Use the activity series below to predict whether the following reactions will take place.

Answer:

70g Na

Explanation:

The sodium reacts with water as follows:

2Na + 2H2O → 2NaOH + H2

Where 2 moles of Na produce 1 mole of H2.

To solve this question we must find the moles of H2. With the balanced equation we can find the moles of Na and its mass as follows:

Moles H2:

PV = nRT; n = PV/RT

Where P is pressure = 1atm,

V is volume = 34L,

R is gas constant = 0.082atmL/molK

T is absolute temperature = 273.15K = 0°C

Replacing:

n = 1atm*34L/0.082atmL/molK*273.15K

n = 1.52 moles H2

Moles Na:

1.52 moles H2 * (2mol Na / 1mol H2) = 3.04 moles Na

Mass Na-Molar mass: 22.99g/mol-

3.04 moles Na * (22.99g / mol) =

Answer:

something cyan colored?

Answer:

Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

Explanation:

Density = mass / volume

Density of fuel = 700 g/ 1 gal

Therefore, the mass of fuel in 1 gallon = 700 g

The driver has 5.0 gallons of fuel in the tank.

The mass of 5.0 gallons of fuel = 5 × 700 = 3500 g of fuel

Equation of the combustion of fuel, C₅H₁₂ is given below:

C₅H₁₂ + 8 O₂ ---> 6 H₂O + 5 CO₂

1 mole C₅H₁₂ requires 8 moles of O₂

1 mole of C₅H₁₂ has a mass = 72 g

8 moles of O₂ has a mass = 256 g

Therefore, 300 g of O₂ will require 300 × (72/256) g of C₅H₁₂ = 84.375 g of C₅H₁₂

84.375 g of fuel is used by the car per lap;

20 laps will require 20 × 84.375 g of fuel = 1687.5 g of fuel.

Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

The systematic name for PbO₂ is lead dioxide.Therefore, the correct option is A.

Systematic names are a type of chemical nomenclature that follow a systematic set of rules to name chemical compounds. Lead dioxide (PbO₂) is a chemical compound composed of lead and oxygen. It is an oxide of lead and can also be called lead(IV) oxide.

The systematic name of the compound is derived by using the root word of the metal, “lead,” and adding the suffix “-dioxide” to indicate the two oxygen atoms. Thus, the systematic name for PbO₂ is lead-dioxide.Therefore, the correct option is A.

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The question is incomplete, but most probably the complete question is,

Give the systematic name for PbO₂?

A. Lead dioxide

B. Lead trioxide

C. Lead oxide

D. Lead azide

Answer:

0.86812566700000000000000

The binomial expansion of (1+2x)^7in ascending power of x is 0.868125.

The algebraic expression (x + y)n can be expanded according to the binomial theorem, which represents it as a sum of terms using separate exponents of the variables x and y.

Each word in a binomial expansion has a coefficient, which is a numerical value. A binomial is a two-term algebraic expression. Examples of binomials include a + b, x - y, and more.

When a binomial is raised to exponents 2 and 3, we can use a set of algebraic identities to determine the expansion. As an illustration, (a + b)2 = a2 + 2ab + b2.

By regrouping and combining like phrases, we can arrange our final response in ascending powers of x by placing the lowest power of x first and the highest power of x last.

Therefore, the binomial expansion of (1+2x)^7in ascending power of x is 0.868125.

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Explanation:

magnesium and sodium because they are minerals and part of iron

Answer:

B. A+ B → AB

Explanation:

general form of a synthesis reaction

Answer:

The number of moles is 6.01 moles.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

In this case:

Replacing:

2.56 atm* 56 L= n* 0.080 [tex]\frac{atm*L}{mol*K}[/tex]* 298 K

Solving:

[tex]n=\frac{2.56 atm*56 L}{0.080\frac{atm*L}{mol*K}*298 K}[/tex]

n= 6.01 mol

The number of moles is 6.01 moles.

Answer:

bro

Explanation:

bro

Answer: yes

Explanation:

Because of the mass

Answer:

Explanation:mckxmmxkmsskkskskskxisisisisisisisks

The question is incomplete, the complete question is:

A curium-245 nucleus is hit with a neutron and changes as shown by the equation. Complete the equation by filling in the missing parts.

