Un frutero ha comprado 165kg de manzanas a 2 € el kilo; se le han estropeado 15 kg y el resto los vende a 4 € el kilo. ¿ Cuánto ha ganado? ( 1,25p)

Answers

Answer 1

Answer:

€270

Step-by-step explanation:

If a fruit vendor has bought 165kg of apples at € 2 per kilo, the total amount spent is expressed as;

Cost price = 165 * 2 = €330

If 15kg spoilt, the amount of fruit remaining will be 165 - 15 = 150kg

If he rests he sells for € 4 per kilo, then;

Selling price = 150 * 4 = €600

Amount earned = €600 - €330

Amount earned = €270


Related Questions

How many three digit numbers greater than 540 can be formed using the digits
0,2,4,5,6,8 ?

Answers

Answer:

At least 12

Step-by-step explanation:

I created 12 different number patterns greater than 540. I hope I was able to help you out :)


[tex]64y + 6x = [/tex]

Answers

[tex]\longrightarrow{\blue{ 2 \: ( \: 32 \: y + 3 \: x \: )}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]64 \: y + 6 \: x[/tex]

[tex] = 2 \: ( \: 32 \: y + 3 \: x \: )[/tex]

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer:

2 ( 32y + 3 x)

Step-by-step explanation:

64 y + 6x

factor out 2 from the equation

2 ( 32y + 3 x)

WILL GIVE BRAINLIEST
Determine whether each scenario below is an example of a BIASED or UNBIASED sample

Answers

Answer:

First : Unbiased

Second : Biased

Question: A sample contains 68 grams of radioactive Bruinium. Sixteen days later, the sample had decayed to 47 grams.

A) what is the decay rate, k?
B) what is half-life of bruinium to the nearest 0.1 day?
C) how much bruinium would be left in another 10 days? (After the first 16)
D) how much time is required for the sample to decay to 25 grams (from t=0)?

Answers

The answer is B......

Can you please help me with this

Answers

I’m interested in playing that

In the diagram, the measure of angle 3 is 105°.

A transversal intersects 2 lines to form 8 angles. Clockwise from the top, the angles are 1, 2, 3, 4; 5, 6, 7, 8.

Which angle must also measure 105°?
Angle1
Angle4
Angle6
Angle8

Answers

Answer:

angle 8

Step-by-step explanation:

not sure but if correct 1 heart pls and comment

Answer:           A is Correct

Step-by-step explanation:

angle 1 is opposite of angle 3 which means its also 105°

Divide and simplify
x^2−9/x^2−16/x^2+5x+6/x-4
step by step pls
thanks

Answers

Answer:

Step-by-step explanation:

Answer:

[tex]\frac{(x+2)(x+3)^2(x-3)}{(x-4)^2(x+4)}[/tex]

Step-by-step explanation:

i'm going to assume what you have looks like

[tex]\frac{x^2-9}{\frac{x^2-16}{\frac{x^2+5x+6}{x-4}}}[/tex]

Let's start by factoring everything

x²-9= (x+3)(x-3)

x²-16= (x+4)(x-4)

x²+5x+6=(x+3)(x+2)

x-4= x-4

which means what we have looks like

[tex]\frac{(x+3)(x-3)}{\frac{(x+4)(x-4)}{\frac{(x+3)(x+2)}{x-4}}}=\frac{(x+3)(x-3)}{(x+4)(x-4)}\div\frac{x-4}{(x+3)(x+2)}=\frac{(x+3)(x-3)}{(x+4)(x-4)}*\frac{(x+3)(x+2)}{x-4}=\frac{(x+3)^2(x-3)(x+2)}{(x+4)(x-4)^2}[/tex]

And I think that's as simplified as it can get

14+ (42 + 7) + 32
Pls help me

Answers

Answer:

95

Step-by-step explanation:

14 + (42 + 7) + 32

14 + 49 + 32

63 + 32

95

Answer:

95

Step-by-step explanation:

Let's use BEDMAS to solve this (Brackets, Exponents, Division, Multiplication, Addition, Subtraction)

1. Calculate the brackets.

42 + 7 = 49

2. Add 14 + 49 + 32

14 + 49 + 32 = 95

---------------------------------------------------------------------------------------------------------------

Have a great summer :)

find the value of x.

