If 20 coulombs of charge move past a given point in 4 s, what is the current?
Answer:
5A
Explanation:
[tex]=> Current (I) = \frac{q}{t} [/tex]
Here q = 20 C and t = 4sec
=> I = 20/4 = 5A
calculate the work done 36 kg boxes lifted onto a shelf 1.5 m high
Answer:
529.2 joules
Explanation:
Work done = force x distance = mass x gravity x distance
= 36x9.8 x1.5 =529.2 joules
Vhat are you looking for when you research a potential employer?
personal information about the managers
company history
related industry news
what its product or service is
BRAINLIEST IF ITS CORRECT HEPL
Answer: C.
Explanation: They describe the direction of the magnetic force on a north monopole at any given position.
5 postulates of neil bohr atomic model
Answer:
What is Bohr’s Model of an Atom?
The Bohr model of the atom was proposed by Neil Bohr in 1915. It came into existence with the modification of Rutherford’s model of an atom. Rutherford’s model introduced the nuclear model of an atom, in which he explained that a nucleus (positively charged) is surrounded by negatively charged electrons.
When you are making cold calls while job hunting, be
o 20 minutes early
O on time
O prepared with a résumé and cover letter
O casual
Answer:
The answer is O prepared with a résumé and cover letter
Explanation:
That will get you very far if you are prepared with a résumé and cover letter
Please help!! Look at pic
Answer:
Explanation:
Voltage and Current relation is given by V=IR
I=9A
R=4Ohm
V=IR
V=9x4=36Volts
Resistance = 4 Ohm
Current = 9 Ampere
Voltage = 36 Volts
A satellite with a mass of 150 kg fires its engines to increase velocity, thereby
increasing the size of its orbit about Earth. As a result, it moves from a
circular orbit of radius 7.5 x 106 m to an orbit of radius 7.7 x 106 m. What is
the approximate change in gravitational force from Earth as a result of this
change in the satellite's orbit? (Recall that Earth has a mass of 5.97 x 1024 kg
and G = 6.67 x 10-11 N-m²/kg².)
OA. -113 N
OB. -148 N
O C. -216 N
D. -54 N
The approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N
What is the universal law of gravitation?The universal law of gravitation states that the particle of matter in the universe attracts another particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
It is written thus;
F = G MIM2÷ r∧2
Where
F = Gravitational force
G = Gravitational constant
M1 and M2 are the masses of the object
r = radius
How to calculate the gravitational forceFormula:
F = G MIM2 ÷ r∧2
Given M1 = 150kg, M2 = 5.97 x 1024 kg, r = 7.5 x 106 m, G = 6.67 x 10-11 N-m²/kg²
For the first orbit, substitute the values
F = 6.67 x 10∧-11 × 150 × 5.97 x 10∧24 ÷ (7.5 x 10∧6)²
F = 5.95 × 10∧16 ÷ 56.25 × 10∧12 = 105.77 N
For the second orbit of radius 7.7 x 106 m
F = 6.67 x 10∧-11 × 150 × 5.97 x 10∧24 ÷ (7.7 x 10∧6)²
F = 5.95 × 10∧16 ÷ 59.25 × 10∧12 = 100. 42 N
The approximate change = 105. 77 - 100.42 = 5. 35N
Hence, the approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N
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when an Earthquake occurs energy radiates in all direction from its source called the
Answer:
[tex]\huge\boxed{\sf Focus}[/tex]
Explanation:
Focus:The point at which Earthquake occurs is called Focus.It is also called hypocenter.Epicenter:Epicenter is the point on the Earth surface which is just above the focus.Most of the times, epicenter is confused with focus. However, epicenter lies on the Earth surface and focus is the exact point from where the Earthquake originates.
[tex]\rule[225]{225}{2}[/tex]
A 95kg fullback was running downfield at 8m/s. A defensive player (110kg) was running upfield at 6m/s straight at the fullback. What was the momentum of each player before they impacted?