[tex]_{96}^{245}\textrm{Cm}+_0^1\textrm{n}\rightarrow _{42}^{103}\textrm{Mo}+_{r}^{q}\textrm{p}+3_0^1\textrm{n}[/tex]

Answer: The complete equation formed is [tex]_{96}^{245}\textrm{Cm}+_0^1\textrm{n}\rightarrow _{42}^{103}\textrm{Mo}+_{54}^{140}\textrm{Xe}+3_0^1\textrm{n}[/tex]

Explanation:

The general representation of an isotope is given as:

[rex]_Z^A\textrm{X}[/tex]

where,

A is the mass number, Z is the atomic number and X is the symbol of the element

In a nuclear reaction, total atomic number and total mass number on either side of the reaction remains the same

For the given chemical reaction:

[tex]_{96}^{245}\textrm{Cm}+_0^1\textrm{n}\rightarrow _{42}^{103}\textrm{Mo}+_{r}^{q}\textrm{p}+3_0^1\textrm{n}[/tex]

On the reactant side:

Total atomic number = [96 + 0] = 96

Total mass number = [245 + 1] = 246

On the product side:

Total atomic number = [42 + r + 0] = 42 + r

Total mass number = [103 + q + 3] = 106 + q

Calculating for 'r' and 'q', we get:

[tex]96= 42 + r\\\\r=96-42=54[/tex]

[tex]246 = 106+q\\\\q=246-106=140[/tex]

Thus, the missing isotope is [tex]_{54}^{140}\textrm{Xe}[/tex]

Hence, the complete equation formed is [tex]_{96}^{245}\textrm{Cm}+_0^1\textrm{n}\rightarrow _{42}^{103}\textrm{Mo}+_{54}^{140}\textrm{Xe}+3_0^1\textrm{n}[/tex]

Answer: try 140 52 xe

Explanation:

Answer:

Explanation:

Hope this helps u!!

Answer:

The empirical formula is: CH2

Th powder is not vainillin

Explanation:

We can find empirical formula of a compound CₐHₓOₙ knowing that moles CO2 = Moles C, 2 Moles H2O = Moles H and that we can find the mass of oxygen by the difference of masses of the atoms:

Moles C = Moles CO2 -Molar mass: 44.01g/mol-

5.875g * (1mol/44.01g) = 0.1335 moles C * (12.01g/mol) = 1.60gC

Moles H2O and moles H -Molar mass: 18.01g/mol-

2.41g H2O * (1mol / 18.01g) = 0.1339 moles H2O * (2mol H / 1mol H2O) =

0.2676 moles H * (1g/mol) = 0.27g H

The empirical formula of this compound is the ratio of C:H:

0.2676 moles H / 0.1335 moles C = 2

The empirical formula is:

CH2

In vainillin, the moles of Carbon = Moles of Hydrogen. the experiment shows the moles of hydrogen are twice the moles of carbon. Thus, the powder is not vainillin

Diamond has the highest refractive index, causing the light wave to refract away from the boundary.

Option (C) is correct.

The key observation is that the light wave refracts away from the boundary. This suggests that the second medium has a higher index of refraction than glass. Among the given options, diamond has the highest refractive index, making it the most likely choice.

Diamond has a refractive index of approximately 2.42, which is significantly higher than that of water, air, and glass. When light travels from a medium with a lower refractive index (such as glass) to a medium with a higher refractive index (such as diamond), it bends towards the normal line. This causes the light wave to refract away from the boundary, as described in the scenario.

Therefore, the most plausible answer is that the second medium is diamond.

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Answer:

uryehrufurudududjehshsyshzyyxzhsu

Answer:

The Ice is Less Dense than the Water

Explanation:

I just answered this one myself, and the explanation is also just that Ice isn't dense enough to sink.

Answer:

starch or carbs - amylase

fat - lipase

protien - pepsim

Answer:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s¹4f¹⁴5d¹⁰

Explanation:

Answer:

ok

Explanation:

A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl -> H2O and NaCl.

Answer: In the reaction [tex]HCO^{-}_{3} + H_{2}O \rightarrow H_{3}O^{+} + CO^{2-}_{3}[/tex], [tex]H_{2}O[/tex] acts as a base because it has accepted a hydrogen ion or proton.

Explanation:

According to Arrhenius, species which dissociate to give hydrogen ions when dissolved in a solvent like water are called acid.