Answers

Answer:

x = sqrt(33)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

4^2 + x^2 = 7^2

16 + x^2 = 49

Subtract 16 from each side

x^2 = 49-16

x^2 = 33

Take the square root of each side

sqrt(x^2) = sqrt(33)

x = sqrt(33)

Pythagorean Theorem:

[tex]\quad\quad\quad \boxed{ \tt{\color{blue}{c}^{2} = {a}^{2} + {b}^{2} }}[/tex]

To find the value of x. Let's use this formula:

[tex]\quad\quad\quad \boxed{ \tt{\color{blue}{a} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

Imagine that "a" is the "x".

[tex]\quad\quad\quad \boxed{ \tt{\color{black}{a} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {7}^{2} - {4}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {49} - {16} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt \color{black}{{x} = \sqrt{ 33} }}[/tex]

Hence, The value of x is,

[tex]\quad\quad\quad \boxed{ \tt \color{green}{{x} = \sqrt{ 33} }}[/tex]

_________

#LetsStudy

5 oranges cost $2. Find the cost of 20 oranges.

Answers

Answer:  $8

===================================================

Work Shown:

(5 oranges)/(2 dollars) = (20 oranges)/(x dollars)

5/2 = 20/x

5x = 2*20 .... cross multiply

5x = 40

x = 40/5 .... dividing both sides by 5

x = 8

20 oranges cost $8

--------------

Another way to approach the problem is to note that the jump from "5 oranges" to "20 oranges" is "times 4".

5*4 = 20

So we'll apply the "times 4" operation to the old cost of $2 to get the new cost being 2*4 = 8 dollars

Answer:

$8

Step-by-step explanation:

if 5 oranges cost $2 then 1 orange costs 2/5 of a dollar, or 40 cents

20 oranges multiplied by 40 cents is $8

or you can set up a proportion:

2/5 = x/20

cross-multiply to get:

5x = 40

x = 8

Find the shaded sector and the length of the arc. Round to the nearest hundredth. ​

Answers

Answer:

Step-by-step explanation:

I'll show you how to do the first one; the other are exactly the same, so pay attention.

The formula for arc length is

[tex]AL=\frac{\theta}{360}*2\pi r[/tex] where θ is the central angle's measure. It just so happens that the measure of the central angle is the same as the measure of the arc it intercepts. Our arc shows a measure of 40°; this measure is NOT the same as the length. Measures are in degrees while length is in inches, or cm, or meters, etc. Going off that info, our central angle measures 40°. Filling in the formula and using 3.1415 for π:

[tex]AL=\frac{40}{360}*2(3.1415)(3)[/tex]. I'm going to reduce that fraction a bit (and I'll use the same reduction in the Area of a sector coming up next):

[tex]AL=\frac{1}{9}*2(3.1415)(3)[/tex] which makes

AL = 2.09 units. Now for Area of the Sector. The formula is almost identical, but instead uses the idea that the area of a circle is πr²:

[tex]A_s=\frac{\theta}{360}*\pi r^2[/tex] where θ is, again, the measure of the central angle (which is the same as the measure of the arc it intercepts). Filling in:

[tex]A_s=\frac{1}{9}*(3.1415)(3)^2[/tex] which simplifies a bit to

[tex]A_s=\frac{1}{9}*(3.1415)(9)[/tex]. As you can see, the 9's cancel each other out, leaving you with

[tex]A_s=3.14[/tex] units²

Answer:

Step-by-step explanation:

[tex]Arc \ Length = 2 \pi r \frac{ \theta}{360}[/tex]

[tex]Sector \ Area = \pi r^2 \frac{ \theta }{360}[/tex]

[tex]1) Arc \ Length = 2 \pi \times 3 \times \frac{40}{360} = 2\pi \times 3 \times \frac{1}{9} = \frac{2}{3} \pi = 2.09[/tex]

