Use the graph to calculate the instantaneous rate of formation of HBr at 50 s

Express your answer using one significant figure.

Answer:

pH = 3.68

Explanation:

We can solve this problem by using Henderson-Hasselbach's equation:

Assuming we have 1 L of the buffer solution then the molar concentrations of formate and formic acid would be:

We now have all required data to calculate the pH:

Answer:

The cation affects the intensity of the color more than the color of the solution.

Explanation:

According to Beer Lambert law, the intensity of the colour of the solution depends on the concentration of the specie responsible for the colour in the solution.

Let us recall that transition metal compounds are coloured in solution due to electronic transitions.

Therefore, the cation affects the intensity of the color more than the color of the solution.

Answer:

[tex]pH = - log[H {}^{ + } ] \\ = - log(0.0000067) \\ pH = 5.17[/tex]

Answer:

[tex]x = 2[/tex]

Explanation:

General formula for alkanes

[tex]C _{n}H _{2n + 2}[/tex]

since H = 6

[tex]2n + 2 = 6 \\ 2n = 4 \\ n = 2 \\ since \: x = n\\ \therefore \: x = 2[/tex]

Answer:

x=2

Explanation:

Because alkanes have a general formula of CnH(2n+2).

We known that 2n+2=6, so we solve for n.

2n+2=6

2n=4

n=2

Thus, there are 2 carbon atoms.

Answer:

300m/s is the average molecular speed of Ne

Explanation:

Based on Graham's law, the ratio of speed of two gases under constant temperature is equal to the square root of the inverse of their molar masses. The equation is:

v1 / v2 = √m2 / √m1

Where v is the speed of the gas and m the molar mass of the gas

Assuming gas 1 is Argon and gas 2 is Neon:

v1 = 213m/s

v2 = ?

m2 = 20.18g/mol

m1 = 39.948g/mol

213m/s / v2 = √20.18g/mol / √39.948g/mol

v2 = 213m/s / 0.71074

v2 = 300m/s is the average molecular speed of Ne

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

[tex]PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)[/tex]

Lo cual hace que la expresión de equilibrio se calcule como:

[tex]Ksp=[Pb^{2+}][Cl^-]^2[/tex]

Y que en términos de la solubilidad molar, s, se resuelve como:

[tex]1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L[/tex]

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

[tex]s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L[/tex]

¡Saludos!

Answer:

A (True)

Explanation:

Because ibuprofen has a chiral carbon center (carbon bonded to 4 distinct groups of atoms).

This means that a mixture of ibuprofen can rotate plane-polarized light equally in both the clockwise and counterclockwise direction.

Answer:true

Explanation: ibuprofen is commonly used for most pain, aches ect

Answer:

Electrolysis of water is the process of using electricity to decompose water into oxygen and hydrogen gas. Hydrogen gas released in this way can be used as hydrogen fuel, or remixed with the oxygen to create oxyhydrogen gas, which is used in welding and other applications.Ordinarily, the freezing point of water and melting point is 0 °C or 32 °F. The temperature may be lower if supercooling occurs or if there are impurities present in the water which could cause freezing point depression to occur. Under certain conditions, water may remain a liquid as cold as -40 to -42°

Explanation:

Answer:

5.81 moles

Explanation:

To find the number of moles (n) in 3.5 x 10²⁴ molecules of methane gas, we divide the number of molecules by Avagadro's number (nA). That is,

n = number of molecules ÷ 6.02 × 10²³

According to this question, 3.5 x 10^24 molecules of methane gas was given, hence,

n = 3.5 × 10²⁴ ÷ 6.02 × 10²³

n = 3.5/6.02 × 10(24 - 23)

n = 0.5814 × 10¹

n = 5.81 moles

Answer:

0.1 M NaOH, 3 M NH3, 0.01 M CH3COOH, 0.01 M H2SO4, 0.1 M HCl

Explanation:

Strong acids are more acids than weak acids. In the same way, strong bases are more basic than weak bases that are in the same concentration.

Then, the more concentrated acid or base will be more acidic or basic.

CH3COOH. Weak acid

NaOH. Strong base

H2SO4. Strong acid

NH3. Weak base.

HCl. Strong acid

The less acid (More basic):

Strong base, weak base, weak acid, diluted strong acid, undiluted strong acid

Answer:

Atmospheric water generator is used in regions that have scarcity of water or have polluted water. These generators are reliable sources of clean and safe water and hence reduces dependency on bottled water.

Atmospheric water generator extract water from the air (humid air) through condensation. Extracted water then cools down to temperature below its dew point  thereby producing potable drinking water.

Explanation:

Atmospheric water generator is used in regions that have scarcity of water or have polluted water. These generators are reliable sources of clean and safe water and hence reduces dependency on bottled water.

Atmospheric water generator extract water from the air (humid air) through condensation. Extracted water then cools down to temperature below its dew point  thereby producing potable drinking water.

Answer:

A device that collects water from humid ambient air is known as an atmospheric water generator. Condensation is the process of extracting water vapor from the air by chilling it below its dew point, exposing it to desiccants, or pressurizing it. An AWG, unlike a dehumidifier, is meant to make the water drinkable. Because there is nearly always a little amount of water in the air that may be collected, AWGs are useful in situations where clean drinking water is difficult or impossible to get. Cooling and desiccants are the two most common ways used.

