Use the graph of △ABC with midsegments DE, EF and DF. Show that EF is parallel to AC and that EF=1/2 AC

Use The Graph Of ABC With Midsegments DE, EF And DF. Show That EF Is Parallel To AC And That EF=1/2 AC

Answers

Answer 1

According to the midsegment theorem, the midsegments are parallel to

and half the length of the opposite side.

The completed statement are as follows;

Because the slopes of [tex]\overline{EF}[/tex] and [tex]\overline{AC}[/tex] are both -4, [tex]\overline{EF}[/tex] ║ [tex]\overline{AC}[/tex]EF = [tex]\underline{\sqrt{17}}[/tex] and AC = [tex]\underline{2 \cdot \sqrt{17} }[/tex]Because [tex]\underline{\sqrt{17} }[/tex] = [tex]\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17} }[/tex], [tex]EF = \frac{1}{2} \cdot AC[/tex]

Reasons:

From the given graph of ΔABC, we have;

Coordinates of the points A, B, and C are; A(-5, 2), B(1, -2), and C(-3, -6)

The coordinates of the point D and E on [tex]\mathbf{\overline{DE}}[/tex] are; D(-4, -2), and E(-2, 0)

The coordinates of the point F is; F(-1, -4)

[tex]Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

[tex]\displaystyle Slope \ of \ line \ \overline{AC} = \mathbf{\frac{(-6) - 2}{-3 - (-5)} = \frac{-8}{2}} = -4[/tex]

[tex]\displaystyle Slope \ of \ line \ \overline{EF} = \frac{0 - (-4)}{-2 - (-1)} = \frac{4}{-1} = -4[/tex]

[tex]Length \ of \ segment,\ l = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]

Length of EF  = √((-1 - (-2))² + (-4 - 0)²) = √(17)

Length of AC = √((-3 - (-5))² + (-6 - 2)²) = √(4 × 17) = 2·√(17)

Therefore, we have;

Because the slope of [tex]\mathbf{\overline {EF}}[/tex] and [tex]\mathbf{\overline {AC}}[/tex] are both , -4, [tex]\overline {EF}[/tex] ║ [tex]\overline {AC}[/tex]. EF = [tex]\underline{\sqrt{17}}[/tex], and AC

= [tex]\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}[/tex],. Because [tex]\underline{\sqrt{17}}[/tex] = [tex]\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}[/tex], [tex]EF =\mathbf{ \frac{1}{2} AC}[/tex]

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Answer:

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Step-by-step explanation:

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If x is not equal to zero, what is the value of [tex]\frac{4(3x)^2}{(2x)^2}[/tex]

Answers

Answer:

[tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = 9 ,\ x \neq 0[/tex]

General Formulas and Concepts:

Pre-Algebra

Evaluations

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Distributive Property

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle \frac{4(3x)^2}{(2x)^2}[/tex]

Step 2: Simplify:

Rewrite [Exponential Distributive Property]:                                                  [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = \frac{4(3^2x^2)}{2^2x^2}[/tex][Order of Operations] Evaluate exponents:                                                   [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = \frac{4(9x^2)}{4x^2}[/tex][Order of Operations] Multiply:                                                                        [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = \frac{36x^2}{4x^2}[/tex]Simplify:                                                                                                            [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = \frac{36}{4} ,\ x \neq 0[/tex][Order of Operations] Divide:                                                                          [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = 9 ,\ x \neq 0[/tex]

[tex]\\ \sf\longmapsto \dfrac{4(3x)^2}{(2x)^2}[/tex]

[tex]\\ \sf\longmapsto\dfrac{ 4(9x^2)}{4x^2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{36x^2}{4x^2}[/tex]

Take x^2 common and cancel.

[tex]\\ \sf\longmapsto \dfrac{x^2}{x^2}\left(\dfrac{36}{4}\right)[/tex]

[tex]\\ \sf\longmapsto \dfrac{36}{4}[/tex]

[tex]\\ \sf\longmapsto 9[/tex]

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Answers

Answer:

x=15

Step-by-step explanation:

360-330=30

30/2=15

x=15

hope that helps

please mark as brainliest if correct

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Answer:

In geometry, you will write a line segment using the letters for each of the end points and a line over the top of the letters.