  [tex]Sector \ Area = \pi \times 9 \times \frac{40}{360} = 9\pi \times \frac{1}{9} = \pi = 3.14[/tex]

[tex]2) Arc \ Length = 2 \pi \times 5 \times \frac{88}{360}= 7.68[/tex]

  [tex]Sector \ Area = \pi \times 25 \times \frac{88}{360} = 19.2[/tex]

[tex]3) Arc \ Length = 2 \pi \times 6 \times \frac{260}{360} = 27.22[/tex]

  [tex]Sector \ Area = \pi \times 36 \times \frac{260}{360} = 81.68[/tex]

 

a ball is shot out of a homemade air cannon. It flies through the air such that its height, as a function of time, is given by: h= -16t^2 + 64t + 10. where h is the height of the ball in feet and t is the time since it was fired in seconds. Max estimates that it takes 4 seconds for the ball to hit the ground and Cole estimates it takes 5 second. Algebraically determine who is closer and support your answer.

Answers

Answer:

Max

Step-by-step explanation:

the function given that h = -16t³+64t+10

the general function Equation:

h = at²+bt+c

=> t at the highest point is defined by t = -b/2a

= -64/2(-16) = -64/-32 = 2 second

the total times that the ball hits the ground

= 2× 2 seconds = 4 seconds.

so, Max is right

Answer:

Solution given:

Let h=0=when the ball hit the ground,the height=0.

h= -16t^2 + 64t + 10.

0=16t²-64t-10

8t²-32t-5=0

∆=[tex] \frac{32±\sqrt{32²+4*5*8}}{2*8}=\frac{8±\sqrt{74}}{4}[/tex]

taking positive

t1=[tex] \frac{8+\sqrt{74}}{4}=4.15seconds[/tex]

t2=[tex] \frac{8-\sqrt{74}}{4}(t2<O)(neglected)[/tex]

So

t=4.15seconds closer to 4seconds.So

Max is closer.

help me solve this pleaseeee

Answers

Answer:

f(n) = 6n + 12

Step-by-step explanation:

There is a common difference in consecutive number of seats, that is

42 - 36 = 36 - 30 = 30 - 24 = 24 - 18 = 6

This indicates the sequence is arithmetic with nth term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 18 and d = 6 , then

f(n) = 18 + 6(n - 1) = 18 + 6n - 6 = 6n + 12

Adam is refinishing his basement. 30 ft by 50 ft are the dimensions of Adam's rectangular basement. How much tile would he need to cover the floor? If the height of the basement is 6 ft, how much wall area is there to paint?

Answers

Answer:

Area of four walls is 3960 square feet.

Step-by-step explanation:

length, L = 30 ft

Width, W = 50 ft

height, H = 6 ft

The area of walls is

= 2 (L W + W H + H L)

= 2 (30 x 50 + 50 x 6 + 6 x 30)

= 2 (1500 + 300 + 180)

= 3960 square feet

Answer/Step-by-step explanation:

How much tile would he need to cover the floor?

Answer: 1500 Ft^2

If the height of the basement is 6 ft, how much wall area is there to paint?

Answer: 960 Ft^2

- - - - - - - - - - - - - - - - - - - - - - - - -

Answers

Answer:

x = ±3 sqrt(2)

Step-by-step explanation:

x^2 = 18

Take the square root of each side

sqrt(x^2) = sqrt(18)

x = ± sqrt(18)

x =±sqrt(9*2)

x = ±sqrt(9) sqrt(2)

x = ±3 sqrt(2)

Pls help i'm struggling with this

Answers

Answer:

Click the second one, I truly hope that worked! :)

Find surface area plzzzzz

Answers

The answer to your question is 184m

Answer:

184 m²

Step-by-step explanation:

Surface Area = 2(10*2) + 2(10*6) + 2(2*6)

Surface Area = 2(20 + 60 + 12)

Surface Area = 2(92)

Surface Area = 184 m²

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

please i need help, right now!!! i give the person the brainliest answer!! im giving 15 points… please help

Answers

Answer:

Ummmm its just a black screen

Step-by-step explanation:

