is a balanced force on the child, and the child’s motion will change direction or increase speed.
There is a balanced force on the child, and the child’s motion will change direction or increase speed.
Because of equal and opposite reactions, the child will move in the opposite direction to the force.
A child on ice skates is given a small push from behind by a parent. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
A child on ice skates is given a small push from behind by a parent. How are forces used to describe the resulting motion?
Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move. FALSE. According to Newton's third law of motion, if the parent applies force on the child, there will be a reaction applied by the child on the parent. These forces are applied to different objects so they will not cancel and the child will move. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed. TRUE. The child will have an acceleration as a consequence of the unbalanced force. The acceleration will be responsible for the change in the direction or speed of the child. There is a balanced force on the child, and the child’s motion will change direction or increase speed. FALSE. If the forces were balanced, that is, there was no net force, the movement of the child would not change, as stated by Newton's first law of motion. Because of equal and opposite reactions, the child will move in the opposite direction to the force. FALSE. The child will move in the direction of the net force.A child on ice skates is given a small push from behind by a parent. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
Learn more about Newton's laws here: https://brainly.com/question/6839345
Can someone please help me? Please answer the question in the screenshot. Thank you! I need this answered!
Answer:
Explanation:
Photosynthesis is needed to store energy for the growth of the plant. It is like a factory that uses sunlight energy to convert 6CO₂ and 6H₂O into C₆H₁₂O₆ and 6O₂
Cell respiration is the process of breaking down the glucose and converting it into the other needed components of life. It's the engine that's fueled by the sugar of photosynthesis.
1. In Newton's cannonball experiment, if the velocity is larger than the orbital velocity the Cannon
ball will
1. stay in orbit
2. fall to the earth
3. escape the earth
4. none of the above
Answer:
escape the earth I think
In Newton's cannonball experiment, is the velocity is larger than the orbital velocity the Cannon ball will escape the Earth. Thus, the correct option is 3.
What was Newton's Cannonball experiment?
In this experiment, Newton visualizes a stone that is a cannonball which is being projected on top of a very high mountain. And, if there were no gravitational force or air resistance in that area, the body should follow a straight line path away from the Earth, in the direction in which it was projected.
If the cannonball is launched at a velocity that matches the orbital velocity of the planet, then it will not be able to be drawn in by gravitational force due to the Earth which results into moving away from the cannonball at the same speed at which the cannonball itself is falling.
If the velocity of the cannonball is larger than the orbital velocity than the ball will escape the Earth.
Therefore, the correct option is 3.
Learn more about Cannonball experiment here:
https://brainly.com/question/25838509
#SPJ6
PLEASE ANSWER THIS, I'LL MARK YOU AS BRAINLIEST
Carlito was observing an an that crawled along a table. With a piece of chalk, he followed his path. He determined the ant’s displacements by using a ruler and protractor. The displacements were as follows: 2 cm east, 3.5 cm, 32° north of east and 2.4 cm, 22° west of north. Find the resultant vector using graphical method.
Answer:
this is the answer
Explanation:
hope it's clear
pls Mark me as the brainliest pls
HELPPP!! Thanks!
If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most correct situation?
a. Keep the gas at a constant pressure and keep the temperature constant, but increase the volume of the gas
b. Keep the gas in a fixed container at constant pressure and increase the temperature
c. Keep the gas in a fixed container at constant pressure and decrease the temperature
d. Keep the gas at a constant volume and keep the temperature constant, but decrease the pressure of the gas
Answer:c i think
Explanation: not sure
The density of water is 1000 kg/m the pressure pf water at 10 m depth is about
Answer:
pressure in liquids is given as:
P= hpg
where h is the depth
where p is the density
where g is 10
Explanation:
From the formula above
p = 10 X 1000 X 10
p = 100000N/m
A block of mass m = 3.0 kg is pushed a distance d = 2.0 m along a frictionless horizontal table by
a constant applied force of magnitude F= 20.0 N directed at an angle 0= 30.0° below the horizontal
as shown in Figure. Determine the work done by (a) the applied force, (b) the normal force exerted
by the table, and (d) the net force on the block.
Explanation:
We apply the definition of work by a constant force in the first three parts, but then in the fourth part we add up the answers. The total (net) work is the sum of the amounts of work done by the individual forces, and is the work done by the total (net) force. This identification is not represented by an equation in the chapter text, but is something you know by thinking about it, without relying on an equation in a list.