A)Fullback: 760kgm/s, Defender: 660kgm/s
B)Fullback: 760kgm/s, Defender: -660kgm/s
C)Fullback: 570kgm/s, Defender: 880kgm/s
D) Fullback: 570kgm/s, Defender: -880kgm/s
A 95 kg fullback was running downfield at 8 m/s. A defensive player (110 kg) was running upfield at 6 m/s straight at the fullback. The momentum of each player before they impacted Fullback 760 kgm/s, Defender: 660 kgm/s.
What is impulse?In classical mechanics, the integral of a force, F, over the time period over which it acts, t, is referred to as the "impulse." Impulse is a vector quantity because force is one as well. When an item receives an impulse, it experiences an equivalent vector change in its linear momentum and also in the direction that results.
momentum = mass *velocity
momentum = 95*8 = 760 kg-m/sec Fullback
momentum = 110*6 = 660 kg-m/sec Defender
A 95 kg fullback was running downfield at 8 m/s. A defensive player (110 kg) was running upfield at 6 m/s straight at the fullback. The momentum of each player before they impacted Fullback 760 kgm/s, Defender: 660 kgm/s.
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When the ultrasound beam strikes the surface at or nearly at right angles, the fraction of sound energy that is reflected (R) at the interface between two materials of acoustic impedance Z1 and Z2, respectively, is given by:
Explanation:
the expression of x= -4t+2t^2 where x is displecement?Which of the following is a characteristic of a balanced force?
1) equal in size opposite in direction
2) causes a change in the direction of an object
3) causes a change in the motion of an object
a) First write down what you see in the picture.
Answer:
which picture please,I don't get you
Consider an object of mass 2kg on a ramp with βs=0.5 and βk=0.4.
If we keep increasing the ramp angle, what is the angle() that the object starts to move downward? Give your answer in degree with 1 decimal place.
Answer:
bs angle will move in 1.5
Where would sound NOT be
able to travel?
A. through the ground
B. through the ocean
C. through the air
D. through outer space
What kind of object are the light rays interacting with in the model below?
Convex mirror
Convex lens
Concave mirror
Concave lens
Answer:
Concave lens
.............
.......................................
.
Explanation:
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A stationary sound waves has a series of nodes. The distance between the first and the 6th node is 30cm. What is the wavelength of the sound wave
Answer:
Assume a node at the left end and the right end
N-A-N-A-N-A-N-A-N-A-N shows nodes and anti-nodes
10 quarter wavelengths are shown (or 2.5 wavelengths)
30 / 2.5 = 12 cm wavelength since there is 1/4 wavelength between node and anti-node
Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.
The difference between the node and the anti-node exists 12 cm wavelength.
What is meant by stationary sound waves?Standing waves are created when two identical waves move in opposition to one another along a line. Despite being composed of two waves that are moving in opposition to one another, standing waves do not travel through space or along a string.
A wave that is stationary is one that is not moving, is at a standstill, or is in a relaxed position. A standing wave is created whenever two waves with nearly identical frequencies, wavelengths, and amplitudes that are traveling in opposite directions collide.
A waveform signal that is carried in space or down a wire has a wavelength, This is the distance between two identical locations (contiguous crests) in the following cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm).
The distance over which a periodic wave's shape repeats is known as the wavelength in physics.
Assume that there exists a node at both the left and right ends.
Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.
it displays 10 quarter wavelengths.
Since there exists a 1/4 wavelength difference between the node and the anti-node, 30 / 2.5 = 12 cm wavelength.
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Why is nuclear energy able to be used for practical purposes? the reactions are controlled to regulate energy output. the reactions are uncontrolled for maximum energy output. all of the products are fed back into the reaction to keep it going. all of the products are immediately removed to inhibit more reactions.
