The ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].
The given parameters;
Mass of the electron, [tex]m_e[/tex]= 9.11 x 10⁻¹¹ kgCoulomb's constant, k = 8.99 x 10⁹ Nm²/C²Gravitational constant, G = 6.67 x 10⁻¹¹ Nm²/kg²Charge of electron, q = 1.6 x 10⁻¹⁹ CDistance between the two electrons, r = 1 cmThe electrostatic force between the two electrons is calculated as follows;
[tex]F_c = \frac{kq^2}{r^2} \\\\[/tex]
The gravitational force between the two electrons is calculated as follows;
[tex]F_g = \frac{Gm_e^2}{r^2}[/tex]
The ratio of the electric force to the gravitational force between the two electrons is calculated as follows;
[tex]\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{1}{\frac{Gm^2}{r^2} } \\\\\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{r^2}{Gm^2} \\\\\frac{F_c}{F_g} = \frac{kq^2}{Gm^2}\\\\[/tex]
[tex]\frac{F_c}{F_g} = \frac{(8.99 \times 10^9) \times (1.6 \times 10^{-19}))^2}{(6.67 \times 10^{-11} ) \times (9.11 \times 10^{-31})^2} \\\\\frac{F_c}{F_g} = 4.2 \times 10^{42}[/tex]
Thus, the ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].
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when a viscous fluid flows in a tube, its velocity is __________.
What is the acceleration as an object goes from +20 m/s to +26 m/s over 1.4 s?
Answer:
4.3 m/s^2
Explanation:
a = vf - vi / t
26 - 20 / 1.4
= 4.28 ( round your numbers)
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Jose’s doctor recommends that he add more cardio to his exercise routine. Which exercise would be the BEST choice?
A.
ballet
B.
jogging
C.
bowling
D.
volleyball
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
jogging
Explanation:
Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.
Can an object have positive acceleration and decreasing speed?.
If the circumference of a space shuttle's orbit around Earth is 42,522 km and the space shuttle orbits around it 1.4 times
every hour, what is the speed of the space shuttle in km/hour? In meters/second?
Answer:
105,000km or about 65,244mi
Explanation:
If the space shuttle orbits around it 1.4 times every hour then the speed of the space shuttle in km/hour would be 595330.8 Km/hour, and its speed in meters would be 165369.67 m/s.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.
Average speed = total distance /Total time
As given in the problem If the circumference of a space shuttle's orbit around Earth is 42,522 km and the space shuttle orbits around it 1.4 times every hour, then we have to find the speed of the space shuttle in km/hour
The total distance covered by the space shuttle in an hour = 42,522×1.4
= 595330.8 Km
The speed of the space shuttle in meters/second = 595330.8 × 1000/3600
= 165369.67 m/s
Thus, the speed of the space shuttle would be 595330.8 Km/hour, and its speed in meters would be 165369.67 m/s.
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Each box weighs 10lb. The coefficient of static friction between box A and box B is 0.24, and the coefficient of static friction between box B and the inclined surface is 0.3. What is the largest angle for which box B will not slip
The largest angle for which box B will not slip is 16.7⁰.
The given parameters:
weight of box, W = 10 lbcoefficient of static friction between box A and box B, [tex]\mu_s_1[/tex] = 0.24coefficient of static friction between box B and the inclined surface, [tex]\mu_s_2[/tex] = 0.3The frictional force between box A and box B is calculated as;
[tex]F_f_1= \mu_s_1 (mg)[/tex]
The frictional force between box B and inclined surface is calculated as;
[tex]F_f = \mu_s_2 (2mg) cos(\theta)[/tex]
The net force on the boxes that results in no movement is calculated as;
[tex](2mg) sin(\theta) - F_f= 0\\\\(2mg) sin(\theta) = F_f\\\\(2mg) sin(\theta) = \ \mu_s_2 (2mg) cos(\theta)\\\\ sin(\theta) = \mu_s_2 cos(\theta)\\\\\mu_s_2 = \frac{sin(\theta)}{cos(\theta)} \\\\\mu_s_2 = tan(\theta)\\\\\theta = tan^{-1} (\mu_s_2)\\\\\theta = tan^{-1} (0.3)\\\\\theta = 16.7 \ ^ 0[/tex]
Thus, the largest angle for which box B will not slip is 16.7⁰.
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what happens to light in an object that is translucent?
Translucent objects allow some light to travel through them. The light does not pass directly through the materials. It changes direction many times and is scattered as it passes through. Therefore, we cannot see clearly through them and objects on the other side of a translucent object appear fuzzy and unclear.