The definition of work by a constant force is W=FΔrcosθ.
(a) The applied force does work given by
W=FΔrcosθ=(16.0N)(2.20m)cos25.00=31.9J
(b), (c) The normal force and the weight are both at 900 to the displacement in any time interval. Both do 0 work.
(d) ∑W=31.9J+0+0=31.9J
How much tension must a rope withstand if it is used to accelerate a 1710-kgkg car horizontally along a frictionless surface at 1.30 m/s 2 m/s2
Answer:
Explanation:
Lowest tension will occur when the rope is also horizontal.
F = ma
F = 1710(1.30)
F = 2223 N
A 60.0 kg person jumps onto the floor from a height of 3.0m. Find
the KE of the jumper when she hits the ground.
Answer:
1800 J
Explanation:
GPE= mgh
60*3*10
=1800 J
A 20 metric ton train moves toward the south at 50 m/s. At what speed must it travel to have four times its original momentum
Answer:
200 m/s
Explanation:
as momentum is a product of mass and speed, and mass is not changing, four times the speed will result in four times the momentum.
p = mv
4p = m(4v)
At 200m/s velocity of the train, the momentum of the train will be four times its original momentum. This is because the velocity is directly proportional to the momentum of an object.
What is Momentum?Momentum is the tendency of an object to remain in motion. It is the product of the mass of the object and the velocity of the object. It is denoted by "p". Momentum is a vector quantity because it has both the magnitude and direction. The unit of Momentum is g.m/s.
The momentum can be calculated with the formula:
p = m × v
where, p = momentum of the object,
m = mass of the object,
v = velocity of the object.
The momentum is directly proportional to the mass and velocity of the object. Hence, to increase the momentum of the train by four times the mass or velocity of the train needs to be increased by four times.
The increase in the velocity of the train by four times will increase the momentum of the train.
Original Velocity of the train = 50 m/s
Increased Velocity of the train = 50 × 4 = 200 m/s
Increased new Momentum of the train = mass × new velocity
Increased Momentum = 20 metric ton × 200m/s
Increased Momentum = 4000 metric ton. m/s
Learn more about Momentum here:
https://brainly.com/question/24030570
#SPJ2
The block slides down an inclined friction-less track to a infinite hill that the block begins to climb and slow down. Is energy conserved or not?
Answer:
Energy is conserved.
Explanation:
Without friction, kinetic energy and gravity potential energy are always swapping back and forth.
The block slides down an inclined friction-less track to a infinite hill that the block begins to climb and slow down, in which the energy is conserved.
What is friction?Friction refers to the force that prevents hard surface, fluid layers, as well as material elements from sliding against each other.
There are various kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in contact solid surfaces.
It is thought to be caused by the interactions of tiny bumps on surfaces rubbing against one another.
The bumps on each surface bend and exert force on one another, making it difficult for the surfaces to slide over one another.
A block's speed increases while its acceleration remains constant as it slides down a frictionless incline. After being placed on a ramp inclined at an angle with the horizontal, a crate remains stationary.
Thus, the block slides beneath an inclined friction-less track to an unlimited hill, where it commences to climb as well as slow down, preserving energy.
For more details regarding friction, visit:
https://brainly.com/question/13000653
#SPJ2
What is work? A. What happens when energy is destroyed B. The number of molecules in a substance C. The total size of an object divided by its mass D. What happens when a force causes an object to move
Answer:
Which extended definition would be most helpful to add to this body paragraph?
Laughter Yoga, a new form of yoga, is becoming increasingly popular.
Laughter Yoga, which is becoming more and more popular, was created in the 1990s.
Laughter Yoga is modeled after traditional yoga but includes laughter exercises.
Laughter Yoga is a form of yoga that was created by Dr. Madan Kataria in the 1990s.
Explanation:
c
What are sound detectors?
Answer:
A sound detector comes in the shape of a rectangular board which comprises a microphone as well as a processing circuitry.
Answer:
Sound detection sensor works similarly to our Ears, having diaphragm which converts vibration into signals.
Are these a Chemical or Physical Change??