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Answer:

Step-by-step explanation:

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Answers

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What are Equivalent Expressions?

Expressions that have the same value are said to be equivalent expressions.

Evaluate 3+2x−9−4x+11+5x−x:

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Add like terms together

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Answer:

Step-by-step explanation:

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Answers

Answer:

3/5

Step-by-step explanation:

so first of all...

out of

300

students,

180

are boys.

180/300

which, simply by 60

3/5

so.. 3/5 of the people at rsm (whatever that is) summer  camp are boys! Explanation isn't good, but you didn't really ask for it so i think you're ok... I guess. Now i just need an answer to my problem...

In rsm summer camp, fraction of boys is 3/5.

What is a fraction?

A fraction is a numeral that represents a rational number.

Let a and b be two numbers, then their fraction can be represented as a/b.

Given that,

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Total number of boys at rsm summer camp = 180.

To find the fraction of boys to all students.

Fraction of boys = number of boys / total number of students

                           = 180 / 300
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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:


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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

Let the sister's age = x

Marco's age = 2*x - 5

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Answers

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Step-by-step explanation:

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Step Two: 3 - (2 x 1) = 1

Step Three: 1 1/2

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Answers

Answer:

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Step-by-step explanation:

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Make sure to review composite functions


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Answers

Answer

the area is 26 cm

Step-by-step explanation:

for the first part well call it box C box c is 2 cm by 1 cm the area of that box is 2 because 2 x 1 =2

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Answers

Answer:

-16-7y/3

Step-by-step explanation:

-3x+7y=-16

Subtract 7y from both sides

-3x=-16-7y

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x=-16-7y/3

solve one step equation

x/-2 = -3

Answers

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Answer:

x=6

Step-by-step explanation:

x/-2=-3

*-2    *-2

x=6

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Brainliest reward need brief working out

Answers

Answer:

  1. 125 cm³; 88.8 cm³; 1650 cm³; 0.11 m³

  2. about 1.47 kg

  3. can't tell what the volume of 1 jar is

Step-by-step explanation:

The relationship between volume, mass, and density is ...

  mass = volume × density

Solving for volume, we find ...

  volume = mass ÷ density

__

(a) 50 g/(0.4 g/cm³) = 125 cm³

(b) 770 g/(8.67 g/cm³) ≈ 88.8 cm³ . . . (rounded to 3 significant figures)

(c) 4000 g/(2.42 g/cm³) ≈ 1650 cm³ . . . (rounded to 3 significant figures)

(d) 80 kg/(720 kg/m³) ≈ 0.11 m³ . . . (rounded to 2 significant figures)

_____

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  V = πr²h

  V = π(4 cm)²(15 cm) = 240π cm³ ≈ 754.0 cm³

Using the above relation, we find the mass to be ...

  mass = (754.0 cm³)(1.95 g/cm³) ≈ 1470 g = 1.47 kg

_____

We cannot tell if the volume of each jar is 360 liters, or if that is the total volume of all 6 jars. Either way, we suspect a units problem, as the jars would have to be extremely large and unusually thin relative to what we usually think of as a jar for jam (0.77 m diameter; 0.2 mm thick). The density of the jam would be roughly 10 times the density of air, if that is the volume of all 6 jars. The problem would be more sensible if the units of volume were mm³, and the given volume is that of one jar.

The mass of jam in one jar is (5400/6 -200) = 700 g. Divide that by what you think the volume of one jar is in cm³ to find the density in g/cm³. (For comparison, the density of air is about 0.0012 g/cm³.)

_____

Additional comment

We have rounded the answers to 2 or 3 significant figures. In most cases, this is more than would be justified by the number of significant figures in the given measurements. For purposes of ongoing calculations, it is useful to keep intermediate results to at least 1 more significant figure than required for the answer.

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