Two forest rangers are standing on a road that runs east-west. One sights a forest fire in the direction 31° east of
north. The other sights the same fire 57° west of north.
Find the distance from each ranger to the forest fire and
the shortest distance from the fire to the road.

Two Forest Rangers Are Standing On A Road That Runs East-west. One Sights A Forest Fire In The Direction

Answers

Answer 1

Answer: The forest ranger closest to the fire is at a distance of 9.92 miles (nearest hundredth).

Draw a horizontal line AB of length 15 miles to represent the positions of the two forest rangers.

Point A is to the left and point B is to the right.

Complete triangle ABC so that m∠A = 41° and m∠B = 56°.

The point C represents the location of the fire.

Let x = length of BC. It is the shortest distance from the forest ranger B to the fire because BC is opposite the smaller angle of 41°.

Because the sum of angles in a triangle is 180°,

m∠C = 180° - (41° + 56°) = 83°.

From the Law of Sines,

x/sin(41) = 15/sin(83)

x = 15*[sin(41)/sin(83)] = 9.915 mi

Step-by-step explanation:

Draw a horizontal line AB of length 15 miles to represent the positions of the two forest rangers.

Point A is to the left and point B is to the right.

Complete triangle ABC so that m∠A = 41° and m∠B = 56°.

The point C represents the location of the fire.

Let x = length of BC. It is the shortest distance from the forest ranger B to the fire because BC is opposite the smaller angle of 41°.

Because the sum of angles in a triangle is 180°,

m∠C = 180° - (41° + 56°) = 83°.

From the Law of Sines,

x/sin(41) = 15/sin(83)

x = 15*[sin(41)/sin(83)] = 9.915 mi


Related Questions

At 100°F, a certain Insect chirps at a rate of 97 times per minute, and at 102°F, they chirp 111 times per minute. Write an equation in slope-intercept form that represents the situation.​

Answers

Answer:

y = 7x - 603

Step-by-step explanation:

We start by determining the slope:

m = y2 - y1/x2 - x1 = 111 - 97/102 - 100 = 14/2 = 7,

Now we substitute the slope into the slope-intercept equation y  = mx + b, solving for the y-intercept [b]:

111 = 7(102) + b,

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Equation: y = 7x - 603

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Answer:

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Answer:

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Answers

Answer:

what i did was multiply 33*6 and got 198 and then 228-198 to find out that the initial fee was 30 dollars. then multiply 33*9+30 to get a  9-month total cost of $327

Step-by-step explanation:

cost = $33 per month + fee  

1.  c(m) = 33m + f

 33(6) + f = 228

198 + f = 228

f = $30 membership fee  

c(m) = 33m + 30

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Answer

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

The perimeter is simply 2 times length + 2 times width. In the case of our square, this would simply be 2x+2x (since length = width), or 4x . Therefore, if given an area, all you'd do is take the square root (to get from x2 to x , and then multiply by 4 to find perimeter.

Answer:

The first method

Take a square root, then multiply it by 4.

The defining characteristic of a square is that its length is equal to its width. Take a look below:

Self-created

So, for this particular square, the area is length⋅width, or x⋅x=x2. Now, how can you go from this to perimeter?

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1. Anthony threw a ball from the top of a 10-story building that was 165 feet

tall. The equation g(165 - h) = v2 can be used to find the maximum

height the ball can attain after being thrown from the top of the building,

Rewrite the equation to highlight the maximum height attained by the

ball, h.

Answers

Answer:

[tex]h = 165 - \frac{v^2}{g}[/tex]

Step-by-step explanation:

Given

[tex]g(165 - h) = v^2[/tex]

Required

Make h the subject

[tex]g(165 - h) = v^2[/tex]

Divide both sides by g

[tex]165 - h = \frac{v^2}{g}[/tex]

Subtract 165 from both sides

[tex]165 - 165 - h = \frac{v^2}{g} - 165[/tex]

[tex]- h = \frac{v^2}{g} - 165[/tex]

Multiply both sides by -1

[tex]-1 * - h = (\frac{v^2}{g} - 165)*-1[/tex]

[tex]h = 165 - \frac{v^2}{g}[/tex]

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Answers

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Step-by-step explanation:

Answer:

the area of triangle is height ×base

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Answers

Answer:

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Step-by-step explanation:

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Answers

Complete Question:

Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the base and height of Jerry’s rhombus. Compare the area of Charlene’s rhombus to the area of Jerry’s rhombus.

Answer:

Charlene's rhombus has a larger area

Step-by-step explanation:

Given

Jerry's

[tex]Base = 15in[/tex]

[tex]Height = 9in[/tex]

Charlene's

[tex]Base = Height = 13in[/tex]

Required

Compare both areas

The area of rhombus is:

[tex]Area = Base * Height[/tex]

For Jerry's

[tex]Area = 15in * 9in[/tex]

[tex]Area = 135in^2[/tex]

Charlene's

[tex]Area = 13in * 13in[/tex]

[tex]Area = 169in^2[/tex]

By comparison: Charlene's rhombus has a larger area by 34in^2

Answer:

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Step-by-step explanation:

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