Explanation:

Answer:

151 g/mol

Explanation:

In order to solve this problem we need to keep in mind the formula for the boiling point elevation:

Where:

Input the data and calculate m:

We now can calculate the number of moles of the substance, using the definition of molarity:

In this case kg of solvent = 90.0 g / 1000 = 0.090 kg

Finally we calculate the molar mass, using the number of moles and the mass:

Explanation:

the answer is clay as seen from the picture

Answer:

[tex]1.74molNO_2[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to perform mole-mass relationships by using the molar mass of the involved substance, in this case NO2, which is 46.0 g/mol; then we just set up a conversion factor like the one shown below:

[tex]80g*\frac{1mol}{46g}\\\\1.74molNO_2[/tex]

Regards!

Answer:

Both reactions are acid-base reactions

Explanation:

An acid base reaction is a reaction that occurs between an acid and a base. This reaction often leads to the formation of a salt in the process. The nature of the salt depends on the type of acid and base that reacted in the process.

Both HNO3 and H2SO4 are strong acids. However, ammonia is a weak base. The acid base reaction between ammonia and these strong acids is shown below;

HNO3(aq) + NH3(aq) ------>NH4NO3(aq)

H2SO4(aq) + 2NH3(aq) ----> (NH4)2SO4(aq)

Answer:

Answer to number one

Explanation:

Polyethylene terephthalate (PET) is a plastic material used for milk packaging.

Answer: For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is K = [ H+] [NO2-] / [HNO2].

Explanation:

An expression that depicts the ratio of products and reactants raised to the power of their coefficients at equilibrium is called equilibrium constant.

An equilibrium constant is denoted by the symbol 'K'.

For example, the dissociation of nitrous acid in aqueous solution is as follows.

[tex]HNO_{2} \rightleftharpoons H^{+} + NO^{-}_{2}[/tex]

Hence, its expression for equilibrium constant is as follows.

[tex]K = \frac{[H^{+}][NO^{-}_{2}]}{[HNO_{2}]}[/tex]

Thus, we can conclude that for the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is K = [ H+] [NO2-] / [HNO2].

Answer:

The order of sub-energy levels ( s » p » d » f )

The number of orbitals ( s » 2 ), ( p » 6), ( d» 10), ( f » 14 )

Answer:

Easy my dude let me help you out

A.In

B.27

C.73

D.49

E.56

F.56

G.114

H.180

Also with protons and electrons they equal the same atomic number

Answer:

n-hexane

2-methylpentane

3-methylpentane

2,2-dimethylbutane

2,3-dimethylbutane

Explanation:

There are 5 structural isomers of C6H14.

n-hexane

2-methylpentane

3-methylpentane

2,2-dimethylbutane

2,3-dimethylbutane

Answer:

A. Mass of KMnO₄ = 316.08 g

B. Mass of KMnO₄ = 41.49 g

C. Mass of KMnO₄ = 0.13 g.

Explanation:

A. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 1 L

Molarity = 2 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 2 × 1

Mole of KMnO₄ = 2 moles

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 2 moles

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 2 × 158.04

Mass of KMnO₄ = 316.08 g

B. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 350 mL = 350/1000 = 0.35 L

Molarity = 0.75 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 0.75 × 0.35

Mole of KMnO₄ = 0.2625 mole

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 0.2625 mole

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 0.2625 × 158.04

Mass of KMnO₄ = 41.49 g

C. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 80 mL = 80/1000 = 0.08 L

Molarity = 0.01 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 0.01 × 0.08

Mole of KMnO₄ = 0.0008 mole

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 0.0008 mole

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 0.0008 × 158.04

Mass of KMnO₄ = 0.13 g

Answer: hello your question is poorly written below is the complete question

answer:

For N1 :  sp³  orbital

For N2:  p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

Explanation:

Determining the type of orbital in which the lone pair on each N atom will reside.

From the configuration attached below we can determine the type of orbital and they are ;

For N1 :  sp³  orbital

For N2:  p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

Answer:

B. There is a very large percentage of C-12.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize that, since the average atomic mass is 12.01 amu, then the C-12, with an atomic mass of 12.000 am prevails over C-13 with an atomic mass of 13.003 amu as long as the average is nearer to the former.

In such a way, the answer will be B. There is a very large percentage of C-12.

Regards!

Answer:WHAT GRADE WORK IS THIS ?

Explanation:

Answer:

[tex][Cl_2]=[Br_2]=0.856M[/tex]

[tex][BrCl]=0.229M[/tex]

Explanation:

Hello there!

In this case, for this chemical equilibrium problem, it turns out possible for us to solve for the equilibrium concentrations by firstly setting up the equilibrium expression:

[tex]Keq=\frac{[BrCl]^2}{[Cl_2][Br_2]}[/tex]

Thus, by plugging in an ICE chart, in terms of x (reaction extent), we can write:

[tex]7.20=\frac{(2x)^2}{(0.200-x)^2}[/tex]

And could be solved for x as follows:

[tex]\sqrt{7.20} =\sqrt{\frac{(2x)^2}{(0.200-x)^2} } \\\\2.68=\frac{2x}{0.200-x} \\\\x=0.1146M[/tex]

Therefore, the equilibrium concentrations turn out to be:

[tex][Cl_2]=[Br_2]=0.200M-0.1146M=0.856M[/tex]

[tex][BrCl]=2*0.1146M=0.229M[/tex]

Regards!

Answer:

C2H4I2

Explanation:

Viscosity of a fluid has to do with the internal friction between the internal layers of the fluid.

Molecular weight is found to be related to the viscosity of a fluid even though the relationship may not be strictly linear.

However, the greater the molecular weight of a substance, the greater the viscosity of the material.

Since C2H4I2 has the greatest molecular weight (281.86 g/mol), it is also expected to display the greatest viscosity among all the compounds listed in the question.

Answer:

compound light microscope