Una escalera de 131313 metros está recargada contra una pared cuando su base empieza a resbalar. Cuando la base está a 121212 metros de la pared, se mueve a una razón de 5\text{ m/s}5 m/s5, start text, space, m, slash, s, end text. En ese momento, ¿a qué razón está cambiando el ángulo \thetaθtheta entre el piso y la escalera?
Answers
Answer:
El ángulo entre el piso y la escalera está cambiando a una razón de -1 radian por segundo.
Step-by-step explanation:
Sea [tex]x[/tex] la distancia horizontal entre la pared y la base de la escalera y [tex]l[/tex] la longitud de la escalera, medidas en metros. Además, tenemos que [tex]\theta[/tex] es el ángulo entre la escalera y el piso, medido en radianes.
Si la pared y el piso son ortogonales entre sí, entonces podemos utilizar la siguiente relación trigonométrica que relaciona las variables anteriores:
[tex]\cos \theta = \frac{x}{l}[/tex] (1)
Por diferenciación implícita y la definición de razón de cambio tenemos que:
[tex]-\sin \theta \,\dot \theta = \frac{\dot x}{l}[/tex] (2)
Donde:
[tex]\dot x[/tex] - Razón de cambio de la distancia horizontal entre la pared y la base de la escalera, medida en metros por segundo.
[tex]\dot \theta[/tex] - Razón de cambio del ángulo entre el piso y la escalera, medida en radianes por segundo.
Pero tenemos que el seno del ángulo está definido por:
[tex]\sin \theta = \frac{\sqrt{l^{2}-x^{2}}}{l}[/tex] (3)
Si aplicamos (3) en (2), expandimos la ecuación como sigue:
[tex]-\frac{\sqrt{l^{2}-x^{2}}}{l}\,\dot \theta = \frac{\dot x}{l}[/tex]
[tex]\dot \theta = - \frac{\dot x}{\sqrt{l^{2}-x^{2}}}[/tex] (4)
Si tenemos que [tex]\dot x = 5\,\frac{m}{s}[/tex], [tex]l = 13\,m[/tex] y [tex]x = 12\,m[/tex], entonces la razón de cambio del ángulo es:
[tex]\dot \theta = -\frac{\left(5\,\frac{m}{s} \right)}{\sqrt{(13\,m)^{2}-(12\,m)^{2}}}[/tex]
[tex]\dot \theta \approx -1\,\frac{rad}{s}[/tex]
El ángulo entre el piso y la escalera está cambiando a una razón de -1 radian por segundo.
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Answers
Answer:
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Count the blocks and convert (you can also use an array.) Hope this helps you!
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