A species which readily accepts a hydrogen ion or proton is called a base.

For example, [tex]HCO^{-}_{3} + H_{2}O \rightarrow H_{3}O^{+} + CO^{2-}_{3}[/tex]

Here, [tex]HCO^{-}_{3}[/tex] is donating hydrogen ion. So, it is an acid whereas [tex]H_{2}O[/tex] is accepting the hydrogen ion. Hence, [tex]H_{2}O[/tex] is a base.

Thus, we can conclude that in the reaction [tex]HCO^{-}_{3} + H_{2}O \rightarrow H_{3}O^{+} + CO^{2-}_{3}[/tex], [tex]H_{2}O[/tex] acts as a base because it has accepted a hydrogen ion or proton.

Answer:

Ver explicación

Explanation:

El método científico se refiere al patrón establecido de resolución de un problema científico. Los siguientes son pasos importantes en el método científico;

Haz una observación.

formular preguntas relevantes.

elabore una hipótesis que pueda ser probada.

Diseña un experimento.

Prueba la hipótesis usando tu diseño experimental.

Teniendo en cuenta ambos escenarios, el último caso en el que estudiantes de diferentes capacidades trabajan juntos para resolver un problema refleja mejor el método científico porque pueden hacerse preguntas entre sí y llegar a hipótesis comprobables que pueden demostrarse como verdaderas o falsas mediante experimentos.

Answer: The correct option is D) [tex]Ag^+[/tex]

Explanation:

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when oxidation number of a species decreases.

For the given chemical reaction:

[tex]Zn^0+2Ag^+\rightarrow Zn^{2+}+2Ag^0[/tex]

On the reactant side:

Oxidation number of Zn = 0

Oxidation number of Ag = +1

On the product side:

Oxidation number of Zn = +2

Oxidation number of Ag = 0

As the oxidation number of Ag is decreasing from +1 to 0. Thus, [tex]Ag^+[/tex] is getting reduced.

Hence, the correct option is D) [tex]Ag^+[/tex]

Answer:

0.0178

Explanation:

because you can work out the amount of moles in KOH using moles = mass/mr.

The mr of the KOH is 39.1+16+1=56.1 so you do

[tex] \frac{3}{56.1} [/tex]

which equals to 0.053475 so u 3SF which is 0.0535moles

than u uses the molar ratio which is 3 to 1

so 0.0535÷3=0.0178 which is the moles of FeCl3.

hope this make sense:)

C - 4.32

Explanation:

.44 x 9.81

Answer:

180g

Explanation:

So, 10 mole of water will weigh (18x10) = 180g.

Answer: The enthalpy of the reaction is -1791.31 kJ.

Explanation:

Enthalpy change is the difference between the enthalpies of products and the enthalpies of reactants each multiplied by its stoichiometric coefficients. It is represented by the symbol [tex]Delta H^o_{rxn}[/tex]

[tex]\Delta H^o_{rxn}=\sum (n \times \Delta H^o_{products})-\sum (n \times \Delta H^o_{reactants})[/tex]        .....(1)

For the given chemical reaction:

[tex]3MnO_2(s)+4Al(s)\rightarrow 2Al_2O_3(s)+3Mn(s)[/tex]

The expression for the enthalpy change of the reaction will be:

[tex]\Delta H^o_{rxn}=[(2 \times \Delta H^o_f_{(Al_2O_3(s))}) + (3 \times \Delta H^o_f_{(Mn(s))})] - [(3 \times  \Delta H^o_f_{(MnO_2(s))}) + (4 \times \Delta H^o_f_{(Al(s))})][/tex]

Taking the standard heat of formation values:

[tex]\Delta H^o_f_{(Al_2O_3(s))}=-1675.7kJ/mol\\\Delta H^o_f_{(Al(s))}=0kJ/mol\\\Delta H^o_f_{(MnO_2(s))}=-520.03kJ/mol\\\Delta H^o_f_{(Mn(s))}=0kJ/mol[/tex]

Plugging values in the above expression:

[tex]\Delta H^o_{rxn}=[(2 \times (-1675.7))+(3 \times 0)] - [(3 \times (-520.03))+(4 \times 0)]\\\\\Delta H^o_{rxn}=-1791.31 kJ[/tex]

Hence, the enthalpy of the reaction is -1791.31 kJ.