A sports car accelerates from 0 to 60mph ,27 m/s ,in 6.3 secounds .The car exerts a force of 4106N . What is the mass of the car
The car accelerates 60 mph in 6.3 seconds. Thus, the acceleration is [tex]\frac{60}{6.3}[/tex]. [tex]f=ma[/tex], so [tex]4106 = m(\frac{60}{6.3})[/tex], so [tex]m=431.13[/tex].
please help me solve all of them ( a, b, c and d ) thankiew !!
I’m also kind of in a rush
Answer:
a-
V= IR
9V = I ×( 12+6)
I = 9/ 18 A = 0.5 A
b
V=IR
240 = 6 A ×( 20 + R)
40 = 20 + R
R = 20 ohm
c
resultant resistance of the 2 parallel resistances= Ro
1/Ro = 1/ 5 + 1/ 20
1/Ro =( 20+5)/100
= 1/Ro = 1/4
Ro= 4 ohm
V=IR
V = 2A × ( 1+ 4 OHM)
V = 10V
d
equivalent resistance = Ro
1/Ro = 1/(2+8) + 1/(5+5)
1/Ro = 1/10 +1/10
2/10 = 1/ Ro
Ro= 10/2 = 5 ohm
V = IR
12V = I × 5Ohm
I=2.4 A
Which feature of a balanced chemical equation demonstrates the law of
conservation of mass?
O A. It shows the products of a chemical reaction to the right of the
reaction arrow.
B. It has coefficients to show how much of each substance a
chemical reaction uses.
C. It has the same types of atoms on both sides of the reaction
arrow.
D. It shows the reactants of a chemical reaction to the left of the
reaction arrow.
Answer:
C
Explanation:
don't worry Tama yan base sa pagkakaintindi ko
A car starts from rest and accelerates at 2.5m/s^2 for 2s. What is the final velocity of the car
Answer:
5m/s ez
Explanation:
plz make me brainliest
Explain why the 4th state of matter would and would NOT make an acceptable force field.
The 4th state of matter would make an acceptable force field.
The 4th state of matter which is plasma would make an acceptable force field because this fourth state of matter is present in ionized form which has two charges on it i.e. cation which is a positive charge and anion which is a negative charge.
We know that charges attract as well repel other objects if they are strong enough. Positive charge repel positive charge but attract negative charge so we can conclude that 4th state of matter would make an acceptable force field.
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Which wave has the longest wavelength?
Answer:
A Wave red
Explanation:
Answer:
Answer: Wave E
Explanation:
Why because if you put each in a strait line it would have been longer
hope it helps
What decides free energy.
Answer: when free energy is extensive property that means its magnitude depends on the amount of a substance.
Explanation:
srry if im wrong :( .
Answer:
state of the system
Explanation:
What is the frequency of light having a wavelength of 4. 50 x 10-6 cm.
The frequency of a photon of red light with wavelength 4.50 x 10−7m is 6.67 x 1014Hz.
Which do you think is easiest and hardest to keep track of: hazardous waste that is present as a gas, liquid, or solid? Why?
Answer:
probably liquid cause it can be contained easily
Can anyone help me with this question? I’ll give BRAINLIEST to whoever answers first
Answer:
a) F = 84.64N
b) The force has to increase.
Explanation:
First of all, let's convert everything to the same unit system:
Vo = 0 m/s Vf = 98 mi/h * 1609.34 m / 1mi * 1h / 3600s = 43.8m/s
d = 1.7m m = 0.15kg
We can calculate force as:
F = m*a where a is the acceleration experiencd by the ball and m is its mass.
In order to calculate acceleration, we can use this formula:
Solving for a:
Now, the force will be:
F = m * a = 84.6N
As we can see in that previous equation, the force is directly proportional to the mass of the ball, so, assuming the final speed of the ball is the same as before (that is, the acceleration is the same), the force will increase in the same proportion as the mass does.
Calculate the weight of an object that displaces 3 m2 of water and exerts a pressure of 500 Pa (500 N/m ).
The weight of the object from the information provided in the question is 1500 N.
