Two towers of height 40 m and 30 m respectively support a transmission line conductor at water crossing. The horizontal distance between the towers is 300 m. If the tension in the conductor is 1590 kg, find the clearance of the conductor at a point mid-way between the supports. Weight of conductor is 0·8 kg/m. Bases of the towers can be considered to be at the water level.

Answers

Answer 1

The sag in the tensioned cable depends on the weight of the cable and

the applied tension.

The clearance midway between the support is approximately 29.34 meters

Reasons:

The given parameters are;

Height of the towers are; h₁ = 40 m and h₂ = 30 m

Horizontal distance between the towers, l = 300 m

The tension in the conductor, T = 1,590 kg

Weight of the conductor, w = 0.8 kg/m

Required:

The clearance space of the conductor mid-way between the support

Solution:

The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;

[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]

Where;

h = h₂ - h₁ = 40 m - 30 m = 10 m

Which gives;

[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]

The sag at the lowest point is give by the formula;

[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]

Therefore;

[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]

The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m

The distance of the midpoint from the lowest point, x, is therefore;

[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]

Which gives;

[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]

The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34

The clearance midway between the support ≈ 29.34 m

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Answer:

Kepler's First Law: each planet's orbit about the Sun is an ellipse. The Sun's center is always located at one focus of the orbital ellipse. The Sun is at one focus. The planet follows the ellipse in its orbit, meaning that the planet to Sun distance is constantly changing as the planet goes around its orbit.

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Kepler 's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. An ellipse can easily be constructed using a pencil, two tacks, a string, a sheet of paper and a piece of cardboard. Tack the sheet of paper to the cardboard using the two tacks.

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Answer:

d/t = (230 km)/(3.25 h) = 70.8 km/h.

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Answers

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Answer:

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Explanation:

An experiment used to determine the resistance of a metallic conductor is the resistance of a metallic conductor at different temperatures.

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Answer:

Frictional Force: Frictional force is the force caused by the relative motion of two surfaces that come into contact with each other.

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b) Centripetal Acceleration
c) Centripetal Force.​

Answers

For the honeybee that circles a field looking for a flower upon which to land, we have:

a) The tangential velocity is 10.01 m/s.

b) The centripetal acceleration is 40.1 m/s².

c) The centripetal force is 1.60 N.

a) The tangential velocity can be calculated as follows:

[tex] v = \omega r = \frac{2\pi r}{T} [/tex]  (1)

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r: is the radius of the circle = 2.5 m

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[tex] v = \frac{2\pi r}{T} = \frac{2\pi 2.5 m}{1.57 s} = 10.01 m/s [/tex]  

Hence, the tangential velocity is 10.01 m/s.

b) The centripetal acceleration is related to the tangential velocity as follows:

[tex] a_{c} = \frac{v^{2}}{r} = \frac{(10.01 m/s)^{2}}{2.5 m} = 40.1 m/s^{2} [/tex]

Therefore, the centripetal acceleration is 40.1 m/s².

c) The centripetal force is given by:

[tex] F = ma_{c} [/tex]

Where:

m: is the honeybee's mass = 0.04 kg

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Answer:

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What is Weight?

The weight of an object is defined as the force that acts on the object due to gravity. Sometimes weight is defined as a vector quantity, the force of gravity acting on an object. Others define weight as a scalar quantity, the magnitude of the force of gravity.

It is gravitational force of attraction on an object which is caused by the presence of a massive second object like Earth or Moon. Weight is expressed by multiplying the mass times the acceleration due to gravity.

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Where, W= weight of the object

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In above information,

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Using the formula

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m=1150/9.8

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Answer:

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Answer:

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Explanation:

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This is written as W = -P∆V and is known as pressure-volume work.

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In this problem, the gas is being compressed, i.e. the volume decreases, and so work is being done ON the system. Thus, the sign of W is positive (+).  This comes out automatically because of negative sign in front of P∆V,                                                                                                                                                                                           So,                                                                                                                                       we have W = -P∆V and substituting values, we have

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Answer:

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Answer:

0.7 m between the balance point and Tiny

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It's intuitive to say she sould be on the side the smaller mass is placed. How far from the balance point?

Let's call x that distance. and assume that the contraption is "oriented" so that being on the side with tiny (and teeny) gives you a positive distance from the balance point, and negative on the other side.

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Answers

Answer:

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Answer:

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Answers

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Answer:

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Explanation:

have a great day!! :)

what the guy above me said

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Answer:

D) 4.9 m/s

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--

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Explanation: Good luck box BrokenTag27

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simple subtract and ummmmmm.....

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Hello guys! Can you please help me with physics. I translated it in English. Can yall help me please how much you can!!

A body 60 m above the ground shall be thrown vertically upwards at an initial speed of 20 m / s. Air resistance can be ignored!
1. How high will the body fly from the point of ejection?
2. What is the maximum height it will reach above the ground?
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Answers

Answer:

1. 60m

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Answers

they are converted into thermal and sound energy as well as the kinetic energy in the air

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Answers

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Answers

Answer:

a=v/t (searched)

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(searched)

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Answer:

Answer is below….

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_________________________________________________________

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