Two cables are attached to a 30-foot wall and a 22-foot wall. If the tie down for the cables is located in the center of a 40-foot wide alley between the two walls, what is the angle \thetaθ that is formed between the cables? Round your answer to the nearest whole number.

Answers

Answer 1

Answer:

76°

Step-by-step explanation:

Applying trigonometry :

Angle x ;

Tan x = opposite / adjacent

Tan x = (30/20)

x = tan^-1(30/20)

x = 56.31°

Angle y;

Tan y = opposite / adjacent

Tan y = (22/20)

x = tan^-1(22/20)

x = 47.73°

The angle θ ;

Sum of angles in a straight line = 180

56.31 + 47.73 + θ = 180°

θ = 75.96°

Two Cables Are Attached To A 30-foot Wall And A 22-foot Wall. If The Tie Down For The Cables Is Located

Related Questions

Answer the question pleaseeeee

Answers

would you be able to upload a clear picture please

Can anyone do this thanks

Answers

1) oct.
2) sept.
4) aug. &' sept
Not 100% though .



Find the 10th term in the following geometric sequence.
8, 4, 2, 1,

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I hope you'll understand my caculation.

Please help!
Find the length of the triangle.

Answers

Answer: 12.

Step-by-step explanation: Use Pythagorean Theorem. We that a = 9, b = ?, and c = 15. Plugging that in gives us 9^2 + b^2 + 15^2. Solving for b gets us b^2 = 144. Taking the square root of both sides gets us b = 12.

the answer is 12 :) the above person is right

Simplify. the square root of 3 times the square root of 5

Answers

Answer:

[tex]\sqrt{15}[/tex]

Step-by-step explanation:

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then

[tex]\sqrt{3}[/tex] × [tex]\sqrt{5}[/tex] = [tex]\sqrt{3(5)}[/tex] = [tex]\sqrt{15}[/tex]

Pls help will mark brainliest

Answers

Answer:

1/ 4^2

Step-by-step explanation:

4^4 * 4^-6

We know that a^b * a^c = a^(b+c)

4^(4-6)

4^-2

We also know that a^-b = 1/a^b

1/4^2

Write the equation for a parabola with a focus at (-4,-2) and a directrix at y = 3.

Answers

Answer:

[tex]\displaystyle y=-\frac{1}{10}x^2-\frac{4}{5}x-\frac{11}{10}[/tex]

Step-by-step explanation:

By definition, any point (x, y) on the parabola is equidistant from the focus and the directrix.

The distance between a point (x, y) on the parabola and the focus can be described using the distance formula:

[tex]d=\sqrt{(x-(-4))^2+(y-(-2))^2[/tex]

Simplify:

[tex]d=\sqrt{(x+4)^2+(y+2)^2}[/tex]

Since the directrix is an equation of y, we will use the y-coordinate. The vertical distance between a point (x, y) on the parabola and the directrix can be described using absolute value:

[tex]d=|y-3|\text{ or } |3-y|[/tex]

The two equations are equivalent. Therefore:

[tex]\sqrt{(x+4)^2+(y+2)^2}=|y-3|[/tex]

Solve for y. We can square both sides. Since anything squared is positive, we can remove the absolute value:

[tex](x+4)^2+(y+2)^2 = (y-3)^2[/tex]

Expand:

[tex](x^2+8x+16)+(y^2+4y+4)=(y^2-6y+9)[/tex]

Isolate:

[tex]x^2+8x+11=-10y[/tex]

Divide both sides by -10. Hence, our equation is:

[tex]\displaystyle y=-\frac{1}{10}x^2-\frac{4}{5}x-\frac{11}{10}[/tex]

How many x-intercepts appear on the graph of this polynomial function?
f(x) = x - 5x?
O 1 x-intercept
O 2 x-intercepts
O 3 x-intercepts
O 4 x-intercepts

Answers

Answer: B

Step-by-step explanation:

There are two x-intercepts: x = -√5 and x = √5. The answer is: 2 x-intercepts.

What is x-Intercept?

The x-intercept is defined as an intercept that is located at the x-axis of the plane, is the location or coordinate from where the line crosses.

To find the x-intercepts of the polynomial function f(x) = x⁴ - 5x², we set f(x) equal to zero and solve for x.

Setting f(x) = 0:

x⁴ - 5x² = 0

Factoring out the common term x²:

x²(x² - 5) = 0

Now we have two factors: x² = 0 and x² - 5 = 0.

For x² = 0, we have a double root at x = 0.

This means the graph touches the x-axis at x = 0 but does not cross it.

For x² - 5 = 0, we can solve for x by taking the square root:

x² = 5

x = ±√5

Therefore, there are two x-intercepts: x = -√5 and x = √5.

The answer is: 2 x-intercepts.