We know that pressure = Force/area. We have the following information from the question;
Pressure =500 Nm-2
Area = 3 m2
Hence;
Force = Pressure × area
Force = 500 Nm-2 × 3 m2
Force = 1500 N
Hence, the weight of the object is 1500 N
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a 1200-kg pick-up truck traveling south at 15 m/s suddenly collides with a 750-kg car that is traveling east. the two vehicles stick together and slide along the road after colliding. a highway patrol officer investigating the accident determines that the final position of the wreckage after the collision is 25 m, at an angle of 50° south of east, from the point of impact. she also determines that the coefficient of kinetic friction between the tires and the road at that location was 0.40. what was the speed of the car just before the collision?
The conservation of momentum, Newton's second law and kinematics allows to find the result for the initial speed of the car is:
The speed of the car is 40 m/s at the East direction.
Given parameters
Mass of the truck M = 1200 kg. Truck speed v₀₁ = 15 m / s towards the South. Mass of the car m = 750 kg. Travel east The two vehicles unite. The braking distance d = 25m at 50º SE The friction coefficient μ = 0.40To find
The initial speed of the car.
The momentum is defined by the product of the mass and the velocity of the body, so it is a vector quantity. In the case of an isolated system the momentum is conserved.
In the attachment we see a diagram of the vehicle crash, let's write the moment for each axis.
y-axis
Initial instant. Before the shock.
[tex]p_{oy}[/tex] = M v₀₁
Final moment. After the crash
[tex]p_{fy}[/tex] = (M + m) [tex]v_{fy}[/tex]
The system is formed by the two vehicles for which during the crash it is isolated and the momentum is conserved.
[tex]p_{oy} = p_{fy} \\\\M v_{o1} = (M+m) v_{fy} \\v_{fy} = \frac{M}{M+m} \ v_{o1}[/tex]
Calculate us
[tex]v_{fy} = \frac{1200}{1200+750} \ 15[/tex]
vfx = 9.23 m / s
x-axis
Initial instant. Before the crash.
p₀ₓ = m v₀₂
Final moment. After the crash.
[tex]p_{fx}[/tex] = (M + m) [tex]v_{fx}[/tex]
The momentum is preserved.
[tex]p_{ox}= p_{fx} \\m v_{o2) = (M+m) \ v_{fx}[/tex]
Let's find the velocity just after the collision, let's use Newton's second law,
y-axis
N-W = 0
N = W = (M + m) g
x-axis
fr = (M + m) a
The friction force is the macroscopic manifestation of the interactions between the two bodies.
fr = μ N
We substitute.
μ g = a
Now we can use kinematics.
v² = v₀² - 2a d
When the vehicles stop their speed is zero.
v₀² = 2 a x
v₀ = [tex]\sqrt{2\ \mu \ g \ d}[/tex]
Let's calculate.
v₀ = [tex]\sqrt{2 \ 0.40 \ 9.8 25 }[/tex]
v₀ = 14 m / s
This is the speed of the two vehicles just after the collision, that is, let's use trigonometry to find their components.
cos 25 = [tex]\frac{v_{ox}}{v_o}[/tex]
v₀ₓ = v₀ cos 25
v₀ₓ = 14 cos 25
v₀ₓ = 12.69 m / s
We substitute in the expression of the conservation of the momentum in the x-axis.
m v₀₂ = (M + m) [tex]v_{fx}[/tex]
[tex]v_{o2} = \frac{M+m}{m} v_{fx}[/tex]
Let's calculate.
[tex]v_{o2} = \frac{1200+750}{750} \ 12.69[/tex]
vfy = 32.99 m / s = 40 m / s
In conclusion using the conservation of momentum, Newton's second law and kinematics we can find the result for the initial speed of the car is:
The speed of the car is 40 m/s at the East direction.
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solar power generates electricity from what source
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Jinan has high cholesterol and wants to do what he can to improve it through his diet. What would be the BEST thing for him to increase in his diet to address this issue?
A.
sugars
B.
protein
C.
carbohydrates
D.
unsaturated fat
PLEASE NO LINKS
Answer:
D. unsaturated fat
Explanation:
Unsaturated fats are considered the healthiest fats because they improve cholesterol, help reduce inflammation (a risk factor for heart disease), and help decrease the overall risk of developing heart disease. The main source of unsaturated fats are plant-based foods.
Answer:unsaturated fat
Explanation:
Compare the amplitude of these waves.
Answer:
a smooth
b less smooth
c faster
d faster than fast c
e to fast for fast
Explanation:
A father pushes his child in a cart. The cart starts to move.
Scientists can use many physical quantities to describe what is happening.
The car is placed on a ramp, which is 20 meters high. The mass of the car and the child is 100kg.