Nuclear energy is able to be used for practical purposes because ; ( A ) The reactions are controlled to regulate energy output
Nuclear energy generationNuclear energy is a clean energy source which has a zero-emission, nuclear energy is used to generate electricity/power following a controlled reaction known as fission of uranium atoms to produce heat energy required to drive a turbine to produce electricity
Hence we can conclude that Nuclear energy is able to be used for practical purposes because ; ( A ) The reactions are controlled to regulate energy output.
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Answer:
option A
Explanation:
A copper atom has an atomic number of 29 and an atomic mass of 64. What
is the structure of this atom?
OA. It has a central nucleus composed of 29 protons and 64 neutrons,
surrounded by an electron cloud containing 29 electrons.
B. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
OC. It has a central nucleus composed of 29 protons and 29 neutrons,
surrounded by an electron cloud containing 35 electrons.
D. It has a central nucleus composed of 35 protons and 29 neutrons,
surrounded by an electron cloud containing 29 electrons.
Answer:
It has a central nucleus composed of 29 protons and 35 neutrons, surrounded by an electron cloud containing 29 electrons
Explanation:
Atoms Composition:
A atom is mainly composed of a centrally-placed nucleus. A nucleus consists of protons and neutrons with a cloud of electrons surrounding the outside. A proton is a nuclear particle having a positive charge equal to that of an electron and a mass more than 1800 times the electron. A neutron is a nuclear particle having a mass almost identical to that of an electron, but no electric charge.Calculation:
Mass number = Proton + Neutron64 = 29 + NeutronCollect like termsNeutron = 64 – 29Neutron = 35a toy car needs a source of energy to move. how could you give gravitational potential energy to a toy car so that it will move when you let it go?
Answer:
wait one second im about to go get some milk im thirsty
Explanation:
do you want any chicken on your salad
Which circuit contains the smallest voltage?
- A circuit with a current of 20amps and a resistance of 15 ohms?
- A circuit with a current of 10 amps and a resistance of 10 ohms?
- A circuit with a current of 25 amps and a resistance of 10 ohms?
- A circuit with a current of 20 amps and a resistance of 10 ohms?
Answer:
10 amps 10 ohms ( 100 v)
Explanation:
Voltage = current * ohm
the smallest of those listed is 10 amps 10 ohms
The magnetic field lines of a bar magnet spread out from the
A. north end to the south end.
B. south end to the north end.
C. edges to the center.
D. center to the edges.
Answer:
I think the letter B. But I'm not sure pero I try mo Lang po baka Yan po ang tamang sagot kac Yan po Yung nilagay na sagot saakin e Kaya try mo Lang po
Find the charge on the capacitor in an LRC-series circuit at t = 0.03 s when L = 0.05 h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A. (Round your answer to four decimal places.)
Determine the first time at which the charge on the capacitor is equal to zero. (Round your answer to four decimal places.)
The charge on the capacitor in an LRC-series circuit is 2.8907 C.
The first time at which the charge on the capacitor is equal to zero is 0.1409s.
What is capacitor?The capacitor consists of two parallel plates used to store the charge when current flows through it, and provides energy when shuts off.
By the Kirchoff's second law,
Lq'' +Lq' +q/C =E(t)
Where, L =0.05h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A.
Equations becomes q''+120q' +4000 =0
The auxiliary equation is m² +120m+4000 =0
Solving this quadratic equation, we have
m =-6± 20i
Then , q(t) = Ae^(-60t)cos 20t + Be^(-60t)sin 20t where, A and B are constants.
At t=0, q(0) =7 =A
and q'(t) = A [ -20e^(-60t)sin 20t - 60e^(-60t)cos 20t ] +B [ 20e^(-60t)cos 20t - 60e^(-60t)sin 20t ]
So, i(0)= q'(0) =0 =-60A +20 B
Putting the value of A=7 above, we have B =21.