The table of values represents an exponential function ​f(x). What is the average rate of change over the interval −2≤x≤2? Enter your answer, as a decimal rounded to the nearest hundredth, in the box.
−3 64
−2 16
−1 4
0 1
1 1/4
2 1/16
3 1/64
(Worth 60pts)

Answers

Answer:

-1456

-864

4

-11

-5,25

-1,93

Step-by-step explanation:

Answer:

-3.98

Step-by-step explanation:

Rate of change is:

[f(2) - f(-2)]/[2 - (-2)] = (1/16 - 16)/4 = -255/16*1/4 = -255/64 = -3.98

The number of spectators at the 2010 World Cup match between Argentina and Mexico was 82000 correct to the nearest thousand. If each spectator paid 2600 Rand to attend the game what is the lower bound for the total amount paid? Write your answer in standard form

Answers

Answer:

$213,200,000 or 2.132*10[tex]^{5\\}[/tex]

Step-by-step explanation:

82000*2600

solve the following the unknown -3(×+1)-2=4×-5(×-3)​

Answers

Answer:

x = - 10

Step-by-step explanation:

Expand the equation first then simplify it

can someone help my find the fraction and explain how you got it please please​

Answers

the fraction is 1/3. on the input side, it’s going up by one, (6,7,8 etc) and on the output side it’s going up by 3. (18+3=21). if u were to double check 6/18 reduces to 1/3! so the answer is 1/3

Câu 4: Cho chiết suất tuyệt đối của nước là n= 4/3 . Một người nhìn một hòn sỏi nhỏ S nằm ở đáy một bể nước sâu 1,2 m theo phương gần vuông góc với mặt nước, thấy ảnh S' nằm cách mặt nước một khoảng bằng

Answers

goodStep-by-step explanation:

Volunteers who had developed a cold within the previous 24 hours were randomized to take either zinc or placebo lozenges every 2 to 3 hours until their cold symptoms were gone (Prasad et al., 2000). Twenty-five participants took zinc lozenges, and 23 participants took placebo lozenges. The mean overall duration of symptoms for the zinc lozenge group was 4.5 days, and the standard deviation of overall duration of symptoms was 1.6 days. For the placebo group, the mean overall duration of symptoms was 8.1 days, and the standard deviation was 1.8 days.

a. Calculate a 95% confidence interval for the mean overall duration of symptoms if everyone in the population were to take the zinc lozenges.

b. Calculate a 95% confidence interval for the mean overall duration of symptoms if everyone in the population were to take the placebo lozenges.

c. On the basis of the intervals computed in parts (a) and (b) and/or the picture you constructed in part (c), is it reasonable to conclude generally that taking zinc loz-enges reduces the overall duration of cold symptoms more than if taking a placebo? Explain why you think this is or is not an appropriate conclusion.

d. In their paper, the researchers say that they checked whether it was reasonable to assume that the data were sampled from a normal curve population and decided that it was. How is this relevant to the calculations done in parts (a) and (b)?

Answers

Answer:

a. (3.83952, 5.16049)

b. (7.32, 8.88)

c. The difference in the range of the confidence intervals suggest that taking the zinc loz-enges reduces the overall duration of cold symptoms

d. The assumptions required for the validity validity of a t-test include that the data is sampled from a source that have data that are normally distributed

Step-by-step explanation:

The given parameters are;

The number of participants that took zinc lozenges, n₁ = 25

The number of participants that took a placebo, n₂ = 23

The mean duration of the symptoms for the zinc lozenge group, [tex]\overline x_1[/tex] = 4.5 days

The standard deviation of overall duration, s₁ = 1.6 days

The mean duration of the symptoms for the placebo group, [tex]\overline x_2[/tex] = 8.1 days

The standard deviation, s₂ = 1.8 days

a. The 95% confidence interval if everyone in the population were to take zinc lozenges is given as follows;

[tex]CI=\bar{x}_1\pm t_{\alpha/2} \times \dfrac{s_1}{\sqrt{n_1}}[/tex]

n₁ = 25, the degrees of freedom (df) = n₁ - 1 = 24

The t-value for 95% confidence interval, with df = 24, with t = 2.064

Therefore, we have;