Learn more about the x-intercept here:

https://brainly.com/question/14180189

#SPJ7

Thank you please shwo your work if you can<3 !!!!
x=
y=

Answers

Answer:

x = 2, y = - 1

Step-by-step explanation:

Given the 2 equations

y = - 7x + 13 → (1)

y = - 1 → (2)

Substitute y = - 7x + 13 into (2)

- 7x + 13 = - 1 ( subtract 13 from both sides )

- 7x = - 14 ( divide both sides by - 7 )

x = 2

y = - 1 is already given in (2)

Then x = 2, y = - 1

It showed that: y = -1
So the equation will be: -1 = -7x + 13

Now we solve from here, start by subtracting 13 on both sides:
-14 = -7x

Divide -7 on both sides:
2 = x

What is the force on the surface of a square of side 5 m if the pressure acting on it is 25 pascal ?

Answers

Answer:

625 N

Step-by-step explanation:

First, find the area of the square.

Area = side x side

        = 5 x 5

        = 25 m²

Force = pressure x area

          = 25 x 25

          = 625 N

Hope this helps!

Can someone please help me?the question is in the picture. Thank you

Answers

Answer:

It would be 9π

Step-by-step explanation:

(x-1)²π

(x-1)(2x-4)

PLs! 100 points the integers 1,2,3,4,5,6,7,8 are placed in a list so that each value is either bigger than all the numbers it precedes or smaller than all the numbers it precedes. How many such lists are possible? 100 points!

Answers

2

Hope this helps! :)

______________

Answer:

you can know by the minimum number or the maximum e.g minimum 1 maximum 20 answer 20

Step-by-step explanation:

so in this kind it is 2

hope its useful

explain why 7x+3 cannot be factorised

Answers

Answer:

There is no common factor

Step-by-step explanation:

Use the sum of cubes identity to write this polynomial expression in factored form:
8x3 + 27.

Answers

Answer:

[tex] {8x}^{3} + 27 \\ = {8x}^{3} + {3}^{3} \\ let : 8x \: be \: a \\ : 3 \: be \: b \\ = > {a}^{3} + {b}^{3} : \\ {(a + b)}^{3} = (a + b)( {a}^{2} + 2ab + {b}^{2} ) \\ {(a + b)}^{3} = ( {a}^{3} + 3{a}^{2} b + 3a {b}^{2} + {b}^{3} ) \\ ( {a}^{3} + {b}^{3} ) = {(a + b)}^{3} - 3ab(a + b) \\ \therefore( {8x}^{3} + 27) = {(8x + 3)}^{3} - 72(8x + 3)[/tex]

Can anyone help ? :) thanks

Answers

the product of 5 x 2 is 10, this is the same as adding 2 to 2 5 times brainliest pls

no se ingles xd asi que la verdad sorry aun que dime si es potensiacion

Please help me with this question...​

Answers

Answer:

my answer is in this picture. sorry about my presentation and English

Which expression can be used to find 80% of 120?


80% of 120
20%
20%
20%
20%
20%

Answers

Answer:

96

Step-by-step explanation:

80*120=9600 divided by 100

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far is she from her camp base and what is her bearing from it

Answers

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

[tex]\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}[/tex] (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

[tex](x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})[/tex] (1b)

Where:

[tex]x, y[/tex] - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

[tex]r_{1}, r_{2}[/tex] - Length of each vector, in kilometers.

[tex]\theta_{1}, \theta_{2}[/tex] - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that [tex]r_{1} = 42\,km[/tex], [tex]r_{2} = 28\,km[/tex], [tex]\theta_{1} = 32^{\circ}[/tex] and [tex]\theta_{2} = 154^{\circ}[/tex], then the resulting coordinates of the final position of the surveyor is:

[tex](x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})[/tex]

[tex](x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km][/tex]

[tex](x,y) = (10.452, 34.531)\,[km][/tex]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

[tex]\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}[/tex]

[tex]\theta \approx 16.840^{\circ}[/tex]

And the distance from the camp is calculated by the Pythagorean Theorem:

[tex]r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}[/tex]

[tex]r = 36.078\,km[/tex]

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

(15 points!!) please help!! If you can answer the other questions on my page I will Venmo u!

Answers

Answer:

y = (x - 3)² - 4      Vertex form

(3, -4)    Vertex

Step-by-step explanation:

f(x) = x² - 6x + 5

Complete the square

y = (x - 3)² + 5 - (-3)²

y = (x - 3)² + 5 - 9

y = (x - 3)² - 4      Vertex form

(3, -4)    Vertex

This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the triangle is 15.7 centimeters. The equation 2a + b = 15.7 models this information.

If one of the longer si
des is 6.3 centimeters, which equation can be used to find the length of the base

Answers

Answer:

2(6.3) + b = 15.7

12.6 + b = 15.7

b = 3.1

A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. Using this equation, find out the maximum amount of profit the company can make, to the nearest dollar.
y=−9x^2+571x−3884

Answers

Your answer is 5173.

Ambwene cut 3 lawns in his neighborhood on Friday and more on Saturday,
He earns $22.50 for each lawn cut. His total earning for both days is $135.
How many lawes did he cut on Saturday?