So, q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t
The charge on the capacitor at time t =0.015
q(0.015) = 2.8907 C
Thus the charge on capacitor is 2.8907 C.
q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t =0
Solve for t, we get
e^(-60t)cos 20t + 3e^(-60t)sin 20t\
-1/3 = sin 20t /cos20t
t =1/20 arctan(-1/3)
As, arctan is defined within -90 to +90,
So, 20t = -0.3218 +π =2.8197
t =0.1409s
Thus the first time at which the charge is zero is 0.1409s.
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HELP MEEE!!!!!!!!!
A series circuit is made up of a battery and 4 Resistors.
The Resistors are:
R1 = 10 ohms
R2 = 20 ohms
R3= 5 ohms
R4= 10 ohms
What is the total resistance in the circuit is...
ohms
7
8
What happens when the thermal energy of a substance increases?
O The motion of the particles in the substance increases, and the temperature of the substance decreases.
O The motion of the particles in the substance decreases, and the temperature of the substance increases.
O Both the motion of the particles in the substance and the temperature of the substance decrease.
O Both the motion of the particles in the substance and the temperature of the substance increase
Answer:
D
Explanation:
it is because when the thermal energy increases the particles move faster and the temperature increases.
A 3 kg toy plane is attached to a 1.8 m string that it can be whirled around in a horizontal circle above the users head. If one’s exerts a force of 10 N on the string, what speed should the plane have as it rotates
With the use of formula, The plane should rotate at the speed of 3 m/s
Circular MotionWhen a body is moving rotationally at a point, the motion is said to be a circular motion. There are two types of motion in a circle
Vertical circular motionHorizontal circular motionGiven that a 3 kg toy plane is attached to a 1.8 m string that it can be whirled around in a horizontal circle above the users head rotates.
The given parameters are:
mass m = 3 kg
Length L = 1.8 m = radius
Force F = 10 N
Velocity V = ?
If one’s exerts a force of 10 N on the string, The speed the plane should have can be calculated by using the below formula
F = M[tex]V^{2}[/tex] / r
Substitute all the parameters into the formula
10 = 3 x [tex]V^{2}[/tex] / 1.8
Cross multiply
18 = 3[tex]V^{2}[/tex]
[tex]V^{2}[/tex] = 18/3
[tex]V^{2}[/tex] = 9
V = [tex]\sqrt{9}[/tex]
V = 3 m/s
Therefore, The plane should rotate at the speed of 3 m/s
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What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?
The energy emitted by a photon when it falls from level f to energy level b is 2.84 eV.
Energy of photon at level f and level b
The energy of a photon at level F is given as -268 eV and the energy photon at level b is given as -5.52 eV.
Energy emitted by a photon when it falls from level f to energy level b is calculated as follows;
ΔE = -2.68 eV - (-5.52 eV)
ΔE = -2.68 eV + 5.52 eV
ΔE = 2.84 eV
Thus, the energy emitted by a photon when it falls from level f to energy level b is 2.84 eV.
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Determine the CM of the uniform thin L-shaped construction brace shown in (Figure 1) . Suppose that a = 2.20 m and b = 1.63 m Determine the x coordinate of the CM
By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.
How to determine the coordinates of the center of mass of a compound figure
Let suppose that the entire construction has a uniform mass, then the coordinates of the center of mass can be determined by definition of weighted average:
[tex]\bar x = \frac{\sum \limits_{i = 1}^{n}x_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex] (1)
[tex]\bar y = \frac{\sum \limits_{i = 1}^{n}y_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex] (2)
If we know that a = 2.20 m and b = 1.63 m, then the x-coordinates of the center of mass of the compound figure is:
[tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex]
By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.
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An object of mass 20 kg is raised vertically through a distance of 8 m above ground level. If g = 10 m/s2, what is the gravitational potential energy of this object at this position?
Answer:
1600 joules
Explanation:
Potential Energy = m * g * h
= 20 kg * 10 m/s^2 * 8 m = 1600 J