[tex]CI_{zl}=4.5 \pm 2.064 \times \dfrac{1.6}{\sqrt{25}}[/tex]

[tex]CI_{zl}[/tex] = 4.5 ± 0.66048

[tex]CI_{zl}[/tex] = (3.83952, 5.16049)

b. The 95% confidence interval if everyone in the population were to take the placebo is given as follows;

[tex]CI_p=\bar{x_2}\pm t_{\alpha/2} \times \dfrac{s_2}{\sqrt{n_2}}[/tex]

n₂ = 23, the degrees of freedom (df) = n₂ - 1 = 22

The t-value for 95% confidence interval, with df = 22, with t = 2.074

Therefore, we have;

[tex]CI_p =8.1 \pm 2.074 \times \dfrac{1.8}{\sqrt{23}}[/tex]

[tex]CI_p[/tex] = 8.1 ± 0.7784

[tex]CI_p[/tex] = (7.32, 8.88)

c. Based on the difference in the range of the 95% confidence interval for the mean duration of cold symptoms of the group that take zinc lozenges, (3.83952, 5.16049), and the mean of the group that are on a placebo, (7.32, 8.88), there is sufficient statistical evidence to suggest that there is a difference between the mean and taking zinc lozenges reduces the overall duration of cold symptoms more than if taking placebo

d. The assumptions required for validity when carrying out a t-test include;

i) The measurement scale is ordinal or continuous

ii) The sample is a simple random sample

iii) The data gives a normal distribution curve

iv) The sample size is reasonably large

v) The variance are homogeneous

Among these assumptions, the data must be randomly sampled from the population of interest and that the data variables follow a normal distribution

The common assumptions made when doing a t-test include those regarding the scale of measurement, random sampling, normality of data distribution, adequacy of sample size and equality of variance in standard deviation

If both spinners are spun simultaneously, what is the probability that either spinner will land on orange?

5/64
5/8
3/8
4/64

Answers

Answer:

I am not completly sure, cause the answer might be a bit more complex but, for the spinner on the left 4/8 and the right 1/8 chances

Step-by-step explanation:

Answer: 5/8 is the correct answer.

Step-by-step explanation: The other dude is completely wrong.

what is the answer? becuase i am just confused

Answers

Answer:

Step-by-step explanation:

radius of circle is 12

also there is 2 right angles in the triangle if you wanted to solve this problem yourself

but here's the answer:

arc angle of the triangle inside the sircle is double the angle closest to x.

(the pointy area of the triangle is half the angle length of the arc)

i can add more though:

Solve the equation. 5 = g/8 what does g equal

Answers

Answer:

Step-by-step explanation:

multiply both sides by 8

do over and write g=8x5

solve 8x5=40

g=40

simplify
x2 + 6 − (3x2 − 2x − 5)

Answers

Your answer should be -2x^2+2x+11! I hope this helps!

Olivia went to a dance party. She paid $12 as an entry fee. Once inside the dance party, she paid $2 per snack. She started the night with $30 and spent all her money.


write an equation that represents this situation?

Pls help​

Answers

Answer:

30-12=18

18-18=0

Step-by-step explanation:

2x + 12 = 30

X represents the snacks, 2 represents the $2 per snack, 12 represents the $12 entry fee, and 30 represents the $30 Olivia had.

1. Two identical cubes each of total surface area of 6 cm2 are joined end to end. Which of the following is the total surface area of the cuboid so formed?

Answers

Answer:

10 cm³

Step-by-step explanation:

The total surface area of a cube = 6 cm²

The formula for the surface area of the cube is :

A = 6a², a is the side of the cube

6 = 6a²

a = 1 cm

Now, the length of the formed cuboid = 2 cm

Breadth = 1 cm

Height = 1 cm

Required volume of the formed cubiod is :

V = 2(lb+bh+hl)

Put all the values,

V = 2(2(1)+1(1)+2(1))

V = 10 cm³

So, the required volume of the formed cuboid is equal to 10 cm³

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