Answers

On Friday he made $67.50 by cutting three lawns. In order to find out how much he made on Saturday you would subtract 67.50 from 135 which would equal $67.50.

Mr. Ali cut a wooden plank into three parts in the ratio 2:3:8. The longest part was 72 centimeters

Answers

Answer:

117 centimeters

Step-by-step explanation:

Since the longest pieces is 72 centimeters and it’s ratio is 8, that means the individual unit of the ratio is 9 (72/8=9). You can multiply each part of the ratio by 9

2x9=18

3x9=27

We already know the third part of the ratio is 72. Add all of it together to get the original length.

18+27+72=117 cm

Triangle ABC is on a coordinate plane.

If its rotated 180 degrees around a specific point to create A'B'C'

Which characteristics are true for both the original triangle and the triangle's image?

Question 11 options:

The measures of

The coordinates of B' will be the same as B.


The coordinates of A' will be the same as A.


The Area of ABC will be the same as A'B'C'


The perimeter of ABC will be the same for A'B'C'


The length of segment AB will be the same as Segment A'B'

Answers

Answer:

The last 3 choices are correct

Step-by-step explanation:

A rotation of 180 degrees has the rule (x,y) →(-x,y) , so the coordinates will not be the same. The shape's size doesn't change.

Find three consecutive even integers such that the product of the second and
third integers is equal to 35.

Answers

Step-by-step explanation:

first number=x

second number=x+2

third number=x+4

(x+2)(x+4)=35

x(x+4)+2(x+4)=35

x²+4x+2x+8=35

x²+6x+8=35

x²+6x=35-8

x²+6x=33

x²+6x-33=0

using that, you can find the first number,

then use the data to find the other two.

The interior angle of a regular polygon is 120. Work out the number of sides of the polygon.

Answers

Answer:

6 sides

Step-by-step explanation:

The interior angle and the exterior angle sum to 180° , then

exterior angle = 180° - 120° = 60°

The sum of the exterior angles of a polygon is 360° , so

number of sides = 360° ÷ 60 = 6

Answer:

6 sides

Step-by-step explanation:

180 - 120 =60°

sum of exterior angles is 360°

therefore , 360°/60°

ans = 6 sides

Good luck :-)

1+2+3+4+5+6+7+8+9+2000+1000000

Answers

1+2+3+4+5+6+7+8+9+2000+1000000 =10,020.45

if a person gives you their card number and they say you can spend a certain amount of money and u spend more is it considered stealing? or is it not because they gave u their card willingly and all u did was go over the limit.

Answers

Answer:

It would be considered stealing.

Step-by-step explanation:

They did willingly give you their card BUT, they trusted you to only spend a certain amount and not go over that certain limit. You went over the limit even though they specifically told you not to go over it so yes, it would be classified as stealing.

Mathssssssssssssssssssssssssss

Answers

Answer:

The value of x is 5

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions parallel to and normal to the plane that makes an angle of theta equals tangent Superscript negative 1 Baseline (StartFraction StartRoot 3 EndRoot Over 3 EndFraction )θ=tan−1 3 3 with the positive​ x-axis. Show that the total force is the sum of the two component forces. What is the component of the force parallel to the​ plane? left angle nothing comma nothing right angle , What is the component of the force perpendicular to the​ plane? left angle nothing comma nothing right angle , Find the sum of these two forces. left angle nothing comma nothing right angle

Answers

Solution :

Let [tex]$v_0$[/tex] be the unit vector in the direction parallel to the plane and let [tex]$F_1$[/tex] be the component of F in the direction of [tex]v_0[/tex] and [tex]F_2[/tex] be the component normal to [tex]v_0[/tex].

Since, [tex]|v_0| = 1,[/tex]

[tex]$(v_0)_x=\cos 60^\circ= \frac{1}{2}$[/tex]

[tex]$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$[/tex]

Therefore, [tex]v_0 = \left<\frac{1}{2},\frac{\sqrt 3}{2}\right>[/tex]

From figure,

[tex]|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3[/tex]

We know that the direction of [tex]F_1[/tex] is opposite of the direction of [tex]v_0[/tex], so we have

[tex]$F_1 = -5\sqrt3 v_0$[/tex]

    [tex]$=-5\sqrt3 \left<\frac{1}{2},\frac{\sqrt3}{2} \right>$[/tex]

    [tex]$= \left<-\frac{5 \sqrt3}{2},-\frac{15}{2} \right>$[/tex]

The unit vector in the direction normal to the plane, [tex]v_1[/tex] has components :

[tex]$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$[/tex]

[tex]$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$[/tex]

Therefore, [tex]$v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$[/tex]

From figure,

[tex]|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5[/tex]

∴  [tex]F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>[/tex]

                   [tex]$=\left<\frac{5 \sqrt3}{2},-\frac{5}{2} \right>$[/tex]

Therefore,

[tex]$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$[/tex]

           [tex]$=<0,- 10> = F$[/tex]

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