1. Sodium Bicarbonate breaks down into sodium carbonate and water.
A. Chemical Change
B. Physical Change
2. Mercury is cooled until it is in the solid state.
A. Chemical Change
B. Physical Change
The change of sodium bicarbonate breaking down into sodium carbonate and water is a chemical change. The cooling of mercury until it is in the solid state is physical change. The correct option for 1 is A and for 2 is B.
What is chemical and physical change?A chemical change occurs as a consequence of a reaction, whereas a physical change occurs when transformation occurs forms but retains its chemical identity.
Chemical changes include burning, cooking, rusting, and rotting. Physical changes include boiling, melting, freezing, and shredding.
A physical change is required to a specimen of matter in which some of the material's properties change but the matter's identity does not.
Physical changes can be classified as either reversible or irreversible. Melting is a reversible physical change because the melted ice cube can be refrozen.
In the first case, sodium bicarbonate is breaking down and forming sodium carbonate and water, this implies a chemical change.
In the second case, mercury is just cooling down, changing its physical shape. So it is physical change.
Thus, the correct option for 1 is A and for 2 is B.
For more details regarding chemical and physical changes, visit:
https://brainly.com/question/11321843
#SPJ2
Calculate the net force acting on a body of mass 20 kg moving with a
uniform velocity of 4 ms-1.
Answer:
0 N
Explanation:
Uniform velocity means no acceleration and therefore no net force.
If a 35 kg box collides with a stationary 120 kg box with a force of 90 N, what must be true of the magnitude of the reaction force?
Newton's third law allows to find the result for the value of the reaction force during the collision is:
The reaction force is F = 90 N and is applied to the lighter body.Newton's third law stable that the forces appear in pairs or ea that when two bodies interact, the interaction forces appear in the two bodies simultaneously, in general they are called action and reaction forces.
These furas are of the same magnitude, but in the opposite direction, each one applied to one of the bodies.
They indicate that the most lighter body collides with the one with the greatest mass with a force of F = 90 N. If we call this the action, the larger body must react with a force of equal magnitude on the lighter body.
Consequently, the reaction force is F = 90 N directed towards the lighter body.
Learn more about Newton's third law here: https://brainly.com/question/9857272
Which car is experiencing negative acceleration?
A. a car sitting at a red light
B. a car slowing down as it approaches a red light
C. a car driving in a circle at a constant speed
D. a car changing its speed from 0 km/hr to 10 km/hr
Answer:B
Explanation:
Answer: b
Explanation: b as it slows down and decelerates
An object of mass 6.36 kg is released from rest and drops 2.05 m to the floor. The collision is completely inelastic. How much kinetic energy is lost during the collision
Answer:
Essentially all of it
Explanation:
The potential energy was
PE = mgh = 6.36(9.81)(2.05) = 127.90278 = 128 J
ignoring air resistance, this PE converts to KE
With no rebound final velocity is zero, so Kinetic energy lost = 128 J
What are the three major types of severe weather? Describe at least two characteristics of each type
Answer:
High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.
Explanation:High winds- wind speeds as low as 23 knots (43 km/h) may lead to power outages when tree branches fall and disrupt power lines. Once wind exceed 135 knots (250 km/h) within strong tropical cyclones and tornadoes, homes completely collapse, and significant damage is done to larger buildings. Total disruption occurs once wind exceeds 175 knots (324 km/h)
Tornado- Typically look like a narrow funnel reaching from the clouds to the ground. Their wind speed goes from 65 to 250 miles per hour.
"An extreme weather condition in which we face the high speed wind in combination with heavy snow."
As for any blizzard has the normal wind speed of about 40 mph, and the visibility range reduces to less then 500 ft.
Answer: High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.
Explanation:
PLEASE HELP FOR PHYSICS!
All objects exert a gravitational force on all other objects. This force is given by, F = GMm r2 , where the value of G = 6.673 × 10–11 N–m2/kg2 , M is the mass of the heavier object, m is the mass of the lighter object, and r is the distance between the two objects.
What is the force of gravity between two balls of mass 50 kg each if the distance between them is 25 m. Assume that there is no interference from any other gravitational field.
Hi there!
Recall Newton's Law of Universal Gravitation:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]
Where:
Fg = Force of gravity (N)
G = Gravitational Constant
m1, m2 = masses of objects (kg)
r = distance between objects (m)
Plug in the given values stated in the problem:
[tex]F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}[/tex]