Calculate the potential energy the car will have before it is let go and the velocity the car will travel at down the ramp assuming no frictional forces.
Acceleration due to gravity (g) = 10 m/s2
The potential energy of the car when it let go is 20,000 J.
The speed of the car at the bottom of the ramp is 20 m/s.
The given parameters;
mass of the car, m = 100 kgheight of the car, h = 20 mThe potential energy of the car is calculated as follows;
P.E = mgh
P.E = 100 x 10 x 20
P.E = 20,000 J
The speed of the car at the bottom of the ramp is calculated as follows;
[tex]K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 10 \times 20} \\\\v = 20 \ m/s[/tex]
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2. A student becomes so excited by the whole idea of black holes that he decides to jump into one. It has a mass 10 times the mass of our Sun. What is the trip like for him
Answer:
*Disclaimer you can't actually do that, or at least not yet because the nearest black hole is at least 1,000 light years away. But if we could...
His journy would be pretty fast and horrific. For him, he would slowly be streched apart or spegetified into a string of atoms as he nears the event horizoin. But for an outside observer he would apear to go slower and slower and would never actualy reach the event horizion. This is becuase of einstines general relativity, massive objects slow time down. He would also apear to become red as the lights wavelength is streched out due to the entense gravity of the black hole.
A box with a weight of 20 newtons rest at a bottom of a ramp and is pushed to the end of the ramp with a force of 40 newtons. This ramp is an incline of 15 meters long. What is the maximum height of the ramp.
To move maximum height the friction force can be assumed to be
negligible.
The height of the ramp is 15 metersReasons:
The component of the weight acting on the incline, w = m·g·sin(θ)
Length of the ramp = 15 m
Potential energy of the box = 15 × sin(θ) ×20 = 300·sin(θ)
F × 15 = 300·sin(θ)
F = 20·sin(θ)
Work done by net force = Potential energy gained by the box
Work done by net force = (40 - 20·sin(θ)) × 15 = 300·sin(θ)
40 = 20·sin(θ) + 20·sin(θ) = 40·sin(θ)
sin(θ) = 1
θ = arcsin(1) = 90°
The ramp is at an inclination of 90°, therefore, the ramp is oriented vertically
The height of the ramp = The length of the ramp = 15 m
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Explanation:
The rod can be in equilibrium only if the resultant force is 0 and the moment around any point of the rod must be equal to 0.
We have to take moments around the pivoted point.
Moment = Force × Perpendicular distance to the force
For the rod to be in equilibrium,
Clockwise moment - Anticlockwise moment = 0
Clockwise moment = Anticlockwise moment
The distance between pivoted point and the weight of rod = 50 cm - 30 cm = 20 cm
So 20 cm× 1.2 N produces a Clockwise moment
If Perpendicular distance between pivoted point and 2N load is x,
Anticlockwise moment = x × 2N
20 cm× 1.2N = 2N × x
x = 12 cm
So 2 N load is at 12 from the pivoted point.
From the left edge of the meter ruler, 2N load is at 30-12 cm distance
= 18 cm
Answer: 18 cm
Explanation:
A 0.14-MIN baseball is dropped from rest. It has a momentum of 0.90 kg⋅m/skg⋅m/s just before it lands on the ground.
For what amount of time was the ball in the air?
The time spent in the air by the ball at the given momentum is 6.43 s.
The given parameters;
momentum of the ball, P = 0.9 kgm/sweight of the ball, W = 0.14 NThe impulse experienced by the ball is calculated as follows;
[tex]Ft = \Delta P[/tex]
where;
[tex]Ft[/tex] is impulse
[tex]\Delta P[/tex] is change in momentum
The time of motion of the ball is calculated as follows;
[tex]t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s[/tex]
Thus, the time spent in the air by the ball at the given momentum is 6.43 s.
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find the impulse of a 20.0 KG object accelerates to8.1 M/S from 2.3 M/S
Answer:
116 N•s
Explanation:
change in momentum = mvf-mvi
= m(Vf - Vi)
= 20( 8.1-2.3)
change in momentum= 116 kg•m/s
: .impulse is 116 N•s
What does gravity, electricity, and magnesium have in common?
Answer:
magnesium (Mg), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table, and the lightest structural metal. Its compounds are widely used in construction and medicine, and magnesium is one of the elements essential to all cellular life.
Explanation:
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does the force change if the density change in a object
Answer:
No
Explanation:
It doesn't depend on the density
Answer:No. If you take all your masses and and squeeze them into a tiny volume,